© 2015 Pearson Education, Inc. Clicker Questions Chapter 6 Barbara Mowery York College.

Clicker Questions

Chapter 6

Barbara Mowery

York College

The wavelength of a photon multiplied by its frequency equals

a. c, the speed of light.

b. h, Planck’s constant.

c. Avogadro’s Number.

d. 4.184.

The wavelength of a photon multiplied by its frequency equals

d. 4.184.

The energy of a photon divided by its frequency equals

d. 4.184.

The energy of a photon divided by its frequency equals

d. 4.184.

The “rainbow of colors” produced by sunlight striking a prism is called

a. a continuous spectrum.

b. monochromatic light.

c. a line spectrum.

d. a Balmer series.

The “rainbow of colors” produced by sunlight striking a prism is called

a. a continuous spectrum.

b. monochromatic light.

c. a line spectrum.

d. a Balmer series.

The lowest energy state of a hydrogen atom is called its _______ state.

a. bottom

b. ground

c. fundamental

d. original

The lowest energy state of a hydrogen atom is called its _______ state.

a. bottom

b. ground

c. fundamental

d. original

When an electron moves from the n = 3 orbit to the n = 2 orbit of a hydrogen atom, what wavelength of light is emitted?

a. 410 nm

b. 434 nm

c. 486 nm

d. 656 nm

a. 410 nm

b. 434 nm

c. 486 nm

d. 656 nm

a. 410 nm

b. 434 nm

c. 486 nm

d. 656 nm

a. 410 nm

b. 434 nm

c. 486 nm

d. 656 nm

“It is impossible to simultaneously know both the position and the momentum of an electron in an atom” is

a. Hund’s rule.

b. deBroglie’s hypothesis.

c. Pauli’s exclusion principle.

d. Heisenberg’s uncertainty principle.

“It is impossible to simultaneously know both the position and the momentum of an electron in an atom” is

a. Hund’s rule.

“No two electrons in an atom may have the same values for all four quantum numbers” is

a. Hund’s rule.

“No two electrons in an atom may have the same values for all four quantum numbers” is

a. Hund’s rule.

The line spectrum of hydrogen includes lines at 447, 502, 587, and 668 nm. The line at ___ nm represents the most energetic transition.

a. 447 b. 502

c. 587 d. 668

The line spectrum of hydrogen includes lines at 447, 502, 587, and 668 nm. The line at ___ nm represents the most energetic transition.

a. 447 b. 502

c. 587 d. 668

Which sequence lists types of electromagnetic energy in order of increasing energy?

a. microwave, IR, visible, UV

b. IR, microwave, UV, visible

c. UV, visible, IR, microwave

d. visible, UV, microwave, IR

Which sequence lists types of electromagnetic energy in order of increasing energy?

a. microwave, IR, visible, UV

b. IR, microwave, UV, visible

c. UV, visible, IR, microwave

d. visible, UV, microwave, IR

n and l are the principal and angular momentum quantum numbers. When n = 3, the allowed values of l are

a. 1, 2, and 3.

b. 1 and 2.

c. 0, 1, 2, and 3.

d. 0, 1, and 2.

n and l are the principal and angular momentum quantum numbers. When n = 3, the allowed values of l are

a. 1, 2, and 3.

b. 1 and 2.

c. 0, 1, 2, and 3.

d. 0, 1, and 2.

Which set of quantum numbers correctly describes an electron in the outermost orbital of a sulfur atom?

a. n = 3, l = 2, ml = –2

b. n = 2, l = 1, ml = –1

c. n = 2, l = 0, ml = 0

d. n = 3, l = 1, ml = –1

Which set of quantum numbers correctly describes an electron in the outermost orbital of a sulfur atom?

a. n = 3, l = 2, ml = –2

b. n = 2, l = 1, ml = –1

c. n = 2, l = 0, ml = 0

d. n = 3, l = 1, ml = –1

Which set of values is not correct for an electron occupying a 4d orbital?

a. n = 4, l = 2, ml = 0

b. n = 4, l = 2, ml = –1/2

c. n = 3, l = 4, ml = 1

d. n = 3, l = 1, ml = 1

Which set of values is not correct for an electron occupying a 4d orbital?

a. n = 4, l = 2, ml = 0

b. n = 4, l = 2, ml = –1/2

c. n = 3, l = 4, ml = 1

d. n = 3, l = 1, ml = 1

The only allowed values for the spin magnetic quantum number are

a. 0 and 1.

b. 0 and +1/2.

c. +1/2 and 1.

d. +1/2 and –1/2.

The only allowed values for the spin magnetic quantum number are

a. 0 and 1.

b. 0 and +1/2.

c. +1/2 and 1.

d. +1/2 and –1/2.

s orbitals are shaped like

a. four-leaf clovers.

b. dumbbells.

c. spheres.

d. triangles.

s orbitals are shaped like

b. dumbbells.

c. spheres.

d. triangles.

p orbitals are shaped like

b. dumbbells.

c. spheres.

d. triangles.

p orbitals are shaped like

b. dumbbells.

c. spheres.

d. triangles.

At a node, the probability of finding an electron is ___ %.

d. 100

At a node, the probability of finding an electron is ___ %.

d. 100

The electron configuration of a carbon atom is

a. [He]2s22p6.

b. [He]2s22p4.

c. [He]2s22p2.

d. [He]2s2.

The electron configuration of a carbon atom is

a. [He]2s22p6.

b. [He]2s22p4.

c. [He]2s22p2.

d. [He]2s2.

The electron configuration of a germanium atom is

a. [Ar]4s24p2.

b. [Ar]4s23d104p2.

c. [Kr]4s23d104p2.

d. [Kr]4s23d104p2.

The electron configuration of a germanium atom is

a. [Ar]4s24p2.

b. [Ar]4s23d104p2.

c. [Kr]4s23d104p2.

d. [Kr]4s23d104p2.

The electron configuration of a copper atom is

a. [Ar]4s23d9.

b. [Ar]4s13d10.

c. [Ar]4s23d10.

d. [Ar]4s23d7.

The electron configuration of a copper atom is

a. [Ar]4s23d9.

b. [Ar]4s13d10.

c. [Ar]4s23d10.

d. [Ar]4s23d7.

The valence electron configuration of elements in column 6A(16) of the Periodic Table is

a. np6.

b. ns0np6.

c. ns2np4.

d. impossible to predict because each element is unique.

The valence electron configuration of elements in column 6A(16) of the Periodic Table is

a. np6.

b. ns0np6.

c. ns2np4.

d. impossible to predict becauseeach element is unique.

© 2015 Pearson Education, Inc. Clicker Questions Chapter 6 Barbara Mowery York College.

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