Post on 27-Jul-2015
2du
xdx
u = x2 - 5
v= 2x2
4dv
xdx
2 2
2 2
(2 )(2 ) ( 5)(4 )
(2 )
dy x x x x
dx x
3 3
4
4 4 20
4
dy x x x
dx x
3
5dy
dx x
2
2
x -5y=
2x
1Differentiate with respect to x.
2+5x
u=1
du=0
dx
v=2+5x
dv=5
dx
2 2
dy (2+5x)0-1(5) -5= =
dx (2+5x) (2+5x)