Post on 06-Nov-2015
Jawab :
FAy
A
FAx 60 75 45
90
60 B
45 15
C W
Joint A
FAy
FAx
B
C
FC
x
MA =
= FCx . AC cos 30
= FCx .
Cx .
2W = 3 FCx
Cx
FAx = FCx
FAy = W
FAB cos 45 + FAC cos 60 = FAX
FAB +
FAC =FAX
FAB +FAC = 2 FAX
FAY =
FAC -
FAB
Joint C A
45 B
FCX
C
FCX + FAC cos 60 = FCB cos 15
FCX +
FAC = 0.96 FCB
FAC sin 60 = FCB Sin 15
FAC = 0.26 FBC
15