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Feb,2012

Eng.Mohammed Elasmer

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2

MatLab :Matrix Laboratory

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3

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5

14

Compute:

e and 382801 to 15 digits .Which is bigger?

>> format long; [exp(14), 382801*pi]

ans =

1.0e+006 *

1.202604284164777 1.202604809386827

The second number is bigger.

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6

The fractions : 2709/1024 , 10583/4000 , 2024/765

which of these is the best approximation to 7

[2709/1024, 10583/4000, 2024/765, sqrt(7)]

ans =

2.645507812500000 2.645750000000000 2.645751633986928 2.645751311064591

The third, that is, 2024/765, is the best approximation

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7

Solve:

+ +

+ 1

6 3

3x 4y 5z = 2

2x 3y 7z

x y z

[x, y, z] = solve('3*x + 4*y + 5*z = 2',

'2*x - 3*y + 7*z = -1', 'x - 6*y + z = 3',

'x', 'y', 'z')

x =241/92

y =-21/92

z =-91/92

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8

2 2simplify: cos sinx x

syms x y

simplify((cos(x)).^2-(sin(x)).^2)

ans = 2*cos(x)^2-1

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randint>> help randint

RANDINT Generate matrix of uniformly distributed

random integers.

>> randint(1,4)

ans = 0 0 1 1

>> randint(1,4,[-1 1])

ans = -1 0 1 -1

>> randint(2,4,[10 12])

ans = 10 12 11 11

12 12 12 12

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10

Figure Palette (subplot)

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11

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12

Solving Equation

2x 2x 4 = 0 >> solve('x^2 - 2*x - 4 = 0')

ans = 5^(1/2)+1

1-5^(1/2)

>> double(ans)

ans = 3.2361

-1.2361

% or

>> roots([1 -2 -4])

ans =

3.2361

-1.2361

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13

Loops

10! 10*9*8*...*2*1

f = 1;

for n = 2:10

f = f*n;

end

f

f = 3628800>> factorial(10)

ans =3628800

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14

While

i = 1

i = 2

i = 3

i=0

while i<3

i=i+1

end

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15

f = 1;

for n = 2:10

f = f*n;

pause

f

end

Pause in Loops

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16

Break

y=0;

while y>0

A=input('enter the value of A= ')

y=y+A

if y>10;

break

end

end

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17

Loopsx=[ ];

for i=1:4

x=[x,i^2]

end

x = 1

x = 1 4

x = 1 4 9

x = 1 4 9 16

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18

Compute the absolute value of a real number

x=input('enter the number= ');

if x >= 0

y = x;

else

y = -x;

end

If

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19

If

function y = signum(x)

if x > 0

y = 1;

elseif x == 0

y = 0;

else

y = -1;

end

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5

1

If : [2, 2,3,1,8]

and ( )

Write a Matlab code to get the value of y

n

x

y x n

x=[2 2 3 1 8];

y=0;

for i=1:5;

y=x(i)+y;

end

or

>> sum(x)

ans= 16

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21

5

1

Given: [2, 2,3,1,8]

and ( ) ( ) * , k=1,2,3,4,5

Write a Matlab code to get the value of y

n

x

y k x n k

x=[2,2,3,1,8];

y=zeros(1,5);

for k=1:5;

for n=1:5;

y(k)=y(k)+x(n)*k;

end

end

y = 16 32 48 64 80

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22

2015

1510

100

2

0

5.0

][

n

n

n

nx

x=0:0.1:20;

y=0.5*(x<10)+0*(x>=10 & x<15) -2*(x>=15 & x<=20);

plot(x,y)

0 10 20-2

-1

0

1

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23

15 9

[ ] 5 0 9

2 0

x

f x x

x

x=-10:0.01:30 ;

for k=1:length(x)

if x(k)>=9

y(k)=15;

elseif x(k)>=0

y(k)=5;

else

y(k)=2;

end

end

plot(x,y)-10 0 10 20 300

5

10

15

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24

theta=320;

if(theta>=0 & theta<90)

y=1;

elseif(theta>=90 & theta<180)

y=2;

elseif(theta>=180 & theta<270)

y=3;

else

y=4;

end

y

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25

Switch …case

Your lost

angle = 80;

switch angle

case 0

disp('East')

case 90

disp('North')

case 180

disp('West')

case 270

disp('South')

otherwise

disp('Your lost')

end

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26

< less than

> greater than

<= less than or equal

>= greater than or equal

== equal

~= not equal

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27

>> x=[1 0 1 1 0];

>> y=[0 1 1 0 1];

>> x&y

ans = 0 0 1 0 0

>> x|y

ans = 1 1 1 1 1

>> ~x

ans = 0 1 0 0 1

>> xor(x,y)

ans = 1 1 0 1 1

& and | or

~ not xor

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Let A=[5 17 -3 8 0 -1 12 15 20 -6 6 4 -7 16].

write code that doubles the element that are :

positive and are divisible by 3 or 5,

and raise to the power of 3 the element that are:

negative but greater than -5

Hint

Use OR | , AND & , rem(a,b)

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Let y=[5 17 -3 8 0 -1 12 15 20 -6 6 4 -7 16].

write code that doubles the element that are :

positive and are divisible by 3 or 5,

and raise to the power of 3 the element that are:

negative but greater than -5

Hint

Use OR | , AND & , rem(a,b)

y = [5 17 -3 8 0 -1 12 15 20 -6 6 4 -7 16].

out=[10 17 -27 8 0 -1 24 30 40 -6 12 4 -7 16].

Example:

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y=[5 17 -3 8 0 -1 12 15 20 -6 6 4 -7 16];

A=y;

for x=1:length(y);

if y(x)>=0&rem(y(x),3)==0|rem(y(x),5)==0

y(x)=2*y(x);

elseif y(x)<0&y(x)>-5

y(x)=y(x)^3;

end

end

[A;y]

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Let y=[5 17 -3 8;0 -1 12 15;20 -6 6 4];

write code that doubles the element that are :

positive and are divisible by 3 or 5,

and raise to the power of 3 the element that are:

negative but greater than -5

Hint

Use OR | , AND & , rem(a,b)

Repeat if :

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y=[5 17 -3 8;0 -1 12 15;20 -6 6 4];

A=y;

[a,b]=size(y);

for i=1:a;

for j=1:b;

if y(i,j)>=0&rem(y(i,j),3)==0|rem(y(i,j),5)==0

y(i,j)=2*y(i,j);

elseif y(i,j)<0&y(i,j)>-5

y(i,j)=y(i,j)^3;

end

end

end

A

y

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33

>> help bi2de

BI2DE Convert binary vectors to decimal

numbers.

>> B = [0 0 1 1; 1 0 1 0]

B =

0 0 1 1

1 0 1 0

>> D = bi2de(B,'left-msb')

D =

3

10

bi2de

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34

>> B = de2bi([3;10],'left-msb')

B = 0 0 1 1

1 0 1 0

de2bi

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35

dec2hex & hex2dec >> dec2hex(12)

ans =C

>> dec2hex(18)

ans =12

>> dec2hex(26)

ans =1A

>> hex2dec('1A')

ans =26

>> hex2dec('12')

ans =18

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>> help mod

MOD Modulus after division.

Modulus

>> mod(9,3)

ans = 0

>> mod(10,3)

ans =1

>> mod(11,3)

ans =2

>> mod(3,9)

ans =3

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37

Convert Point P(1,3,5) form Cartesian to spherical

( , , ) (5.91,32.31 ,71.56 )o or

>> [phi,theta,r]=cart2sph(1,3,5)

phi =1.2490

theta =1.0069

r =5.9161

cart2sph

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38

Convert Point P(1,3,5) form Cartesian to spherical

Sph2cart(phi,theta,r)

>> [x,y,z]=sph2cart(1.249,1.0069,5.916)

x =1.0001

y = 2.9997

z =5.0001

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39

pol2cart(phi,rho,z)

>> [X,Y,Z] = pol2cart(pi/6,2,5)

X =1.7321

Y =1.0000

Z =5

Convert Point P(2,pi/6,5) form cylindrical to Cartesian

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cov Covariance matrix

max Largest elements in array

mean Average or mean value of array

median Median value of array

min Smallest elements in array

mode Most frequent values in array

std Standard deviation

var Variance

Descriptive Statistics

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>> x=[60 70 62 73 75 70 80 90 99 100];

>> var(x)

ans =201.6556

>> std(x)

ans =14.2005

>> mean(x)

ans =77.9000

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>> median([1 2 3 4 5])

ans =3

>> median([1 2 3 4 5 6])

ans =3.5000

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>> A=[1,2,3;4,5,6;7,8,9];

>> xlswrite('data.xls',A)

xlswriteWrite Microsoft Excel spreadsheet file

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Read Microsoft Excel spreadsheet file

xlsread

>> y=xlsread('data.xls')

y = 1 2 3

4 5 6

7 8 9

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Database>>E(1)=struct('Name','Ali','Age','24','Phone','12355');

>>E(2)=struct('Name','Ahmed','Age','23','Phone','99324');

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Database>>E(1)=struct('Name','Ali','Age','24','Phone','12355');

>>E(2)=struct('Name','Ahmed','Age','23','Phone','99324');

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Eng.Mohammed Elasmar