Report - Izvodi - elfak.ni.ac.rs · 6 = 2e2x(e2x +1)¡(e2x ¡1)2e2x e4x +2e2x +1+e4x ¡2e2x +1 2e2x(e2x +1¡e2x +1) 2(e4x +1)2e2x e4x +1 d) y0 = µ esinx +ecosx sinx¡cosx ¶0 esinx +ecosx

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