Report - SQL · 2018. 9. 9. · 8/13/2018 15 18 or z = substr(s,mod(ind-1,9)-8+lp*9,1) 19 or z = substr(s,mod(trunc((ind-1)/3),3)*3 20 +trunc((ind-1)/27)*27+lp 21 +trunc((lp-1)/3)*6,1) 22

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