∆= = 0.01 v / kg
* = 1.04 v / kg
∆v= = = 9.61x10-3 ⇔ 0.01
∆v= - = 0.01 y si Rf = 100 Ω entonces Ri = 10 KΩ
∆out = = 5x10-4 A/
∆I = =
+1 =
Rf = -1 * Ri
Si Ri= 1KΩ
Rf = - 1 * 1KΩ = 49KΩ
∆out = = 1 v/kg/cm2
* = -1.42 mA/ kg/cm2
∆v = =
=
Rf = * Ri * -1
Si Ri = 1KΩ entonces:
Rf = * 1KΩ * -1 = 704.22Ω
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