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Page 1: Do now!

Do now!Can you write

in your planners that

today’s homework is to read pages 44 and 45 of your new text book!

Due next lesson Monday

12th Oct

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Last lesson

Momentum

YouTube - Spectacular 100mph Train Crash Test

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Momentum

Momentum is a useful quantity to consider when thinking about "unstoppability". It is also useful when considering collisions and explosions. It is defined as

Momentum (kg.m/s) = Mass (kg) x Velocity (m./s)

p = mv

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An easy example

A lorry has a mass of 10 000 kg and a velocity of 3 m.s-1. What is its momentum?

Momentum = Mass x velocity = 10 000 x 3 = 30 000 kg.m.s-1.

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Conservation of momentum

In a collision between two objects, momentum is conserved (total momentum stays the same). i.e.

Total momentum before the collision = Total momentum after

Momentum is not energy!

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A harder example!

A car of mass 1000 kg travelling at 5 m/s hits a stationary truck of mass 2000 kg. After the collision they stick together. What is their joint velocity after the collision?

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A harder example!

5 m/s

1000kg

2000kgBefore

After

V m/s

Combined mass = 3000 kg

Momentum before = 1000x5 + 2000x0 = 5000 kg.m/s

Momentum after = 3000v

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A harder example

The law of conservation of momentum tells us that momentum before equals momentum after, so

Momentum before = momentum after5000 = 3000v

V = 5000/3000 = 1.67 m/s

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Momentum is a vector

Momentum is a vector, so if velocities are in opposite directions we must take this into account in our calculations

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An even harder example!

Snoopy (mass 10kg) running at 4.5 m/s jumps onto a skateboard of mass 4 kg travelling in the opposite direction at 7 m/s. What is the velocity of Snoopy and skateboard after Snoopy has jumped on?

I love physics

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An even harder example!

10kg

4kg-4.5 m/s7 m/s

Because they are in opposite directions, we make one velocity negative

14kg

v m/s

Momentum before = 10 x -4.5 + 4 x 7 = -45 + 28 = -17

Momentum after = 14v

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An even harder example!

Momentum before = Momentum after-17 = 14v

V = -17/14 = -1.21 m/s

The negative sign tells us that the velocity is from left to right (we choose this as our “negative direction”)

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Today’s lesson

Impulse

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Let’s follow Mr Porter

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Impulse

Ft = mv – mu

The quantity Ft is called the impulse, and of course mv – mu is the change in momentum (v = final velocity and u = initial velocity)

Impulse = Change in momentum

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Units

Impulse is measured in N.s (Ft)

or kg.m/s (mv – mu)

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Impulse

Note; For a ball bouncing off a wall, don’t forget the initial and final velocity are in different directions, so you will have to make one of them negative.

In this case mv – mu = 5m - -3m = 8m

5 m/s

-3 m/s

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Example

Dylan punches Henry in the face. If Henry’s head (mass 10 kg) was initially at rest and moves away from Dylans fist at 3 m/s, and the fist was in contact with the face for 0.2 seconds, what was the force of the punch?

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Example

Dylan punches Henry in the face. If Henry’s head (mass 10 kg) was initially at rest and moves away from Dylans fist at 3 m/s, and the fist was in contact with the face for 0.2 seconds, what was the force of the punch?

m = 10kg, t = 0.2, u = 0, v = 3

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Example

Dylan punches Henry in the face. If Henry’s head (mass 10 kg) was initially at rest and moves away from Dylans fist at 3 m/s, and the fist was in contact with the face for 0.2 seconds, what was the force of the punch?

m = 10kg, t = 0.2, u = 0, v = 3 Ft = mv - mu

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Example

Dylan punches Henry in the face. If Henry’s head (mass 10 kg) was initially at rest and moves away from Dylans fist at 3 m/s, and the fist was in contact with the face for 0.2 seconds, what was the force of the punch?

m = 10kg, t = 0.2, u = 0, v = 3 Ft = mv – mu 0.2F = 10x3 – 10x0

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Example

Dylan punches Henry in the face. If Henry’s head (mass 10 kg) was initially at rest and moves away from Dylans fist at 3 m/s, and the fist was in contact with the face for 0.2 seconds, what was the force of the punch?

m = 10kg, t = 0.2, u = 0, v = 3 Ft = mv – mu 0.2F = 10x3 – 10x0 0.2F = 30

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Example

Dylan punches Henry in the face. If Henry’s head (mass 10 kg) was initially at rest and moves away from Dylans fist at 3 m/s, and the fist was in contact with the face for 0.2 seconds, what was the force of the punch?

m = 10kg, t = 0.2, u = 0, v = 3 Ft = mv – mu 0.2F = 10x3 – 10x0 0.2F = 30 F = 30/0.2 = 150N

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Now let’s try some fun questions!