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Material Sciences and Engineering, MatE271 1

Material Sciences and Engineering MatE271 1Week6

Diffusion

Atomic Motion in Solids

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Diffusion in Materials

A. Atoms must be able to move around (diffusion)

Diffusion occurs in solids, liquids and gases:

� Redistribution of non-uniform chemical species (impurity diffusion or interdiffusion)

� Random atomic movement can also occur inchemically uniform materials (self diffusion)

Q. How do changes in microstructure and chemicalcomposition actually occur?

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Diffusion is �driven� by Nonuniformity

A B

Distance (x)

Conc

entr

atio

n of

�A�

Time

TemperatureA B

Distance (x)Co

ncen

trat

ion

of �

A�Concentration Profile

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Interdiffusion forming a solid solution

Initial

Intermediate time

Much longer time

What is this time scale?

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Diffusion?

Diffusion is necessary for:� Redistribution of chemical species� Physical changes in microstructure� Densification of powder compacts� Deformation at high temperature (creep)� Formation of solid state reaction products� One kind of conductivity in ceramics (ionic)

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Atoms would not move around because

there would be no places for them to move to

(all sites would be occupied)-- �locked in place�

Diffusion:

Perfect crystal:

� Point defects must be present in a crystal to permit atomic movement (diffusion)

In a way, atomic diffusion is actually the movement of defects.

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Diffusion Mechanisms

I. Vacancy diffusiono Only adjacent atoms can move into a vacancyo Vacancy moves in opposite direction of atomic

motiono Rate depends on concentration of vacancies

Atomic flux

Vacancy flux

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II. Interstitial Diffusiono Atom can move into any adjacent empty

interstitial position (usually smaller atoms)o Rate depends on concentration of interstitial

atoms� (Usually faster than vacancy diffusion)

Diffusion Mechanisms

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o Would you expect vacancy or interstitial diffusion to be faster?

o Why?

Diffusion Mechanisms

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Net migrationafter n jump

� After many random jumps by an atom, it�s displacment� can be calculated by the theory of �random walks�

Diffusion occurs by random jumps

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- The rate of diffusion is characterized by describing atomic

fluxes at particular locations in the material

- Critical quantities

J = atomic flux (atoms/m2-s, kg/ m2-s)

(dc/dx) = concentration gradient

(atoms/m4)

D = diffusion coefficient (m2/s)

Quantitative Description of Diffusion

area

J

c

dc/dx x

Fick�s first law: J = - D (dc/dx)

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Interrelating the quantities

� Fick�s first law: J = - D (dc/dx)

(negative sign indicates that the direction of diffusion flux

is �down� the concentration gradient from high to low

concentration)

� For steady state diffusion (local flux doesn�t change

with time), Fick�s First Law can be solved directly

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Hydrogen (H) gas can be purified by passing atomic hydrogen through a thin sheet of palladium (Pa) at 700oC in a paladium diffusion cell. If the impure hydrogen gas is maintained at 1 atm on one side of a 1 mm thick Pd sheet (A=1 m2), and the pressure on the purified side is maintained at 0.1 atm by pumping, what is the mass of the hydrogen purified in 1 hr? Assume steady state conditions. The concentration of H2 at 1 atm is 9.0x10-3 gm/cm3 and D(H) in Pa is 1.2x10-6 cm2/sec.

Example

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Non-steady state diffusion

The diffusion flux at a particular point varies with time

� � (There is a net accumulation or depletion of the diffusing species at a given location)

� � i.e., local concentration of diffusing species changes with time as diffusion proceeds

� � This is the most common situation

What is this time scale?

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Non-steady state diffusion

� Fick�s Second Law governs

� Many solutions exist for particular geometries (initial and boundary conditions)

� Diffusion from a constant source into an semi-infinite solidBC-1: For t = 0, C = C0 at 0 ≤ x ≤ ∞ BC-3: C = C0 at x = ∞

BC-2: t > 0, C = Cs at x = 0

(Cx - C0) = 1 - erf x(Cs-C0) 2√Dt

∂C = D ∂2C∂t ∂x2 x

C(∞,t)=Co

C(x, t)=Cx ?

C(0,t)=Cs

C(x,0)=Co

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Non-steady state diffusion

x = 0

Cs

C0

to< t1 < t2 < t3

t1t2

t3

Cx

x

C

C(0,t)=Cs C(∞,t)=Co

C(x,0)=Co

to

C(x, t)=Cx ?

(Cx - C0) = 1 - erf x(Cs-C0) 2√Dt

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Example

For some applications (e.g. gears), it is necessary to harden the surface of a steel (Fe-C alloy) above that of its interior. One way of accomplishing this is by increasing the surface concentration of carbon in the steel (as we will see later) using a process termed carburizing. In carburizing the steel piece is exposed, at elevated temperature, to an atmosphere rich in a hydrocarbon gas, such as methane (CH4).

Surface Treatment of Steel:

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Example: Surface Treatment of Steel:

Consider on such alloy that initially has a uniform carbon concentration of 0.25 wt% and is to be treated at 950° C. If the concentration of carbon at the surface is suddenly brought to and maintained at 1.20 wt%, how long will it take to achieve a carbon content of 0.80 wt% at a position 0.5 mm below the surface? The diffusion coefficient for C in Fe at this temperature is 1.6 x 10-11 m2/sec. Assume piece is semi-infinite.

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Factors that Influence Diffusion

I. Diffusing Species� magnitude of diffusion coefficient, D - indicates

the rate at which atoms diffuse� both diffusing species and host material

influence the coefficient� Relative sizes of atoms� �Openess� of lattice� Ionic charges

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Factors that Influence Diffusion

For example:

� For the host species of iron:- Self diffusion at 500°C (Fe moving in Fe)

D = 1.1 x 10-20 m2/s (vacancy diffusion)

- Carbon interdiffusion at 500°C (C moving in FeD = 2.3 x 10-12 m2/s (interstitial diffusion)

� Atomic Size/Mechanism

This shows the contrast between rates of

vacancy and interstitial diffusion

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Factors that Influence Diffusion

II. Temperature� very strong effect on the diffusion coefficient:

� A large activation energy results in a small D

D = Do exp −Q d

RT� �

� �

Do = T independent preexponential Qd = the activation energy for diffusion (J/mol, or eV/atom)

R = the gas constant, 8.31 J/mol - K or 8.662 x 10-5 eV/ atom − KT = absolute temperature, (K)

ln D = ln Do − −Qd

R1T

� �

� �

Plot ln D vs 1/T - get straight line(to measure activation energy and Do)

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Example:

o Using data from Table 5.2, compute the diffusion coefficient of C in α−Fe and γ−Fe at 900ºC.

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Solution:

D = Do exp −Q d

RT� �

� �

Do = T independent preexponential Qd = the activation energy for diffusion (J/mol, or eV/atom)

R = the gas constant, 8.31 J/mol - K or 8.662 x 10-5 eV/ atom − KT = absolute temperature, (K)

o C in α−Fe (BCC) at 900ºC D = 6.2x10-7 m2/sec exp (-0.83 eV/atom / (1173K)(8.62x10-5 eV/atom-K)D = 1.7x10-10 m2/sec

o C in γ−Fe (FCC) at 900ºCD = 2.3x10-5 m2/sec exp (-1.53 eV/atom / (1173K)(8.62x10-5 eV/atom-K)D = 5.9x10-12 m2/sec

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What does this tell you about interstitial sites in BCC and FCC?�.

� BCC more open than FCC for interstitial diffusion�i.e. it is easier to move from one interstitial site to another in BCC

� But it does not say anything about the sizeor number of interstitial sites in each�.actually, as you will see, FCC has bigger (and more) interstitial sites

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(Besides through volume of the crystal)

� Atomic migration often occurs more rapidly along so-called �short circuiting paths�

� Dislocations

� Grain boundaries

� External surfaces

� However, there is usually small total area

for this to occur - so not always important

Other Diffusion Paths

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Volume, grain boundary and surface diffusion

surface

Grain boundary

volume

Ag in Ag

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Diffusion and Materials Processing

o Properties of materials are altered through diffusion

� steelmaking� sintering� semiconductor doping

o �Heat treatment� is used to allow these to occur over a reasonable time frame.

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Summary� Recognize various imperfections in crystals

� Point imperfections

� Impurities

� Line imperfections (dislocations)

� Bulk imperfections

� Define various diffusion mechanisms

� Identify factors controlling diffusion processes

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Reading Assignment

Shackelford 2001(5th Ed)

� Read Chapter 5, pp 158-181