Download - CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

Transcript
Page 1: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

1 www.cbse.entrancei.com

cbse.entrancei.com

CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS

MISCELLANEOUS EXERCISE Question 1:

Using chain rule, we obtain

Question 2:

Question 3:

Page 2: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

2 www.cbse.entrancei.com

cbse.entrancei.com

Taking logarithm on both the sides, we obtain

Differentiating both sides with respect to x, we obtain

Question 4:

Using chain rule, we obtain

Page 3: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

3 www.cbse.entrancei.com

cbse.entrancei.com

Question 5:

Question 6:

Page 4: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

4 www.cbse.entrancei.com

cbse.entrancei.com

Therefore, equation (1) becomes

Question 7:

Taking logarithm on both the sides, we obtain

Page 5: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

5 www.cbse.entrancei.com

cbse.entrancei.com

Differentiating both sides with respect to x, we obtain

Question 8:

, for some constant a and b.

By using chain rule, we obtain

Question 9:

Taking logarithm on both the sides, we obtain

Page 6: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

6 www.cbse.entrancei.com

cbse.entrancei.com

Differentiating both sides with respect to x, we obtain

Question 10:

, for some fixed and

Differentiating both sides with respect to x, we obtain

Page 7: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

7 www.cbse.entrancei.com

cbse.entrancei.com

Differentiating both sides with respect to x, we obtain

s = aa

Since a is constant, aa is also a constant.

From (1), (2), (3), (4), and (5), we obtain

Question 11:

, for

Differentiating both sides with respect to x, we obtain

Page 8: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

8 www.cbse.entrancei.com

cbse.entrancei.com

Differentiating with respect to x, we obtain

Also,

Differentiating both sides with respect to x, we obtain

Substituting the expressions of in equation (1), we obtain

Page 9: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

9 www.cbse.entrancei.com

cbse.entrancei.com

Question 12:

Find , if

Question 13:

Find , if

Question 14:

Page 10: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

10 www.cbse.entrancei.com

cbse.entrancei.com

If , for, −1 < x <1, prove that

It is given that,

Differentiating both sides with respect to x, we obtain

Hence, proved.

Question 15:

If , for some prove that

Page 11: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

11 www.cbse.entrancei.com

cbse.entrancei.com

is a constant independent of a and b.

It is given that,

Differentiating both sides with respect to x, we obtain

Page 12: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

12 www.cbse.entrancei.com

cbse.entrancei.com

Hence, proved.

Question 16:

If with prove that

Page 13: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

13 www.cbse.entrancei.com

cbse.entrancei.com

Then, equation (1) reduces to

Hence, proved.

Question 17:

If and , find

Page 14: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

14 www.cbse.entrancei.com

cbse.entrancei.com

Question 18:

If , show that exists for all real x, and find it.

It is known that,

Therefore, when x ≥ 0,

In this case, and hence,

When x < 0,

Page 15: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

15 www.cbse.entrancei.com

cbse.entrancei.com

In this case, and hence,

Thus, for , exists for all real x and is given by,

Question 19:

Using mathematical induction prove that for all positive integers n.

For n = 1,

∴P(n) is true for n = 1

Let P(k) is true for some positive integer k.

That is,

It has to be proved that P(k + 1) is also true.

Thus, P(k + 1) is true whenever P (k) is true.

Therefore, by the principle of mathematical induction, the statement P(n) is true for every positive integer n.

Page 16: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

16 www.cbse.entrancei.com

cbse.entrancei.com

Hence, proved.

Question 20:

Using the fact that sin (A + B) = sin A cos B + cos A sin B and the differentiation, obtain the sum formula for

cosines.

Differentiating both sides with respect to x, we obtain

Question 22:

If , prove that

Page 17: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

17 www.cbse.entrancei.com

cbse.entrancei.com

Thus,

Question 23:

If , show that

It is given that,

Page 18: CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS miscallaneous.pdf · CONTINUITY AND DIFFERENTIABILITY - NCERT SOLUTIONS MISCELLANEOUS EXERCISE Question 1: Using chain rule, we

18 www.cbse.entrancei.com

cbse.entrancei.com