Chapter 22Diatomic Molecules
P. J. Grandinetti
Chem. 4300
P. J. Grandinetti Chapter 22: Diatomic Molecules
The Hydrogen Molecular IonSimplest molecule to consider is H+
2 , with only 1 electron. Hamiltonian is
H+2= โ โ2
2mp
(โ2
A + โ2B)
โโโโโโโโโโโโโโโโโโโโโ1
โ โ2
2meโ2
e
โโโโโ2
โZAq2
e4๐๐0rA
โโโโโ3
โZBq2
e4๐๐0rB
โโโโโ4
+ZAZBq2
e4๐๐0RABโโโโโ
5
1 is kinetic energy of nuclei2 is kinetic energy of eโ
3 is Coulomb attraction between eโ and nucleus A4 is Coulomb attraction between eโ and nucleus B5 is Coulomb repulsion between nuclei A and B
Written in terms of atomic units
H+2= โ1
2memp
(โ2
A + โ2B)โ 1
2โ2
e โZArA
โZBrB
+ZAZBRAB
P. J. Grandinetti Chapter 22: Diatomic Molecules
Born-Oppenheimer (B-O) ApproximationSince nuclei are much heavier than eโ we separate motion into 2 timescales:
fast time scale of eโ motion and slow time scale of nuclear motion.Born-Oppenheimer approximation assumes nuclei are fixed in place and solve for eโ wave functionin potential of 2 fixed nuclei.We then change internuclear spacing and repeat process.Not allowing nuclei to move while solving for eโ wave function has 2 effects:
1 nuclear kinetic energy terms: 1 go away2 nuclearโnuclear repulsion potential energy term 5 becomes constant and can be simply
added to energy eigenvalue.With this approximation wave equation for eโ (in atomic units) becomes[
โ12โ2
e โZArA
โZBrB
]โโโโโโโโโโโโโโโโโโโโโโโโโโโ
el
๐el(r,RAB) = E(RAB)๐el(r,RAB).
Solving this wave equation gives eโ wave function, ๐el(r,RAB), and its energy for given internucleardistance, RAB.P. J. Grandinetti Chapter 22: Diatomic Molecules
Born-Oppenheimer (B-O) ApproximationNext in B-O approximation we take total wave function as
๐(r,RAB) โ ๐el(r,RAB)๐nuc(RAB)
Next we assume that ๐el(r,RAB) varies so slowly with RAB that
โ12
memp
(โ2
A + โ2B)๐el(r,RAB)๐nuc(RAB) โ ๐el(r,RAB)
[โ1
2memp
(โ2
A + โ2B)๐nuc(RAB)
]In other words we assume
(โ2
A + โ2B)๐el(r,RAB) โ 0
Putting B-O wave function approximation
H+2๐(r,RAB) = E๐(r,RAB)
into full Schrรถdinger equation
H+2= โ1
2memp
(โ2
A + โ2B)โ 1
2โ2
e โZArA
โZBrB
+ZAZBRAB
we obtain...P. J. Grandinetti Chapter 22: Diatomic Molecules
Born-Oppenheimer (B-O) Approximation
๐el(r,RAB)[โ1
2memp
(โ2
A + โ2B)]๐nuc(RAB) +
[โ1
2โ2
e โZArA
โZBrB
]โโโโโโโโโโโโโโโโโโโโโโโโโโโ
el
๐el(r,RAB)๐nuc(RAB)
+ZAZBRAB
๐el(r,RAB)๐nuc(RAB) = E๐el(r,RAB)๐nuc(RAB)
Making the replacement el๐el(r,RAB) = E(RAB)๐el(r,RAB) gives
๐el(r,RAB)[โ1
2memp
(โ2
A + โ2B)+ E(RAB) +
ZAZBRAB
]๐nuc(RAB) = ๐el(r,RAB)E๐nuc(RAB)
Dividing both sides by ๐el(r,RAB) gives...
P. J. Grandinetti Chapter 22: Diatomic Molecules
Born-Oppenheimer ApproximationDividing both sides by ๐el(r,RAB) and obtain wave equation for nuclei:[
โ12
memp
(โ2
A + โ2B)
โโโโโโโโโโโโโโโโโโโโโโโnuclear kinetic energy
+ E(RAB) +ZAZBRAB
โโโโโโโโโโโโโโโโโnuclear effective potential
]๐nuc(RAB) = E๐nuc(RAB)
General strategy is to
fix nuclei in position and calculate ๐el(r,RAB) and energy, E(RAB). Do this for all possible values ofRAB, and
use E(RAB) + ZAZBโRAB as effective nuclear potential energy (Ground state looks like Morsepotential) in nuclear wave equation to obtain ๐nuc(RAB) and energies:
P. J. Grandinetti Chapter 22: Diatomic Molecules
Solving one electron Schrรถdinger equation for the H2+ ion
With B-O approximation out of way letโs look at solutions for ๐el(r,RAB) of H+2 , given the
electronic Hamiltonian in atomic units[โ1
2โ2
e โZArA
โZBrB
]โโโโโโโโโโโโโโโโโโโโโโโโโโโ
el
๐el(r,RAB) = E(RAB)๐el(r,RAB).
Problem is no longer spherically symmetric. So, what coordinate system should we use?
P. J. Grandinetti Chapter 22: Diatomic Molecules
Spheroidal Coordinates : ๐el(r,RAB) to ๐el(๐, ๐, ๐,RAB)
We can derive exact solution for ๐el(r,RAB) using spheroidal coordinates,where ๐ = (rA + rB)โR, ๐ = (rA โ rB)โR, and R is internuclear distance.Lines of constant ๐ are ellipses which share foci rA and rB.Lines of constant ๐ are hyperbolas with rA and rB as foci.Ellipses and hyperbolas form orthogonal system of curves.
P. J. Grandinetti Chapter 22: Diatomic Molecules
Spheroidal Coordinates : ๐el(r,RAB) to ๐el(๐, ๐, ๐,RAB)
Variable ๐ varies over range 1 โค ๐ โค โ, and plays role analogous to r in usual polar coordinatesystem.Variable ๐ varies over range โ1 โค ๐ โค 1.As ๐ changes point (๐, ๐) moves around origin, so ๐ plays role similar to quantity cos ๐ in polarcoordinates.
P. J. Grandinetti Chapter 22: Diatomic Molecules
Spheroidal Coordinates : ๐el(r,RAB) to ๐el(๐, ๐, ๐,RAB)
Three dimensional prolate ellipsoidal coordinates are obtained by rotating figure around z axis.Ellipses generate set of confocal ellipsoidsHyperbolas generate family of hyperboloids with 2 sheets.Surface of constant ๐ are half-planes though x axis.
P. J. Grandinetti Chapter 22: Diatomic Molecules
Two sheet hyperboloid
P. J. Grandinetti Chapter 22: Diatomic Molecules
Spheroidal Coordinates : ๐el(r,RAB) to ๐el(๐, ๐, ๐,RAB)
Prolate ellipsoidal coordinates in 3D space are obtained by rotating figure around z axis.Ellipses generate set of confocal ellipsoidsHyperbolas generate family of hyperboloids with 2 sheets.Surface of constant ๐ are half-planes though x axis.
P. J. Grandinetti Chapter 22: Diatomic Molecules
Spheroidal Coordinates : ๐el(r,RAB) to ๐el(๐, ๐, ๐,RAB)
Spheroidal Coordinates allows us to separate wave function into product
๐(๐, ๐, ๐) = L(๐)M(๐)ฮฆ(๐)
Substituting ๐(๐, ๐, ๐) into electronic wave equation gives 3 ODEs.Weโll do no derivations, just look at results ...
P. J. Grandinetti Chapter 22: Diatomic Molecules
Solutions to ฮฆ(๐)Solutions to ฮฆ(๐) which are eigenfunctions of Lz,
ฮฆ(๐) = 1โ2๐
eim๐
Each value of |m| leads to different energy. States associated with ยฑm are degenerate.We refer to states by their m value:
m = 0 ๐ state,m = ยฑ1 ๐ state,m = ยฑ2 ๐ฟ state,
โซโชโฌโชโญthese follow same lettersequence as ๐ usingGreek letters instead.
States are also labeled by their inversion symmetry.
when ๐u(r) = โ๐u(โr), odd symmetry,when ๐g(r) = ๐g(โr), even symmetry,
Use subscript u for odd wave functions (ungerade)Use subscript g for even wave functions (gerade).Wave functions labeled as ๐g, ๐u, ๐g, ๐u, ๐ฟg, ๐ฟu, and so on.
P. J. Grandinetti Chapter 22: Diatomic Molecules
Lowest energy levels of H+2 as function of internuclear R
with internuclear repulsive energy.
Minimum in 1๐g energy is Re โ 2a0, corresponding toequilibrium length of 1๐g ground state of H+
2 .
As R โ โ energy of 1๐g state approaches โ0.5Eh.As expected, this is energy of electron in 1s state ofH-atom infinitely separated from isolated proton.Difference between this energy and energy at equilibriumbond length is binding energy,E1๐g
(Re) โ E1๐g(โ) = 0.1Eh.
Both equilibrium distance and binding energy from thisexact solution are in excellent agreement withexperimentally determined values of 2.00a0 and 0.102Eh,respectively.
P. J. Grandinetti Chapter 22: Diatomic Molecules
Lowest energy levels of H+2 as function of internuclear R
without internuclear repulsive energy.
As R โ 0, i.e., both protons at origin form He nucleus, wefind energy of โ2Eh. This is ground state energy of singleelectron bound to He nucleus.
P. J. Grandinetti Chapter 22: Diatomic Molecules
Exact solutions for 1๐g and 1๐u of H+2 as a function of R
(A)
(D)
(E)
(F)
(B) (C)
P. J. Grandinetti Chapter 22: Diatomic Molecules
Shape of H+2 wave functions
When R = 0 solution becomes identical to He+ wave function.
P. J. Grandinetti Chapter 22: Diatomic Molecules
Shape of H+2 wave functions
When R = 8a0 observe 2 sharp peaks at ยฑ4a0 where nucleiare located.
When R โ โ two peaks correspond to 1s orbital centeredon each nucleus.
In case of H+2 only one of these 1s orbitals is occupied.
Difference between 1๐g and 1๐u is in how two 1s orbitalsare combined.
Normalization factors aside, in R โ โ limit we find (in atomic units)
1๐g = eโrA + eโrB , and 1๐u = โeโrA + eโrB .
Results suggest approximate approach to describe bonding wave functions as a linear combinationof atomic orbitals (LCAO) on each nucleus.LCAO approach more useful than exact solutionโwhich only works for H+
2 .
P. J. Grandinetti Chapter 22: Diatomic Molecules
Linear Combination of Atomic Orbitals (LCAO)
P. J. Grandinetti Chapter 22: Diatomic Molecules
Linear Combination of Atomic Orbitals (LCAO)Use variational theorem with LCAO as trial H+
2 wave function
๐guess(r,RAB) = cA๐1sA+ cB๐1sB
๐1sAand ๐1sB
are atomic orbitals associated with eโ in 1s orbital on nuclei A and B, respectively.There are 2 adjustable parameters, cA and cB, in ๐guess.
โจโฉ = โซ ๐โguess๐guessd๐ โฅ E0
E0 is true ground state energy. Canโt assume trial wave function is normalized so need to minimizeenergy for
E =โซV ๐
โguess๐guessd๐
โซV ๐โguess๐guessd๐
โฅ E0
Even though atomic orbitals are normalized, LCAO wave function is not. Substituting ๐guess(r,RAB) weobtain
E =c2
A โซV๐โ
1sA๐1sA
d๐ + c2B โซV
๐โ1sB
๐1sBd๐ + 2cAcB โซV
๐โ1sA
๐1sBd๐
c2A + c2
B + 2cAcB โซV๐โ
1sA๐1sB
d๐โฅ E0
P. J. Grandinetti Chapter 22: Diatomic Molecules
Linear Combination of Atomic Orbitals (LCAO)To simplify equations define
HAB โก โซV๐โ
1sA๐1sB
d๐, and SAB โก โซV๐โ
1sA๐1sB
d๐
SAB is called overlap integral. These definitions allow us to write
E =c2
AHAA + c2BHBB + 2cAcBHAB
c2A + c2
B + 2cAcBSABโฅ E0
Next, find values of cA and cB where E is at minimum by taking derivative of E wrt cA and cB andsetting equal to zero,
๐E๐cA
= 0, and ๐E๐cB
= 0
To make this easier letโs move the denominator to the left(c2
A + c2B + 2cAcBSAB
)E = c2
AHAA + c2BHBB + 2cAcBHAB
P. J. Grandinetti Chapter 22: Diatomic Molecules
Linear Combination of Atomic Orbitals (LCAO)Taking the derivative of both sides
๐๐cA
(c2
A + c2B + 2cAcBSAB
)E = ๐
๐cA
(c2
AHAA + c2BHBB + 2cAcBHAB
)gives
(2cA + 2cBSAB)E +(c2
A + c2B + 2cAcBSAB
) ๐E๐cA
= 2cAHAA + 2cBHAB
Doing same with ๐โ๐cB gives
(2cB + 2cASAB)E +(c2
A + c2B + 2cAcBSAB
) ๐E๐cB
= 2cBHBB + 2cAHAB
Setting ๐Eโ๐cA = ๐Eโ๐cB = 0 leads to two simultaneous equations
cA(HAA โ E) + cB(HAB โ ESAB) = 0
cA(HAB โ ESAB) + cB(HBB โ E) = 0
P. J. Grandinetti Chapter 22: Diatomic Molecules
Linear Combination of Atomic Orbitals (LCAO)Writing these in matrix form givesโโโโ
HAA โ E HAB โ ESAB
HAB โ ESAB HBB โ E
โโโโ โโโโ
cA
cB
โโโโ = 0
Matrix diagonalization problem can be solved with determinant,|||||||HAA โ E HAB โ ESAB
HAB โ ESAB HBB โ E
||||||| = 0
In homonuclear example make it little easier since HAA = HBB = ๐ผ.Also set HAB = ๐ฝ and S = SAB|||||||
๐ผ โ E ๐ฝ โ ES
๐ฝ โ ES ๐ผ โ E
||||||| = 0, which gives (๐ผ โ E)2 โ (๐ฝ โ ES)2 = 0
P. J. Grandinetti Chapter 22: Diatomic Molecules
Linear Combination of Atomic Orbitals (LCAO)
(๐ผ โ E)2 โ (๐ฝ โ ES)2 = 0
which leads to๐ผ โ E = ยฑ(๐ฝ โ ES) = ยฑ๐ฝ โ ES
and we find 2 solutions for E:E+ =
๐ผ + ๐ฝ1 + S
and Eโ =๐ผ โ ๐ฝ1 โ S
Putting solution for E+ back into simultaneous Eqs one can show that cA = cB.Put solution for Eโ into 2 simultaneous equations and obtain cA = โcB.Thus, 2 solutions for wave function are
๐๐g= c
(๐1sA
+ ๐1sB
), and ๐๐u
= c(๐1sA
โ ๐1sB
)Normalizing these two wave functions gives
๐๐g= 1โ
2 + 2S
(๐1sA
+ ๐1sB
)and ๐๐u
= 1โ2 โ 2S
(๐1sA
โ ๐1sB
)P. J. Grandinetti Chapter 22: Diatomic Molecules
Linear Combination of Atomic Orbitals (LCAO)
Bring two 1s orbitals together in phase for ๐๐gand out of phase for ๐๐u
(A) (B)
Above is comparison of Exact (solid lines) and LCAO (dashed lines) wave functions ๐๐gand
๐๐ufor H+
2 with R = 2 for (A) bonding and (B) anti-bonding states.
Simple LCAO approximation is not bad, and is good starting point for refining LCAO method.
P. J. Grandinetti Chapter 22: Diatomic Molecules
LCAO : Overlap Integral STo finish derivation need to evaluate overlap integral S and energies. Starting with S we find
S = โซV๐โ
1sA๐1sB
d๐ = eโRAB
(1 + RAB +
R2AB3
)
0 1 2 3 40.0
0.2
0.4
0.6
0.8
1.0
As expected, overlap integral goes to zero in limit that R โ โ.With decreasing R overlap integral increases and reaches value of 1 at R = 0.
P. J. Grandinetti Chapter 22: Diatomic Molecules
LCAO : Coulomb Integral๐ผ integral is called Coulomb Integral
๐ผ = โซV๐โ
1sA๐1sA
d๐
To evaluate ๐ผ start with electronic Hamiltonian in atomic units = โ1
2โ2
e โ1rA
โ 1rB
+ 1RAB
which can be written = A โ 1rB
+ 1RAB
or = B โ 1rA
+ 1RAB
A or B are Hamiltonians for eโ in H-atom alone. Thus,
๐ผ = โซV๐โ
1sA
[A โ 1
rB+ 1
RAB
]๐1sA
d๐ = โซV๐โ
1sAA๐1sA
d๐ โ โซV๐โ
1sA
1rB๐1sA
d๐ + 1RAB
which gives ๐ผ = E1s +2E1sRAB
[1 โ eโ2RAB(1 + RAB)
]+ 1
RABCoulomb Integral contains energy of eโ in 1s orbital of H-atom, attractive energy of nucleus Bfor eโ, and repulsive force of nuclei B with A.
P. J. Grandinetti Chapter 22: Diatomic Molecules
LCAO : Coulomb Integral
10 2 3 4-1
0
1
2
3
4
๐ผ decreases monotonically (i.e., no minimum) from โ at RAB = 0 to โ1โ2 at RAB = โ. In other words,๐ผ, which is leading term in
E+ =๐ผ + ๐ฝ1 + S
and Eโ =๐ผ โ ๐ฝ1 โ S
does not give any stability to H+2 over 2 infinitely separated nuclei (recall H atom has energy of โEhโ2).
P. J. Grandinetti Chapter 22: Diatomic Molecules
LCAO : Exchange Integral
Finally, examine ๐ฝ integral, also called the resonance or Exchange Integral
๐ฝ = โซV๐โ
1sA๐1sB
d๐
which becomes
๐ฝ = โซV๐โ
1sA
[B โ 1
rA+ 1
RAB
]๐1sB
d๐ = โซV๐โ
1sAB๐1sB
d๐โโซV๐โ
1sA
1rA๐1sB
d๐+โซV๐โ
1sA
1RAB
๐1sBd๐
to obtain๐ฝ = E1sS + 2E1seโRAB(1 + RAB) +
SRAB
P. J. Grandinetti Chapter 22: Diatomic Molecules
LCAO : Exchange Integral
10 2 3 4-1
0
1
2
3
4 ๐ฝ integral goes through a minimum inenergy.It is stabilization energy from allowing eโto move (exchange) between 2 nuclei.Since both ๐ผ and ๐ฝ are negative, E+ willbe lowest energy,
E1๐g= E+ =
๐ผ + ๐ฝ1 + S
, (bonding)
P. J. Grandinetti Chapter 22: Diatomic Molecules
LCAO : Energy
-1.0
-0.5
0.0
0.5
1.0
10 2 3 4
LCAO model predicts that energy of groundstate has minimum at bond length ofRe = 2.50a0 and has binding energy ofE+(Re) โ E(โ) = 0.0648Eh.
Predicted bond length is longer thanexperimentally observed Re = 2.00a0
Predicted binding energy is lower thanexperimentally observed value of 0.102Eh.
P. J. Grandinetti Chapter 22: Diatomic Molecules
LCAO : Energy
Anti-bonding orbital energy is
E1๐u= Eโ =
๐ผ โ ๐ฝ1 โ S
, (anti-bonding)
This orbital gives no stability since ๐ฝ raises total energy in this case.Putting lone electron into ๐1๐u
would destabilize H+2 molecule and cause it to break apart.
P. J. Grandinetti Chapter 22: Diatomic Molecules
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