BELLRINGER
Compare and explain in complete
sentences what is
a saturated solution.
Previous homework
Finish and submit 4 BRs for the previous week.
SOLUTIONSIII
Water and Solutions
Concentration and Solubility
4 9.2 Concentration and Solubility
Suppose you dissolve 10.0 g of sugar in 90.0 g of water. What is the mass percent concentration of sugar in the solution?
Asked: The mass percent concentration
Given: 10 g of solute (sugar) and 90 g of solvent (water)
Relationships: 100%mass of solute
concentrationtotal mass of solution
5 9.2 Concentration and Solubility
Suppose you dissolve 10.0 g of sugar in 90.0 g of water. What is the mass percent concentration of sugar in the solution?
Asked: The mass percent concentration
Given: 10 g of solute (sugar) and 90 g of solvent (water)
Relationships:
Solve:
100%mass of solute
concentrationtotal mass of solution
10
100%10 90
10%g sugar
concentrationg of solution
sugar
6 9.2 Concentration and Solubility
( )( )
( )
( )( / )
( )
( )(%) 100
( )
,
mass of solute gconcentration g L
volume of solution L
mass of solute gconcentration
m
mol
ass of solution
es of solute mmol
oleconcentration
volume of solarity M
n
g
utio L
Concentration
There are several ways to express concentration
7 9.2 Concentration and Solubility
Concentration
Calculate the molarity of a salt solution made by adding 6.0 g of NaCl to 100 mL of distilled water.
8 9.2 Concentration and Solubility
Calculate the molarity of a salt solution made by adding 6.0 g of NaCl to 100 mL of distilled water.
Concentration
Asked: Molarity of solution
Given: Volume of solution = 100.0 mL, mass of solute (NaCl) = 6.0 g
Relationships:
22.99 35.45 58.44 /
1,000 1.0 , 100 0.10
molesM
L
Formula mass of NaCl g mole
mL L therefore mL L
9 9.2 Concentration and Solubility
Calculate the molarity of a salt solution made by adding 6.0 g of NaCl to 100 mL of distilled water.
Concentration
Asked: Molarity of solution
Given: Volume of solution = 100.0 mL, mass of solute (NaCl) = 6.0 g
Relationships:
Solve:
22.99 35.45 58.44 /
1,000 1.0 , 100 0.10
molesM
L
Formula mass of NaCl g mole
mL L therefore mL L
0.
0.1031.03
16.0
58.
0.100
344
10mole NaCl
moles NaCl g NaClg NaC
mole
moles Na
s
Cl
M
l
ML
10 9.2 Concentration and Solubility
Calculate the molarity of a salt solution made by adding 6.0 g of NaCl to 100 mL of distilled water.
Concentration
Asked: Molarity of solution
Given: Volume of solution = 100.0 mL, mass of solute (NaCl) = 6.0 g
Relationships:
Solve:
Answer: 1.03 M solution of NaCl
22.99 35.45 58.44 /
1,000 1.0 , 100 0.10
molesM
L
Formula mass of NaCl g mole
mL L therefore mL L
16.0 0.103
58.4
0.
4
103
0.101 03
0.
mole NaClmoles NaCl g NaCl moles NaCl
g NaCl
Mmoles
ML
11 9.2 Concentration and Solubility
sugar
100 mLH2O
10 g
What happens when you add 10 g of sugar to 100 mL of water?
Conc. (%) = 10 g/110 g
Solubility
12 9.2 Concentration and Solubility
100 mLH2O
What happens when you add 10 g of sugar to 100 mL of water?
Conc. (%) = 10 g/110 g
Water molecules dissolve sugar molecules
sugar10 g
Solubility
13 9.2 Concentration and Solubility
What happens when you add 10 g of sugar to 100 mL of water?
But when two sugar molecules find each other, they will become “undissolved” (solid) again…
Solubility
14 9.2 Concentration and Solubility
What happens when you add 10 g of sugar to 100 mL of water?
But when two sugar molecules find each other, they will become “undissolved” (solid) again…
… then, they become redissolved in water again.
Solubility
15 9.2 Concentration and Solubility
What happens when you add 10 g of sugar to 100 mL of water?
This is an aqueous equilibrium!
Equilibrium
Solubility
16 9.2 Concentration and Solubility
Solubility
low
high
Co
nce
ntr
atio
n
Equilibrium
dissolving “undissolving”
10 g sugar
100 mLH2O Conc. (%) = 10 g/110 g
20oC
17 9.2 Concentration and Solubility
Solubility
low
high
Co
nce
ntr
atio
n
Equilibrium
dissolving “undissolving”
18 9.2 Concentration and Solubility
saturation: situation that occurs when the amount of dissolved solute in a solution gets high enough that the rate of “undissolving” matches the rate of dissolving.
Equilibrium
dissolving “undissolving”
19 9.2 Concentration and Solubility
saturation: situation that occurs when the amount of dissolved solute in a solution gets high enough that the rate of “undissolving” matches the rate of dissolving.
204 g sugar
100 mLH2O Conc. = 204 g/100 mL
20oC
Solubility
20 9.2 Concentration and Solubility
Solubility
low
high
Co
nce
ntr
atio
n
Equilibrium
dissolving “undissolving”
250 g sugar
100 mLH2O
Conc. = 250 g/100 mL
20oC
Undissolved sugar
21 9.2 Concentration and Solubility
210 gsugar
100 mLH2O
20oC
Undissolved sugar
Temperature and solubility
210 gsugar
100 mLH2O
30oC
All the sugar is dissolved
22 9.2 Concentration and Solubility
Temperature has an effect on solubility
Temperature and solubility
210 gsugar
100 mLH2O
20oC
Undissolved sugar
210 gsugar
100 mLH2O
30oC
All the sugar is dissolved
23 9.2 Concentration and Solubility
ACTIVITY
READ THE TEXTBOOK FROM PAGE 239.
WORK PROBLEMS FROM PAGES 244 and 245.
24 9.2 Concentration and Solubility
Homework
FINISH YOUR ACTIVITY ASSIGNMENT AND SUBMIT IT
TOMORROW.
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