Year 13 Chemistry Notes 2015nceachemistry.weebly.com/uploads/3/1/0/1/31014091/...Year 13 Chemistry...
Transcript of Year 13 Chemistry Notes 2015nceachemistry.weebly.com/uploads/3/1/0/1/31014091/...Year 13 Chemistry...
Year 13 Chemistry Notes 2015
Chemistry 3.6 (5 credits)
Describe properties of organic chemistry
Name:
Townshend 2
Learning Outcomes
Use IUPAC conventions to name and draw alkanes with up to eight carbons in their longest chain.
Draw and name the constitutional isomers for an alkane’s given molecular formula.
Explain how the number and arrangement of carbons effects the melting and boiling points of alkanes.
Use IUPAC conventions to name and draw alkenes with up to eight carbons in their longest chain.
Draw and name the constitutional and geometric isomers for an alkene’s given molecular formula.
Explain how the geometric arrangement of the alkene effects the melting and boiling point
Use IUPAC conventions to name and draw haloalkanes with up to eight carbons in their longest chain.
Draw and name the constitutional isomers for an alcohol’s given molecular formula.
Describe how to test for the presence of 1⁰, 2⁰ and 3⁰ alcohols.
Use IUPAC conventions to name and draw amines with up to eight carbons in their longest chain.
Describe how to test for the presence of amines.
Use IUPAC conventions to name and draw aldehydes and ketones with up to eight carbons in their longest chain.
Describe how to test for the presence of aldehydes.
Use IUPAC conventions to name and draw carboxylic acids with up to eight carbons in their longest chain.
Describe how to test for the presence of carboxylic acids.
Use IUPAC conventions to name and draw esters with up to eight carbons in their longest chain.
Describe how to test for the presence of esters.
Townshend 3
Use IUPAC conventions to name and draw acyl chlorides with up to eight carbons in their longest chain.
Describe how to test for the presence of acyl chlorides.
Use IUPAC conventions to name and draw amides with up to eight carbons in their longest chain.
Draw and name triglycerides, glycerol, alanine, glycine.
Identify optical isomers by recognising chiral carbon atoms.
Describe how enantiomers can be distinguished by using polarised light.
Organic Chemistry
Organic chemistry is the study of carbon compounds.
Revision
Organic compounds are made up of chains of carbon atoms bonded together and to hydrogen atoms and other functional group.
Functional group is the group of atoms responsible for the chemical properties of a compound.
Molecular Formula gives the type and number of each atom in a compound eg C2H6.
Structural Formula shows how each atom is arranged and bonded in a compound.
Townshend 4
Alkanes
Use IUPAC conventions to name and draw alkanes with up to eight carbons in their longest chain.
These contain only C-C and C-H bonds. They are called saturated hydrocarbons as the have the maximum number of C-H bonds possible and contain only hydrogen and carbon atoms. Rules for naming organic compounds When naming a specific alkane we need to follow the following steps.
Identify the organic family the molecule is a member of, this will form the last part of the name.
Identify the largest carbon chain. This is the main part of the name.
Count the number of carbon atoms in the longest chain to work out the base of the name. Use the following table to work out the base name of the organic molecule.
Number the carbons on the carbon chain so any branches coming of have the smallest number possible.
The branches are named first with the number of its position on the longest chain preceding it. The name of each branch is dependent on the number of carbons in the branch.
Alkyl branches have the following names Multiple groups are named one after each other. Each identical group must have its own name. Multiple groups have the prefix di (two identical groups), tri (three identical groups) or tetra (four identical groups).
Number of C 1 2 3 4 5 6 7 8 9 10
Prefix meth eth prop but pent hex hept oct non dec
C H
H
H
C C
H
H
H
H
H C C C
H
H
H
H
H
H
Hmethyl ethyl propyl
C C C C CH
H
H
CH2
H H
H H
CH3
H
H
H
CH3
Townshend 5
Exercises
1. Name the following molecules
a) b) c)
2. Draw the following molecules
a) methylpropane b) 2,3-dimethylpentane c) 4-ethyl-2-methyloctane
Condensed Structural Formula
The structural formula represents how the atoms in an organic compound are joined to each other. The structural formulas can be drawn in a condensed form. Each carbon atom in the longest chain is written with atoms attached to written to the right of it.
Brackets can be used to identify alkyl branches(i) or condense long structural formulae(ii).
C C C C CH
H
H
H
H CH3
CH3H
H
H
H
HC C C C CH
H
H
H
H CH3
CH3H
H
H
H
H C C C C CH
H
H
H
CH2
CH3H H
H
C
CH3
H H
H
H
H
C C C CH
H
H
H
H H
H H
H
H CH3CH2CH2CH3
Structural formula Condensed structural
formula
C C C CC
H
CH3
H
H CH3
CH3H
H
C
H
H
H H
H
H
CH3CH(CH3)CH2CH(CH3)2CH2CH3
C C C CC
H
H
H
H H
H H
H
C
H
H
H H
H
H
CH3(CH2)4CH3
i
ii
i
Townshend 6
Exercise
3. Draw the structural formula for each of the following condensed formulae.
Constitutional Isomers
Draw and name the constitutional isomers for an alkane’s given molecular formula.
Alkanes that have the same molecular formula but different structural formulae are called constitutional isomers. Constitutional isomers generally have different physical properties as the shape of each isomer affects intermolecular attraction forces. They can also have different chemical properties.
Drawing Constitutional isomers
Draw the carbon frame.
Starting with the longest chain, draw all possible structure.
Draw all of the possible structures for second longest chain, then third longest chain etc…
Check that each of the structures you have drawn is different to each other.
Draw the complete structures for each of the isomers.
The constitutional isomers of C4H10
Four carbons in the longest chain
Three carbons in the second longest chain
CH3(CH2)8CH3 CH3CH(CH2)CH3
C C CC
C CC
C Each C-C bond can rotate 360° this structure is four carbons in the longest chain. The 1
st carbon is just
twisted up instead of being straight.
Ball and stick model
Townshend 7
So there are just two constitutional isomers for C4H10
Exercise
4. Circle the six different unique constitutional isomers of C6H14.
Six C in the longest chain
Five C in the second longest chain
Four C in the third longest chain
C C C CC C
C C C CC
C
C C C CC
C
CCCC C
C
C C C CC
C
C C C C
C
C
C C C C
C C
C C C C
C
C
C CC
C
C CC
C
These are representations of the same molecule as if you flip one 180⁰ you will get the other.
C C CC
H
H H
H
H
H
HH
H
H
C CC
C
H H
H
HH
H
H
H
H
H
butane methylpropane
C C C C
C
C
Townshend 8
Exercise
5. Draw and name the eight constitutional isomers of C7H16.
Physical Properties of Alkanes
Explain how the number and arrangement of carbons effects the melting and boiling points of alkanes.
The boiling and melting of alkanes generally increase with increasing molecular mass.
Number of C atoms 1 2 3 4 5 6 7 8 9 10
Melting point (°C) -182 -183 -188 -138 -130 -95 -90 -57 -53 -29
Boiling point (°C) -161 -88 -42 0 36 69 99 126 151 174
The most important thing that effect. The difference in electronegativity between carbon and hydrogen is very small so are essentially non-polar.
When a substance dissolves in water the following happen. The hydrogen bonds between the water molecules have to break to accommodate the new molecules and the weak intermolecular bonds between the dissolving molecules need to break. Also weak intermolecular attractions between the molecules and water are formed. The solid will dissolve if the bonds formed are stronger than the bonds broken. In the case of alkanes dissolving in water very strong hydrogen bonds between the water molecules have to be broken but only weak temporary dipole attractions are formed between the alkane molecules and the water particles. The ΔH of this reaction is positive so a lot of energy is needed in order for the alkanes to dissolve. Essentially they are insoluble in water.
Exercises
6. Plot the melting point against the number of carbon atoms and the boiling point against the number of carbon atoms.
Townshend 9
M.p. and B.p vs number of carbons in alkane
On the previous graph, draw a horizontal line at 25° to represent room temperature.
What alkane molecules are liquid at room temperature?
All alkanes are insoluble in water as the intermolecular attractions between alkanes and water are a lot weaker than the intermolecular attractions between water molecules.
Number of carbon atoms
Tem
per
atu
re (
°C)
Townshend 10
Alkenes CnH2n
Use IUPAC conventions to name and draw alkenes with up to eight carbons in their longest chain.
Draw and name the constitutional and geometric isomers for an alkene’s given molecular formula.
Explain how the geometric arrangement of the alkene effects the melting and boiling point
Alkenes are a group of hydrocarbons that contain a double bond. They are unsaturated as the carbons with double bond could potentially have more atoms attached to them.
Naming
Alkenes have the suffix ene instead of ane. The number of the carbon atoms on the main chain the double bond is bonded to is placed before the ene. A cis or trans prefix is used when the alkene is a geometric isomer.
The C=C has more importance than the alkyl functional group so should have the smallest number.
Hint: Be sure each carbon atom only has 4 bonds coming of it.
Stereo isomer - Geometric isomers
Atoms at the end of a single bond can swivel 360, this means it makes no difference at what position a substituent is placed around a carbon atom. However atoms at either end of a double bond cannot rotate and substituents are held firmly in place on one side of the alkene. This gives us two different types of geometric isomers.
C C
H H
4-methylpent-2-ene
C C
CH3
CH3
H
H
C C
H
CH3
H
CH3
C C
CH3
CH
H
H
CH3
CH3
cis trans
Townshend 11
C C CH
H H H
H
H
C C C C
H
H
H H H H
H
H
C C C C
H
H
H H
H CH3
H
H C C C C C
H
H
H Cl
Cl
H
H
H
H
H
An alkene will have geometric isomers if the following two conditions are met:
It has a double bond
It has different substituent groups coming of each carbon of the double bond
The polar cis isomer will have higher melting and boiling points due to the increased strength of the intermolecular attractions caused by the dipole-dipole attractions.
Exercise
7. Draw the following molecules
a) cis but-2-ene b) pent-1-ene c) trans hex-2-ene d) 7-methyloct-2-ene
8. Name the following molecules
a) b) c) d)
C C
H
Cl H
Cl
C C
H
Cl Cl
H
δ- δ- δ-
δ-
δ+ δ+ δ+ δ+
The difference in electronegative between the chlorine and carbon atom produces dipoles. These dipoles, along with the asymmetric shape of the cis isomer cause the molecule to be polar.
The trans isomer also has dipoles, however as this shape is symmetric the dipoles cancel out and the molecule is non-polar.
Townshend 12
Identifying alkenes
The presence of double or triple bonds in a molecule can be identified by using bromine water or permanganate (MnO4
-).
Add 10 drops of alkene ample to 2 mL of bromine water. The orange brome water will become colorless on shaking.
Alkynes CnH(2n-2)
Organic molecules that have a triple bond are called alkenes. These are unsaturated hydrocarbons.
Naming
Alkenes have the suffix yne instead of ane
The number of the carbon atoms on the main chain the double bond comes of is placed before the yne.
.
C C
C C CC
H
H
C
H
H
H H
H
H
C C CH
H
H
H
CH3
C Br
pent-2-yne 1-bromo-3-methylbutane
C C CH
H
H
H H
H + Br2(aq) C C CH
H
H
H
Br
H
Br
H
orange colourless
Townshend 13
Townshend 14
Haloalkanes
Use IUPAC conventions to name and draw haloalkanes with up to eight carbons in their longest chain.
Organic molecules that have a halogen (group 17) functional group are called haloalkanes.
Naming
The main part of the name is the same as for alkanes. The halogen substituents are named, Cl, chloro, Br, bromo and are more , or 3important that alkyl groups when naming.
Classification (1°, 2°, or 3°)
Haloalkanes, alcohols or amines can be classified as primary (1°), secondary (2°) or tertiary (3°) depending on the number of carbon atoms the carbon that is attached to the functional group is bonded to.
C
H
X
C C CH
H
H
H
Br
H
H
HC C CH
H
H
H
CH3
H
H
C
H
Br
H
2-bromopropane 3-methyl-1-bromobutane
C C C C CH
H
H
H
CH2
Cl H H
H
C
CH3
H H
H
H
H
Br C C C
CH2
CH3CH3H
H
C
CH3
H
H
F
H
C C C C CH
H
H
H
H CH3
CH3H
Cl
H
H
H
C C C C CH
H
H
H
H CH3
CH3
H
F
H
H
H
primary tertiary
secondary
secondary
primary
Townshend 15
Exercise
9. Draw the following molecules
a) 1 chloro hexane b) 2,2 dibromo pentane c) cis 2,3 dichloro hex-2-ene
10. Name the following molecules
a) b) c) d)
C C C C CH
H
H
H
H Cl
Cl H
H
H
H
HO C C C
H
CH2
CH3CH3H
Cl
C
CH3
H
Br
H
H
C C C C CH
H
H
H
H CH3
Br
H
OH
H
H
H
C C C C CH
H
Cl
H H H
H
C
Cl H
H
H
H
H
CH3
Townshend 16
Alcohols (Alkanols)
Draw and name the constitutional isomers for an alcohol’s given molecular formula.
Describe how to test for the presence of 1⁰, 2⁰ and 3⁰ alcohols.
An alcohol is an organic compound that contains an OH functional group. The general formula for an alcohol is R-OH where R represents an alkyl group (CH3-, CH3CH2-, CH3CH2CH2-).
Naming
Alcohols are named with the suffix ol replacing the e of an alkane. A number in front of the -ol identifies the carbon the OH substituent is attached to.
Exercise
11. Draw the following molecules.
a) methanol b) propan-2-ol c) butan-1,2-diol d) 3 methyl butan-2-ol
12. Name the following molecules
a) b) c) d)
C
H
OH
pentan-2-ol 5-methylhexan-2-ol
C C C C CH
H
H
H
OH H
H H
H
H
H
H C C C C C CH
H
H
H
CH3H
H H
H OH
H H
H
H
Hydroxyl groups are given the lowest number possible
C C C C CH
H
H
H
H CH3
CH3H
OH
H
H
H C C C C CH
H
H
H
H CH3
CH3OH
H
OH
H
H C C C C CH
H
H
H
CH2
OH H H
H
C
CH3
H H
H
H
H
O C C C
H
CH2
CH3CH3H
H
C
CH3
H
H
H
H
Townshend 17
Identifying alcohols – Oxidising agents
Primary or secondary alcohols react with the common oxidants acidified dichromate (Cr2O72-
/H+) and
acidified permanganate (MnO4-/H
+)
Add 10 drops of acidified permanganate to alcohol sample. Purple solution will quickly become colourless is 1° or 2° alcohol is present.
Add 10 drops of acidified dichromate to alcohol sample and heat. The orange solution will turn green/blue if 1° or 2° alcohol is present
Identifying alcohols – Lucas Reagent
The ability and rate of primary, secondary and tertiary alcohols reacting with Lucas reagent can be used as a way to distinguish between these three types of alcohol. Lucas reagent is a mixture of concentrated hydrochloric acid and ZnCl2 (This acts as a catalyst)
Add 5 drops of alcohol sample to 2 mL of Lucas Reagent in a test tube. Shake and observe. If the solution goes cloudy a tertiary alcohol is present. If the solution does not do cloudy, place the test tube in a water bath 30° for 5 min. If the solution goes cloudy after the second step a secondary alcohol is present.
C C C CH
H
H
H
H OH
H H
H
H
Cr2O7
2-/H
+
C C C CH
H
H
H
H O
H
H
H
C C C
H
H H
H H
OH
HH
MnO4
-/H
+
C C C OHH
H
H
H
H O
C C C CH
H
H
H
H OH
CH3H
H
H
HCl/ZnCl2
C C C CH
H
H
H
H Cl
CH3H
H
H
C C C
H
H OH
H H
H
HH
HCl/ZnCl2
C C C
H
H Cl
H H
H
HH
Heat 5 min.
Townshend 18
Hydrogen bond Hydrogen atom bonded to same
carbon as N, O or F atom.
Lone pair of electrons on N, O or F
atom.
Townshend 19
Townshend 20
Amine
Use IUPAC conventions to name and draw amines with up to eight carbons in their longest chain.
Describe how to test for the presence of amines.
Amines are a group of organic molecules that contain the –NH2 functional group. Amines can be classified as primary, secondary or tertiary amines.
Amides can be classified as 1, 2 or 3 depending on how many carbons are bonded to the N atom.
Naming
Primary amines are named by putting the prefix amino and the name of the alkane chain. A number may be needed to say which carbon the NH2 is attached to.
Identification of amines
The smell of decomposing fish is caused by a 3° amine. All amines are weak bases, they form alkaline solutions when they are mixed with water and can be neutralized by reacting them with acids.
Add 10 drops of amine sample to 2 mL of water in a test tube and shake. Test the solution with some red litmus paper, if it goes blue then the sample is basic and probably an amine.
C
H
NH2
2-aminopropane 3-aminoheptane
C C CH
H
H
H
NH2
H
H
H C C C C C C CH
H
H
H
H NH2
H H
H H
H H
H
H
H
H
C C C
H
H NH2
H H
H
HH C C C
H
H NH3
+
H H
H
HH+ OH2 OH3
++
C C C
H
H H
NH2
H
H
H
H
C C N CH3
HH
H
H H
H1⁰ 2⁰ 3⁰
C C N CH3
CH3H
H
H H
H
Townshend 21
Exercise
13. Name the following molecules
a) b) c) d)
e) NH2CH2CH3 f) CH3(CH2)6CH(NH2)CH3 g) CH3CH2CH(NH2)CH2CH3
14. Draw the following molecules
a) 1-aminoheptane b) aminomethane c) 3-aminooctane
15. Classify the following as 1, 2 or 3 amines.
a) b) c)
C C C C HH
H
H
H
H NH2
H H
H
NH2 C C C
CH3
H
H
NH2
H
H
H
C C C C CH
H
NH2
H H H
NH2
C
Cl H
H
H
H
H
CH3
NH2 C C C
CH2
H H H
H
C
CH3
H
Br
H
H
NH2 C C C
CH2
H H H
H
C
CH3
H
Br
H
H C C C C CH
H
H
H H H
H
C
Cl H
H
H
H
NH2
CH3
NH2 C C C
CH3
H
H
NH2
H
H
H
Townshend 22
Aldehydes and Ketones
Use IUPAC conventions to name and draw aldehydes and ketones with up to eight carbons in their longest chain.
Describe how to test for the presence of aldehydes.
Aldehydes
Aldehydes are a group of organic compounds that contain a double bond oxygen at the end of a molecule
Naming
Aldehydes are named on the same way as alkanes but the e on the end of an alkane is replaced by al.
Ketones
Ketones are a group of organic compound that contain a carbon oxygen double bond not at the end of a molecule.
Naming
Ketones are named by replacing the e of alkane with one and by placing the number of the carbon the double bond oxygen is attached to just before.
.
C
O
H
butanal 3-ethyloctanal
C C C CH
H
H
H
H H
H
O
HC C C C C C C C
CH2
CH3
O
H
H
H
H H
H
H
H
H
H
H
H
H
H
H
C
O
propanone 2-bromhexan-3-one
C C CH
H
H O
H
H
H C C C C C CH
H
H
H
Br O
H
H H
H H
H
H
Townshend 23
Exercise
16. Draw the following molecules
a) pentanal b) butan-2-one c) methanal d) 5-methyl-heptan-2-one
17. Name the following molecules
a) CH3CH2CH2CHO b) CH3COCH2 c) CH3CH2COCH2CH3
d) e) f)
Identification of aldehydes and ketones
The carbonyl group in ketones is attached directly to carbon atoms so they cannot be easily oxidised. As aldehydes have a hydrogen atom attached directly to the carbonyl group the can be easily oxidised by weak oxidising agents containing Cu
2+
and Ag+. These oxidising agents will not oxidise alcohols so they are a specific test
for the presence of an aldehyde group.
Tollen’s reagent is a common test for aldehydes. It is distinctive as it produces a silver mirror when aldehydes are present.
Fehling’s solution is another test for aldehydes. Fehling’s solution contains Cu2+
ions and so has a distinctive blue colour. When the solution has a positive reaction with an aldehyde group orange Cu2O(s) is produced.
C C C
H
H H
H
O
HH C C C
H
H H
H
O
O-
H+ 2H2O+2[Ag(NH3)2]2+
+ OH-
4NH32Ag(s) + +
Tollen's reagent silver mirror
C C C C HH
H
H
H
H O
H
H
C C C C
CH3
H
H O
H
H
H
HH
C C C C CH
H
H
H H H
H
C
Cl H
H
H
HO
Townshend 24
Carboxylic acids
Use IUPAC conventions to name and draw carboxylic acids with up to eight carbons in their longest chain.
Describe how to test for the presence of carboxylic acids.
Carboxylic acids are a group of organic compounds that contain the COOH functional group.
Naming
Carboxylic acids are named by putting a suffix –oic acid on the end of the name.
Exercise
30 Draw the following molecules
a) propanoic acid b) hexanoic acid c) methanoic acid d) 5-ethyloctanoic acid
31 Name the following molecules
a) CH3CH2CH2COOH b) CH3(CH2)5CO2H c)
C
O
OH
propanoic acid 5-bromohexanoic acid
C C CH
H
H O
OH
H
H
CH3 CH CH2CH2CH2C
Br O
OH
The numbering always starts from the COOH functional group.
C C C C CH
H
H
H
H H
H H
H O
OH
Townshend 25
Identification of carboxylic acids
All carboxylic acids are weak acids, they form acidic solutions when they are mixed with water and can be neutralized by reacting them with bases.
Add 10 drops of carboxylic acid sample to 2 mL of water in a test tube and shake. Test the solution with some blue litmus paper. If the paper goes red then the sample is acidic and possibly a carboxylic acids.
C C C
H
H H
H
O
OHH C C C
H
H H
H
O
O-
H+ OH2 OH3
++
Townshend 26
Esters
Use IUPAC conventions to name and draw esters with up to eight carbons in their longest chain.
Describe how to test for the presence of esters.
Esters are a group of organic compounds that contain the –COO- functional group.
Naming
Esters have two parts to their name. If we split the molecule at the -O- bond then there is an alkyl side and the side with the carbon oxygen double bond.
Exercise
39 Draw the following molecules.
a) methylpropanoate b) propylbutanoate c) pentylethanoate
40 Name the following molecules
a) b) c) CHOOCH2CH2CH3
d) e)
ethylpropanoate propylmethanoate
C
O
O
C C C
O C C
OH
H H
H
H
H H
HH
H C
O C C C
O
H
H H
H H
H
H
H
C C C O C C
H
H
H H
H O H
H H
H
H
CCCOCC
H
H
HH
HOH
HH
C
H
H
H
H
COCC
OH
HH
C
H
H
H
H
H
C C C O C C
H
H
H H
H O H
H H
C
H
H
C
H
H
C
H
H
C
H
H
H
H
Townshend 27
Identification of esters
Esters are insoluble in water and will often appear as an oily layer floating on top of water. They have a sweet fruity smell.
Townshend 28
Acyl chlorides CnH2n
Use IUPAC conventions to name and draw acyl chlorides with up to eight carbons in their longest chain.
Describe how to test for the presence of acyl chlorides.
Acyl chlorides are a group of organic compounds that contain the COCl functional group.
Naming
Acly chlorides are named by replacing the e of alkane with oyl chloride and by placing the number of the carbon the double bond oxygen is attached to just before.
Exercise
18. Draw the following molecules
a) butanoyl chloride b) ethanoyl chloride c) heptanoyl chloride
19. Name the following molecules
a) CH3COCl b) c) CH3(CH2)4COCl
d) e) f)
C
O
Cl
ethyl chloride butanoyl chloride
C C ClH
H
H O
Cl C C C C
O
H
H H
H H
H
H
C C C ClH
H
H
H
H O
ClCCH2CH2CH2
O
CH3 Cl C C C C
O
H
H CH3
H H
H
H ClCCCC
O
H
HH
HH
H
C
H
C
Br
H
H
H
Townshend 29
Identification of acids chlorides
Acyl chlorides react violently when added to water.
Add five drop of acyl chloride sample to water. Test the gas evolved with moist blue litmus paper. If the sample reacts vigorously and the gas evolved is acid then the sample is an acyl chloride.
C C C
H
H H
H
O
ClH C C C
H
H H
H
O
OHH+ OH2 + HCl(g)
Townshend 30
Amides
Use IUPAC conventions to name and draw amides with up to eight carbons in their longest chain.
Amides are a group of organic compounds that contain the CONH2 functional group.
Amides can be classified as 1, 2 or 3 depending on how many carbons are bonded to the N atom.
Naming
Primary amides are named by replacing the e of alkane with amide. Secondary amides are named by using thre prefix N istead of a number to when aming the alkyle group.
.
Exercise
20. Draw the following molecules
a) methanamide b) heptanamide c) propanamide
21. Name the following molecules
a) CH3CONH2 b) CH3CH2CH2CONH2 c)
C
O
NH2
butanamide N-methylethanamide
C C NH
H
H O
CH3
H
NH2CCCC
O
H
HH
HH
H
H
C C C C CH
H
H
H
H H
H H
H O
O
NH2
C C C
H
H H
H O
O NH2H C C C
H
H H
H O
O NH CH3
H
C C C
H
H H
H O
O NH CH3
CH3
1⁰ 2⁰ 3⁰
Townshend 31
Townshend 32
Amino acids
Draw and name triglycerides, glycerol, alanine, glycine.
Identify optical isomers by recognising chiral carbon atoms.
Describe how enantiomers can be distinguished by using polarised light.
Amino acids are a group of organic compounds that contain the both the COOH and the NH2 functional groups. There are 20 different amino acids that the human body uses to synthesize proteins. 12 of these our bodies can make themselves, 8 have to be sourced from our diet already made, they are called essential amino acids
Naming
Each Amino acid has its own specific name. We need to learn the name and structure of the two simplest α amino acids glycine and alanine.
.
Optical Isomers
Alanine has a carbon atom that has four different substituents attached to it, this is called a chiral carbon. Because of this Alanine can be one of two mirror images (enantoimers).
C C NH2
O
OH
R2
R1
C C NH2
O
OH
H
H
C C NH2
O
OH
CH3
H
glycine alanine
CCNH2
OH
OH
H
L R
Townshend 33
An optical isomer cannot be superimposed (placed on top) of its image.
Right and left hands are optical isomers as they are mirror images but cannot be superimposed on top of each other.
Biological systems are so picky that only one of these optical isomers is used by our body. Optical isomers have identical physical and chemical properties but different biological properties.
A pure mixture of an enantiomer will rotate polarised light in an opposite direction to its optical isomer.
Exercise
22. Draw the following molecules
a) Alanine b) Glycine
L
L
R
R
Chiral carbon
Townshend 34
23. Which of the following molecules can exist as optical isomers, draw the molecules and put an * beside any asymmetric carbon?
a) 2-methylbutan-2-ol b) 1-chloropropane c) pentan-2-ol
24. Draw a 3-D representation for the two enantiomers of 2-chlorobutane.
Solubility of Organic compounds
There are two major factors that affect the solubility of organic compounds.
The molar mass of the molecule: The larger the molar mass of an organic molecule the less likely it will be soluble in water.
Presence of NH2 or OH functional groups: The amine and hydroxyl functional groups are able to form an especially strong type of intra-molecular attraction with water. This attraction is called a hydrogen bond.
Melting and boiling point of Organic compounds
There are three major factors that affect the solubility of organic compounds.
The molar mass of the molecule. The more carbon atoms an organic molecule has the larger the molar mass and the larger the inter-molecular attraction
Highly electronegative elements O, N and the halogens can create polar molecules increasing inter-molecular attractions
The presence of NH2 or OH functional groups: The amine and hydroxyl functional groups are able to form especially strong hydrogen bond between molecules.
Townshend 35
Exercise
25. Name the following molecules
1. 2.
3. 4.
5. 6.
7. 8.
9. 10.
11. 12.
13. 14.
15. 16.
17. 18.
CH3 CH2 CH2 CH2 CH3
CH3 CH2 CH2 CH3
CH3 CH2 CH3
CH3 CH3CH3 CH2 CH2 CH CH2 CH3
OH
CH3 CH2 CH2 CH CH3
OHCH3 CH2 CH2 CH2 OH
CH3 CH CH3
OHCH3 CH2 OH
CH3 CH2 CH CH CH2 CH3 CH3 CH CH CH2 CH3
CH3 CH CH CH3 CH2 CH CH3
CH2 CH2 CH3 C C CH2 CH2 CH3
CH C CH2 CH2 CH3 CH3 C C CH3
CH3 CH CH2 CH3
CH3
Townshend 36
19. 20.
21. 22.
23. 24.
25. 26.
27. 28.
29. 30.
31. 32.
33. 34.
35. 36.
37. 38.
CH3 CH2 Cl
CH3 CH CH3
Br
CH C CH3 CH CH
CH3 CH2 CH2 C CH2 CH3
CH3
CH3
CH3 CH CH CH2 CH3
CH3
CH3
CH3 C CH3
CH3
ClCH3 CH3
CH3 CH2 CH2 CH CH2 CH3
Cl
CH3 CH2 CH2 CH CH3
Cl
CH3 CH2 CH2 CH2 Br
CH3 CH2 C OH
O
CH3 CH2 CH2 CH2 CH2 C OH
O
CH3 CH2 CH2 C OH
O
CH3 CH2 CH CH2 Br
OH
CH2 CH CH2 CH2 OH
CH3 CH2 CH CH2 Cl
CH3CH3
C C
CH3H
H
H
C C
CH3H
HH
C C
CH3CH3
H
Townshend 37
39. 40.
41. 42.
43. 44.
45. 46.
47. 48.
49. 50.
51. 52.
53. 54.
55. 56.
57. 58.
CH3
C C
CH2H
H
CH3CH3 CH2 C O CH2 CH3
O
CH3 CH2 C O CH3
O
CH3 C O CH2 CH3
O
CH3 CH2 C O CH2 CH3
O
CH3 O C CH2 CH2 CH2
O
CH3
CH3 CH2 CH2 CH OH
OH
CH3 C CH2 CH OH
Cl
H
Cl
CH3 C CH3
CH3
NH2
CH2 CH2
NH2
NH2
CH3 CH2 CH2 C CH2 CH3
O
CH3 CH2 CH2 C CH3
O
CH3 C CH3
O
CH3 CH2 CH2 C H
O
CH3 C H
O
CH3 CH2 CH2 CH2 CH2 C NH2
O
CH3 CH2 CH2 C NH2
O
CH3 CH2 CH C NH2
OH O
CH3 CH2 C Cl
O
CH3 CH2 CH2 C Cl
O
Townshend 38
59. 60.
61. 62.
63. 64.
CH3 CH2 CH C Cl
CH3 O
CH3 CH2 C O CH2 CH3
O
CH3 CH2 C N CH3
O H
CH3 C NH CH2 CH3
O
NH2 CH2 C OH
O
NH2 CH C OH
O
CH3
Townshend 39
Exercise
26. Describe the expected observations for each of the distinguishing tests below.
Functional Group Distinguishing tests Observations
Alkene Add 5 drops to bromine water
Add 5 drops to permanganate solution
1⁰ alcohol Add 5 drops to acidified dichromate
Add 5 drops to acidified permanganate
2⁰ alcohol Add 1 ml to Lucas reagent
Add 5 drops to acidified dichromate
3⁰ alcohol Add 1 ml to Lucas reagent
aldehyde Add 5 drops to Fehling’s solution and heat.
Carry out silver mirror test (Tollen’s reagent)
amine Test with red litmus paper
enantiomer Shine polarised light through a solution of one of the enantiomers
carboxylic acid Test with blue litmus paper
Mix with sodium bicarbonate solution
acid chloride Add 5 drops to water. Test solution with moist blue litmus paper
C
H
H
NH2
Cl C
H
CH3
NH2*
C X
C
H
H
OH
C
OH
H
C
OH
H
C
O
OH
C
O
Cl
C
O
H
Townshend 40
Exercise
27. Describe a sequence of tests you could carry out to distinguished between
unlabeled samples of propan-1-ol, propan-2-ol, propanal and propanone.
Townshend 41
28. Describe how you could distinguished between unlabeled bottles of the liquids of
1-aminobutane, butanoic acid, butanoyl chloride, butan-1-ol and butanone using
just water and blue and red litmus paper.
Townshend 42
Exercise
29. Highlight and name the functional groups present in each og the following
organic molecules that we meet in our everyday lives.
dopamine
Dopamine is commonly associated with the pleasure system of the brain, providing feelings of enjoyment and reinforcement to motivate a person proactively to perform certain activities.
tetrahydrocannabinol (chocolate)
salicylic acid (aspirin)
paracetamol
vitamin C
Salbutamol (asthma)
Townshend 43
In the central nervous system, serotonin is believed to play an important role in the regulation of anger, aggression, body temperature, mood, sleep, vomiting, and appetite.
serotonin
oestrogen
testosterone
cholesterol
Townshend
Key Word Definitions
acyl chloride
alanine
alcohol
aldehyde
alkane
alkene
alkyl group
alkyne
amide
amine
amino acid
boiling point
bromine water
carbonyl group
carboxylic acid
chiral carbon
cis
classification
condensed structural formula
Townshend
constitutional isomer
double bond
enantiomer
ester
functional group
geometric isomer
glycine
haloalkane
hydrocarbon
hydroxyl group
Intermolecular attraction forces
isomer
ketone
litmus paper
Lucas reagent
melting point
molecular formula
optical isomer
polarised light
room temperature
saturated
Townshend
soluble
structural formula
substituents
Tollen’s reagent
trans
unsaturated