Unit B Matter and Chemical Change. Changes of states Properties of matter Classification of matter.
Unit 2: Classification of Matter.
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Transcript of Unit 2: Classification of Matter.
www.unit5.org/chemistry
Unit 2
“Chemical change has always been part of the Universe, even before human beings evolved. Indeed, scientists believe that life
began on Earth as a result of complex chemicals reproducing themselves over billions of years. Chemistry is a physical
science; it lies between the biological sciences helping to explain many of life’s processes, and the laws of physics, which include
matter and energy. Chemical processes are constantly occurring within us – when our bodies move, a series of chemical reactions takes place to give the muscles the energy that is taken in from
food. Many species of the animal world make use of chemistry to defend themselves, to kill their prey, and to build fragile structures
that have incredible strength. Modern methods of chemical analysis have led to greater understanding of the chemistry of
nature, so that it is possible to identify those chemical compounds that produce the color, taste, and smell of a flower or a fruit.”
Eyewitness Science “Chemistry” , Dr. Ann Newmark, DK Publishing, Inc., 1993, pg 8
Classification of Matter
MATTER(gas. Liquid,
solid, plasma)
PURESUBSTANCES MIXTURES
HETEROGENEOUSMIXTURE
HOMOGENEOUSMIXTURESELEMENTSCOMPOUNDS
Separated by
physical means into
Separated by
chemical means into
Kotz & Treichel, Chemistry & Chemical Reactivity, 3rd Edition , 1996, page 31
MatterMatter
SubstanceDefinite composition
(homogeneous)
SubstanceDefinite composition
(homogeneous)
Element(Examples: iron, sulfur,
carbon, hydrogen,oxygen, silver)
Element(Examples: iron, sulfur,
carbon, hydrogen,oxygen, silver)
Mixture ofSubstances
Variable composition
Mixture ofSubstances
Variable composition
Compound(Examples: water.
iron (II) sulfide, methane,Aluminum silicate)
Compound(Examples: water.
iron (II) sulfide, methane,Aluminum silicate)
Homogeneous mixtureUniform throughout,also called a solution
(Examples: air, tap water,gold alloy)
Homogeneous mixtureUniform throughout,also called a solution
(Examples: air, tap water,gold alloy)
Heterogeneous mixtureNonuniform
distinct phases(Examples: soup, concrete, granite)
Heterogeneous mixtureNonuniform
distinct phases(Examples: soup, concrete, granite)
Chemicallyseparable
Physicallyseparable
The Organization of Matter
MATTER
PURESUBSTANCES
HETEROGENEOUSMIXTURE
HOMOGENEOUSMIXTURES
ELEMENTS COMPOUNDS
Physical methods
Chemical methods
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 41
1) Chemistry:The study of matter, the changes matter goes through, and the associated energy changes.2) Matter:
Anything that has mass and takes up space (volume)
Pure SubstanceA sample of matter in which all parts have the same properties
Mixture2 or more substances that are physically combined – individual properties are
retained
ElementA substance that can’t be broken down into any other substance by ordinary chemical change
CompoundA substance made of 2 or more elements chemically
combined
HomogeneousConsistent properties
throughout
HeterogeneousUneven, inconsistent distribution
of particles
8) Mixtures vs Elements & Cmpds
a)Mixtures retain properties of constituents
b)Composition of a mixture can vary
c)Mixtures can be homogeneous or heterogeneous
10) Ways to Make Mixtures
a)Element + 1 or more elements
b)Cmpd + 1 or more elements
c)Cmpd + 1 or more cmpds
Gold
24 karat gold 18 karat gold 14 karat gold
Gold
Copper
Silver
18/24 atoms Au24/24 atoms Au 14/24 atoms Au
Elements, Compounds, and Mixtures12) If you have H2 and O2 in a container,
do you have water?
(a)an element(hydrogen)
(b)a compound(water)
(c)a mixture(hydrogen and oxygen)
(d)a mixture(hydrogenand oxygen)
Dorin, Demmin, Gabel, Chemistry The Study of Matter , 3rd Edition, 1990, page 68
hydrogenatoms hydrogen
atoms
oxygen atoms
= Oxygen atom = hydrogen atom
MatterMatter
Pure SubstanceDefinite composition
(homogeneous)
Pure SubstanceDefinite composition
(homogeneous)
Element(Examples: iron, sulfur,
carbon, hydrogen,oxygen, silver)
Element(Examples: iron, sulfur,
carbon, hydrogen,oxygen, silver)
Mixture ofSubstances
Variable composition
Mixture ofSubstances
Variable composition
Compound(Examples: water.
iron (II) sulfide, methane,Aluminum silicate)
Compound(Examples: water.
iron (II) sulfide, methane,Aluminum silicate)
Homogeneous mixtureUniform throughout,also called a solution
(Examples: air, tap water,gold alloy)
Homogeneous mixtureUniform throughout,also called a solution
(Examples: air, tap water,gold alloy)
Heterogeneous mixtureNonuniform
distinct phases(Examples: soup, concrete, granite)
Heterogeneous mixtureNonuniform
distinct phases(Examples: soup, concrete, granite)
Chemicallyseparable
Physicallyseparable
How would you categorize elements and compounds?
During a“physical change”
a substance changes some physical property…
During a“physical change”
a substance changes some physical property…
H2O
…but it is still the same material with the same chemical composition.
…but it is still the same material with the same chemical composition.
H2Ogas
solid
liquid
Physical and Chemical PropertiesExamples of Physical Properties –
properties that can be observed without changing the substance
Boiling point Color Slipperiness Electrical conductivity
Melting point Taste Odor Dissolves in water
Shininess (luster) Softness Ductility Viscosity (resistance to flow)
Volatility Hardness Malleability Density (mass / volume ratio)
Examples of Chemical Properties – the ability of a substance to undergo a chemical reaction
Burns in air Reacts with certain acids Decomposes when heated
Explodes Reacts with certain metals Reacts with certain nonmetals
Tarnishes Reacts with water Is toxic
Ralph A. Burns, Fundamentals of Chemistry 1999, page 23Chemical properties can ONLY be observed during a chemical reaction!
The formation of a mixture
The formation of a mixture
The formation of a compound
The formation of a compoundChemical Change
Chemical Change
Physical Change
Physical Change
Physical & Chemical Changes
Limestone,CaCO3
crushing
PHYSICALCHANGE
Crushed limestone,CaCO3
heating
CHEMICALCHANGE
PyrexPyrex
CO2
CaO
Lime andcarbon dioxide,
CaO + CO2
PyrexPyrex
O2
H2O
PyrexPyrex
H2O2
Light hastens the decomposition of hydrogen peroxide, H2O2. The dark bottle in which hydrogen peroxide is usually storedkeeps out the light, thus protecting the H2O2 from decomposition.
Sunlight energy
Properties of Matter
http://antoine.frostburg.edu/chem/senese/101/matter/slides/sld001.htm
PyrexPyrex PyrexPyrex
ExtensiveProperties
IntensiveProperties
volume:mass:
density:temperature:
100 mL99.9347 g
0.999 g/mL20oC
15 mL14.9902 g
0.999 g/mL20oC
Solubility – a measure of the amount of solute that can be dissolved in a solvent at a given temperature.
Dissolving of Salt in Water
NaCl(s) + H2O Na+(aq) + Cl-(aq)
Cl-
ions
Na+
ions Water molecules
Dissolving of NaCl
Timberlake, Chemistry 7th Edition, page 287
HH
O
Na+
+
-- + -+
+
-
Cl-
+ -
+
hydrated ions
Density
• Density is an INTENSIVEINTENSIVE property of matter.
- does NOT depend on quantity of matter. - color, melting point, boiling point, odor, density
• Contrast with EXTENSIVEEXTENSIVE
- depends on quantity of matter.- mass, volume, heat content (calories)
Styrofoam Brick
Styrofoam Brick
?It appears that the brick is ~40x more dense than the Styrofoam.
MMMM
VV= =DD
VVDD
BrickBrickStyrofoamStyrofoam
Styrofoam Brick
Determining the volume of an irregular solid
Vfinal = 98.5 cm3
- Vinitial = 44.5 cm3
Vfishing sinker = 54.0 cm3
Before immersion
Water
44.5 cm3
After immersion
Fishing sinker
98.5 cm3
Thread
Density
D
M
Vensity
ass
olume
D = M V
M = D x V
V =M D
Cube Representations
1 m3 = 1 000 000 cm3
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 119
Consider Equal Volumes
The more massive object(the gold cube) has the_________ density.
Equal volumes…
…but unequal masses
aluminum gold
GREATER
Density = Mass
Volume
Dorin, Demmin, Gabel, Chemistry The Study of Matter , 3rd Edition, 1990, page 71
Consider Equal MassesEqual masses……but unequal volumes.
The object with the larger volume (aluminum cube) has the density.
aluminum
gold
Dorin, Demmin, Gabel, Chemistry The Study of Matter , 3rd Edition, 1990, page 71
smaller
Christopherson Scales
Made in Normal, Illinois USA
Two ways of viewing density
Dorin, Demmin, Gabel, Chemistry The Study of Matter , 3rd Edition, 1990, page 71
Equal volumes…
…but unequal masses
The more massive object(the gold cube) has thegreater density.
aluminum gold
(A)
Equal masses……but unequal volumes.
(B)
gold
aluminumThe object with the larger volume (aluminum cube) has the smaller density.
Density of Some Common Substances
Density of Some Common Substances
Substance Density (g / cm3)
Air 0.0013* Lithium 0.53 Ice 0.917 Water 1.00 Aluminum 2.70 Iron 7.86 Lead 11.4 Gold 19.3
Density of Some Common Substances
Substance Density (g / cm3)
Air 0.0013* Lithium 0.53 Ice 0.917 Water 1.00 Aluminum 2.70 Iron 7.86 Lead 11.4 Gold 19.3
*at 0oC and 1 atm pressure
Which liquid has the highest density?
52
3
1
4
Coussement, DeSchepper, et al. , Brain Strains Power Puzzles 2002, page 16
least dense 1 < 3 < 5 < 2 < 4 most dense
Specific Gravity
Jaffe, New World of Chemistry, 1955, page 66
0.90.25
water 1.0
ice
cork
aluminum
2.7
reference
substance Density
Density
It is a unitless quantity that expresses a ratio of the substance’s density compared to the reference’s density
Chapter 13: States of Matter Solid, Liquid, and Gas (13.3) (13.2) (13.1)
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 441
Gas Liquid Solid
Average Kinetic Energy and Temperature – they’re the same thing
Kinetic energy
Fra
ctio
ns o
f pa
rtic
les
Average KE1 = lower temperature
Average KE2 = higher temperature
minimum energyfor reaction
Hot vs. Cold Tea
Kinetic energy
Many molecules have anintermediate kinetic energy
Few molecules have avery high kinetic energy
Low temperature(iced tea)
High temperature(hot tea)
Perc
ent o
f mol
ecul
es
~~~
SOLIDS – Chapter 13, Section 3 (p. 396-399)
True solids, or crystaline solids, have a crystal lattice structure – a characteristic, geometric arrangement of particles in a solid
Amorphous(Glass)Crystalline
Crystalline Amorphous
Particle Arrangement
Regular, geometric lattice structure
Irregular, no specific internal order
Shape Characteristic crystal structure
Irregular(broken glass)
Attractive Forces
Strong Variable / Weak
Melting Point
Definite, specific Indefinite – softens gradually
Examples Quartz Glass
Diamond Butter
Allotropes of Carbon
Graphite
Allotropes of Carbon
Diamond
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 455
Sodium Chloride Crystal
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 455
= Cl-
= Na+
crystal lattice structure
a characteristic,
geometric
arrangement of
particles in a solid
Macromolecules and Allotropes of Carbon
Graphite BuckminsterfullereneDiamond
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 27
Allotropes of Carbon
C60 & C70
“Buckytubes”
Buckminsterfullerene“Buckyballs”
Fullerenes
Credit: Baughman et al., Science 297, 787 (2002)
Trojan Horse
Can use ‘camouflage’ to hide things. Be careful what’s in the Trojan!
Buckyballs can hide medicine to treat the human body.
Solid
H2O(s) Ice
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 31
Liquid
H2O(l) Water
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 31
In a liquid• molecules are in constant motion
• there are appreciable intermolecular forces
• molecules are close together
• Liquids are almost incompressible
• Liquids do not fill the container
Gas
H2O(g) Steam
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 31
Characteristics of GasesGases expand to fill any container.
– random motion, no attraction
Gases are fluids (like liquids).– no attraction
Gases have very low densities.– no volume = lots of empty space
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Phase Changes
Kinetic Theory
Kinetic Molecular Theory
• The main assumptions of KMT are…– Gases are made of tiny, individual particles.– The particles move in rapid, random straight-line motion.– Collisions between particles are elastic
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Kinetic Molecular Theory• Particles in an ideal gas…
– have no attractive forces between them. – have no individual volume.
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Kinetic Molecular Theory• Particles in an ideal gas…
– have no attractive forces between them. – have no individual volume.
Why do we use a gas that doesn’t really exist?– It simplifies the model and makes it easier to use– Under most normal conditions real gases behave like ideal
gases
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Real Gases
• Particles in a REAL gas…– have their own volume– attract each other
• Gas behavior is most ideal…– at low pressures– at high temperatures– in nonpolar atoms/molecules
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
8
Elastic vs. Inelastic Collisions
8v1
elastic collision
inelastic collision
v2
v3 v4
Model Gas Behavior
• All collisions must be elastic • Take one step per beat of the
metronome • Container
– Class stands outside tape box
• Higher temperature – Faster beats of metronome
• Decreased volume– Divide box in half
• More Moles – More students are inside box
Mark area of container with tape on ground.
Add only a few molecules of inert gas
Increase temperature Decrease volume Add more gas Effect of diffusion Effect of effusion
(opening size)
Average Kinetic Energy and Temperature – they’re the same thing
Kinetic energy
Fra
ctio
ns o
f pa
rtic
les
Average KE1 = lower temperature
Average KE2 = higher temperature
minimum energyfor reaction
Microscopic view of a liquid near its surfaceThe high energymolecules escapethe surface.
Kinetic energy
Fra
ctio
ns o
f pa
rtic
les Average KE1 = lower temperature
Average KE2 = higher temperature
minimum energyto change phase
Evaporation
H2O(g)molecules
(water vapor)
H2O(l)molecules
A dynamic equilibrium can only be achieved in a closed container
Liquid/Vapor Dynamic EquilibriumThe two key properties we need to describe are
EVAPORATIONEVAPORATION and its opposite CONDENSATIONCONDENSATIONHH22O (O (l l ) ) →→ H H22O (O (gg) H) H22O (O (gg) ) → H→ H22O (O (l l ) )
At At equilibriumequilibrium the the raterate of evaporation of evaporation is equal to the is equal to the raterate of condensation of condensation
add energy and break intermolecular attractions
EVAPORATION
release energy and form intermolecular attractions
CONDENSATION
Water Molecules in Liquid and
Steam
Microscopic view of a liquid near its surface
The high energymolecules escapethe surface.
•Evaporation can only take place at the surface of the liquid
•At higher temperatures, more particles can escape intermolecular attractions
Behavior of a liquid in a closed container
A dynamic equilibriumcan only be achieved in a closed container
• To evaporate, molecules must have sufficient energy to break IM forces.
• Molecules at the surface break away and become gas.
• Only those with enough KE escape.• Breaking IM forces requires energy. The
process of evaporation is endothermicendothermic.• Evaporation is a cooling process.• It requires heat.
Evaporation
Change from gas to liquid
Achieves a dynamic equilibrium with vaporization in a closed system.
What is a closed system?
A closed system means matter can’t go in or out. (put a cork in it)
What the heck is a “dynamic equilibrium?”
Condensation
When first sealed, the molecules gradually escape the surface of the liquid.
As the molecules build up above the liquid - some condense back to a liquid.
The rate at which the molecules evaporate and condense are equal.
Dynamic Equilibrium
As time goes by the rate of vaporization remains constant but the rate of condensation increases because there are more molecules to condense.
Equilibrium is reached when:Rate of Vaporization = Rate of Condensation
Molecules are constantly changing phase “dynamic”
The total amount of liquid and vapor remains constant “equilibrium”
Dynamic Equilibrium
Vapor Pressure
more“sticky”
less likely tovaporize
In general:LOW v.p.
not very“sticky”
more likely tovaporize
In general:HIGH v.p.
measure of the tendency for liquid particles to enter gas phase at a given temp.
a measure of “stickiness” of liquid particles to each other
NOT all liquids have same v.p. at same temp.
Vapor Pressure of:
Propanone @ 40°C =
Ethanol @ 40°C =
Water @ 40°C =
58 kPa
17 kPa
8 kPa
101.3 kPa is Standard Atmospheric Pressure
Copyright © 2007 Pearson Benjamin Cummings. All rights reserved.
Component Percent composition
Nitrogen, N2 78%Oxygen, O2 21%Argon, Ar 0.9%Water, H2O 0 – 4% (variable)Carbon dioxide, CO2 0.034% (variable)
The Earth’s AtmosphereFrom Space
Pressure
KEY UNITS AT SEA LEVELKEY UNITS AT SEA LEVEL
101.3 kPa (kilopascal)
1 atm
760 mm Hg
760 torr
14.7 psi
1013 mbar
14.7 psi
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
2m
NkPa
Sea level
Formation of a bubble is opposed by the pressure of the atmosphere
When the vapor pressure is equal to atmospheric pressure the bubble can expand and the liquid boils
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 452
0 20 40 60 80 1000
20
40
60
80
100
TEMPERATURE (oC)
PRESSURE (kPa)
CHLOROFORM
ETHANOL
WATER
Volatile substances evaporate easily (have high v.p.’s).
BOILING when vapor pressure = confining pressure (usually from atmosphere)
b.p. = 78oC
b.p. = 100oC
atmospheric pressure is 101.3 kPa
Vapor Pressure
93.3
80.0
66.6
53.3
40.0
26.7
13.3
0 10 20 30 40 50 60 70 80 90 100
61.3oC 78.4oC 100oC
chlo
rofo
rm
ethy
l alc
ohol
water
Pre
ssur
e (K
Pa)
Temperature (oC)
101.3
Boiling vs. EvaporationBoiling point: temperature at which
vapor pressure = atmospheric pressure
Revolutionary process - fast
AIRPRESSURE
90 kPa
VAPORPRESSURE
90 kPa
Normal Boiling point: temperature at which vapor pressure = standard atmospheric pressure
AIRPRESSURE
101.3 kPa
VAPORPRESSURE
101.3 kPa
Evaporation vs. Boiling
Boiling: Change from liquid to gas at the boiling point temperature
Evaporation: molecules change from liquid to gas phase below boiling point temperature.
If water is boiling at 89°C, what is the pressure?
Think: if a liquid is boiling, then it MUST have a VAPOR PRESSURE = TO ATMOSPHERIC PRESSURE
101.3 kPa is Standard Atmospheric Pressure
The pressure is approximately 65 kPa
Boiling Point of:
Propanone @ 80 kPa =
Ethanol @ 80 kPa =
Water @ 80 kPa =
48°C
101.3 kPa is Standard Atmospheric Pressure
73°C
94°C
Boiling Point on Mt. Everest
Water exerts a vapor pressure of 101.3 kPa at a temperature of 100 oC. This is defined as its normal boiling point: ‘vapor pressure = atmospheric pressure’
101.3
93.3
80.0
66.6
53.3
40.0
26.7
13.3
0 10 20 30 40 50 60 70 80 90 100
61.3oC 78.4oC 100oC
chlo
rofo
rm
ethy
l alc
ohol
water
Temperature (oC)
Pre
ssur
e (K
Pa)
On top of Mt. Everest
760 mm Hgx kPa = 253 mm Hg
101.3 kPa= 33.7 kPa
Why is boiling a cooling process?Which particles would change phase andhow would that effect the average KE?
Kinetic energy
Fra
ctio
ns o
f pa
rtic
les
minimum energyTo change phase
Average KE = temperature
LiquefactionA gas will change from a gas to a liquid under
conditions of:• High pressure = particles are closer together
causing ↑ attractive forces• Low temperature = particles move slower
allowing more attractive forces to develop
LiquefactionA gas will change from a gas to a liquid under
conditions of:• High pressure = particles are closer together
causing ↑ attractive forces• Low temperature = particles move slower
allowing more attractive forces to develop
Heating CurvesEnergy is added at a constant rate
over time
Tem
per
atu
re (
oC
)
40
20
0
-20
-40
-60
-80
-100
120
100
80
60
140
Time
Melting - PE
Solid - KE
Liquid - KE
Boiling - PE
Gas - KE
Heating Curves (Chapter 17)
• Temperature Change– change in KE (molecular motion) – depends on the specific heat capacity
• Specific Heat (Cstate)– energy required to raise the temp of 1 gram of a
substance by 1°C– water has a very high specific heat capacity
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Specific Heats of Some Substances
Specific Heat
Substance (cal/ g oC) (J/g oC)
Water 1.00 4.18Alcohol 0.58 2.4Wood 0.42 1.8Aluminum 0.22 0.90Sand 0.19 0.79Iron 0.11 0.46Copper 0.093 0.39Silver 0.057 0.24Gold 0.031 0.13
Heating Curves• Phase Change
– change in PE (molecular arrangement)– temp remains constant
• Heat of Fusion (Hf)– energy required to melt 1 gram of a substance at its
m.p.
Heating Curves• Heat of Vaporization (Hv)
– energy required to change 1 gram of a substance from liquid to gas
– usually larger than Hf…why?
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Joule (J ) –
The SI unit used to measure the amount of heat absorbed or released during a reaction.
Calculating Energy Changes - Heating Curve for Water
q = heat m = mass Cstate = specific heat ΔT = change in temp
Tem
per
atu
re (
oC
)
40
20
0
-20
-40
-60
-80
-100
120
100
80
60
140
Time
q = m x Hf
q = m x Hv
q = m x Cwater x
q = m x Csteam x
q = m x Cice x
Csteam = 1.86 J / g • °C
Hf = 334 J / gHv = 2260 J / g
Cwater = 4.18 J / g • °C
Cice = 2.14 J / g •°C
112: Calculating Energy Changes - Heating Curve for Water
How many Joules of heat are needed to completely
melt 100g of ice at 0°C to water at 0°C ?
Tem
per
atu
re (
oC
)
40
20
0
-20
-40
-60
-80
-100
120
100
80
60
140
Time
q = m x HfHf = 334 J / g
q = m Hf
q = (100g)(334 J/g)
q = 33,400 J
113: Calculating Energy Changes - Heating Curve for Water
How many Joules are needed to completely boil 200g of water at 100°C to steam at 100°C ?
Tem
per
atu
re (
oC
)
40
20
0
-20
-40
-60
-80
-100
120
100
80
60
140
Time
q = m x HvHv = 2260 J / g
q = m Hv
q = (200g)(2260 J/g)
q = 452,000 J
114: Calculating Energy Changes - Heating Curve for Water
How many Joules are needed to change the temperature of 50g of water from 25°C to 95°C ?
Tem
per
atu
re (
oC
)
40
20
0
-20
-40
-60
-80
-100
120
100
80
60
140
Time
q = m x Cwater x Cwater = 4.18 J / g • °C
q = m Cwater ΔT
q = (50g)(4.18J/g • °C)(70°C)
q = 14,630 J
ΔT = 95°C - 25°C = 70°C
Cooling Curve for Water – energy is being removed at a constant rate
solid
liquid
gas
Heat added
Te
mp
era
ture
(oC
)
A
B
C
DE
Heating Curve for Water
0
100
LeMay Jr, Beall, Robblee, Brower, Chemistry Connections to Our Changing World , 1996, page 487
Energy Changes Accompanying Phase Changes Exothermic – Energy is released Endothermic – Energy is absorbed
Solid
Liquid
Gas
Melting Freezing
Deposition
CondensationVaporization
Sublimation
Ene
rgy
of s
yste
m
End
othe
rmic
cha
nges
Brown, LeMay, Bursten, Chemistry 2000, page 405
Energy of system
Exotherm
ic changes
solid
liquid
gas
vaporization
condensation
melting
freezing
Heat added
Te
mp
era
ture
(oC
)
A
B
C
DE
Heating Curve for Water
0
100
LeMay Jr, Beall, Robblee, Brower, Chemistry Connections to Our Changing World , 1996, page 487
Endotherm
ic Changes
Exotherm
ic Changes
Reaction RatesAmount of reactant used or product
produced per unit of time
A catalyst is a substance that increases the rate of a chemical reaction.
Ex., Enzymes, catalytic convertors
An inhibitor is a substance that decreases the rate of a chemical reaction.
Ex., Preservatives
Elements, Compounds and MixturesClassification of Matter
MATTER(gas. Liquid,
solid, plasma)
PURESUBSTANCES MIXTURES
HETEROGENEOUSMIXTURE
HOMOGENEOUSMIXTURESELEMENTSCOMPOUNDS
Separated by
physical means into
Separated by
chemical means into
Kotz & Treichel, Chemistry & Chemical Reactivity, 3rd Edition , 1996, page 31
Classification of Matter
uniformproperties?
fixedcomposition?
chemicallydecomposable?
no
no
no
yes
hetero-geneousmixture
solution
element
compound
http://antoine.frostburg.edu/chem/senese/101/matter/slides/sld003.htm
The Chemical Parts List
Diatomic Elements, 1 and 7H2
N2 O2 F2
Cl2
Br2
F2
The 7 Diatomic Elements
Chemical Formulas – shorthand notation for a chemical compound
5 H2SO4Subscript – tells the number of atoms of the preceding element in one formula unit
Coefficient – tells the number of formula units in the entire expression
Chemical Formula – tells the number of atoms of each element in one formula unit of the substance
Number of atoms of an element in an each formula unit is given by the subscript.
Coefficient x Subscript = Number of atoms in an expression
What Do Chemical Formulas Represent?
Chemical Formulas – shorthand notation for a chemical compound
Expression # of formula units
# of atoms of each type in a formula unit
# of atoms of each type in entire expression
Total atoms in the expression
2 NaOH
NH4OH
5 Ca(OH)2
Subscripts outside of parentheses apply to everything inside the parentheses
2
1
5
7
25
8Na = 1 O = 1
H = 2
Na = 2 O = 2
H = 4
Ca = 1
O = 2 x 1 = 2
H = 2 x 1 = 2
N = 1 O = 1
H = 4 +1 = 5
N = 1 O = 1
H = 4 +1 = 5
Ca = 5
O = 10
H = 10
Methods of Separating Mixtures
• Filtration
• Evaporation
• Distillation
• Fractional Distillation
• Crystallization
• Decanting
Filtration separates
a liquid from an
insoluble solid
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 40
Mixture ofsolid andliquid Stirring
rod
Filtrate (liquidcomponentof the mixture)
Filter papertraps solid
Funnel
A Distillation Apparatusused to separate a soluble solid from a
liquid when either or both are to be retained
liquid with a soliddissolved in it
thermometer
condenser
tube
distillingflask
pure liquid
receiving flaskhose connected to
cold water faucetDorin, Demmin, Gabel, Chemistry The Study of Matter , 3rd Edition, 1990, page 282
The solution is boiled and steam is driven off.
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 39
Salt remains after all water is boiled off.
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 39
No chemical change occurs when salt water is distilled.
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 40
Saltwater solution(homogeneous mixture)
Distillation(physical method)
Salt
Pure water
Distillation
Copyright © 2007 Pearson Benjamin Cummings. All rights reserved.
long spout helpsvapors to condense
mixture for distillation placed in here
Furnace
Glass retortA Hero’s Fountain
Eyewitness Science “Chemistry” , Dr. Ann Newmark, DK Publishing, Inc., 1993, pg 13
Fractional Distillation: separation of two or more miscible liquids based on deiiference
in boiling point
Used in petroleum industry to separate crude oil into its varoius components
Decanting is used to separate a liquid from an insoluble solid when either the liquid,
solid or both are to be retained
Separation of a sand-saltwater mixture.
Zumdahl, Zumdahl, DeCoste, World of Chemistry 2002, page 40
Separation of Sand from Salt1. Gently break up your salt-crusted sand with a plastic spoon.
Follow this flowchart to make a complete separation.
Salt-crusted
sand.
Dry
sand.
Wetsand.
Weigh themixture.
Decant clearliquid.
Evaporateto
dryness.
Pour intoheat-resistant
container.
Fill with water.
Stir and letsettle 1 minute.
Weighsand.
Calculateweight of
salt.
Repeat3 times?
Yes
No
2. How does this flowchart insure a completeseparation?