WWU -- Chemistry Experiment 11 ISOLATION OF CAFFEINE FROM TEA Reading Assignment –pp. 119 – 127...
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Transcript of WWU -- Chemistry Experiment 11 ISOLATION OF CAFFEINE FROM TEA Reading Assignment –pp. 119 – 127...
WWU -- ChemistryWWU -- Chemistry
Experiment 11ISOLATION OF CAFFEINE FROM
TEA
• Reading Assignment– pp. 119 – 127– Technique 7, pp. 595 – 613– Green Lab people: download materials– Technique 16, pp. 726 - 731
WWU -- ChemistryWWU -- Chemistry
See page 597 for an example on how this equation is applied to extraction.
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Bottom line!
You will remove more solute (caffeine) from an aqueous solution by using two 1 mL portions of methylene chloride than by using one 2 mL portionof methylene chloride! See the textbook for an example.
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Separatory funnel
Remove from topbefore you start to drain!
Remember! Closestopcock beforepouring stuff in thetop of the funnel!
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Which layer on the top?Which layer is on the bottom?
You need to know the density of the methylene chloride and the density of the aqueous phase to answer this question!
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Green extraction of caffeine from tea
You will remove caffeine from tea using a Solid PhaseExtraction column (SPE).
Be sure to download the experiment and some of the technique materials from Charles Wandler’s web page.
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Solid Phase Extraction (SPE)
Two Neoprene adapters
SPE columnfilled withC-18 silica
Filter flaskTo housevacuum
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C-18 silica Silica is alkylated with long chain hydrocarbon groups, using 18carbons long. This is usually referred to as C-18 silica.
O
Si
O
O
Si
OO
O
O
Si
OO
O
Si
OO
O
Si
O OO
Si
OO
Si
OO
Si
OO
Si
O OO
Si
OO
Si
OO
Si
O OO
CH2
CH3
17Si
CH3
CH3
CH2
CH3
17Si
CH3
CH3
SiCH3)3SiCH3)3
SiCH3)3
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Solid phase extraction (SPE)
• The C-18 column packing is NON-POLAR• Caffeine will move more slowly because
it is attracted to the column packing.• The more polar components such as
tannins, gallic acid and chlorophyll move more quickly down the column with the the polar water
• Once the aqueous materials have moved down the column, then you elute the caffeine with ethyl acetate.
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Three examples:
1. A solid will melt if its vapor pressure is below the applied pressure when the solid is heated to its melting point.
2. A solid will sublime if its vapor pressure is higher than the applied pressure as it is heated. You will not observe melting behavior.
3. If you want to sublime a solid that has a vapor pressure of 50 mm Hg, you can do this if you reduce the pressure, under vacuum, to below this value.
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MIDTERM EXAMINATION
• Friday, February 10th • 2:00 to 2:50 PM• Distillation lab (Exp 6) is due Monday
or Tuesday, depending on your section.Dr. Pavia will post answers to the questions in the post lab on his bulletin board after Tuesday so you have them for the test on Friday!
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Coverage• EXP. 2 SOLUBILITY• EXP. 3 CRYSTALLIZATION• EXP. 5 CHROMATOGRAPHY• EXP. 6 SIMPLE AND FRACTIONAL
DISTILLATION AND GAS CHROMATOGRAPHY
ALSO READ:• PP. 1 - 36• 49 – 71• 80 - 93• TECHNIQUES 1, 2, 3, 4, 5, 6, 8, 10, 12, 14, 15
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Experiment 52PREPARATION OF A C-4 OR C-5
ACETATE ESTER
• Reading Assignment– pp. 128 – 135– pp. 470 – 475– Technique 3, pp. 529 – 534; 536– Technique 6, pp. 585 – 595– Technique 7, pp. 605 – 611– Technique 8, pp. 617 – 629– Technique 19, pp. 742 – 760– Appendix 3, pp. A14 – A32– Appendix 4, pp. A32 – A50 (probably not
required
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* *
Ideal stopping place
ROHCH3COOHH2SO4CH3COORH2O
extract withH2O
aqueousphase
ROHCH3COOH (most)H2SO4 (most)H2O
organic phase
CH3COORH2SO4 (trace)CH3COOH (trace)H2O (trace)ROH (some)
extract withNaHCO3
aqueousphase
organic phase
CH3COORH2O (trace)ROH (some)
H2SO4CH3COOH
CH3COORH2O (trace)ROH (some)
saturatedNaCl
aqueousphase
organic phase
H2OROH
CH3COORH2O (trace)
Na2SO4
H2O
CH3COOR(crude)
CH3COOR(crude)
distillationCH3COOR(pure) There may be some ROH
left in the ester
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Why the extraction with NaHCO3?
CH3
C
O
O HNa HCO3 CH3
C
O NaH2CO3
O CO2 + H2O
Partly solubleIn the ester
Ionic substancenow soluble in theaqueous phase
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3 4 5 6
Minutes
-18
0
50
100
150
mVolts
4.94
3
6.39
2
s:\iln\chemistry\fall2003-summer2004\summer 2004\chem 354\lampman_kriz\c4c5esters\kjester_7;05;45 pm.run
X:Y:
5.2355 Minutes0.00600 mVolts
SR+SR-
WI:2
Preparation of Esters: Gas Chromatography
O C CH3
O
solvent
Unreactedcyclopentanol
Some Alkene mayAppear here
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Preparation of Esters: Gas Chromatography
Ret. Time Width Peak Peak Result Time Offset Area Sep. 1/2 Status No. Name () (min) (min) (counts) Code (sec) Codes ---- ------------ ---------- ------- ------- ---------- ---- ----- ------ 1 4.2884 4.943 0.000 10754 BB 1.8 2 95.7116 6.392 0.000 240011 BB 1.4 ---- ------------ ========== ------- ======= ========== ---- ----- ------ Totals: 100.0000 0.000 250765 Total Identified Counts : 250765 counts
Assume that all response factors = 1.000
In some cases, you may observe extra unknown peaks. Recalculatethe percentages of your data based on the alcohol and ester peaks. Round off the percentages:
4.3 % cyclopentanol95.7% cyclopentyl acetate
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We will not be using response factors for the esters Lab (assuming that they are 1.0). However, you may need to recalculate the data to give new areas if you have “extra” peaks that don’t belong.
The example data in the previous slide can be used directly without doing calculations. The usual productsinclude alkene from dehydration, unreacted alcohol and ester. Esters have the longest retention times, alkenes are lowest and unreacted alcohol is in the middle someplace!
You will also be running the infrared spectrum of yourproduct.
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1)
2)
3)
O
CCH3 OH + H+
O
CCH3 OH
HO
CCH3 OH
H
fast
O
CCH3 OH
H
RO
H
O
CCH3 OH
H
OR H
rate-determining
O
CCH3 O
H
OR
H
H
O
CCH3 O
H
OR
H
H
O
CCH3
OR
HO
HH+ +
fast