Written examination 1 - vcaa.vic.edu.au€¦ · Question 1 Stefan swam laps of his pool each day...

39
9LFWRULDQ &HUWL¿FDWH RI (GXFDWLRQ 2011 )857+(5 0$7+(0$7,&6 Written examination 1 )ULGD\ 1RYHPEHU 5HDGLQJ WLPH DP WR QRRQ PLQXWHV :ULWLQJ WLPH QRRQ WR SP KRXU PLQXWHV 08/7,3/(&+2,&( 48(67,21 %22. 6WUXFWXUH RI ERRN Section Number of questions Number of questions to be answered Number of modules Number of modules to be answered Number of marks A 13 13 13 B 54 27 6 3 27 Total 40 6WXGHQWV DUH SHUPLWWHG WR EULQJ LQWR WKH H[DPLQDWLRQ URRP SHQV SHQFLOV KLJKOLJKWHUV HUDVHUV VKDUSHQHUV UXOHUV RQH ERXQG UHIHUHQFH RQH DSSURYHG JUDSKLFV FDOFXODWRU RU DSSURYHG &$6 FDOFXODWRU RU &$6 VRIWZDUH DQG LI GHVLUHG RQH VFLHQWL¿F FDOFXODWRU &DOFXODWRU PHPRU\ '2(6 127 QHHG WR EH FOHDUHG 6WXGHQWV DUH 127 SHUPLWWHG WR EULQJ LQWR WKH H[DPLQDWLRQ URRP EODQN VKHHWV RI SDSHU DQGRU ZKLWH RXW OLTXLGWDSH 0DWHULDOV VXSSOLHG 4XHVWLRQ ERRN RI SDJHV ZLWK D GHWDFKDEOH VKHHW RI PLVFHOODQHRXV IRUPXODV LQ WKH FHQWUHIROG $QVZHU VKHHW IRU PXOWLSOHFKRLFH TXHVWLRQV :RUNLQJ VSDFH LV SURYLGHG WKURXJKRXW WKH ERRN ,QVWUXFWLRQV 'HWDFK WKH IRUPXOD VKHHW IURP WKH FHQWUH RI WKLV ERRN GXULQJ UHDGLQJ WLPH &KHFN WKDW \RXU name DQG VWXGHQW QXPEHU DV SULQWHG RQ \RXU DQVZHU VKHHW IRU PXOWLSOHFKRLFH TXHVWLRQV DUH FRUUHFW DQG VLJQ \RXU QDPH LQ WKH VSDFH SURYLGHG WR YHULI\ WKLV 8QOHVV RWKHUZLVH LQGLFDWHG WKH GLDJUDPV LQ WKLV ERRN DUH not GUDZQ WR VFDOH $W WKH HQG RI WKH H[DPLQDWLRQ <RX PD\ NHHS WKLV TXHVWLRQ ERRN 6WXGHQWV DUH 127 SHUPLWWHG WR EULQJ PRELOH SKRQHV DQGRU DQ\ RWKHU XQDXWKRULVHG HOHFWURQLF GHYLFHV LQWR WKH H[DPLQDWLRQ URRP 9,&725,$1 &855,&8/80 $1' $66(660(17 $87+25,7<

Transcript of Written examination 1 - vcaa.vic.edu.au€¦ · Question 1 Stefan swam laps of his pool each day...

Page 1: Written examination 1 - vcaa.vic.edu.au€¦ · Question 1 Stefan swam laps of his pool each day last week. The number of laps he swam each day followed a geometric sequence. He swam

2011

Written examination 1

Section Number of questions

Number of questions to be answered

Number of modules

Number of modulesto be answered

Number of marks

A 13 13 13B 54 27 6 3 27

Total 40

name

not

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correct

not

Use the following information to answer Questions 1, 2 and 3.

1009080706050403020100

35

30

25

20

15

10

5

0

number ofcountries

percentage of Internet users

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10 16 22 32 54

region

population density

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200019901980year

average pay rate ($/hour)

25

20

15

10

5

0

not

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Use the following information to answer Questions 6, 7 and 8.

1 121 73

2 126 75

3 141 73

4 125 73

5 122 67

6 126 74

7 70

130 72

125

10 121 65

11 66

12 134 77

13 125 70

14 127 64

15

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systolic diastolic

systolic = + × diastolic diastolic = + × systolic systolic = + × diastolic diastolic = + × systolic systolic = + × diastolic

Use the following information to answer Questions 9 and 10.

z =

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r =

Year 2004 2005 2006 2007

1 012 000 2 016 000 5 140 000

3 455 500 3 661 500

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correct

not

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2011 FURMATH EXAM 1 10

SECTION B – Module 1: Number patterns – continued

Question 1Stefan swam laps of his pool each day last week.The number of laps he swam each day followed a geometric sequence.He swam 1 lap on Monday, 2 laps on Tuesday and 4 laps on Wednesday.The number of laps that he swam on Thursday wasA. 5B. 6C. 8D. 12E. 16

Question 2

An expression for the nth term of this sequence, tn , isA. tn = 1 – 4nB. tn = 1 – 8n C. tn = nD. tn = + 4nE. tn = + 4n

Module 1: Number patterns

Before answering these questions you must shade the Number patterns box on the answer sheet for multiple-choice questions and write the name of the module in the box provided.

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11 2011 FURMATH EXAM 1

SECTION B – Module 1: Number patterns – continuedTURN OVER

Question 3

n

An

0 1 2 3 4 5

8

–8

Let An be the n

A. An+1 = 2An – 2 where A1 = 8

B. An+1 = 3An where A1 = 8

C. An+1 = –2An where A1 = 8

D. An+1 = 12An where A1 = 8

E. An+1 = –An – 1 where A1 = 8

Question 4

Month 1 2 3

Number of bees 10 30 90

not true?A.B.C.D.E.

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tn+2 = tn+1 + tn t1 = a t2 = 7

t5a

0 1 2 3 4

not12

12

121418

12

1418

P2011

P2012P2012 P2011

P2012 P2011 + 15 P2012 P2011 P2012 P2011 + 15 P2012 P2011 P2012 P2011 + 15

n Sn

Sn = n2

Sn = n2– n Sn = 2n Sn = 2n – 1 Sn = 2n + 1

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13

21 47

55 57

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ABC BCA AB = BC

B

x° 69°CA

x 42

111

building A

building B

Q

P

16 m

23 m

Q B P AA B

P QQ P

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15

ACB CAB ABCAB

C

A B80°60°

50 m

AC

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V

C

O 3 m

4 m

2 m

VCO VC

PQRS QPSPQ PS

RQ

18 cm

74°SP 25 cm

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17

AB = BC = CD PAB

A B C D

R

Q

P

16°2400 mm 2400 mm 2400 mm

QD 2741 2767

5201

PQRS

11 m8 m

1 mshallow end

Q

P

R

S

1.8 m deep end

U

T

TU

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ABD = BD BC

ABD 2

A

D

CB 40 cm

24 cm

ABC 2

167

267

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Use the following information to answer Questions 1 and 2.

charge ($)

2.00

1.50

1.00

0.50

00 10 20 30 40 50 60 70 80 90 100

weight (grams)

cannot

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A

3x + 4y = 26

A

F n

F = a + bn

b

C x C = 60 + 5x. R x R = 15x.

2 4

12 16

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21

A.height

number ofmagazines

B.height

number ofmagazines

C.height

number ofmagazines

E.height

number ofmagazines

D.height

number ofmagazines

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2011 FURMATH EXAM 1 22

SECTION B – Module 3: Graphs and relations – continued

Use the following information to answer Questions 7, 8 and 9.Craig plays sport and computer games every Saturday.Let x be the number of hours that he spends playing sport. Let y be the number of hours that he spends playing computer games.Craig has placed some constraints on the amount of time that he spends playing sport and computer games.

y

10

9

8

7

6

5

4

3

2

1

O 1 2 3 4 5x

A

B

x = 2x + y = 9

2x + y = 6

y = 1E

D C

4x – y = 11

Question 7

A. yB. xC. x + yD. 2x + yE. 4x – y

Question 8By spending Saturday playing sport and computer games, Craig believes he can improve his health. Let W be the health rating Craig achieves by spending a day playing sport and computer games. The value of W is determined by using the rule W = 5x – 2y.

W occurs atA. point AB. point BC. point CD. point DE. point E

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23

M

MA B

M M = 2x – 5y M = 5x – 2y M = 5x – 5y M = 5x + 2y M = 5x + 5y

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2011 FURMATH EXAM 1 24

SECTION B – Module 4: Business-related mathematics – continued

Question 1An electrician charges $68 per hour to complete a job. A Goods and Services Tax (GST) of 10% is added to the charge.Including GST, the cost of a job that takes three hours is A. $6.80B. $20.40C. $204.00D. $210.80E. $224.40

Question 2An amount of $22 000 is invested for three years at an interest rate of 3.5% per annum, compounding annually.The value of the investment at the end of three years is closest toA. $2 310B. $9 433C. $24 040D. $24 392E. $31 433

Question 3A van is purchased for $56 000. Its value depreciates at a rate of 42 cents for each kilometre that it travels.The value of the van after it has travelled 32 000 km isA. $13 440B. $26 880C. $29 120D. $32 480E. $42 560

Question 4Nathan bought a $2 500 bedroom suite on a contract that involves no deposit and an interest-free loan for a period of 48 months. He has to pay an initial set-up fee of $25. In addition, he pays an administration fee of $3.95 per month.The total amount that Nathan will have to pay in fees for the entire 48 months, as a percentage of the original price of $2 500, is closest to A. 1.6%B. 4.0%C. 7.6%D. 8.5%E. 8.6%

Module 4: Business-related mathematics

Before answering these questions you must shade the Business-related mathematics box on the answer sheet for multiple-choice questions and write the name of the module in the box provided.

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25

r

15000 11200

15000 11200

3 2

+⎛⎝⎜

⎞⎠⎟ − +⎛

⎝⎜

⎞⎠⎟

r r

15000 11200

15000 11200

36 24

+⎛⎝⎜

⎞⎠⎟ − +⎛

⎝⎜

⎞⎠⎟

r r

15000 1100

15000 1100

3 2

+⎛⎝⎜

⎞⎠⎟ − +⎛

⎝⎜

⎞⎠⎟

r r

15000 1100

15000 1100

36 24

+⎛⎝⎜

⎞⎠⎟ − +⎛

⎝⎜

⎞⎠⎟

r r

15000 11200

15000 11200

4 3

+⎛⎝⎜

⎞⎠⎟ − +⎛

⎝⎜

⎞⎠⎟

r r

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27

2 3 4 5 6

Kip Lab

Nim Max

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Use the following information to answer Questions 3 and 4.

Western Australia

NorthernTerritory

Queensland

New SouthWales ACT

Victoria

SouthAustralia

Tasmania

E

GFA B C

D

H

0 1 2 3 4

ABCDE

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not

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2011 FURMATH EXAM 1 30

SECTION B – Module 5: Networks and decision mathematics – continued

Question 6

A.B.C.D.E.

Question 7K, L and M

Person Activity Duration Immediate predecessor

Andy K 13 –

Brian L 5 K

M 16 L

A. 5B. 13C. 18D.E.

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31

dummy

dummy

E, 4

B, 3

D, 2

C, 5

H, 3

L, 2I, 2

K, 4

J, 5G, 6

F, 7A, 4start finish

B I C H D E F K G J

P Q

QP Q

0 1 2 3 4

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2011 FURMATH EXAM 1 32

SECTION B – Module 6: Matrices – continued

Question 1The matrix below shows the airfares (in dollars) that are charged by Zeniff Airlines to fly between Adelaide (A), Melbourne (M) and Sydney (S).

from

A M S

08597

850

101

8999

0

A

M to

S

A. $85B. $89C. $97D. $99E. $101

Question 2

If A = 0 11 0⎡

⎣⎢

⎦⎥ , B =

10⎡

⎣⎢⎤

⎦⎥ and C =

01⎡

⎣⎢⎤

⎦⎥ , then AB + 2C equals

A. 03⎡

⎣⎢⎤

⎦⎥

B. 30⎡

⎣⎢⎤

⎦⎥

C. 12⎡

⎣⎢⎤

⎦⎥

D. 20⎡

⎣⎢⎤

⎦⎥

E. 23⎡

⎣⎢⎤

⎦⎥

Module 6: Matrices

Before answering these questions you must shade the Matrices box on the answer sheet for multiple-choice questions and write the name of the module in the box provided.

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33

10

32

x

y

48

=

12

12

x

y

53

=

10

02

x

y

48

=

00

32

x

y

612

=

0 1 2 3 4

AB

BA2

BA – 2A A + 2B B2 – AB A–1

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2011 FURMATH EXAM 1 34

SECTION B – Module 6: Matrices – continued

Use the following information to answer Questions 5 and 6.Two politicians, Rob and Anna, are the only candidates for a forthcoming election. At the beginning of the election campaign, people were asked for whom they planned to vote. The numbers were as follows.

Candidate Number of people who plan to vote for the candidate

Rob 5692

Anna 3450

During the election campaign, it is expected that people may change the candidate that they plan to vote for each week according to the following transition diagram.

75% 76%

24%

25%

Rob Anna

Question 5The total number of people who are expected to change the candidate that they plan to vote for one week after the election campaign begins isA. 828B. 1423C. 2251D. 4269E. 6891

Question 6The election campaign will run for ten weeks. If people continue to follow this pattern of changing the candidate they plan to vote for, the expected winner after ten weeks will beA. Rob by about 50 votes.B. Rob by about 100 votes.C. Rob by fewer than 10 votes.D. Anna by about 100 votes.E. Anna by about 200 votes.

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35

A B

T A B

T

this nightA B

0.80.2

0.40.6

A

Bnext nightT=

this nightA B

0.70.3

0.10.9

A

Bnext nightT=

this nightA B

0.50.5

0.50.5

A

Bnext nightT=

this nightA B

0.60.4

0.20.8

A

Bnext nightT=

this nightA B

0.10.9

0.80.2

A

Bnext nightT=

Page 36: Written examination 1 - vcaa.vic.edu.au€¦ · Question 1 Stefan swam laps of his pool each day last week. The number of laps he swam each day followed a geometric sequence. He swam

A

3–4

k

–3A=

A A–1 kk

–4 –2 0 2 4

A A B

AB AB 0 1 2 4 6

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FURTHER MATHEMATICS

Written examinations 1 and 2

FORMULA SHEET

Directions to students

Detach this formula sheet during reading time.

This formula sheet is provided for your reference.

© VICTORIAN CURRICULUM AND ASSESSMENT AUTHORITY 2011

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FURMATH EX 1 & 2 2

Further Mathematics Formulas

Core: Data analysis

standardised score: z x xsx

=−

least squares line: y = a + bx where b rssy

x= and a y bx= −

residual value: residual value = actual value – predicted value

seasonal index: seasonal index = actual figuredeseasonalised figure

Module 1: Number patterns

arithmetic series: a + (a + d ) + … + (a + (n – 1)d ) = n a n d n a l22 1

2+ −( ) = +( )

geometric series: a + ar + ar2 + … + arn–1 = a r

r

n( )11−−

, r ≠ 1

infinite geometric series: a + ar + ar2 + ar3 + … = arr

11

−<,

Module 2: Geometry and trigonometry

area of a triangle: 12bc Asin

Heron’s formula: A = s s a s b s c( )( )( )− − − where s a b c= + +12( )

circumference of a circle: 2π r

area of a circle: π r 2

volume of a sphere: 43π r 3

surface area of a sphere: 4π r 2

volume of a cone: 13π r 2h

volume of a cylinder: π r 2h

volume of a prism: area of base × height

volume of a pyramid: 13

area of base × height

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3 FURMATH EX 1 & 2

END OF FORMULA SHEET

Pythagoras’ theorem: c2 = a2 + b2

sine rule: aA

bB

cCsin sin sin

= =

cosine rule: c2 = a2 + b2 – 2ab cos C

Module 3: Graphs and relations

Straight line graphs

gradient (slope): m y yx x

=−−

2 1

2 1

equation: y = mx + c

Module 4: Business-related mathematics

simple interest: I T=Pr100

compound interest: A = PRn where R r= +1

100

hire purchase: effective rate of interest ≈+

×2

1n

nflat rate

Module 5: Networks and decision mathematics

Euler’s formula: v + f = e + 2

Module 6: Matrices

determinant of a 2 × 2 matrix: A a bc d=

; det A

acbd ad bc= = −

inverse of a 2 × 2 matrix: AAd bc a

− =−

1 1det

where det A ≠ 0