WHMIS
-
Upload
nasim-farley -
Category
Documents
-
view
29 -
download
0
description
Transcript of WHMIS
WHMIS workplace hazardous materials
information system
all chemicals are treated with
WHMIS has been developed to provide guidelines for of reactive materials
respect
handling, storage and disposal
MSDS is amaterial safety data sheet
compressed gas corrosive
flammable and combustible
poisonous and infectious
material causing immediate and serious toxic
effects
biohazardous infectious material
oxidizing material
dangerously reactive material
poisonous and infectious causing other
toxic effects
A. The Atom
proton
neutronelectron
p+
n0
e–
zero charge
positive charge
negative charge
electrons are found in a cloud region around the nucleus
nucleus contains the protons and neutrons which make up most of mass of atom
Science 10 Review
mass number =
isotope =
# protons + # neutrons
atoms with the same # of protons but a different # of neutrons (different mass numbers)
eg) carbon-12 carbon-14
6 p+, 6 n0
6 p+, 8 n0
# neutrons = mass number - # protons
B. Periodic Table
arranged in and
group number =
period number =
groups (columns) periods (rows)
number of outer level (valence) e-
number of energy levels occupied by e-
Ex. Na
Group number =Period number =
13
This info is helpful for drawing Energy Level
Diagrams
C. Energy Level Diagrams
atoms are which means that the
maximum number of e-: 3rd level = 2nd level = 1st level =
electrically neutral # of p+ = # of e-
8 e- 8 e- 2 e-
Examples
11 p+
Na
3 p+
Li
2 e-
8 e-
1 e-
2 e-
1 e-
D. Ions
ions are
neutral atoms are unstable if
atoms will strive to satisfy the in order to become stable…in other words, they strive to have
particles or groups of particles that have a net charge (either positive or negative)
their valence level is not full
octet rule
a full valence level and do so by giving away or taking e-
metals give away e- and become positive ions
eg) Na+, Ca2+, Fe3+
take e- and become negative ions
non-metals
eg) Cl-, P3-, O2-
Examples
11 p+
Na
2 e-
8 e-
1 e-
2 e-
8 e-
11 p+
Na+
sodium atom sodium ion
17 p+
Cl
2 e-
8 e-
7 e-
2 e-
8 e-
17 p+
Cl–
chlorine atom chloride ion
8 e-
Your Assignment: 1. Draw argon and neon and compare to Na+ and Cl–
2. pgs 1,2 in workbook
E. Elements
metals exist as
nonmetals and hydrogen
single atoms
eg) Li(s), Cu(s), Hg(l)
do not exist as single atoms – flagpole!
H2
N2 O2 F2
P4 S8 Cl2
Br2
I2
Try These:
1. Cu(s) =
2. O2(g) =
3. Al(s) =
4. fluorine gas =
5. barium =
6. nitrogen gas =
copper
oxygen gas
aluminum
F2(g)
Ba(s)
N2(g)
F. Ionic Compounds
eg) K+, Be2+ or metals eg) Fe3+, Fe2+
monovalent multivalent
charges on the ions are the result of taking or giving e-
to go from formula to name: name of first ion,
eg) AlCl3 =aluminum chloride
metals + nonmetals or polyatomic ions
then name for second ion then brackets for charge if multivalent,
Fe2O3 =iron (III) oxide
i.e. first element ( ) second element-ide
Try These:
1. Zn3P2 =
2. NaNO3 =
3. NiF3 =
4. MnO2 =
5. Cr2(SO4)3 =
nickel (III) fluoride
manganese (IV) oxide
zinc phosphide
chromium (III) sulphate
sodium nitrate
to go from name to formula: write the symbol for each ion,
eg) calcium sulphide = iron (II) hydroxide =
CaS Fe(OH)2
Try These:
1. lithium bromide =
2. sodium phosphate =
3. magnesium nitride =
4. ammonium sulphate =
5. calcium phosphate =
Na3PO4
Mg3N2
(NH4)2SO4
then add subscripts to balance charges
Ca3(PO4)2
LiBr
Hydrated Compounds
ionic compounds containing in their structure
water is represented by in the formula where is the number of water molecules prefixes:
1 = 6 =
2 = 7 =
3 = 8 =
4 = 9 =
5 = 10 =
water
“xH2O”
mono
di
tri
tetra
penta
hexa
hepta
octa
nona
deca
x
to go from name to formula: give the for the first part of the compound, then name the part as
eg) NaF3H2O =
CuSO45H2O =
ionic name
“xH2O” prefix + “hydrate”
sodium fluoride trihydrate
copper (II) sulphate pentahydrate
to go from name to formula: first part is the …look up the symbol for each ion then balance the charges using subscripts, then for the hydrate part…add where
is the number given in the prefix eg) iron (III) nitrate nonahydrate =
sodium chlorate tetrahydrate =
nickel (II) sulphite heptahydrate =
Fe(NO3)39H2O
NaClO34H2O
NiSO37H2O
same as before
“xH2O”x
Your Assignment: pgs 3,4 in workbook
G. Molecular Compounds
nonmetals only
e- are shared therefore no ions are formedno charges involved
use prefixes in naming
eg) N2O = CO2 =P4O10 =
dinitrogen monoxide carbon dioxide
to go from formula to name:
then name for second element with “ide” ending (including prefix)
tetraphosphorus decaoxide
to go from name to formula: write the symbol for each element,
eg) carbon monoxide = carbon
tetrachloride =
CO CCl4
name of first element (including prefix if necessary),
then use the prefixes to determine the subscripts
i.e. ___first element ___second element -ide
remember the memorizers??????
NH3(g)=
H2O(l) =
H2S(g) =
HF, HCl, HBr, HI =
CH4(g)=
CH3OH(l) =
C2H6(g)=
C2H5OH(l) =
C6H12O6(s)=
C12H22O11(s)=
O3(g)=
H2O2(l)=
ammonia
water
hydrogen sulphide
no prefixes
methane
methanol
ethane
ethanolglucose
sucrose
ozone
hydrogen peroxide
H. Acids always have as the
state and always have
Rules1. hydrogen becomes acid2. hydrogen becomes acid3. hydrogen becomes acid
aqueous (aq)hydrogen
____ide hydro___ic
____ate _______ic____ite ______ous
Try These:
1. hydrogen iodide =
2. hydrogen phosphate =
3. hydrogen nitrite =
4. hydrogen sulphite =
hydroiodic acid
phosphoric acid
nitrous acid
sulphurous acid
HI(aq)
H3PO4(aq)
HNO2(aq)
H2SO3(aq)
Your Assignment: pgs 5-7 in workbook
I. States
acids –
elements –
molecular compounds –
ionic compounds
always (aq)
can be (s), (l) or (g)…see periodic table
can be (s), (l), or (g)
- If not in a solution always (s)
- If in a solution either (s) or (aq)…look up on the solubility chart
Try These:
1. NaCH3COO( ) 6. CaCO3( )
2. BaSO4( ) 7. FeSO4( )
3. KOH( ) 8. (NH4)2S( )
4. Pb(NO3)4( ) 9. Pb(SO4)2( )
5. Hg(CH3COO)2( ) 10. Ca3(PO4)2( )
aq
s
aq
aq
aq
s
aq
aq
aq
s
J. Chemical Reactions
vs.
reaction types:
endothermic
exothermic
1. hydrocarbon combustion
2. simple composition
C?H? + O2(g) CO2(g) + H2O(g)
eg) CH4(g) + 2 O2(g) CO2(g) + 2 H2O(g)
element + element compound eg) 2 Mg(s) + O2(g) 2 MgO(s)
5. double replacement
4. single replacement
3. simple decomposition compound element +
element eg) 2 H2O(l) 2 H2(g) + O2(g)
element + compound element + compound eg) Cu(s) + 2 AgNO3(aq) 2 Ag(s) + Cu(NO3)2(aq)
compound + compound compound + compound eg) Pb(NO3)2(aq) + 2 KI(aq) 2 KNO3(aq) + PbI2(s)
law of conservation of matter says that
we must chemical equations to conserve matter
matter cannot be created or destroyed, it can only change forms
balance
CH4 (g) + O2(g) CO2(g) + H2O(g)
C2H6 (g) + O2(g) CO2(g) + H2O(g)
2 3
2 7 4 6
Balancing Reactions
Your Assignment: pg 8, 1st half p. 9
Try the following:
Potassium iodide solution is added to lead (II) nitrate solution.
KI(aq) + + 2 2
Predicting Reactions
Pb(NO3)2(aq) KNO3(aq) PbI2(s)
NOTE:
- SR and DR reactions always happen in solutions so for ionic compounds check solubility table
- Composition and decomposition do NOT happen in solutions so ionic compounds are (s)
Predicting: single replacement
Copper metal is added to a solution of silver nitrate
Cu(s) + 2 AgNO3(aq) 2 Ag(s) + Cu(NO3)2(aq)Chlorine gas is bubbled through a solution of sodiumphosphide
6 Cl2(g) + 4 Na3P(aq) P4(s) + 12 NaCl(aq)
Your Assignment: pg 2nd half p. 9
K. Significant Digits
any digit from is significant
are significant eg)
are significant eg)
are not significant eg)
1-9
trailing zeros
counted objects and constants are not included in sig digs
“sandwich” zeros
leading zeros
6.3800, 12 000
2.04, 1005.002
0.0065
/ :
+/ :
multiply or divide then round answer to the lowest number of sig digs
add or subtract then round answer to the lowest number of decimal places
L. The Mole
it is a = number 6.02 x 1023 “items”
1. Molar Mass sum of the
eg) CO2 =Al(OH)3 =Cu(ClO3)2 =
44.01 g/mol78.01 g/mol230.45 g/mol
individual atomic masses for each element in a compound
2. Mole/Mass Calculations
n = m M
where: n =
m =
M =
number of moles in mol
mass in g
molar mass in g/mol
m = nM
Example 1
How many moles are in 8.06 g of magnesium oxide? m = 8.06 gM = 40.31 g/moln = ?
n = m M = 8.06 g 40.31 g/mol = 0.1999503 mol = 0.200 mol
Example 2
What is the mass of 0.677 mol of potassium sulphide?n = 0.677 mol
M = 110.27 g/molm = ?
m = nM = (0.677 mol)(110.27 g/mol) = 74.65…g = 74.7 g
Your Assignment: p. 10 & 1st half p. 11
Your Review Assignment: finish p. 11 – p. 13