week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3...

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week 3 February 03, 2016

Transcript of week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3...

Page 1: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

Page 2: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

Page 3: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

Page 4: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

y=mx+b

y = 2x ­ 6

is (10,12) on line?  No 2*10 ­ 6 not equal 12

slope(m)

intercept(b)

y=mx+b

Page 5: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

m=5/2 point slope form:

y­y1=m(x­x1)

(x1,y1) is a pointy­(­6)=(5/2)(x­(­4))

y + 6 = (5/2)(x + 4)

y + 6 = (5/2)x + 10

    ­6                ­6

 y     =   (5/2)x   +  4

m= ­4  /  3

(2,6)  (5,2)

m=   y2 ­ y1

        x2 ­ x1

 6 ­ 2

 2 ­ 5y ­ y1 = m ( x ­ x1)

y ­ 6  = (­4/3) (x ­ 2)

Page 6: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

 lines L1  and L2 with slopes m1 and m2

Parallel   m1 = m2

Perpendicular m1 = ­1/m2 negativereciprocol

ex: perependicular to slope m1 = ­4/3

                     is m2 = 3/4

y=3

x = ­7

Page 7: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

General Form of a Line

Ax  + By  = C

6x  + 2y  = 24

I know (0,12) is y intercept

and (4,0) is x interceptslope: ­12/4

     or ­3

Functions  =  job

domain: input 

range: output

data                graphs          equations

(1,2) (3,4)

(1,2)  (1,3)fun:

not:

f(x) = x + 1

x = 2

g(x)  =  2x ­ 7

find g(3) = 2 * 3 ­ 7  = 6 ­ 7 = ­1 ex:

Page 8: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

40

450

Page 9: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

Page 10: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

Page 11: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

(­2,5] domain

range [­4,2)

x ­ 4 > 0x >   4[ 4 , oo )

Page 12: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

Page 13: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016

Page 14: week 3 February 03, 2016 - MCCC › ~porterr › course › 135 › documents › i3.pdf · week 3 February 03, 2016 y=mx+b y = 2x 6 ... [ 4 , oo ) week 3 February 03, 2016. week

week 3 February 03, 2016