strybosch.files.wordpress.com · Web view1. U 2a)b). down. y-value. x-intercept. y= ax 2 +bx+c ....
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1. U 2a) b) down y-value x-intercept y=ax 2 +bx+c negative second factored vertex c 3a) GCF=3 b) GCF= y or −y 4a) 3 ( 2 x+ 6 y−z) b) y (−2 y 3 + 4 y 2 +1) or −y ( 2 y 3 −4 y 2 −1) 5a) b) c) 6i) V =(3,8 ) ii) x− ∫ ¿ 1∧5 iii) y− ∫ ¿ −10 iv) aos is x= 1+5 2 = 6 2 =3 v) opens down – maximum vi) max value of 8 vii) Moving from the vertex normally (when a=1) is 1 over and 1 down 2 over and 4 down Looking at the graph, we moved 1 over and 2 down 2 over and 4 down We multiplied by 2 – thus the value of a is 2 7a) ( e−6)(e +6) b) c) d) 8a) b) c)
Transcript of strybosch.files.wordpress.com · Web view1. U 2a)b). down. y-value. x-intercept. y= ax 2 +bx+c ....
1. U 2a) b) down y-value x-intercept y=ax2+bx+c negative second factored vertex c
3a) GCF=3 b) GCF=y or − y 4a) 3(2 x+6 y−z ) b) y (−2 y3+4 y2+1) or − y (2 y3−4 y2−1)5a) b) c)
6i) V=(3,8) ii) x−∫¿1∧5 iii) y−∫¿−10 iv) aos is x=1+52
=62=3 v) opens down – maximum
vi) max value of 8
vii) Moving from the vertex normally (when a=1) is 1 over and 1 down 2 over and 4 down Looking at the graph, we moved 1 over and 2 down 2 over and 4 downWe multiplied by 2 – thus the value of a is 2
7a) (e−6)(e+6) b) c) d)
8a) b) c)
9.
10a) The height of the bridge is 21.3 metres
b)
c) y=−0.0044 ¿
Therefore the wire is 21.2m long 5m from the middle.11a)
b) height = 4×6.5=26 feet width = 8×8.4=67.2 feet