Water Resources Planning and Management Daene C. McKinney Water Quality.

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Water Resources Planning and Management Daene C. McKinney Water Quality

Transcript of Water Resources Planning and Management Daene C. McKinney Water Quality.

Page 1: Water Resources Planning and Management Daene C. McKinney Water Quality.

Water Resources Planning and Management

Daene C. McKinney

Water Quality

Page 2: Water Resources Planning and Management Daene C. McKinney Water Quality.

Water Quality Management• Critical component of overall water management in a basin• Water bodies serve many uses, including

– Transport and assimilation of wastes – Assimilative capacities of water bodies can be exceeded WRT intended

uses • Water quality management measures

– Standards• Minimum acceptable levels of ambient water quality

– Actions• Insure pollutant load does not exceed assimilative capacity while

maintaining quality standards– Treatment

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Water Quality Management Process

• Identify – Problem– Indicators – Target Values

• Assess source(s)• Determine linkages

– Sources Targets

• Allocate permissible loads

• Monitor and evaluate• Implement

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Physical Processes Controlling Flux

• Advection– Solutes carried along by flowing water

• Diffusion– Transport by molecular diffusion

• Dispersion– Transport by mechanical mixing

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Models

• Advection + dispersion - major processes by which dissolved matter is distributed throughout a water body (e.g., river)

C = concentration (M/L3)V = Average velocity in reach (L/T)D = Longitudinal dispersion coefficient (L2/T)t = timex = longitudinal distance

Advection term

Dispersion term

Source term

Reaction term

Eq. 10.10 in text

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Steady-state Model• Steady-state

– Where k = decay rate (1/T) kC

x

CV

x

CD

2

20

2

41

V

kDm

– Solution is

– W = loading (M/T) at x = 0

Eq 10.12 in text

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Advection - Dispersion

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Advection Dominated Flow

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Water Quality Example

• W1, W2 = Pollutant loads (kg/day)• x1, x2 = Waste removal efficiencies (%)• P2

max, P3max = Water quality standards (mg/l)

• P2, P3 = Concentrations (mg/l)• Q1, Q2, Q3 = Flows (m3/sec)• a12, a13, a23, = Transfer coefficients

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Water Quality Example

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Water Quality ExampleParamet

erUnits Value

Q1 m3/s 10

Q2 m3/s 12

Q3 m3/s 13

W1 kg/day 250,000

W2 kg/day 80,000

P1 mg/l 32

P2max mg/l 20

P3max mg/l 20

a12 - 0.25

a13 - 0.15

a23 - 0.60

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Water Quality Example

0.11 x79.128.1 21 xx

8.01 x

0.12 x

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Water Quality Example

• Cost of treatment at 1 greater than cost at 2 (bigger waste load at 1)

• Marginal cost at 1 greater than marginal cost at 2, c1 > c2 for same level of treatment

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Water Quality Example

2,10.10.0

79.128.1

8.0

toSubject

Minimize

21

1

2211

ix

xx

x

xcxc

i

Cost of treatment at 1 >= cost at 2marginal cost at 1, c1, >= marginal cost at 2, c1, for the sameamount of treatment.

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Water Quality Example

Page 16: Water Resources Planning and Management Daene C. McKinney Water Quality.

Example

• Irrigation project– 1800 acre-feet of water per year

• Decision variables

– xA = acres of Crop A to plant?

– xB = acres of Crop B to plant?

1,800 acre feet = 2,220,267 m3

400 acre = 1,618,742 m2

Crop A Crop B

Water requirement (Acre feet/acre) 3 2

Profit ($/acre) 300 500

Max area (acres) 400 600

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Example

2

4

6

8

10

2 4 6 8 10xA (hundreds acres)

x B (

hu

nd

red

s ac

res)

xB< 600

xA> 0 xA< 400

3xA +2 xB < 1800

xB > 0

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Example

2

4

6

8

10

2 4 6 8 10xA (hundreds acres)

x B (

hu

nd

red

s ac

res)

xB< 600

xA> 0 xA< 400

xB > 0

Z=3600=300xA +500xB

Z=2000=300xA +500xB

Z=1000=300xA +500xB

(200, 600)

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GAMS CodePOSITIVE VARIABLESxA, xB;

VARIABLESobj;

EQUATIONS objective, xAup, xBup, limit;

objective.. obj =E= 300*xA+500*xB;xAup.. xA =L= 400.;xBup.. xB =L= 600.;limit.. 3*xA+2*xB =L= 1800;

MODEL Calibrate / ALL /;SOLVE Calibrate USING LP MAXIMIZING obj;

Display xA.l;Display xB.l;

Marginal, Lagrange multiplier, shadow price, dual variable

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GAMS Output LOWER LEVEL UPPER MARGINAL

---- EQU objective . . . 1.000---- EQU xAup -INF 200.000 400.000 .---- EQU xBup -INF 600.000 600.000 300.000---- EQU limit -INF 1800.000 1800.000 100.000

LOWER LEVEL UPPER MARGINAL

---- VAR xA . 200.000 +INF .---- VAR xB . 600.000 +INF .---- VAR obj -INF 3.6000E+5 +INF .

Marginal

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Marginals

• Marginal for a constraint = Change in the objective per unit increase in RHS of that constraint.– i.e., change xB

– Objective = 360,000– Marginal for constraint = 300– Expect new objective value = 360,300

600Bx 601Bx

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New Solution LOWER LEVEL UPPER MARGINAL

---- EQU objective . . . 1.000---- EQU xAup -INF 199.333 400.000 .---- EQU xBup -INF 601.000 601.000 300.000---- EQU limit -INF 1800.000 1800.000 100.000

LOWER LEVEL UPPER MARGINAL

---- VAR xA . 199.333 +INF .---- VAR xB . 601.000 +INF .---- VAR obj -INF 3.6030E+5 +INF .

180023 BA xxNote: Adding 1 unit to xB adds 300 to the objective, but constraint 3 says

and this constraint is “tight” (no slack) so it holds as an equality, therefore xA must decrease by 1/3 unit for xB to increase by a unit.

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Unbounded Solution

00

400

toSubject

500300Maximize

BA

A

BA

xx

x

xxZ

2

4

6

8

10

2 4 6 8 10xA (hundreds acres)

x B (

hu

nd

red

s ac

res)

xA> 0 xA< 400

xB > 0

unbounded

Take out constraints3 and 4, objective can Increase without bound

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Infeasibility

00

300023

600

400

toSubject

500300Maximize

BA

BA

B

A

BA

xx

xx

x

x

xxZ

2

4

6

8

10

2 4 6 8 10xA (hundreds acres)

x B (

hu

nd

red

s ac

res)

xB< 600

xA> 0 xA< 400

3xA +2 xB > 3000

xB > 0

Change constraint 4to >= 3000, then no intersection of constraints exists and no feasible solution can be found

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Multiple Optima

BA xxZ 200300Objective

Change objective coefficient to 200, then objective has same slope as constraint and infinite solutions exist 2

4

6

8

10

2 4 6 8 10xA (hundreds acres)

x B (

hu

nd

red

s ac

res)

xB< 600

xA> 0 xA< 400

xB > 0

Z=1800=300xA +200xB

Infinite solutions on this edge

3xA +2 xB < 1800