Variantim 71 םיטנאירו April 2017 תורעהו םינורתפ :תוירוקמ ... · Two...
Transcript of Variantim 71 םיטנאירו April 2017 תורעהו םינורתפ :תוירוקמ ... · Two...
1
Variantim 71 וריאנטים
April 2017
מקוריות: פתרונים והערות
Originals: Solutions & Comments
IRT judges: #2: Givi Mosiashvili (2017) #3: Zoran Gavrilovski (2016-7); #n: Viktor Volchek (2015-
7); Studies: Ofer Comay (2017) H#: Valery Gurov (2017); S#: TBD (2017-8)
Fairies: Alexander Bulavka (2017)
Editors: :עורכים
Orthodox: Evgeni Bourd
Fairies: Michael Grushko
Studies: Ofer Comay
יבגני בורדבעיות רגילות:
מיכאל גרושקובעיות אגדתיות:
עופר קומאיסיומים:
2915
Givi Mosiashvili
Georgia
#2vv 12+10
1.Qd3? [2.Sxf7#] 1...Qxe4 2.Qxe4# 1...Sg5 2.Bxf6# 1...cxd6 2.Re7#
1...Qxd6 2.Qd4# but 1...Ra8+! 1.Rxf6? [2.Re7#] 1...Qxe4 2.Sxf7# 1...Sg5
2.Re6# 1...Bxf6+ 2.Bxf6# 1...Sf4 2.gxf4# but 1...Qxd6!
1.Sxf6! [2.Sxf7#] 1...Qxe4 2.Re7# 1...Sg5 2.Sg4# 1...Bxf6+ 2.Bxf6#
1...Qxd6 2.Qc3#
Barnes, Dombrovskis theme, Rice +le Grand =Mosiashvili sintesis, changed
mates (Author)
2916
David Shtern
Petach Tikva
#2vvvv 8+7
1.Rf6? [2.Sc6#] but 1...dxe3! 1.Qd1? [2.Qxd4#] but 1...d3!
1.Qe1? zz but 1...Qg8! Try: 1.Qd3? [2.Qxd4#] but 1...Qd5!
1.Qc1! zz 1...Qe7/d7/c4 2.S(x)c4# 1...Qe6 2.Rxe6# 1...Qd5 2.Sd3# 1...Qe8
2.Sc4, Qc5/c7# 1...Qg8 2.Qc7# 1...dxe3 2.Qxe3# 1...d3 2.Qc3#
(1...Qc7 2.Re6, Qxc7# 1...Qb7/f8 2.Re6, Sc4# 1...Qa7/g7/h7 2.Re6, Sc4,
Qc5# 1...Qf6 2.Sc4, Qc5#)
The focal play by the BQ is aided by additional moves defending both c7 &
c4. However, there are too many moves by the BQ that give rise to more than
one mate (namely, duals). Can this be somehow corrected (PE)
2917
Evgeni Bourd
Givataim
#2v 8+12
1.Sfe4? [2.Qc3#] 1...Qc5 2.Qxc5# 1...Bxe4 2.Rxe4# 1...Rc6 2.Qd5# 1...Sb4
2.Qxb4# but 1...Re6!
1.Sge4! [2.Qc3#] 1...Qc5 2.Qxc5# 1...Bxe4 2.Rxe4# 1...Rg3 2.Qe5#
1...Sb4 2.Qxb4#
The choice of WS key is determined by the Nowotny refutation (PE)
'd'I'dNG dp0Rdpd' 'd'H'0'$ d'dPiPdr '1'dPd'g !'d')')n rd'd'd'd d'd'd'd'
'd'd'd'h d'd'dqd' '$'d'dpd H'd'ip)' 'd'0'H'd dpd')Pd' 'I'd'd'd dQd'd'd'
'd'd'dBI 1bd'$'0p pd'd'Hrd !'d'd'H' 'd'i'd'h d'd'd'd' 'dn0P)'g d'drd'd'
2
2918
Feliks Rossomakho
Russia
#3vv 9+11
1.Sb4 A? [2.Sd3#] but 1...Se5 a! 1.Sc7 B? [2.Se6#] but 1...Sg5 b!
1.O-O-O! [2.Qe4 [3.Qd4, Qb4, b4#] 2....cxd5 3.Qxd5# 2....b4 3.Qxb4#]
1...Se5 a 2.Sb4 A! [3.Bxd6#] 2....Sf7/c4/d3+ 3.S(x)d3#
1...Sg5 b 2.Sc7 B! [3.Bxd6#] 2....Sf7/e4 3.Se6# 2....f3 3.b4#
1...b4 2.cxb4+ Kb5 3.Qf1# Vladimirov theme
A castling key is always entertaining, especially when combined with such a
prominent theme as “Vladimiriov” (PE)
2919
Arieh Grinblat
Evgeni Bourd
Ashdod/Givataim
#3 12+9
1.f5! [2.Re8+ Kxf5 3.Re5#]
1...Bxf5 2.Rg4+ Bxg4 3.Rff4# 2....Kf3 3.Rxf5#
1...Rxc5 2.Sc3+ Rxc3 3.Rxe3# 2....Kd4 3.Bxc5#
Very good key leading to two Umnov variations (PE)
2920
L. Lyubashevsky
L. Makaronez
Rishon Lezion/Haifa
#3 8+6
1.Qe7! [2.Sg6+ Kg4 3.Qg5#]
1...Qxf5 2.Se2+ fxe2 3.Bg3#
1...Qg4 2.Sd3+ exd3 3.Qe3#
1...Qh1 2.Qg5+ Kxe5 3.f6#
1...Qh4 2.Sg6+ Kg4 3.Qxh4#
The black queen tries to correct its defenses and causes white to keep
changing its strategy (PE)
2921
Alexandr Kuzovkov
Russia
#3v 7+12
1.S1f2? [2.fxe5+ [A] Kd5 3.Rxc5 [C]#]
1...Sc4 a 2.bxc5+ [B] Kd5 3.Sb4#
1...Kd5 b 2.Rxc5+ [C] Kd6 3.fxe5 [A]#
1...Se4 c 2.Rxe5 [D] [3.Sxe4#] 2....Se4~ 3.bxc5#
1...exf4 2.Sxf4 [3.bxc5#] 2...Re6/cxb4,c4/Se4 3.Rxe6/Rd7/Sxe4# but 1...e4!
1.S1b2! [2.bxc5+ [B] 2....Kd5 3.Rxe5 [D]#]
1...Sc4 a 2.Rxc5 [C] [3.Sxc4#] 2....Sc4~ 3.fxe5#
1...Kd5 b 2.Rxe5+ [D] Kd6 3.bxc5 [B]#
1...Se4 c 2.fxe5+ [A] Kd5 3.Sf4#
A special combination featuring a 4-fold Shedey! In addition, there is
exchange of 2nd & 3rd white moves between threat & 1…Kd5 defenses (PE)
2922
Paz Einat
Nes Ziona
#3 10+10
1.Qa8 ! [2.Qa1 C+ Kf4 3.Bd2#]
1...Bxg1 2.Qe4 A+ fxe4 3.f4#
1...Sa7 2.Qd5 B+ exd5 3.Bd6# 2...Kf4 3.Bd2#
1...Kf4 2.Sh3 + gxh3 3.Qe4 A # 2...Ke5 3.Qa1 C#
1...Ba4 2.Rxe6 + Kxe6 3.Qd5 B # 2...Kf4 3.Bd2#
The two Q-sacrifice variations are the core of the problem. These are
combined with return of the 2nd moves, including the threat, as mates (author)
'd'd'G'd dpd'dnd' b0p4'd'0 dpiNd'd' 'd'd'0'$ dP)'d'd' 'd'd')Qg $'d'I'd'
'd'd'$Bd d'0'd'I' 'G'd'dNd dN)'d'd' ')'dk)bd d'4p0'$P ')pdpd'd d'd'd'dq
'd'd'd'd d'I'd'd' 'd'd'd'd dp!'HPd' 'd'Hpi') $'d'dpdq 'd'd'Gbd d'd'd'd'
bd'I'd'd d'd'$'dp 'dpi'd'4 $'0'0'dp ')'0')pd d'dNh'h' 'd'd'd'd d'dNd'd'
'dnd'd'd dQ)bd'I' '0'dp$'d d'd'ipdp 'GPd'dpd d'dpdPd' 'dNd'dRg d'd'd'H'
3
2923
Semion Shifrin
Nesher
#3 10+6
1.Qa8! [2.Rd4+ Kxd4/e5 3.Qd5#]
1...Qb5 2.Sf5 [3.Sg3#] 2...Bxf5 3.Bxf5# 2...Qxd5 3.Qxd5#
1...Sc7/xf6 2.Qa4+ Qxa4 3.Sxd6#
1...Qxe6 2.Rxd6+ Qd5+ 3.Qxd5# 2....Ke5 3.Sxf3#
1...Qg7+ 2.fxg7 ~ 3.Qa4#
Queen defense choice and good sacrifices (PE)
2924
Alberto Armeni
Italy
#3 8+9
1...d5 2.Bxe2+ c4 3.Se6# 2....Sxa4 3.Sb5#
1.Qa8? but 1...e6!
1.Qc6! [2.Qd5+ Sxd5 3.Sb5#]
1...e6 2.Qxd6+ Sd5 3.Sb5#
1...Rh5 2.Qe4+ Bxe4 3.Se6# 2....Sxe4 3.Sb5# 2....Rxe4 3.Sc2#
Nice Nowotny variation (PE)
2925
Jan Timman
Netherlands
Win 6+5
2926
Pavel Arestov
Russia
Win 4+5
2927
Michal Hlinka
Luboš Kekely
Slovakia
Draw B 5+3
'!Ndnd'd d'dqd'db ')'0B)'d d'dRd'I' 'd'dkd'H d'd'dpd' ')'d')'d d'd'd'd'
'I'd'd'd d'd'0'Hb '0'0'd'd d'0'd'd' QdBi'G'd HPh'dPd' 'd'drd'4 d'd'd'd'
'd'd'd'd d'd'd'd' 'd'd'd'd d'd'd'd' 'd'0'dBH 0'd'd')' Pd'0P0'I d'd'dkd'
'd'd'd'd d'd'd'd' 'd'd'd'd d'd'i'0p 'dB$'d'd d'd'dpd' 'dpd'I'd d'd'd'dN
'd'd'drd d'd')')' 'd'd'd'd d'drd'i' 'd'd'd'd d'd'd'I' 'd'd'HBd d'd'd'd'
4
2928
Steffen Nielsen
Martin Minski
Denmark/Germany
Win 9+9
2929
David Gurgenidze
Martin Minski
Georgia/Germany
Win 7+6
2930
Amatzia Avni
Eli Amit
G.Shmuel/Tel Aviv
Draw 8+8
2931
Peter S. Krug
Mario Garcia
Austria/Argentine
Win 6+8
rd'd'd'i 1'0'd'0' 'd'd'dPd hR)'d'dP 'd'0'd'$ d'g'dP0' 'd'd'dPd dQd'd'dK
'1'g'd'd 4Pd'0Bd' 'd'd'd'd d'd'd'd' 'd'd'd'd i'd'H'0' Pd'd'dRd HKd'd'd'
'd'dQ4kd d'd'dpdp 'd'1pd'd d'dNd'dB 'dRd')'d 0'd'd')' bd'd')'d d'd'd'dK
'd'dbi'd dp0'd'd' 'd'd'd'g d')'d'd' ')'d'd'd d'0Kh'!R Pd'0'd'd d'd'd'd'
5
2932
F. Abdurahmanovic
Zvonimir Hernitz
Bosnia/Croatia
H#2 2.1.1.1 8+11
1.dxc2!+ Sd6 2.cxd1=S Bb1#
1.Rxg2! Se3 2.Rg1 Rxg1#
Two line clearance solutions, but clearly the 1st solution is better (PE)
2933
Evgeni Bourd
Givataim
H#2 4.1.1.1 8+6
1.e5 Rd6 2.exf4 Re5#
1.Se5 Rxc2 2.Kd4 Rd6#
1.Sd2 Rf5 2.Qd3 Rxe6#
1.Kxf4 Rg5 2.e5 Rf6#
The half-battery is nicely used to give mates on a “plus” like squares (PE)
2934
Christer Jonsson
Sweden
H#2 2.1.1.1 5+5
1.Qg4 Rf7 2.Kc4 Rd7#
1.Qe4 Rg7 2.Kd4 Rg3#
Interferences for black king arrival square are well known, including the
black/white combination shown here, but this is admirably well constructed
(PE)
2935
Emanuel Navon
Holon
H#2 b)bd4e5 6+11
a) 1.Kd3 Rc7 2.Kc3 Rxh3#
b) 1.Kd4 Ra5 2.Kc5 Qg1#
Anticipatory direct pins by white and the black king makes two moves into a
double-pin (PE)
2936
Jean Haymann
Pardes-Hana
H#2 2.1.1.1 9+11
1.Qxc5 Sc4+ 2.Qd4 Sb2#
1.Rxf6 Qh8 2.Rf2 Sf3#
A very interesting concept: in each variation black captures a white piece on
the intended mating battery and moves away to enable the mate. However,
each solution shows unique strategy with self-pin as the central idea in the
first and interferences in the second (PE)
'd'4'd'd g'd'd'1b 'dnd'dkd d'd'd'dp 'd'dNGNd d'dpdp4' BdPIpdPd d'dRd'd'
Bd'd'd'd G')'d'd' n$'dpd'd dq$'d'dK ')nd')'d d'd'i'd' 'dpd'd'd d'd'd'd'
'dbd'dBG d'd'd'dR 'd'd'dqd I'0'd'd' 'd'd'd'$ d'dkd'd' 'd'd'd'd d'd'd'4'
qd'd'd'd $'dKd'!' 'd'0'd'h dnd'd'dR 'dbgPd'd )'d'i'dp '0p0'd'd d'd'd'd'
'dQd'd'd d'dpd'dp '1')'G'4 dpHPH'd' '0'd'd'0 dPi'd'd' Pd'd'd'0 d'I'd'gr
6
2937
Semion Shifrin
Nesher
H#2 5+6 b) in mate po. Bd6=b c) in mate pos. Sf3=n
a) 1.Bg3 ? d4+ 2.Kf4 d3+ ??
1.Bg5 Ba3 2.Kf4 Bd6#
b) in mating position of a) wBd6 = bBd6 1.Ke5 Kg7 2.Bf4 Sf3#
c) in mating position a) wSf3 = bSf3 1.Sg5 dc 2.Se4 d4#
Nice switchback in b) and good exploitation of the position for the further
solution (PE)
2938
Emil Klemanic
Slovakia
H#2 2.1.1.1 5+12
b) rd8=b
a) 1.Sxg7 Qxg7 2.Ke8 Sxc7#
1.c3 Qxc3 2.Sf6 Qxc7#
b) 1.Sxb5 Qxb5 2.Kc7 Sxe8#
1.e5 Qxe5 2.Sa8 Qxe8#
Two matching pairs showing harmony and unity (PE)
2939
Emanuel Navon
Holon
H#2 4+12 b) in mate pos. Pe4=R c) in mate pos. Rd7=B d) in mate pos. Be6=S
a) 1.Re6 b4 2.Rd6 e4#
b) after a) wP=R 1.Ra6 Re7 2.Bb6 Rxd7#
c) after b) wR=B 1.Bc5 Bc8 2.Bd6 Be6#
d) after c) wB=S 1.Bc5 bxa5 2.Rd6 Sxc7#
The move 1…b4 is the only one possible in the 1st solution but proves
constructive in the further two solutions and just to enable a tempo move the
4th solution (PE)
2940
Christer Jonsson
Sweden
H#3 2.1.1.1 3+5
1.Kg8 Bg1 2.hxg1=R Se4 3.Rg7 Sf6#
1.Kh6 Sb1 2.cxb1=B Kf7 3.Bh7 Be3#
Zilahi with minor promotions with excellent construction (PE)
'd'd'd'I d'd'd'd' 'd'dbd'd d'dnipd' 'd'd'g'd d'0Pd'd' 'd')'d'H d'G'd'd'
'db4nd'd )phkd'H' pd'0pd'd dNdrd'd' 'dpd'1'd d'd'd'd' '!'d'd'd d'd'I'd'
'd'd'd'h d'0pd'd' 'd'd'0'd 0PgkdK0' 'dr0rdpd dPd')'d' 'd'd'd'd d'd'd'd'
'd'dKd'g d'd'd'i' 'd'd'd'd d'G'd'dp 'd'd'd'd d'd'd'd' 'dpH'd'0 d'd'd'd'
7
2941
Menachem Witztum
Tel Aviv
H#3 4+13
b)B=S & b=n
a) 1.Bd1 Bg5 2.c1=S Bxf6 3.Bf3 Be5#
b) 1.Sg1 Sb3 2.c1=B Sd4 3.Sf3 Se2#
Successful twinning leading to unified solutions including two self-blocks on
f3 (PE)
2942 G. Voulgaris & I. Kalkavouras
Greece
H#4.5 2+10
1...Kd6? 2.Ka3! Bf7! 3.Bd3 Kd5 4.Bb1 Kc4 5.Ka2 5.Kb4# (??) d5! (Indian
theme)
1.....Be2? 2.Bd3! Bxf3 3.Bb1 Kc4 4.Ka3 Bd5 5.Ka2 Kb4#(??) Rb3!
(Platzweschel)
1....Bb5+! 2.Ka3! Bxd7 3.Bd3 Be6 4.Bb1 Kc4 5.Ka2 Kb4# (Herlin)
Two strategic maneuvers due to some reason fail, while a third one succeeds
in resolving the puzzle. (authors)
2943
Evgeni Bourd
Givataim
S#2 10+15
1.Sbd3! zz
1...Rxd3 2.Qd5+ Rxd5#
1...Qxd3 2.Qd6+ Qxd6#
Only two variations, but very interesting ones (PE)
2944
Daniele Gatti
Italy
S#5 9+7
1.Bd6! zz
1...Kb7 2.Rcxb6+ Ka8 3.Ra5 Ra6 4.Rb8+ Ka7 5.c5 Rxa5#
1...b5 2.Rc8+ Kb7 3.Rb8+ Kxa6 4.cxb5+ Ka5 5.Bxb4+ Kxb4#
The two variations show very different strategies (PE)
2945
Raffi Ruppin
Rehovot
#6 AntiCirce 9+6
1.Sg6? (2.Se7#) Bxb2(Bf8)!
1.b4 ! [2.b5#]
1...Ba6 2.b5 + Bxb5[bBb5c8] 3.b4 [4.b5#] 3...Ba6 4.b5+ Bxb5[bBb5c8]
5.Sg6 [6.Se7#] 5...Bxe5[bBe5f8] 6.Se5#
A nice logical problem: the two WP’s must be removed, and after 3.b4 black
does not have time for 3…Bc3 (PE)
'd'd'd'd d'd'd'd' 'd'dp0'd d'd'd'd' 'd'd'dp0 d'dPd'ip P0pdb0rd 1rG'd'dK
'd'd'd'd d'dpd'd' b0'd'd'd d'dKdpd' kdBd'd'd d'd'dn4' '0'd'd'd g'd'd'h'
'd'i'db$ dPd'd'dR 'd'dQ4'd d'I'd'dB 'H'd'd'G d'd'0pdp 'dp4q0p) d'Hbgbh'
kd'd'd'd 4'G'd'd' R0Rd'0'd d'd'dBd' '0Pd')'d dP0'd'd' Kdpd'd'd d'H'd'd'
'dbd'd'd G'0pdKd' 'dkH'd'd d'd')Pd' 'd'dPd'H dPd'dpd' ')'d'd'd g'd'd'd'
8
2946
Menachem Witztum
Tel Aviv
H#2 Circe 2 sol. 7+7
1.Sxg4[+wBf1] hxg4[+bSg8] 2.Sxe3 [+wRa1] Rxa5[+bRh8] #
1.Sxe3[+wRa1] fxe3[+bSb8] 2.Sxg4 [+wBf1] Bxb5[+bRa8] #
Perfect scheme with pins, circe-specific anticipatory line closures and fairy
mates (PE)
2947
Emanuel Navon
Holon
#2 b) S#2 10+6
c) H#2 d) Bg4f3
a) #2 : 1.Bxd7! zz 1...f5 2.Re6#
b) S#2 : 1.Rg6! zz 1...f5 2.Bf3 f4#
c) h#2: 1.f5 Sxd3 2.Kd5 Bf3#
d) h#2: +g4f3 1.f5 c6 2.dxc6 Sxc6#
with three different stipulations, and one twin, there are four different
continuations after the black’s move f5 (PE)
2948
Sébastien Luce
France
H==5 Circe 3+2
Locust Q Neut. pawn P
1.b1=Q Kb3 2.d1=Q+ Qxd1-e1(Qd8) 3.Qf8 Kc4
4.Ke8 Kd5 5.Qxb4-a5(Qb8)+ Ke6==
Nice final position in which the two kings and BQ are neutralized (PE)
2949
Janos Csak
Hungary
Ser-S#11 4+9
b)qe8d7
a) 1.Qxe2 2.Qxe8 3.bxa3 4.a4 5.a5 6.a6 7.a7 8.a8=S
9.Sb6 10.Sxc4 11.Qa4 + Bxa4 #
b) 1.Qxd1 2.b4 3.b5 4.b6 5.b7 6.b8=R 7.Rxb1 8.Rb4
9.Rxc4 10.Ra4 11.Qc2 + Sxc2 #
In both solutions W must remove, or control, the B pieces that would interfere
with the selfmate in the last move. (PE)
'dKd'd'd 1'd'd'd' kdPd'd'd 4r)'hnd' '0'd'dBd d'd'$'dP 'd'd')'d d'd'd'd'
'd'd'd'd d'dpd'd' 'd')'0'$ d')'i'dP 'Hpd'dBd d')pI'0' 'd')'dPd d'd'd'd'
'd'd'd'd d'd'dkd' 'd'd'd'd d'd'd'd' '!'d'd'd d'd'd'd' K)'0'd'd d'd'd'd'
'd'dqd'd d'd'd'd' 'd'd'd'd d'd'd'd' 'dnd'd'd g')'d'd' k)Qdpd'4 hrdbI'd'
9
2950
Emanuel Navon
Holon
HS#4.5 9+11
1...a3 2.Sc2 + Ka4 3.Sa1 Sb4 4.Ke1 Ba5 5.Ra8 Sc2,Sd3,Sa6#
An interesting approach to help-self mate: in the final position the BS gives
mate either by double checks or by interfering with WRa8 (PE)
2951
Paz Einat
Nes Ziona
#2vvvvv 16+15 Gr.Hopper < N.rider ±
B,R Hopper B,R
1.<f5-f1 ? [2.Sb5#] 1...<h7xc2 a + 2.Sa3xc2 A #
(1...<xf1 2.Rxd3# 1...<e2 2.<h8#) but 1...dxe5 !
1.<f5-d5 ? [2.±a6-b8#] 1...<h7xc2 a + 2.±a6xc2 B # but 1...b5 !
1.f3 ? [2.±a6-b8#] 1...<h2xc2 b + 2.±a6-xc2 B # but 1...b5 !
1.f4 ? [2.±g4xh2#] 1...<h2xc2 b + 2.±g4xc2 C # but 1...Rg1-g5 !
1.<e4 ? [2.±g4xh2#] 1...<c8xc2 c + 2.±g4xc2 C #
(1...<f1 2.Rxd3# 1...<e2 2.<h8#) but 1...Sxf2 !
1.<e2 ! ]2.Sb5#] 1...<c8xc2 c + 2.Sa3xc2 A # 1...<xe2 2.<h8#
In the 5 tries & solution there is a “dismantled” cyclical Zagoruiko (Rice
cycle) following the 6 different captures on c2 by the 3 grasshoppers on h7, h2
and c8. I believe this is the first time such a theme is realized. I didn’t find a
way to avoid the repeated refutation 1…b5 (author)
2952
R. Krätschmer F. Pachl
Germany
HS#2.5 Circe 7+7
b)bf8b8
a) 1...Qf4 2.Bxg5[+bRh8] + Kxg5 [+wBc1] 3.Qe7 + Bxe7[+wQd1] #
b) 1...Qxg4 2.Qxh5[+bRa8] + Kxh5 [+wQd1] 3.Rh1 + Bh2#
The circe is well used to create mating batteries, self-pins and square guards in
the two harmonious solutions (PE)
2953
Eugene Rosner
USA
#2v AMU 10+6
1.Rb6 ? [2.Rb4 A #] 1...Qxa2 a 2.Rc3 B #
1...Sc2 2.Bxb3# 1...Ba7 2.Qxf7# 1...Bc7 2.Qxf7# but 1...Ra6 !
1.Re3 ! [2.Rc3 B #] 1...Qxa2 a 2.Rb4 A #
1...Sc2 2.Bxb3# 1...Bf4 2.Qxf7#
In AMU the mating, (but not checking), move may only be made by a unit
which is observed by precisely one enemy unit (including King)
A natural AMU Le Grand mechanism with subtle movement of the WR’s and
good thematic refutation (PE)
'd'g'dRd d'd'd')' 'dpdpd'd dp)p)'d' pi')')'d d'dndpd' pd'Ip)'d d'd'H'd'
Bd>d'd'd G'dR0Bd> ±0'0pd'= 0'd')<d' 'd<i'd±d H'0pd'd' K0P$')'? d>d'='4n
'd'I'g'd dpdPGQd' pd'd'd'd d'd'd'4r 'd'd'dNi d'd'd'1' 'd'd'd'd dBd'd'$'
rg'd'dQd dRd'drd' 'd'd'd'd )'G'd'd' 'dk)Pd'd dqd'dRd' Bd')'d'd h'I'd'd'
10
2954
Georgy Bakcsi
Hungary
Ser-S#14 3+9
1.e4 2.e5 3.e6 4.e7 5.e8=S 6.Sc7 7.Sxa6 8.Sxb4 9.Sc6
10.Sxa5 11.Sxb3 12.Sc5 13.Sxa4 14.Sb6 + axb6#
A precise capturing sequence after the WS promotion (PE)
2955
Semion Shifrin Nesher
H#3 2.1.1.. 2+3
a) Take&MakeChess
SymmetryCirce b) Take&MakeChess
FileCirce
a) 1.Bxe2-g3[+wSd7] Sxg3-e1[+bBb6] + 2.Kg4 Sxb6-f2[+bBg3] + 3.Kh4
Sf3# 1.Rh4 Sg3 2.Kxg3-h5[+wSb6] Sxc4-f7[+bBf5] 3.Bg4 Sf4#
b) 1.Kxe2-g1[+wSe1] Sg3 2.Bf1 Sxh5-h4[+bRh8] 3.Rxh4-g2[+wSh1]
Sf3# 1.Rh2 Sg3 2.Kxg3-h1[+wSg1] Se2 3.Bxe2-g1[+wSe1] Sg3#
2956
Sébastien Luce France
H#2 3.1.1.1 4+1
Circe
b)Qa1e1 Neut. Locust, pawn QP
a) 1.Ph2-h1=R + Re1 2.Pxe1=Q Qxe1-f1[+Qe1] #
1.Ke4 Kg4 2.Pd2-d1=Q + Qxd1-e1[+Qd8] #
1.Kf4 Pd4 2.Ph2-h1=B Qxd4 -e5[+Pd7] #
b) 1.Pd2-d1=N Ne3 2.Kf4 Qxe3 -e4[+nSb8] #
1.Pxe1=R[+Qe8] Kh3 2.Re4 Qxe4-e3[+Ra8] #
1.Ph2-h1=N Nf2 2.Pxe1=Q [+Qe8] nLxf2-g3[+Nb8] #
Nice neutral locust mates with a plethora of promotions (PE)
2957
Michael Grushko Kiryat Bialik
Ser-H#5 2.1.1.. 3+1
Parraincirce
PhantomChess GridChess
Neut. Lion Q Pawn P
1.Qc7-cxg5 2.Pe3-e7-e6[+Pg8=Q] 3.Qgd5 4.Pxd5
5.Qg8-d8-d7 [+Qa4] Pd5-d2-d4#
1.Qf4 2.Kxf4 3.Pe3-e7-e6 [+Qf7] 4.Qf7-f1-f5
5.Kxg5 Qc8 [+Pd8=B] #
The combination of fairy conditions allow unusual movements, but makes
following the combination, as well as the mating positions, rather difficult
(PE)
Kdkh'd'd 0'd'd'd' pd')'d'd 0'd'd'd' p4'd'd'd dqd'd'd' 'd'dPd'd 4'd'd'd'
'd'd'd'd d'd'd'd' 'd'd'd'd d'd'd'dr 'dbd'd'd d'd'dkd' 'd'dNd'd d'd'dNd'
'd'd'd'd d'd'd'd' 'd'd'd'd d'd'd'd' 'd'd'd'I d'd'dkd' 'd')'d') !'d'd'd'
'd'd'd'd d'!'d'd' 'd'd'd'd d'd'i')' 'd'd'd'd d'd')'d' 'd'd'd'd d'd'd'd'
11
2958
Michael Grushko Kiryat Bialik
Ser-H#5 0+1+3 PhantomChess GridChess
Parraincirce
Neutral Lion Q pawn P
b) Pc6c5 Ser-H#6
c) Pg4d4 Ser-H#5
d) Pg4e2 Ser-H#6 2 sol
a) 1.Kc7 2.Qxc6 3.Pg4-g7-g6 [+Pc8=Q] 4.Qe6 5.Qxg6 Qe6-b6[+Pd6] #
b) 1.Ke5 2.Kf4 3.Qc8-c1-h6 4.Kg3 5.Kh2 6.Pg4-gxh6 Pc5-c2-c4 [+Qh5] #
c) 1.Ke7 2.Pd4-dxc6 3.Kd8 [+Pb7] 4.Qh8 5.Qh8-hxb7 Pc6-c7[+Pb8=Q]#
d) 1.Pe2-e7-e6 2.Qf5 3.Kxe6 4.Qf5-d7[+Pc8=Q] 5.Ke7
6.nQxc6 Qd7-g7[+Pf6] #
1.Kc7 2.Qxc6 3.Kc7-d6[+Pd5] 4.Ke7 5.Kf6 6.Pe2-e7-e5 Pxe6 ep. #
My comment to the previous problem can be extended here, Michael is
finding ingenious ways to find and implement new mating schemes (PE)
2959
G. Bakcsi & J. Csak Hungary
Ser-S#19 3+9
1.Kf1 2.Ke2 3.Kd3 4.Kd4 5.Ke5 6.Kxf6 7.Kg6 8.f6 9.f7 10.f8=Q 11.Qxc8
12.Qxc1 13.Kg5 14.Kxh4 15.Kxg4 16.Kf3 17.Ke2 18.Kf1 19.Kg1 Rxc1 #
The WK is making its way back to its diagram square. The position of BBc1
forces move order as the WQ must capture the B before the WK can move to
g5 (PE)
2960
Georgy Bakcsi
Hungary
Ser-R#10 5+6
1.Kh7 2.Kh6 3.Kh5 4.Kh4 5.Kxh3 6.Kh4 7.Kh5 8.Kh6
9.Kh7 10.Kh8 Rxh2#
Switchback along the h-file driven by the need to re-pin the WR (PE)
2961
Sébastien Luce
France
H==4.5 Circe 3+2 Neut. Locust Q Rose N
1...Nd5 2.Qxd5-c6[+wNd8] Nb7 3.Qxb7-a8[+wNb8] Nf8
4.Qxf8-g8[+wNf8] + Kh4 5.h1=Q + Nh3 ==
The neutral Locust and the Rose combine forces to neutralize the BK (PE)
'dQd'd'd d'd'd'd' 'dPi'd'd d'd'd'd' 'd'd'dPd d'd'd'd' 'd'd'd'd d'd'd'd'
'dnd'd'd d'd'd'd' 'd'd'h'd d'd'dPd' 'd'd'dp4 d'd'd'0' pd'd'dPd irg'd'I'
'd'd'd'I d'd'd'd' 'd'd'd'd dpd'd'd' ')'d'd'd G'd'd'dp '$'d'dr) g'i'd'4'
Nd'd'd'd d'd'd'd' 'd'd'd'i d'd'd'd' 'd'd'dKd d'd'd'd' 'd'd'd'0 d'd'd'dQ