Unit3 Binary Rectification 1
Transcript of Unit3 Binary Rectification 1
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The McCabe-Thiele
Graphical MethodEpisode 1
Application toBinary Rectification
Whats Showing?
Rewind of the McCabe Thiele Method Special Clip on Binary Rectification Rectification and Stripping in Plates Drama of the Rectifying and Stripping Sections
Intrigues of the Feed Plate Putting our Act Together to Determine the
Number of Ideal Plates
It is a graphical method for solvingmultistage applications.
It assumes constant molal overflow fromeach stage.
Like the Kremser Equation, the M-T
Method assumes that some constantrates exist in the flow.
However, the equilibrium relation for thesystem is not linear.
The McCabe-Thiele MethodA Rewind This is a distillation application to a
binary system where a fractionatingcolumn is used.
A Reflux Rate from a Condenser and aBoil-up Rate from a Reboiler generatethe liquid and vapor flows throughseveral contact plates.
The Feed is introduced in a properplate; the section above the feed iscalled the Rectifying Section; below it isthe Stripping Section.
Binary Rectification
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A Simple FractionatingColumn
Distillate
Feed
Bottoms
Reflux
TC
PR
Total Condenser
Partial Reboiler
F
D
B
x
x
xF
D
B
LV
V L
RectifyingSection
StrippingSection
Boil-up
Visualization of the Column
Plates are numbered serially fromtop to bottom.
The McCabe-Thiele Methodassumes that the liquid and vaporflows from each plate are constant
in each section.For Rectifying Section: L & VFor Stripping Section: L & V
Plate Analysis Plate Analysis
n
n - 1
n + 1
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As contact between liquid and vaporoccurs in each plate, the vaporbecomes richer in MVC; while MVC isremoved from the liquid.
Rectification - enrichment of the vaporwith MVCStripping- removal of MVC from theliquid
Plate Analysis
This means that the MVC fraction inthe vapor (y) increases from bottomto top and the MVC fraction in the
liquid (x) decreases from top tobottom.
The plate temperature (T) increasesfrom top to bottom.
Plate Analysis
Plate Analysis
n
n - 1
n + 1 T
T
T
n + 1
n
n - 1
xn
xn-1yn
yn+1
Equilibrium Data
Binary Equilibrium Data Sources Handbook Distillation Section Ideal System
A plot of y versus x equilibrium data isneeded.
A diagonal (x = y) plot is also drawn for
use in the McCabe-Thiele Method.
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Methanol -Water Equilibrium Data
y
x0 0.2 0.4 0.6 0.8 1
0
0.2
0.4
0.6
0.8
11
0
10
DistillateReflux
TC Total Condenser
D xD
n
LV
n + 1y x
n
L
VAnalysis of the Rectifying Section
Material Balances:Stream Balance:
V = L + D
MVC Balance: V y = L x + D xn + 1 n D
n + 1y x
nxD
L D
V V= +
Rectifying LineEquation
n + 1y x
nxD
D
V
L
V= +
Rectifying LineEquation
Analysis of the Rectifying Section
But: V = L + D Let: RD
L
D= Reflux Ratio
The RLE is a straight line with slope:L
V
L
V
RD
RD 1+
=
n + 1y
RD
RD
1+
xn
xD
RD
1++=
1
D
V
=
RD +
1
Another Form ofthe RLE
Analysis of the Rectifying Sectionn + 1
y
RD
RD
1+
xn
xD
RD
1++=
Slope =
RD
RD
1+
Y-Intercept =
xD
RD
1+
Diagonal (x=y) Analysis:
If x = y , then x = xD
This means that the RL willintersect the diagonal when
Dx x=
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Analysis of the Rectifying SectionProcedure To Plot the Rectifying Line:
1. Given the Reflux Ratio and Distil late Composition,calculate the y-intercept of the RL.
2. Plot xD in the diagonal.3. Connect xD in the diagonal with the y-intercept.
Example:
Given a Distillate with 90 mole% Methanol, 10 mole% Waterand a Reflux Ratio of 0.8.
xD =0.9
RD
= 0.8xD
RD
1+= 0.5
xD
Y-int
RL
0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
Analysis of the Stripping Section
BottomsPR
Partial Reboiler B xB
xm - 1m
y
V L
Material Balances:Stream Balance:
BL V= +
V L B= -
MVC Balance: L xm - 1
Vm
y B xB
= +
L
V
B
Vm
y xm - 1
xB=
Stripping LineEquation
m
V
L
Analysis of the Stripping SectionL
V
B
Vm
y xm - 1
xB=
The SLE is a straight line with slope:L
V
Note that the Y-intercept of the SLE is negative.
Diagonal (x=y) Analysis:
This means that the SL will
intersect the diagonal when
x =
If x = y , then x = xB
xB
To plot easier the SL, another straight line equation may bederived by combining the RLE and SLE. This is the FeedLine Equation (FLE).
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Analysis of the Feed Plate
FeedF
L
LV
V
Let q = mole of liquid contributed by 1 moleof feed to the Stripping Section1 - q = mole of vapor contributed by 1 moleof feed to the Rectifying Section
Analysis of the Feed Plate
FeedF
L
LV
V
Therefore: L L
(1 - q)
q
+=
F= +
V V F
Derivation of the Feed Line Equation From the RLE: V y = L x + D xDFrom the SLE: V y = L x - B xB
Subtracting: (V - V) y = (L - L) x + D xD + B xB
Also the Over-all MVC Balance is: F xF = D xD + B xB
From the Analysis of the Feed Plate:
Eqn A
(V - V) = (1 - q) F and (L - L) = -q F
Eqn A therefore becomes: (1 - q) F y = -q F x + F xF
(1- q)y x=
-q
(1- q)+
xF
(1- q)y x= +
xFq
(q - 1)Feed LineEquation
Derivation of the Feed Line Equation(1- q)
y x= +xFq
(q - 1)
The FLE is also a straight line with slope:q
(q - 1)
Diagonal (x=y) Analysis:
If x = y , then x =This means that the FL willintersect the diagonal when
x =
xF
xF
Since the FLE is derived from the RLE and SLE, this meansthat the three lines intersect. Thus the SL should pass theintersection of the RL and FL.
NOTE: THE VALUE OF q DEPENDS ON THE TYPE OF FEED.
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Types of Feed
Saturated Liquid
FeedF
L
LV
V
q = 1
V V= LL = F+
Slope of the Feed Line is Infinity.
Types of Feed
Saturated Vapor
FeedF
q = 0
V V= LL =F+
Slope of the Feed Line is Zero.
L
LV
V
Types of Feed
Wet Mixture
FeedF
0 < q < 1
V V= LL =+ (1 - q) F + q F
Slope of the Feed Line is Negative.
L
LV
V
Types of Feed
Subcooled Liquid
FeedF
q > 1
V V
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Types of Feed
Superheated Vapor
FeedF
q < 0
V V= LL
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xF
Feed Line forWet Mixture
0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
xF
Feed Line forSaturated Vapor
0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
xF
Feed Line forSuperheated Vapor
0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
Plotting of the Stripping Line
1. Plot the Rectifying Line.2. Plot the Feed Line.3. Plot xB in the Diagonal.4. From xB in the Diagonal, draw a straight
line passing through the intersection ofthe Rectifying and Feed Lines.
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xDxFxB0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
Determination of the Number of Ideal Stages
Example: A saturated liquid mixture of 50%methanol, 50% water by mole will be distilled in acolumn using a total condenser and partial reboiler.The distillate is to contain 90 mole% methanol whilethe bottoms shall have 5 mole% methanol. RefluxRatio is 0.8. Using a Feed Rate of 100 Moles/hr and
the McCabe-Thiele Method, determine:
a) Molal Rates of Liquid and Vapor in RS and SSb) Number of Ideal Plates Neededc) Mole % Methanol in L & V from each plated) Location of the Feed Plate
Determination of the Number of Ideal Stages
Given: F = 100 moles/hr xF = 0.5 q = 1xD = 0.9 xB = 0.05 Rd = 0.8
Required: a) L, V in RS & SSb) No. of ideal platesc) y and x from each plate
Solution:
V = L + D Rd = L/D = 0.8V = (Rd + 1)D F = D + B = 100F xF = D xD + B xB D = 52.9412L = 42.3529 V = 95.2941 = VL = L + F = 142.3529
Determination of the Number of Ideal Stages
Procedure to Get No. of Ideal Stages:1. Plot the RL, FL, and SL.2. From xD in the diagonal, draw triangular
steps using the EL and RL alternately.3. Shift to the SL once the intersection of
the RL and FL is reached or passed by.4. Continue drawing the triangular steps
until xB is reached or passed by.5. Number of Ideal Stages = No. of Steps
Number of Ideal Plates = No. of Steps - 1since the Partial Reboiler is an Ideal Stage
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xDxFxB0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
Determination of the Number of Ideal Stages
Reflux
TC Total Condenser
D xD1 L xo
V y1
x1y2
Analysis of the First Plate
y1 = xo = xD
(X1, y1) - equilibrium composition
Drawing the First Plate
xDxFxB
y1
x1
y2
0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
Locating the Feed Plate
xDxFxB0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
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Shifting to the Stripping Section
xDxFxB0 0.2 0.4 0.6 0.8 1
0
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
Completing All the Ideal Stages
xDxFxB0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi
Determination of Plate Compositionsand Feed Plate Location
To Get the Liquid and Vapor Compositionsfrom Each Plate:
Using the EL, read the x and y valuesfor each step corresponding to a plate.
To Locate the Feed Plate:Locate the step that crosses over the
intersection of the RL and FL. Thiscorresponds to the feed plate.
xDxFxB
1
23
4
5
PR
0 0.2 0.4 0.6 0.8 10
0.2
0.4
0.6
0.8
11
0
yi
di
10 xi