Unit V: Logarithms Solving Exponential and Logarithmic ...

23
Objective: SWBAT apply properties of exponential functions and will apply properties of logarithms. Bell Ringer: Complete Exit Ticket HW Requests: 1) Solving Exponential Equations Worksheet and 2) Log Equations WS from Friday 3) Solve Log and Exponential Eqns using logs WS Homework: Review Worksheet odds Announcements: Chapter 3 Test Friday. Break Packet available online Friday (ACT Prep) State Champions MPHS Date: 3/20/13

Transcript of Unit V: Logarithms Solving Exponential and Logarithmic ...

Page 1: Unit V: Logarithms Solving Exponential and Logarithmic ...

Objective: SWBAT apply properties of exponential functions and will

apply properties of logarithms.

Bell Ringer: Complete Exit Ticket

HW Requests: 1) Solving Exponential Equations Worksheet and 2) Log Equations WS from Friday 3) Solve Log and Exponential

Eqns using logs WS

Homework: Review

Worksheet odds Announcements:

Chapter 3 Test Friday.

Break Packet available

online Friday (ACT Prep)

State Champions MPHS

Date: 3/20/13

Page 2: Unit V: Logarithms Solving Exponential and Logarithmic ...

Logs and Exponentials of the same base are inverse functions

of each other they “undo” each other. Swap x and y to find

inverse. Logs and Exponentials are opposites.

xxfaxf a

x log1

Remember that: xffxff 11 and

This means that: log1 xaff

xa

xaff x

a log1

5log22

inverses “undo”

each each other

= 5

7

3 3log= 7

Page 4: Unit V: Logarithms Solving Exponential and Logarithmic ...

Solving Exponential and

Logarithmic Equations Section 4.4

JMerrill, 2005

Revised, 2008

Page 5: Unit V: Logarithms Solving Exponential and Logarithmic ...

Same Base

Solve: 4x-2 = 64x

4x-2 = (43)x

4x-2 = 43x

x–2 = 3x

-2 = 2x

-1 = x

If bM = bN, then M = N

64 = 43

If the bases are already =, just solve

the exponents

Page 6: Unit V: Logarithms Solving Exponential and Logarithmic ...

You Do

Solve 27x+3 = 9x-1

x 3 x 13 2

3x 9 2x 2

3 3

3 3

3x 9 2x 2

x 9 2

x 11

Page 7: Unit V: Logarithms Solving Exponential and Logarithmic ...

Review – Change Logs to

Exponents

log3x = 2

logx16 = 2

log 1000 = x

32 = x, x = 9

x2 = 16, x = 4

10x = 1000, x = 3

Page 8: Unit V: Logarithms Solving Exponential and Logarithmic ...

Using Properties to Solve

Logarithmic Equations

If the exponent is a variable, then take the

natural log of both sides of the equation and

use the appropriate property.

Then solve for the variable.

Page 9: Unit V: Logarithms Solving Exponential and Logarithmic ...

Example: Solving

2x = 7 problem

ln2x = ln7 take ln both sides

xln2 = ln7 power rule

x = divide to solve for x

x = 2.807

ln7

ln2

Page 10: Unit V: Logarithms Solving Exponential and Logarithmic ...

Example: Solving

ex = 72 problem

lnex = ln 72 take ln both sides

x lne = ln 72 power rule

x = 4.277 solution: because

ln e = ?

Page 11: Unit V: Logarithms Solving Exponential and Logarithmic ...

You Do: Solving

2ex + 8 = 20 problem

2ex = 12 subtract 8

ex = 6 divide by 2

ln ex = ln 6 take ln both sides

x lne = 1.792 power rule

x = 1.792 (remember: lne = 1)

Page 12: Unit V: Logarithms Solving Exponential and Logarithmic ...

Example

Solve 5x-2 = 42x+3

ln5x-2 = ln42x+3

(x-2)ln5 = (2x+3)ln4

The book wants you to distribute…

Instead, divide by ln4

(x-2)1.1609 = 2x+3

1.1609x-2.3219 = 2x+3

x≈6.3424

Page 13: Unit V: Logarithms Solving Exponential and Logarithmic ...

Solving by Rewriting as an

Exponential

Solve log4(x+3) = 2

42 = x+3

16 = x+3

13 = x

Page 14: Unit V: Logarithms Solving Exponential and Logarithmic ...

You Do

Solve 3ln(2x) = 12

ln(2x) = 4

Realize that our base is e, so

e4 = 2x

x ≈ 27.299

You always need to check your answers because sometimes they don’t work!

Page 15: Unit V: Logarithms Solving Exponential and Logarithmic ...

Using Properties to Solve

Logarithmic Equations

1. Condense both sides first (if necessary).

2. If the bases are the same on both sides,

you can cancel the logs on both sides.

3. Solve the simple equation

Page 16: Unit V: Logarithms Solving Exponential and Logarithmic ...

Example: Solve for x

log36 = log33 + log3x problem

log36 = log33x condense

6 = 3x drop logs

2 = x solution

Page 17: Unit V: Logarithms Solving Exponential and Logarithmic ...

You Do: Solve for x

log 16 = x log 2 problem

log 16 = log 2x condense

16 = 2x drop logs

x = 4 solution

Page 18: Unit V: Logarithms Solving Exponential and Logarithmic ...

You Do: Solve for x

log4x = log44 problem

= log44 condense

= 4 drop logs

cube each side

X = 64 solution

1

31

34log x

1

3x

3133 4x

Page 19: Unit V: Logarithms Solving Exponential and Logarithmic ...

Example

7xlog25 = 3xlog25 + ½ log225

log257x = log25

3x + log225 ½

log257x = log25

3x + log251

7x = 3x + 1

4x = 1

1

4x

Page 20: Unit V: Logarithms Solving Exponential and Logarithmic ...

You Do

Solve: log77 + log72 = log7x + log7(5x – 3)

Page 21: Unit V: Logarithms Solving Exponential and Logarithmic ...

You Do Answer

Solve: log77 + log72 = log7x + log7(5x – 3)

log714 = log7 x(5x – 3)

14 = 5x2 -3x

0 = 5x2 – 3x – 14

0 = (5x + 7)(x – 2)

7,2

5x

Do both answers work? NO!!

Page 22: Unit V: Logarithms Solving Exponential and Logarithmic ...

Final Example

How long will it take for $25,000 to grow to

$500,000 at 9% annual interest

compounded monthly?

0( ) 1

ntrA t A

n

Page 23: Unit V: Logarithms Solving Exponential and Logarithmic ...

Example

0( ) 1

ntrA t A

n12

0.09500,000 25,000 1

12

t

12

20 1.0075t

12tln(1.0075) ln20

ln20t

12ln1.0075t 33.4