UNIT IVKa and Kb

WHAT IS KA?Recall:Find pH of 0.100 M HCl.

But…What is pH of 0.10 M HF?

WHAT IS KA?Look at equilibrium for weak acid HF:

HF(aq) + H2O(l) H3O+(aq)

+ F- (aq)

Keq = [H3O+][F-] [HF]

For WA’s Keq is called Ka (acid ionization constant).

See acid table for list of Ka’s.• higher Ka stronger acid• lower Ka weaker acid

For SA’s (eg. HCl) Ka = [H3O+] [Cl-] = called “very large” [HCl]

CALCULATIONS USING KAI. [H3O+] (or pH) from KaEx. Find the [H3O+] in 0.10 M HF.

Hebden Textbook Questions #74, 75, 79, 81

CALCULATIONS USING KAII. Ka from pHEx. A 0.350 M solution of the weak acid HA has

a pH of 1.620. Find the Ka of HA.

Hebden Textbook Questions #77, 80

CALCULATIONS USING KAIII. Co from pH and KaEx. Find the concentration of HCOOH needed

to form a solution with pH = 2.69.

Hebden Textbook Questions #76, 78

WHAT IS KB?Base Ionization: NH3 is a very common weak base. It partially ionizes

in water to form NH4+ and OH- :

NH3(aq) + H2O(l) NH4+

(aq) + OH-(aq)

Kb expression: Kb = [NH4+] [OH-]

[NH3]

Equilibrium constant is called base ionization constant (Kb).

WHAT IS KB?Ex. CN-

(aq) + H2O(l) HCN(aq) + OH-(aq)

Kb expression: Kb = [HCN][OH-] [CN-]

Ex. N2H4 (aq) + H2O (l) N2H5+

(aq) + OH-

(aq)

Kb expression: Kb = [N2H5+] [OH-]

[N2H4] 

Hebden Textbook Page 128 Question #32

HOW TO DETERMINE VALUE OF KBLook at hydrolysis of base F-: F- + H2O HF + OH ‑

Kb (F-) = [HF] [OH-] [F-]

Look at ionization of weak acid HF: HF + H2O H3O+ + F-

Ka (HF) = [H3O+] [F-] [HF]

Multiply Ka[HF] x Kb[F-]

Ka[HF] x Kb[F-] = [H3O+] [F-] x [HF] [OH-] = [H3O+] [OH-]

[HF] [F-]

HOW TO DETERMINE VALUE OF KBKa(HF) x Kb(F

-) = Kw

Or Kb(F-) = Kw

Ka(HF) In general:

Kb(weak base) = Kw Ka(its conj.

acid)

 

HOW TO DETERMINE VALUE OF KBUsing Acid Table: 1. Find base on right side ( if amphiprotic -

locate base on right side only).2. Its conjugate acid will be across from it on

the left side.3. The Ka of its conjugate acid is on the far

right of the same line.4. Use equation: Kb(base) = Kw Ka(conj. acid)

HOW TO DETERMINE VALUE OF KBEx. Calculate the Kb for HCO3

-.

Ex. Find Kb of SO32-

.

HOW TO DETERMINE VALUE OF KBSimilarly, if Kb (base) given:

Ka (weak acid) = Kw Kb(its conj. base)NOTES: • Table only states Ka values. For questions like this

Kb will have to be calculated if not given.• All Ka’s on table are 2 SD’s—limits any calculation

using them to 2 SD’s maximum.• The larger the Kb, the “stronger ” the weak base -

the more OH- produced.• The smaller the Ka of an acid, the larger the Kb of

its conjugate Base. Weaker acids have stronger conjugate bases.

CALCULATIONS USING KBI. [OH-] (or pH) from KbEx. Find [OH-] in a 0.20 M solution of KNO2

(this is a salt, so it must be dissociated into its ions first).

CALCULATIONS USING KBII. Kb from pHEx. At a certain temperature, a 0.20 M solution of

K2SO3 has a pH of 10.25. Calculate the Kb of SO32-

at this temp.

Hebden Textbook Page 153 Questions #84, 87, 88, 89

WHAT IS HYDROLYSIS?Reaction between a salt (ion or ions in a salt)

and water to produce an acidic or basic solution.

Net ionic equation for hydrolysis:ion + water molecule or ion + H3O+ or OH-

SPECTATORS IN HYDROLYSISSpectator Cations (look on Periodic Table):• Group 1 (Alkali Metal ions) eg. Li+, Na+, K+, Rb+, Cs+, Fr+

• Group 2 (Alkaline Earth ions) eg. Be+, Mg2+, Ca2+, Ba2+, Sr2+, Ra2+

Spectator Anions (look on Acid Table):• Top 5 ions on the right side of table.• ClO4

- I- Br- Cl - NO3

• HSO4- is not a spectator – it is amphiprotic – will be dealt

with later

Spectators are eliminated in net ionic equations for hydrolysis!

PROCESS FOR HYDROLYSISStrategy:(dissociate eliminate evaluate)1. Write dissociation equation.2. Eliminate spectators.3. Remaining ions: left side of table – undergo acid hydrolysis –

produce H3O+

right side of table – undergo base hydrolysis – produce OH-

amphiprotic – determine Ka and Kb to find dominant hydrolysis

HYDROLYSISEx. Is the salt NaF acidic, basic or neutral in

water?

Ex. Is the salt NH4NO3 acidic, basic or neutral in aqueous solution?

Ex. Is the salt KCl acidic, basic or neutral?

HYDROLYZING IONSHydrolyzing Cations: (LEFT SIDE OF ACID TABLE)• Fe(H2O)6

3+ = Fe3+

• Cr(H2O)63+ = Cr3+ undergo acid hydrolysis

• Al(H2O)63+ = Al3+

•  NH4+

Hydrolyzing Anions: (RIGHT SIDE OF ACID TABLE)• Most of the anions from IO3

- down to PO43- will

undergo base hydrolysis. (Amphiprotic anions will be discussed next.)

HYDROLYZING IONSEx. Is the salt ammonium nitrite NH4NO2

acidic, basic or neutral?

Ex. Determine whether the salt NH4CN (ammonium cyanide) is acidic, basic or neutral.

HYDROLYZING IONS

If Then the salt is:

Ka (cation) > Kb (anion) Acidic

Kb (anion) > Ka (cation) Basic

Ka (cation) = Kb (anion) Neutral

HYDROLYZING IONS Amphiprotic Anions: Ions which start with “H”

and have a negative charge. Eg. HSO4

- , HSO3-, H2PO4

-, HPO42-, HS-

If Then the predominant hydrolysis is:

And, in aqueous solution, the ion:

Ka (the ion) > Kb (the ion) ACID HYDROLYSIS Acts as an Acid

Kb (the ion) > Ka (the ion) BASE HYDROLYSIS Acts as a Base

HYDROLYZING IONSEx. Find the predominant hydrolysis of the

hydrogen carbonate ion (HCO3-) and write the

net-ionic equation for it.

Hebden Textbook Page 148 Questions #69-73 

HYDROLYSIS...PUTTING IT ALL TOGETHEREx. Calculate the pH of 0.30 M Na2CO3.

HYDROLYSIS...PUTTING IT ALL TOGETHEREx. Calculate the pH of a 0.24 M solution of the

salt aluminum nitrate.