TRU'ONG CONG THANH LE TIEN THANH

NHA XUAT BAN GIAO Dl,JC VII;T NAM

    

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Chju trach nhi~m xuat ban : Chu tjch H9i dong Thanh vien kiem T6ng Giam d6c NGO TRAN AI T6ng bien t$p kiem Ph6 T6ng Giam doc NGUY~N QUY THAO

To chU>c ban thao va chju trach nhi~m n()i dung : Ph6 T6ng bien t$p NGO ANH TUYET Giam doc CTCP MT thu$t va Truyen thong LE HOANG HAl

Bien so<;In : TRU'ONG GONG THANH- LE TIEN THANH

Bien nqi dung : DANG DLYC TRUNG - NGUY~N XUAN MAl

Bien t$p mT thu$t va thi€lt k§ sach : PHAN HU'ONG

Minh ho<;I: PHU'ONG DUNG

Trinh bay bia : BiCH LA

Che bEm: CTCP MTTHUAT & TRUYEN THONG

CTCP MT thucflt & Truyen thong - Nha xuat ban Giao dl,.lc Vit;lt Nam giO> quyen cong bo tac ph~m.

230-20 12/CXB/55-239/G D Ma so : T5N01 V2-MTT

LOI NOI aAu

De aap U'ng nhu cau d9y toan cua thay c6, h9c toan cua h9c sinh, nham g6p phan giup h9c sinh lam quen v6'i tieng Anh can ban, NXB Giao dt,Jc Vi~t Nam xuat ban bQ sach "Em h9c giai toan bang Tieng Anh" (06 cu6n).

V6'i each tiep c~n m6'i va phuang phap d9y va h9c cua b(> sach, chung t6i hi v9ng:

- HQC sinh c6 each hQC hi~u qua.

- Giao vien aoi m6'i phuang phap giang d9y.

- Phl,l huynh d9y con em mlnh v6'i thai luqng ft nhat.

Chung t6i cam an ba Nguyen Th! Blnh aa c6 nhO'ng a6ng g6p quan trQng trong qua trlnh hoan thi~n ban thao cua cu6n sach.

Vi~c viet sach song ngO' c6 nhO'ng kh6 khan rieng, do v~y ban thao kh6ng tranh kh6i m(>t a6i cho dien 09t chua chuan tieng Vi~t ho~c chua sat nghTa tieng An h.

MQi g6p y ve n(Ji dung cua cu6n s6ch xin Quy bc;m OQC gui ve afa chi:

Cong ty co phan Mi thu~t va Truyen thong

187B Giang V6, 86ng 8a, Ha N(>i

8i~n tho9i: 04 35121569; Fax: 04 35121385

Xin chan thanh cam an

Cac tac gia

[ r to. g• 1 t > l bang •1eng A 1r 1 Ou:;t>n ",A 0

Unit 1 Whole numbers

1a ri theo v! tri Place value

Bieu do gia tri thea vi tri c6 the giup em hieu cac so nguyen khong am. Mo1 ~h-., c::.A tm11g ""Ot sA co·"lot g1a tP dl,.l'a vao llEmg cua n6 a so rr,.;

A place-value chart can help you understand whole numbers. Each digit in a number has a value based on its place in the number.

O'p tri~u / Million preriod

4

So 1 a hang tri$u.

Gia tri cua n6 Ia 1 tri$u 11ay 1 ooo ooo. So 6 a hi:mg chvc nghin.

Gia tri cua n6 Ia 6 chvc f"lghin hay 60 ooo. So 9 o· hang tram (16·p dO'n v!).

3'"' ~r' - ··a n6 Ia 9 tra""l h ..... y 900

The 1 is in the millions place.

Its value is 1 millions or 1 000 000.

The 6 is in the ten-thousands place.

Its value is 6 ten thousands or 60 ·ooo. The 9 is in the hundreds place.

Its value is 9 hundreds or 900. 1 0 6 9 0 0

    

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Bh!u do g·a tr! thee, · ric ·so 3 241 968 910 This place-value chart shows 753 241 968 91 0

::l ::l c:- c

.. ------Lop

-~ z. !~· <QJ· :c ·.c c:- > ·.s ::l en en E ()

E >Cil . 1-

7

(f)

"'0 ClJ .....

"'0 c ::l I

7

() >- - •QJ· c c :.c ::l· ::l· 1- E () Cll .c c

;:: E () .£> ..... b .c ::l· 1- u >Cil ::l· "- 1- Gl u ..... .c >Cil L 1- u .....

1- u

Gia tn hang

5 3 2 4 9 b 8 9 ~ c -----Chu· s6

753 ty, 241 tri$u, 968 nghin, 910 L 0'1 rut gon

Place-Value Chart

rJFrc.ds

(f) (f) (f)

ClJ c ClJ c

~ c

0 0 --- Place · Values

1.---- -I-

5 3 2 4 9 6 8 9 ~ _J ------ D1gits

753 billion , 241 million, 968 thousand , 910 - Sho1i Word Form

So dU'Q'C ch1a ra thanh 4 nh6m g6m 3 chCP so, mol nh6m Ia m<)t 16'p. Nh6· '( ~ r.hl? r~ lim vrv1 d8L' nr~y,•'

The number is separated into 4 groups of 3 digits , each called periods. Remember to separate periods with commas.

47 328 000

3 020 080

3 200 008

32 208

80 800 800

3 465 893

1.

2.

3.

4.

5.

6. t

+ t

.. .. ..

* Thay vi dau ph8y, a Vi(!t Nam ngU'&i ta atJ ra m¢t khoang trong.

5

/ GQi ten himg cho chu so 5 i:J moi so / Write the place name for the 5 in each number

0 0 0 ~

@

~

~

~

a. b.

263 050 ... 1151816 ...

678 592 .. . 5 000 209 .. .

207 512 080 ... 2 204 065 .. .

15 128 ... 51 027 047 .. .

Viet gia tri cho chu so du'Q'c g'ch duai Write the value of the underlined digit

a. b.

2 53~ 126 .. . 102 3~9 .. .

1I1 111 001 ... 1523 551 ...

272 004 ... 11285I .. .

~73 000 065 ... 13 Q28 ...

f>9C va viet cac SO Reading and Writing Numbers

My Dinh va Hang Day Ia hai san bong da & Ha Noi. Ca hai san chlia khoang 71 960 ngU'ai.

My Dinh and Hang Day are baseball stad iums in Ha N()i. The two stadiums together hold about 71960 people.

0 rf'l hoc gic\J toan bang tierg Anr j Quyen 5A

8 e e

Ta d9c va vh!t so nay Ia: Bay mu'di mot nghln, chin tram sau mlldi We read and write this number as: Seventy-one thousand, nine hundred sixty

Chl1' so 9 ham nghTa Ia 9 chl,Jc nghin hay 90 000.

Chl1' so 8 ham nghTa Ia 8 nghin hay 8 000.

Chl1' so 7 ham nghTa Ia 7 nghin hay 7 000.

Chl1' so o ham nghTa Ia 0 chl,Jc hay o. Chl1' so 1 ham nghTa Ia 1 dan vi hay 1.

Xem bieu do :

The digit 9 means 9 ten thousands, or 90 000.

The digit 8 means 8 thousand , or 8 000.

The digit 7 means 7 hundreds, or 7 00.

The digit 0 means 0 tens, or 0.

The digit 1 means 1 ones, or 1.

De y rang cac dau phay dung de tach cac chl1' so ra thanh cac nh6m ba, gQi Ia cac l&p. Dieu nay giup vit;lc dQC cac sol&n dU'Q'C de dang.

Notice that commas are used to separate the digits into groups of three called periods. This helps make larger numbers easier to read.

Vh!t h;ti moi so, chen cac dau phay vao cho can thiet Rewrite each number. Insert commas where needed

a. b. c.

2 374 ... 6 473 829 ... 17 472 .. .

2 030 200 ... 48 607 .. . 6 050 407 .. .

398 701 ... 406 702 .. . 890 823 ...

fn- hoc qi<H t.:>ar bang tleng Anr I Ot.yen 5A 0

i "' mo -o c. h u cac c ~ so c Em au ph "'y eu an I

/ Write each number using digits. Insert commas where needed1*l

seven hundred twenty thousand , four hundred sixty-two 720 462

seven thousand , two hundred fifty .. .

six billion, sixty thousand , twelve .. .

eighty million , eight hundred thousand , eight hundred ...

. "' I

/ Write each number in words. Insert commas where needed

16349 aix.l!um JJw.uJ..a.JU:l, ~ Jz..un.ciM.d f.oll.h.j.-.ni..Jw

1304 .. .

32005 .. .

~ng Addition

To add , start with the digits in the ones place. Regroup as needed . ~

I

/ Find: 529 + 192

Add the ones. Regroup. Add the tens. Regroup. Add the hundreds. Regroup.

Th H T 0 Th H T 0 Th H T 0

<0 ..... Q ... ..... cO Ql< co Ql< Q ;;;r 3 c :::1 ;;;r 3 ;;;r •C :::1 0 5' 0 :::1 < :::1 < .S.

+ 5 2 9

+ 5 2 9 1 1

1 9 2 1 9 2 + 5 2 9 1 2 1 1 9 2

7 2 1

\< * 6' Vi?t nam, thay vi chen d!Ju phily, ngU'&i ta a~ each m(J t cho tr6ng.

8

CA g ~ Add

a. b. c. d.

Th H T 0 Th H T 0 Th H T 0 Th H T 0 ..J ""'

( ~ ""' ,") ,_ ...... ::; ...... ~

""' (Q tll< ::r Q (Q tll< ::r Q (Q tll< Q (Q tll< ::r Q ::r 3 ·C ::J ::r 3 ·C ::J ::r 3 ·C ::J ::r 3 c ::J (") (") (") (") ::J < ::J 5 ::J ~. ::J <

3 9 9 2 8 6 4 6 4 3 7 5 +

2 7 2 +

4 6 6 +

2 6 6 +

4 9 7

Th H T 0 Th H T 0 Th H T 0 Th H T 0 -' ""' Q -' ""'

,) 8' .... :...; ...J ""' (

(Q tll< ::r (Q tll< ::r (Q Q)c ::r Q (Q tll< ::r Q ::r 3 ·C ::J ::r 3 c=; ::J ::r 3 ·C ::J ::r 3 ·C ::J ::J

(")

.5 ::J < ::J (")

< ::J (")

<

2 6 6 5 7 9 1 8 4 2 4 7 + + + +

4 $) 8 3 4 2 5 7 9 3 8 3

E) H T 0 H T 0 H T 0 H T 0

- c ""'

(

""' ""' c

""' tll< ::r Q tll< ::r Q Q)t ::r Q tll< ::r- Q 3 ·C ::J ~ ·C ::J 3 ·C ::J 3 c ::J

(") (") (") (")

< < < <

2 9 2 2 0 5 2 9 3 3 5 9 + 3 2 + 7 3 + 4 1 + 1 7 6

0 H T 0 H T 0 H T 0 H T 0

- (

""' ""' ""' ""' Q)c ::r Q tll< ;:,- Q Q)c ::r Q Q) ::r Q 3 -c ::J 3 -c: ::J 3 ·C ::J 3 -c '::l

(") (") (") (")

< < < <

4 8 6 5 9 9 2 4 8 1 8 7 +2 4 8 + 1 8 9 +4 9 2 + 1 5 4

9

~ cc;,ng / Add

a. b. c. d. e.

0 5646 4483 2726 6103 8317 + + + + +

2387 1930 4936 3329 292

0 2208 1036 4381 2933 6908 + + + + + 1729 8399 3742 1462 2132

0 2431 5301 1362 7118 5623 + + + + + 5869 2997 4054 2394 1484

Sap xep cac chit so thimh hang. Ke do tim tong / Line up the digits. Then find the sums

a.

e 3 697 + 840 = 00.

3697 + Kft.O

0 1037+6168= 00 0

b.

6 402 + 3 391 = 000

2 208 + 1 729 = 00 0

club

~Em hQc g1a• toan ba'lg tie"g Anh I Quyer ~4

c.

5 911 + 1 039 = 000

3 318 + 5 462 = 0 0 0

Phuctng phap giai toan: ve do thi Problem -Solving Method :Make a Graph

DU'&i day Ia nhit;lt do hang thang cao nhat ghi dU'Q'C a mot thi tran trong vong 9 thang. Em c6 the bieu hit;!n dCr lit;!u nhU' the nao de chi ra sv thay doi tli thang nay qua thang khac ?

Below are the highest monthly temperatures recorded in a town for nine months. How can you display the data to show the change from month to month?

Thang chin September

Thang ba March

Thang mU'<Yi hai December

Thang hai February

Thang mU'6'i mot November

Hieu bai toan Understand the problem

Khi dqc lc;~i, em hay tv hoi

71°F

39°F

26°F

27°F

41°F

As you reread , ask yourself questions

Kieu bieu hit;!n dCr lit;!u Ia gl?

What type of data is shown ?

C6 the tra I<Yi : DCP lit;!u bieu thi nhit;!t d¢ qua m(>t chu kl cac thang.

Possible answer : The data shown the temperatures over a period of months.

Thang nam 69°F

May

an <Yi 59°F

October

ThangtU' 57°F

April

Thana t i ~.ng 21°F

January

Bai toan yeu cau em lam di~u gl?

What does the problem ask you to do?

C6 the tra I<Yi : Bieu hien dCr lieu chi sv thay doi. · ·

Possible answer : Display the data to show change.

Em roc 91d1 toan bang tu~~rg Anr I Quyen '>A [ 1 ~

, nhuthe nao / Plan how to solve it

Choose a method for solving.

I IIU llt:U I d IJI'U'V118 !JIIdf.- ~ ~j thj. Do du· li$u cho thay Sl,J thay do nen .:tl:.. •h: ~~ ~ ~ L' r~ H ... H)C 1,.....,; r-'~" ? £){; thj dU'CYng thang.

Try the Draw a Graph strategy.

Since the data shows the change, what type of graph should you draw ? Line graph.

< Solve it High Temperatures from September to May

£>tmh dau ti 1$ thu nh6 theo phU'O'ng n~m ngang cho cac thang, er1 c6 th~ thu nga'l la1

Quan sat nhi$t d(>. Gia tq thap nhAt Ia bao nhieu ? 21 G1a tn cao nhat li3 bao nhieu? I1

80 u. 70 ~ 60 ~-!---+ --+--+--+--t---t---:::r-

~ 50 .a 40 ~ 30 ~ 20 ~-+--+~=-~~ E 10 ~ 0

s 0 N D J F M A

Month

M

Dung cac do~n Ia 10 cho tn:~c th~ng dt:mg. Bat dau tli 0, sau d6 ve rr(>t ni8rn trAn 1A thi l"hl"\ rnCii n~i8t nA IAi ~"gr Ao:...,.., u\•i !"'h<:ill

Label the horizontal scale with the months. You may abbreviate. Look at the temperatures. What is the least value? 21

What is the greatest? 71

Use intervals of 10 for the vertical axis. Start at 0. Then draw a point on the graph for each temperature. Connect the points.

/ Look back and check your answer

v:r tr~ tiA thi

Check your graph - ~ ,-I,An hiar" ')

Does the graph show a trend ?

12

    

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duo n e ·e hj d I e o oi bimg Make a line graph to display the data in each table

0 f)o thi nay cho thay nhi~t d(> ngay thu· bay va ngay chu nh~t 6· cac thai gran ''hac nhau cua ngay Dung do thi giur cho vi~c tra 'ai cac cau hoi sau ·

This graph shows the Saturday and Sunday temperatures at different times of the day. Use the graph to help answer the questions that follow :

a. Vao thU' bay hay Ia vao c. ,..J nh~h

thl nhi~t d(> nao cc .. n, vao luc 9 gil'-· sang ? Cao han baa '1hieL' d(> ')

Was the temperature at 9 A.M greater on Saturday or Sunday? By how many degrees was it greater ?

b. Vao khoang gr<:Y nao thl nh.~t d<;> moi ngay bang nhau.

At about what time was the

OF

78

76

74

70

6 Sang A.M .

1\Jt-> d6 an nga· Daytime Temperatures

9 Noon 3 6 l T a Chi ~u Chi

A.M . P.M. P.M.

temperature each day the same. 1 ri g dn Time

c. Nhi~t d(> vao luc 9 g a sa •• g a ngay thli bay Ia 70°F va nhi~t dQ vao iuc 9 gia sang a ngay chu nh~t Ia 73°F. Keo dai do thi va danh dau cac thcYi gian nay cung v&i nhiet do

The temperature at 9 P.M on Saturday was 70°F and the temperature at 9 P.M Sunday was 73°F. Extend the graph and plot these times and temperatures.

f) 8ay Ia bang chieu cao ttl' 1 d~n 5 tuor cua b;;m Gar. Em bieu thi dli' li~u nhu· th~ nao de chi s1,1· khac nhau tll' nam nay qua nam khac ?

Suy nghT : Lo9i do thi nao cho thay "T' ·~av tioi thea ~~a: ~:~n ?

• ;:J

This is a table of Gai's height from 1 to age 5. How can you display the data to show the difference from year to year ?

Think : what type of graph shows changes over time ?

T .. A;

Age --

1

2

3

4

5

rf"!ieL' cao thea inch

Height in inches

29

33

37

43

46

13

C()ng ba ho~c nhieu so Addition of Three or More Numbers

f)~ cong ba ho~c nhieu so, ta cong theo each da lam nhU' cong hai so To add three or more numbers, use the same steps as when adding two numbers.

nm / Find : 486 + 538 + 552

C¢ng cac dO'n vj. Nh6m IQi C¢ng cac ch1,1c. Nh6m IQi Add the ones. Regroup. Add the tens . Regroup.

H T 0

- (') a. .... Q)< :T Q 3 ·C :J

(') .$.

4 8 6 + 5 3 8

5 5 2 6

~ Cc?ng / Add

a.

0 1 2 256

+249 157 662

f) 258 346 +

91 759

b.

456 + 54

168

272 353

+ 348 686

+

H

-.... Ql<

3

1 4 5 5

T 0 (') fr :T -c: :J (')

. $.

1 8 6 3 8 5 2 7 6

c.

43 + 44

46

7425 6813

+ 4259

647

C¢ng cac tram. Nh6m IQi Add the hundreds.

+

1

d.

156 +142

192

3456 2851

+ 1234

659

Regroup

H T

- (') .., Q)< :T

3 -c: 0

1 1 4 8 5 3 5 5 5 7

0

fr :J

.$ .

6 8 2 6

+

e.

315 +342

1 2

76325 81804 97325

936

Sap xep cac chu so thimh hang, ke do tim tong Line up the digits. Then find the sums

a. b.

149 + 753 + 531 = ...

149 + 753

531

736 + 177 + 27 = ...

Pheptru Subtraction

f)~ triJ', ta bat dau v&i cac chCr s6 a hang dan vj . Nh6m lc;3i neu can . To subtract, start with the digits in the ones place. Regroup as needed.

nm Find: 231 - 116

Trll' cac dan vj. Nh6m l<;~i Tnl cac chl,.IC. Nh6m l<;~i Tn.P cac tram. Subtract the ones. Regroup. Subtract the tens. Regroup. Subtract the hundreds.

H T 0 H T 0 H T 0

- 0 a. ~ Q)t ::J" Q 3 -c ::J

() .s

- 0 a. ~

CJ< ::J" Q 3 -c ::J

0 .s

- 0 a. ~ Q)< ::J" Q

3 -c ::J 0

.S .

11 2 3 1 2 3 1 2 3 1 1 1 6 1 1 6 1 1 6 1 5 1 1 5

5

Trlt Subtract

a. b. c. d.

0 H T 0 H T 0 H T 0 H T 0 - 0 a. .., Q)< ::J" Q 3 ·C ::J

0 . ~.

- 0 a. - 0 a. - 0 a. .., ..., .., Q)< ::J" Q Q)< ::J" Q Q)< ::J" Q 3 ·C ::J 3 ·C ::J 3 ·C ::J

0 0 0 . ~ . . ~ . .~ .

7 8 4 6 2 6 4 7 8 5 8 5 4 9 9 3 6 9 3 8 9 3 8 8

~

En h q 1 tua,· bd l'J t1en(j A h OL y" ?A I 15 -._____/

H T ...... ..., Ol< '"::r

3 ·C ()

1 7 1 3

H T -..., :r-Ol< 3 ·C

()

6 7 5

H T - () ..., Ol< :::r 3 ·C

()

9 6 6 8

/ Tru Subtract

0

0

0

16

a.

9250 7140

2367 1400

2900 1875

0 ...... Q :::::l

-~

7 8

0 0· Q :::::l

-~

9 9

0 a. Q :::::l

-~-

6 4

H ...... ..., Ol< 3

3 2

H ..., Ol< 3

9 6

H ..., Ol< 3

5

b.

7520 6380

3320 2032

2467 1829

T ") :::r ·C ()

4 7

T

'· :::r ·C ()

8 9

T () :::r ·C ()

7 8

0 C4 Q :::::l

~

5 9

0 C4 Q :::::l

~

6 4

0 C4 Q :::::l

~-

7 6

c.

2557 936

3780 99

9600 8428

H T

- () ..., Ol< :::r 3 ·C

()

7 2 3 8

H T

- () ..., Ol< :::r 3 ·C

()

9 0 3

H T () ....

Ol< :::r 3 ·C

()

4 1 2 7

0 C4 Q :::::l

.<

4 7

0 C4 Q :::::l

s

6 2

0

Q :::::l

-~-

9 6

d.

7725 6317

2900 1875

1 1 1 1 999

H .. ...,

Ol< 3

9 4

H -..., Ol< 3

3

H ...... .... Ol< 3

5 1

T 0

:::r Q c "J ()

<

4 8 6 9

T 0 () 0 :::r Q ·C :::::l ()

~

1 8 6 6

T 0 c :::r Q ·C :::::l ()

~

1 1 4 2

e.

5000 272

2467 1829

6513 2976

/ Sap xe cac chu so thimh ang ke do tim hi~u / Line up the digits. Then find the differences

a. b. c.

3 697-840 = ... 5 073 - 1 245 = ... 7 981-375 = ...

9 674-5 128 = .. . 8 372-609 = ... 6 270 - 5 327 = .. .

Phep c()ng va phe tru , c so I , Addition and Subtraction of Larger Numbers

- - -- --

De c(>ng hoc;lc tnl' cac so lan, ta bat d~u vai cac chCI' so a hang dan vj. f\Jh6m l9i n~u c~n

To add or subtract larger numbers, start with the ones digits. Regroup as needed.

C~mg / Add

+

a. 1 1 11

38917 61197

100 11ft.

3275 +

959

2 • EHGTB TA.OSA · A

b.

29132 +

30567

5665 +

450

c.

75213 +

57213

17000 +

4000

d.

6758 +

63284

9069 +

4388

17