Tro, Principles of Chemistry: A Molecular Approach Chapter 2 Atoms and Elements Principles of...

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Principles of Chemistry: A Molecular Approach Chapter 2 Atoms and Elements Principles of Chemistry: A Molecular Approach, 1st Ed. Nivaldo Tro Dr. Juana Mendenhall Morehouse College

Transcript of Tro, Principles of Chemistry: A Molecular Approach Chapter 2 Atoms and Elements Principles of...

Page 1: Tro, Principles of Chemistry: A Molecular Approach Chapter 2 Atoms and Elements Principles of Chemistry: A Molecular Approach, 1st Ed. Nivaldo Tro Dr.

Tro, Principles of Chemistry: A Molecular Approach

Chapter 2Atoms and Elements

Principles of Chemistry: A Molecular Approach, 1st Ed.Nivaldo Tro

Dr. Juana MendenhallMorehouse College

Page 2: Tro, Principles of Chemistry: A Molecular Approach Chapter 2 Atoms and Elements Principles of Chemistry: A Molecular Approach, 1st Ed. Nivaldo Tro Dr.

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LECTURE 3: Sept. 1, 2010

Objectives: State & interpret the law of conservation of massState & describe the law of definite proportionsState & explain the law of multiple proportionsExplain Dalton’s Atomic TheoryDefine nucleus, protons, neutrons, and electronsDefine Atomic mass unit (amu), Atomic number, and chemical symbolDefine and categorize isotopes, mass number, and atomic numberDefine ions, anions, and cations

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Law of Conservation of Mass

• In a chemical reaction, matter is neither created nor destroyed.

• Total mass of the materials you have before the reaction must equal the total mass of the materials you have at the end.total mass of reactants = total mass of products

Antoine Lavoisier1743–1794

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Law of Definite Proportions

• All samples of a given compound, regardless of their source or how they were prepared, have the same proportions of their constituent elements.

Joseph Proust1754–1826

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Example 2.1 Show that two samples of carbon dioxide obey the Law of Definite Proportions

Since both samples have the same O:C ratio, the result is consistent with the Law of Definite Proportions.

Check:

Solution:

Conceptual Plan:

Relationships:

Sample 1: 25.6 g O and 9.60 g CSample 2: 21.6 g O and 8.10 g CProportion O:C

Given:

Find:g O1, g C1

g O2, g C2

O:C in each sample

All samples of a compound have the same proportion of elements by mass.

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Law of Multiple Proportions

• When two elements (call them A and B) form two different compounds, the masses of B that combine with 1 g of A can be expressed as a ratio of small whole numbers.

John Dalton1766–1844

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Dalton’s Atomic Theory• Dalton proposed a theory of matter based on it

having ultimate, indivisible particles to explain these laws.

1) Each element is composed of tiny, indestructible particles called atoms.

2) All atoms of a given element have the same mass and other properties that distinguish them from atoms of other elements.

3) Atoms combine in simple, whole-number ratios to form molecules of compounds.

4) In a chemical reaction, atoms of one element cannot change into atoms of another element.

They simply rearrange the way they are attached.

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Tro, Principles of Chemistry: A Molecular Approach

Practice—Decide if each statement is correct according to Dalton’s Model of the Atom

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• Copper atoms can combine with zinc atoms to make gold atoms.

• Water is composed of many identical molecules that have one oxygen atom and two hydrogen atoms.

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Charges of Atoms

• two kinds of charge called + and –

• opposite charges attract + attracted to –

• like charges repel + repels + – repels –

• To be neutral, something must have no charge or equal amounts of opposite charges.

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Some Problems• How could beryllium have 4 protons stuck

together in the nucleus?Shouldn’t they repel each other?

• If a beryllium atom has 4 protons, then it should weigh 4 amu; but it actually weighs 9.01 amu! Where is the extra mass coming from?Each proton weighs 1 amu.Remember, the electron’s mass is only about

0.00055 amu and Be has only 4 electrons—it can’t account for the extra 5 amu of mass.

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Electrons

• Electrons are particles found in all atoms.• Cathode rays are streams of electrons.• The electron has a charge of −1.60 × 1019 C.• The electron has a mass of 9.1 × 10−28 g.

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Structure of the Atom• Rutherford proposed that the nucleus had a

particle that had the same amount of charge as an electron but opposite sign.based on measurements of the nuclear charge of the

elements• These particles are called protons.

charge = +1.60 × 1019 C mass = 1.67262 × 10−24 g

• Since protons and electrons have the same amount of charge, for the atom to be neutral there, must be equal numbers of protons and electrons.

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Relative Mass and Charge• It is sometimes easier to compare things to each other

rather than to an outside standard.• When you do this, the scale of comparison is called a

relative scale.• We generally talk about the size of charge on atoms by

comparing it to the amount of charge on an electron, which we call −1 charge units. A proton has a charge of +1 cu. Protons and electrons have equal amounts of charge, but

opposite signs.• We generally talk about the mass of atoms by comparing

it to 1/12th the mass of a carbon atom with 6 protons and 6 neutrons, which we call 1 atomic mass unit. Protons have a mass of 1 amu. Electrons have a mass of 0.00055 amu, which is generally too

small to be relevant.

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Summary of Subatomic Particles

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Elements• Each element has a unique number of protons

in its nucleus.• The number of protons in the nucleus of an

atom is called the atomic number.The elements are arranged on the Periodic Table

in order of their atomic numbers.• Each element has a unique name and symbol.

symbol either one or two lettersone capital letter or one capital letter and one lowercase

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Structure of the Nucleus• Soddy discovered that the same element

could have atoms with different masses, which he called isotopes.There are two isotopes of chlorine found in nature,

one that has a mass of about 35 amu and another that weighs about 37 amu.

• The observed mass is a weighted average of the weights of all the naturally occurring atoms.The percentage of an element that is one isotope

is called the isotope’s natural abundance.The atomic mass of chlorine is 35.45 amu.

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Atomic Mass• We previously learned that not all atoms of an

element have the same mass. isotopes

• We generally use the average mass of all an element’s atoms found in a sample in calculations.However, the average must take into account the

abundance of each isotope in the sample.

• We call the average mass the atomic mass.

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Isotopes• All isotopes of an element are chemically

identical.undergo the exact same chemical reactions

• All isotopes of an element have the same number of protons.

• Isotopes of an element have different masses.• Isotopes of an element have different numbers of

neutrons.• Isotopes are identified by their mass numbers.

protons + neutrons

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• Atomic NumberNumber of protonsZ

• Mass NumberProtons + NeutronsWhole numberA

• Abundance = relative amount found in a sample

Isotopes

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Tro, Principles of Chemistry: A Molecular Approach

Which of these are isotopes of Nitrogen:

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Neutrons Protons Electrons

7 7 7

8 6 6

7 7 8

6 6 5

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LECTURE 4: September 3, 2010

Objectives: Use periodic table to identify properties of elementsCalculate atomic mass, mole, and number of particles (atoms, things)

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Neon

9.25%221210Ne-22 or

0.27%211110Ne-21 or

90.48%201010Ne-20 or

Percent Natural Abundance

A, Mass Number

Number of Neutrons

Number of ProtonsSymbol

Ne2010

Ne2110

Ne2210

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Example 2.3b How many protons, electrons, and neutrons are in an atom of ?

for most stable isotopes, n0 ≥ p+Check:

Z = 24 = # p+

# e− = # p+ = 24

Solution:

in neutral atom, # p+ = # e−

mass number = # p+ + # n0

Conceptual Plan:

Relationships:

therefore, A = 52, Z = 24# p+, # e−, # n0

Given:Find:

symbol atomicnumber

# p+ # e-

symbol atomic & massnumbers

# n0

A = Z + # n0

52 = 24 + # n0

28 = # n0

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Practice—Complete the Table

Protons Neutrons ElectronsAtomicNumber

MassNumber

AtomicSymbol

6 7

42 96

55 133

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Practice—Complete the Table

Protons Neutrons ElectronsAtomicNumber

MassNumber

AtomicSymbol

6 7 6 6 13

42 54 42 42 96

13 14 13 13 27

55 78 55 55 133

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Reacting Atoms• When elements undergo chemical reactions, the

reacting elements do not turn into other elements.Statement 4 of Dalton’s Atomic Theory

• This requires that all the atoms present when you start the reaction will still be there after the reaction.

• Since the number of protons determines the kind of element, the number of protons in the atom does not change in a chemical reaction.

• However, many reactions involve transferring electrons from one atom to another.

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Charged Atoms

• When atoms gain or lose electrons, they acquire a charge.

• Charged particles are called ions.• When atoms gain electrons, they become

negatively charged ions, called anions.• When atoms lose electrons, they become

positively charged ions, called cations.

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Ions and Compounds

• Ions behave much differently than the neutral atom.e.g., The metal sodium, made of neutral Na

atoms, is highly reactive and quite unstable. However, the sodium cations, Na+, found in table salt are very nonreactive and stable.

• Since materials like table salt are neutral, there must be equal amounts of charge from cations and anions in them.

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A Useful Tool in Describing Chemical Compounds

Metals tend to lose electrons.

Na Na+ + e-

Non-metals tend to gain electrons.

Cl + e- Cl-

Ion: form with different # electrons & protons

Anion = extra electron(s)

Cation = fewer electron (s)

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Atomic Structures of Ions

• Nonmetals form anions.• For each negative charge, the ion has 1 more

electron than the neutral atom.F = 9 p+ and 9 e−, F─ = 9 p+ and 10 e−

P = 15 p+ and 15 e−, P3─ = 15 p+ and 18 e−

• Anions are named by changing the ending of the name to -ide.

fluorine F + 1e− F─ fluoride ionoxygen O + 2e− O2─ oxide ion

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Atomic Structures of Ions• Metals form cations.• For each positive charge, the ion has 1 less

electron than the neutral atom.Na atom = 11 p+ and 11 e−, Na+ ion = 11 p+ and 10 e−

Ca atom = 20 p+ and 20 e−, Ca2+ ion = 20 p+ and 18 e−

• Cations are named the same as the metal.sodium Na Na+ + 1e− sodium ioncalcium Ca Ca2+ + 2e− calcium ion

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Practice—Complete the Table

Atomic Number Protons Electrons

IonCharge

IonSymbol

16 18

12 2+

36 1−

3Al

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Practice—Complete the Table

Atomic Number Protons Electrons

IonCharge

IonSymbol

16 16 18 2−

12 12 10 2+

13 13 10 3+

35 35 36 1−

2Mg

2S

Br

3Al

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= Alkali Metals

= Alkali Earth Metals

= Noble Gases

= Halogens

= Lanthanides

= Actinides

= Transition Metals

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The Periodic table+ 1

+2

Transition Metals

-1

Noble Gases

Lanthanides and Actinides

+3 ±4 -3 -2 -1

Main Group

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Example 2.5 If copper is 69.17% Cu–63 with a mass of 62.9396 amu and the rest Cu–65 with a mass of 64.9278 amu,

find copper’s atomic mass

The average is between the two masses, closer to the major isotope.

Check:

Solution:

Conceptual Plan:

Relationships:

Cu–63 = 69.17%, 62.9396 amuCu–65 = 100 − 69.17%, 64.9278 amu

atomic mass, amu

Given:

Find:

isotope masses,isotope fractions

avg. atomic mass

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Counting Atoms by Moles• If we can find the mass of a

particular number of atoms, we can use this information to convert the mass of an element sample into the number of atoms in the sample.

• The number of atoms we will use is 6.022 x 1023 and we call this a mole.

1 mole = 6.022 × 1023 things (atoms)

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Relationship between Moles and Mass

6.02214 x 1023 atoms = 1 mol

6.02214 x 1023 atoms = Molar Mass of element

Molar mass = g of element over 1 mol

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Example 2.6 Calculate the number of atoms in 2.45 mol of copper

Since atoms are small, the large number of atoms makes sense.

1 mol = 6.022 × 1023 atoms

2.45 mol Cuatoms Cu

Check:

Solution:

Conceptual Plan:

Relationships:

Given:Find:

mol Cu atoms Cu

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Chemical Packages—Moles• mole = number of particles equal to the

number of atoms in 12 g of C-12 1 atom of C-12 weighs exactly 12 amu. 1 mole of C-12 weighs exactly 12 g.

• The number of particles in 1 mole is called Avogadro’s Number = 6.0221421 × 1023.

1 mole of C atoms weighs 12.01 g and has 6.022 × 1023 atoms.

The average mass of a C atom is 12.01 amu.

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Mole and Mass Relationships

1 molesulfur

32.06 g

1 molecarbon12.01 g

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Example 2.7 Calculate the moles of carbon in 0.0265 g of pencil lead

Since the given amount is much less than 1 mol C, the number makes sense.

1 mol C = 12.01 g

0.0265 g Cmol C

Check:

Solution:

Conceptual Plan:

Relationships:

Given:Find:

g C mol C

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Practice—Calculate the moles of sulfur in 57.8 g of sulfur

Page 44: Tro, Principles of Chemistry: A Molecular Approach Chapter 2 Atoms and Elements Principles of Chemistry: A Molecular Approach, 1st Ed. Nivaldo Tro Dr.

Tro, Principles of Chemistry: A Molecular Approach

Practice—Calculate the moles of sulfur in 57.8 g of sulfur

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Since the given amount is much less than 1 mol S, the number makes sense.

1 mol S = 32.07 g

57.8 g Smol S

Check:

Solution:

Conceptual Plan:

Relationships:

Given:Find:

g S mol S

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Example 2.8 How many copper atoms are in a penny weighing 3.10 g

Since the given amount is much less than 1 mol Cu, the number makes sense.

1 mol Cu = 63.55 g, 1 mol = 6.022 × 1023

3.10 g Cuatoms Cu

Check:

Solution:

Conceptual Plan:

Relationships:

Given:Find:

g Cu mol Cu atoms Cu

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Practice—How many aluminum atoms are in a can weighing 16.2 g

Page 47: Tro, Principles of Chemistry: A Molecular Approach Chapter 2 Atoms and Elements Principles of Chemistry: A Molecular Approach, 1st Ed. Nivaldo Tro Dr.

Tro, Principles of Chemistry: A Molecular Approach

Practice—How many aluminum atoms are in a can weighing 16.2 g

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Since the given amount is much less than 1 mol Al, the number makes sense.

1 mol Al = 26.98 g, 1 mol = 6.022 × 1023

16.2 g Alatoms Al

Check:

Solution:

Conceptual Plan:

Relationships:

Given:Find:

g Al mol Al atoms Al