Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting...

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www.naikermaths.com Trigonometric Equations and Identities - Edexcel Past Exam Questions MARK SCHEME Question 1 : Jan 05 Q4

Transcript of Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting...

Page 1: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Trigonometric Equations and Identities - Edexcel Past Exam Questions MARK SCHEME

Question 1 : Jan 05 Q4

Page 2: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 2 : June 05 Q5

Page 3: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 3 : Jan 06 Q8

Page 4: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 4 : June 06 Q6

Page 5: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 5 : Jan 08 Q4

Page 6: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 6 : June 08 Q9

Page 7: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 7 : Jan 09 Q8

Page 8: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 8 : June 09 Q7

Page 9: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 9 : Jan 10 Q2

Page 10: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 10 : June 10 Q5

Page 11: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 11 : Jan11 Q7

Page 12: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

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Question 12 : June 11 Q7

Page 13: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

www.naikermaths.com

Page 14: Trigonometric Equations and Identities MARK SCHEME...(i) 2 0 i = 68.2 2x+6s.2 —90 or Subtracting and dividing by 2 (at least once) (ii) 25sin2 2x = 4cos2 40 —sin 2 2x) 29sin2 2x

www.naikermaths.com


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2 3 2x 4 2 - WordPress.com...2019/03/03  · 3 4 5 4 2x 4113917 8x 6139649 8x 6233807 2x 4142865 8x 6196548 2x 4538456 2x 6175314 2x 6153594 4x 6201911 1x 4529242 2x 6092590 1x 4243838

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Solve for x. 30° 2x + 10 2x + 10 = 60 – 10 – 10 2x = 50 2 2 x = 25.

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Contropiano 68.2

Contropiano 68.2

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