Transmission Line

47
ل ص ف ل ااول ال س سلا ا ة ي م ي م ص ت ل ا مال ع ت س لا راج بلا ا ل ب ق ان دا ب ن دراسة ب س سلا ا ة ي م ي م ص ت ل ا مال ع ت س لا راج بلا ا ة ي ل ك ي ه ل ا ة دي حدب ل ا لا د ب ا ب ل ان رف ع ن ان ب راج بلا ا ورة ص ب عامة ن م@ ث ي حD ها ت ف تH ظ و م س ف ن ى ل ا عة ارن واع ن ا ة ي س يT ئ ر: ي ه و1 راج ب . ا ق ي ل ع ت ل اSuspension Towers ) ) ة وهد راج بلا ا ن م ها ت ي م س ت حة ض وا ل ا ي ه راج بلا ا ي لت ا ق ل ع ن ي عل ة هاي ن ها ع ر اذ لات ص و م ل ا لة ق ا ب ل ا درة ق ل ل ة يT ن ا رب لكه ا واسطة ن ال ب ح ل ا لة عار ل ا ع م ها ن ا ق ح مل( String Insulator ) ون ك ب و ة هد راج بلا ا ات ذ وال ط ا ة ف ل ت ح م ث س ح ات ب ل ط ت م م ي م ص ت ل ا ي ه و ل ك@ ش ت عاذة حدوذ ب( 80 )% ن م راج ب ا ط. خ ل ا2 راج ب . ا د@ ش ل ا ا واب ز ل وا راج ب وا ة داي ب ل ا ة هاي لت واTension angle terminal Towers ة هد راج بلا ا ن م ها ت ي م س ت ي ه راج بلا ا ي لت ا م ي ن د@ ش لات ص و م ل ا لة ق ا ب ل ا درة ق ل ل ة يT ن ا رب لكه ا واسطة ن و ال ب ح ل ا لة عار ل اD ها ن ا ق ح مل و ي عل ة هاي ن ها ع ر اذ ل ك ل ة شاف م ة ي ي ع م ن م ول ط ط خ ل ا ث س ح و ر ب د ق ن دس ب ه م ل ا م م ص م ل ا عة ت ي لط روفH ظ و ط خ ل ا ورات ر ض و د ب ف ت¡ ي ل ا ة اي ب ص ل وا د ب ع او ا واب ر1

description

Transmission line Explaining

Transcript of Transmission Line

:1. Suspension Towers))

(String Insulator) (80%) .2. Tension angle terminal Towers :

. (20) .

. (65) .

.

3. ( Crossing Towers) (Anchor Towers) .4. (Anchor Tower)

Up-Lift Forces) ) . , Basic Span .

:1. Basic Span = 300 m

2. EDS (Every day stress) = 4.5 KG/mm2 at 23C3. Min. electrical clearance to ground at 75 C =6.0 meter

4. Conductor 210/35 ACSR.

Weight of conductor W =0.85 KG/m

Cross sectional area A = 243.2 mm2

Specific weight at still air g 1 = 3.495 10-3 kg/m/mm2

Specific weight at (-5 C + ice) , g2 = 6.826 10-3 kg/m/mm2

Specific weight at (15 C + wind) g w = 7.171 10 -3 kg/m/mm2

Modulus of elasticity E = 7700 kg/mm2

B =1/E = 130 10 -6 mm2/kg

Coefficient of liner expansion a = 19.2 10 -6 Weight of conductor with ice W i =1.66 kg/m

:

1. Sag and tension at (75 C) for basic span equal to 300 meter. C2. Sag and tension at (50 C) for basic span equal to 300 m. And max. Electrical Span =390 meter.

3. Sag and tension at (15 C + wind) for basic span equal to 300 m.

4. Sag and tension at (- 12 C) for basic span equal to 300 meter.

5. Sag and tension at (- 5 C + ice) for basic span equal to 300 m.

(1-1)

32U1

b-b(b1- -w) =U2..(1-5)

22b21

22

U1=(S1)(g1)

24 B

22

U2=(S2)(g2)

24 B

W=a(t2 t1)

B

2

d = sag =(s) g2

8 b2

ACSR 210 / 35

EDS = 4.5 kg/mm2 at 23CBasic span = S = 300 m

S = Max. Span = 1.3 S = 390 m

50

S= 300 75

S=300 15+

S=300 -12

S=300 -5+

S=300 50

S=390m

/24.13.88.325.238.754.24

9979242023127221301031

9.610.359.77.58.7615.67

(1-1)

().

(Max Gust of wind) (10) (50) (10) (35\)

h o = = 10

Vo = = 35 \

:

e

Vh = V0(h) ..(1-1)

h 0

h =

Vh = (h)

e= (0.09) :

2

P =1 n V

2h

h

n = = 1.25 \ 3 (10) (1-1) (1-2) :

0.18

P h= 766 (h).(1-3)

10

h (10) .

(1-3) (C r) ( Wind Span) )).

- Sn (100) C r = 0.8

- Sn (300) C r = 0.6

n S (100) (300) Cr (C r = 0.8) 33..

Pc = Ph Cr.(1-4)

(33 . ) (140)\ (25-30) ) (1-3 (75) \2.

(Design hight) (Conductor) (G.L.) (33) . .(75) (Max. sag) .

Design high (D.H.) = Min. clearance to ground + Max. Sag.

(S- wind Span)

(Transverse Load) :

S1+S2

Sn = Meter (1-6)

2

S2 , S1)) (T2) (1-1)

(S-wight Span) (Vertical Load) (Tem Plate) :

Sg = Sn +T(h1+h2)..(1-7)

gS1S2

S n =

T = - .

h = .

g = (Specific Wight) .

(S- Max. Electrical Span) (50) .

as= Kd+L+V.(1-8)

150

d = (50)

L =

K = .

K = 0.85 (120/20) .

K = 0.75 (210/35) .

V = (KV) ( Ruling span Equivalent Span) :

3333

S+S+S...S

Se=123i

S+S+S...S

123i

(q- Swimging Angle) (String Insolator) (0.35) (Vertical Loads) (Tranvers Loads) :

+W wi

tan q =T L2.......(1-10)

VL

+W Si

2

(q) (TL) (Sn) (VL) (Sg) (Sg) ( Wind Span) ) .

W wi = .

Wsi = .

(Min. Spacing Between Conductors)

Max. Electrical Span (50) :

as=kD + L k+V

150

50c

d = (50) (Sn) (1.3 ).

( (Vertical Load VL

V L=(S g W) +Wsi + G .(2-11)

Sg = Weight Span

W =

W si = .

G = (100) .

((Transvers Load-TL (Angle Pull) :

TL = CPDSn + Wn + ( T1 + T2) sin n/2 ..(1-12)

C = (1-1.2) .

P = 33 . (25) (140) \ (P) (75) \2.

n = .

D =

S = (Wind Span)

Wn = (25) (30) .

T1 = (Kgf)

T2 = Kgf))

.

(Sag and tension Template) .

(Equivalent Span) (Parameter) .. (Parrabola) :

Y=(2-1)

X2

2p

X= S (half of span)

1

2

T = Tens in conductor at that condition in Kgt

W = Wight of conductor per unit length Kg/m

(75) (Up-lift) (-12) (-8) .

:

b 1 = E D S = 4.5 kg/mm2

t 1 = 23 C

t 2 = 75 C for Min. clerance to grand

t 2 = -12 C for Up lift

(U2) :

b3 - b2(b1-U1-w)=U2

22b2

1

(1-1) (Parmater) (Parabola) (X, Y) (2-2) (2-3).

(2-1)

Tension at 75 CEquivalent Span MetersTension KgfParameter

135666784

140681801

145696819

150708833

155717844

160730858

165739869

Tension at -12 C

Equivalent Span MetersTension KgfParameter

13518142134

14017852100

14517562066

15017272032

15516991999

16016711966

16516441934

Y=X2 Catanry Tem- Plate at 75C

2p

E.S=135

P=784E.S=140

P= 801E.S=145

P=819E.S=150

P=833E.S=155

P= 844E.S=160

P=858E.S=165

P=869p.average=823

p=825

XYXYXYXYXYXYXYY.avrrgeYe

501.591.561.531.51.481.461.441.511.51

1006.386.246.116.005.925.836.756.036.06

15014.3514.0513.7413.5113.3313.1112.9513.5813.64

20025.5124.9724.4224.0023.7023.3123.0224.1324.24

25039.8639.0238.1037.5237.0336.4235.9637.7137.88

30057.4056.1854.9554.2053.3252.4551.7854.3354.55

35078.1376.4774.7973.5372.5771.3970.4873.9174.24

40002.0499.8697.6896.0494.7993.2492.0696.5396.97

45029.1526.4023.6321.5519.6718.0016.51122.13122.73

(3-3)

Y=X2 Catanry Tem- Plate at -12C

2p

E.S=135

P=2134E.S=140

P= 2100E.S=145

P=2066E.S=150

P=2032E.S=155

P= 1999E.S=160

P=1966E.S=165

P=1934p.average=823

p=2025

XYXYXYXYXYXYXYY.avrrgeYe

500.580.590.610.620.630.640.650.610.62

1002.342.382.422.462.502.542.562.462.47

1505.275.365.455.545.635.725.825.565.56

2009.379.529.689.8410.0010.1710.349.859.88

2504.6414.8815.1315.3815.6315.9016.1615.3915.43

30021.0921.4321.7822.1522.5122.9023.2722.1622.22

35028.7029.1729.6530.1430.6431.1531.6730.1630.25

40037.4938.0938.7239.3740.0240.6941.3739.3939.51

45047.4548.2149.0149.8350.6551.5052.3549.8650.00

(3-3)

USING OF CONTER WEGHT IN THE DESIGN OF POWER TRANSMISSION LINES

( ) :

1. Up lift forces 2. Swing angle of string insulator 3. Side Slope 4. Down Pull forces (Counter Wight)

( (Wight Span ( (Wind Span ( ) (Up lift) ( - ) ( ) ( ) ( ) ( ) .

( ) ( ) :

Level Span))

( (Weight Span ( (Wind Span :

Wind Span = Weght Span =S1 +S 2

2

(Up lift) .

( (Wight Span

1. :

.

2. (Lowest Point on catenary) ( (Wight Span :

() (S rs = S is) Up lift .

. ( (Wight Span ( ) (Up lift) :

Up lift (Counter wight) (String Insolator) .

V=V1+ V2 =WS1+ S2-T(H1+H2((3-1)

2S1S2

V = KgfS =

H = ( ) .

W = \ .

T = -12 -8 .

.

Side Slope) )

Center Line (Swinging Angle) , .

(Down Pull Forces)

(- ) ( ) :

V=V1+ V2 =WS1+ S2+T(H1+H2((3-2)

2S1S2

33.

.

.

( ( Crossing Span Anchor Towers () .

Type of TowerDesign Hight meterSpacing

Bet. Con.Wind Span mWight Span mMax.Elec. Span meterDesgn Load

Hor. Met.Ver. Met.VLKgTLKgLL

Kg

S2/2RC54.64.845.0591102063017959262090

S1/RC54.08.206.636865086011825873000

S1/AT24.254.64.4210310550618348300

(4-1)

ACSR 210/35

W0 =0.85 kg/m

W2 = 1.66 kg/ m

kg/m/mm2 10 -3 g0 = 3.495 kg/m/mm2 10 -3g 1 =7.17

kg/m/mm2 10-3 g2= 6.826

A = 243.2 mm2 R =0.0203 m

a = 19.2 10 -6 Thermal expansion coefficient of conductor material

B =130 10 -6 mm2/kg =1/E

Where E = Modulus of elasticity =7700

:

(Max. Tension) = 2100 (-5) (-5 + ICE)

b1 = 8.63 \ 2.

.

:

Se =(240)3++(700)3++(250)3= 559.3 =559 m

240700250

(4-1) :

1. (23) S2/2RC S1/RC .2. (23) (470475) S1/RC S2/2RC 3. (12) S2/2RC . : (75) .

(50) . (15) (75) \ 2 . (- 5 ) ( ). (-12) . :

3b22b2u

-(b1-1-w) =U2 (4-1)

b2

1

2

U1=(Se)2g1

24 B

2

U2=(Se)2g2 g2

24 B

W =a(t2 t1)

b

d = Sag =(s) 2 g2(4-2)

8 b2

(4-2)

(700)

50 75 +15

-2 + 5

/24.34.188.854.628.63

10461017215211242100

49.851.249.646.348.5

(4-1) (50) (6.96) .

(700) (3.2) :

aS

= 0.75d+L+33

50ck150

(d50c) (2) (a) = 5.56 (700) (4-1) (6.96)

6.96

= 0.75d+1+33

50c150

d50c =79.82 meter (d 50c) (4-2) (5-1) :

79.82 =3.49510 -3 (S)2

8 b2

2

S2=182707 b2(4-3)

U1 =S2 (6.82610 -3)2

24 13010-6

2

U2=0.015 S(4-4)

U2 =S2 (3.49510 -3 )2

24 13010-6

2

U2=0.004 S(4-5)

(4-5 , 4-4 , 4-3) (4-1) : S = 910 meter b 2 = 4.53 kg/mm2 ( wind Span ( (2,3) (50) (S2/SRC) ...(1-2)

(1-1)

(1-2)

(1-3)

..(1-9)

(1-4)

(1- 5 )

..(1-10)

(1-6)

(3-1)

(3-2)

(3-3)

(3-4)

(3-5)

(3-6)

(4-1)

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