TRAINING PROGRAMME ON ENGINEERING DESIGNS-CANAL STRUCTURES GENERAL DESIGN PRINCIPLES
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TRAINING PROGRAMME ONTRAINING PROGRAMME ON
ENGINEERING DESIGNS-CANAL STRUCTURESENGINEERING DESIGNS-CANAL STRUCTURES
GENERAL DESIGN PRINCIPLES GENERAL DESIGN PRINCIPLES
Off Take Sluices,Off Take Sluices, Canal outlets and ModulesCanal outlets and Modules
BY BY
ROUTHU SATYANARAYANAROUTHU SATYANARAYANA
CHIEF ENGINEER (Retired.)CHIEF ENGINEER (Retired.)
FORMER ADVISOR, GOVERNMENT OF A.PFORMER ADVISOR, GOVERNMENT OF A.P
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Off Take Sluices And Modular Outlets Definition:
Off –take sluices: It is a small structure which admits water from the parent canal to a
distributing channel or to a water course or a filed channel. Water distribution system is classified as:
1. Supply System or Conveyance System:
• Discharge >5.66 cumecs(200 c/s) and perennial and always gated. 2. Distributory System: Discharge < 5.66 cumecs (200 c/s), runs
on and off system, No gates, Water will be distributed proportionately through Modules (APM or OFM).
Gated off takes: i. Square opening or ii. Rectangular openings or iii. Hume pipes Sill levels will be kept at bed level or above bed level of parent canal
depending on the % discharge of the OT with Parent canal discharge:
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Off Take Sluices And Modular Outlets• Sill levels will be kept at bed level or above bed level of parent canal
depending on the % discharge of the OT with Parent canal (PC) discharge:_____________________________________________________________________________% discharge Height of sill of OT above CBL of PC when FSD in PC in m
-------------------------------------------------------------------------------2.14 2.14 to 1.22 below 1.22
____________________________________________________________________>> 15% 0.075 … …10% to 15% 0.15 0.075 …5% to 10% 0.30 0.15 0.0752% to 5% 0.30 0.30 0.15<2% 0.30 0.30 0.30
_____________________________________________________________________• Minimum size of Hume Pipe: : 300mm• Main and branch canals : 900mm• Distributory : 230mm for Q=14.15 to 2.83 cumecs and 150 mm for Q < 2.83
cumecs• The level difference between sill level & CBL of parent canal negotiated by
slope
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Off Take Sluices And Modular Outlets
• Driving Head:
• The driving head at off take is arrived considering Half Supply discharge in parent canal, when the distributory canal runs at full supply level
• Driving Head=Half supply discharge level in parent canal-FSL in distributory
Type of Canal Driving head in mm
Channels taking off from main & branch canals 150Channels taking off from distributaries 75
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Off Take Sluices And Modular Outlets
Driving Head:
• The working heads to be usually allowed (as per Para 2.80 of CBIP Publication No. 171. Manual on Irrigation and Power channels by CWC)
Channel Minimum working head
Head over field 75mm
Major distributaries to minor 300mm
At outlet 150mm
Branch to branch or major distributaries' 500mm
From main canal 600mm
Slope of water course 1 in 5000
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Off Take Sluices And Modular Outlets
• Vent way:
• Vent way calculated from the formula:
Q the discharge in cumecs = C.A.(2gH)1/2
where
C = a constant : 0.62 for Square or Rectangular opening
0.75 for circular opening
A = Area in Sq. m
H = Driving head in m
Q for Rectangular a Square opening = 2.745 A (H)1/2
Q for Circular opening = 3.322 A (H)1/2
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Off Take Sluices And Modular Outle
• Check for driving:
• Length of barrel worked out with respect to position of D/S head wall. The flow condition in the barrel is dependent on D/S condition in the O.T. channel immediately below the vent way. TELs at entrance and exit of barrel are calculated and checked for assumed level.
• Transitions:The U/S and D/S transitions are provided with 1 in 3 and 1 in 5 splay
respectively as per practice.• Stilling Basin:
• The type of stilling basin to be provided depends upon the velocity at the entry of barrel. If the entry velocity is above 6.1 m/sec. (20 ft/sec) the barrel floor is depressed both for rectangular and square vents based on the hydraulic jump calculations. In case of normal velocities which are of the order of 4 m/ sec the floor is at the same level and the floor is checked for arch action for the uplift pressure.
• The design of hydraulic jump basin for energy dissipating arrangements can be followed from ‘Small Dams’ by U.S.B.R. or as per I.S. 4997 – 1968. For shooting flows, an impact type basin - VI with R.C.C. baffle wall is to be provided. The baffle wall is to be designed for the maximum water thrust with 50% impact factor when full discharge is let out in the canal.
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Off Take Sluices And Modular Outle
• Off – takes with hume pipes:
Minimum diameter for off takes from main/ branch canal and distributaries is as follows:
Main/ Branch canal Distributory
Minimum Diameter 0.90m i) 14.15 to 2.83 cumec discharges – 0.23m φ
ii)2.83 cumec and less – 0.15m φ
• Laying of O.T. Pipes:
The condition of laying of off – take pipes such as “Negative projecting condition”, and “Trench condition” etc., relevant to the individual cases are followed as per IS. 783 – 1985 for laying and jointing. For the selection of proper size of pipe for the vents, IS. 458 is to be followed
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Off Take Sluices And Modular Outle
• Controlling arrangements
Type of control to be adopted:
(i) For pipe sluices of 150 mm dia. and below and vents of equivalent area with F.S.D of parent canal not exceeding No control1.22 m. and O.T discharge 0.045 cumecs (1.5 c/s )and less
(ii) For pipe sluices of diameters above 150mmand up to and including 300 mm with F.S.D of parent canal not Stem shutter exceeding 1.22 m.
For all sluices where the FSD in the parent canal Screwis more than1.22 m and for sluices of larger vent ways. gearing shutter –
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Canal Outlets And Modular Outlets
• Canal Outlets and Modular Outlets:
• Definition:
• Canal outlet is a device through which water is released from a distributing channel into a water course whose discharge is less than 0.085 cumecs
• Classification of Outlets:
• Non modular out lets
• Semi modular out lets
• Modular out lets
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Canal Out lets & Modular Outlets
• Requirement:
• Structurally strong, • With out any moving parts, • Difficult for the cultivators to interfere and if so easily detectable, • Work efficiently for small working heads, • Can draw fair share of silt and economical.
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Canal Out lets & Modular Outlets
Non-Modular outlets:
• It is a pipe outlet with one end submerged in water course fixed horizontally at right angle to the flow..
• Consists of circular or rectangular opening and pavements.• Discharge widely varies with the change of water level either in the canal or the
water course.
• Discharge Q in cumecs = CA(2gH)1/2 (Q=5 or6 A H1/2 for pipe sluices in FPS)
Where, A= cross sectional area of the pipe in sq. m. C= Coefficient = 1__ [d/f(L+1.5d/400f)]1/2
2 x 105
H= difference in water levels, f = coefficient of fluid friction, 0.005 and 0.01 for clear and
encrusted iron pipes and 0.0075 for earthenware pipes. L = length of pipe in m d = diameter of the pipe in cm
• Drowned pipe outlet and Masonry sluice comes under this category.
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Canal Outlets & Modular Outlets
Semi-Modular outlets:• Non-Modular outlet works as Semi-Modular outlet if the exit end of the pipe is
made to discharge with a free fall. In this case working head H is the difference between water level in the parent channel and the centre of pipe(PSM)
• It is independent of water level in water course up to minimum working head.• Discharge increases with increase in the water levels in the distributaries'. Pipe outlets, venturi flumes, open flumes and orifice semi modules are the
examples.
Semi-Modular outlets or Flexible modules• Open Flume Outlet (OFMs)
• Crump’s Adjustable proportionate Module (Crump’s APM)
• Adjustable Orifice Semi module (AOSM)
• Pipe Semi Module
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Cross Masonry Works- Modular Outlets
Semi-Modular outlets or Flexible modules
• Open Flume Outlet (OFMs)
• Crump’s Adjustable proportionate Module (Crump’s APM)
• Adjustable Orifice Semi module (AOSM)
• Pipe Semi Module
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Canal Outlets & Modular Outlets
Open Flume Module(OFM):
• A smooth weir with a throat constricted sufficiently to ensure velocity above critical, and long enough to ensure that the controlling section remain with in the parallel throat at all discharges up to the maximum.
• A gradually expanded flume is provided at the outfall to recover the head.
• The entire work can be built in brick, but the controlling section is provided with cast iron or steel bed and check plates.
• Throat width Bt never kept less than 6cm hence it is necessary to raise the crest level of the out let much above bed level.
• Working head required with a 1 in 5 glacis and side walls splaying at 1 in 5 is 20% of depth of water above the crest of out let.
• Formation of hydraulic jump makes the out let independent of water level in the out let channel
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Canal Out lets & Modular Outlets
Open Flume Module (OFM):
• Q in Cumecs = K Bt H3/2
Where K = a constant depending upon the width of the flume
Bt = throat width of the weir (minimum 6 cm)For Bt , 6 cm to 9 cm K=1.6
9 cm to 12 cm K= 1.64> 12cm K= 1.66
H = head over crest in m.• It is most suited to tail cluster and proportionate distribution.• Length of throat (crest) = 2H• Setting H = 0.9 D, where D is FS dept of Parent canal• Minimum modular working head = 0.2 H• Crest level = U/S FSL – 0.9 D• U/S approach to throat ----- one curved and diverging and another straight• D/S expansion------- splayed to 1 in 10 to meet the bed width of the out let
channel
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Open Flume Module
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Canal outlets & Modules
• Adjustable Orifice Semi Module (A.O.S.M) or Adjustable Proportional Module (APM)
• Discharge through outlet in cumecs Q = 4.03 Bt Y Hs
1/2
Y =Height of opening in meters. Bt =Throat width (minimum 0.06 m )
H =Depth of water in parent canal over the crest in metersHs = Depth to under side of the roof block below FSL of parent canal.
Hs = H – Y , Hs ≤ 0.80 D
y > (2/3 ) HSetting of crest, H = 0.750 x D , where D = Full supply depth in the parent canalSetting of crest shall not be below D/S B.L.
•
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Canal outlets & Modules
Setting of crest shall not be below D/S B.L.Minimum modular head Hm = 0.75 Hs for modularity between full supply and any fraction of full supply.Crest level ≈ U/S FSL- 0.75 DLength of throat = width of roof block + HU/S slope of glacis = curve with radius 2H.U/s approach wings =one curved and the other straight, top at FSL + 0.15 mD/S expansion =1 in 10 to meet bed width of outlet channel
•
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Modular Outlets
Crump’s Adjustable Proportionate Module or adjustable Orifice Semi-Modules ( APM):• Most commonly used module. • CI base, CI roof block and check plates on sides nucleus around
masonry.• It can not be tampered and can conveniently adjusted at a very small
cost.Setting of d/s wing wall of approach, W = k(q/Q){Bu+D/2}Where, k= ratio between mean velocities of distributory and the
water courseq= discharge in cumecs of the water courseQ= discharge in cumecs in the distributoryBu= bed width of the distributor u/s of outletD= depth of water in the distributory
Q in cumecs k0.283 1.000.283 to 1.415 1.251.415 to 5.660 1.50> 5.660 2.00
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CRUMP’S ADJUSTABLE PROPORTIONAL MODULE
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Canal Out lets & Modular Outlets
Adjustable orifice Semi Module (AOSM)
• An orifice provided with gradually expanding flume on the d/s side of the orifice. The flow through the orifice is super critical , resulting in the formation of hydraulic jump in the expanded flume portion. The formation of jump makes the discharge isdependent of water level in the out let channel.
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Canal Outlets & Modules
• Pipe semi module • Design criteria
The discharge through pipe semi module is given by Q = Cd . A (2g hc )1/2
Where Cd = 0.62 for free pipe out let hc = head on U/S above the centre of pipe
hc should be more than 1.5 times the dia of the pipe proposed.
The above formulae can be reduced to Q = 0.62 x √ (2x 9.81 ) A √ (hcnt)
=2.746 A hc 1/2
• For free fall condition set the F.S.L of OT Channel below the pipe sill level keeping in view the command under the pipe sluice .It is a simplest type and the users will appreciate.
•
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Modular Outlets • The suitability of the type of the semi module outlet is determined based on the ratio of parent canal discharge (Q) to the discharge of
the out let (q) and the throat width (Bt) as detailed below.
i) for (Q/q ) < or = 20 and B t ≥ 6 cm Open Flume Module( OFM)
ii) for (Q/q ) < or = 20 and B t < 6 cm Adjustable Proportional module ( APM )
for (Q/q ) > 20
• If the above requirements do not suit the site condition, provide pipe semi module (where possible) with diaphragm of required
diameter inserted at the first joint. The minimum diametre of pipe used will be 150 mm.
• The above conditions are further explained as below• Arrive at the ratio of parent channel / out let channel.• If it is < or = 20, select OFM. Calculate the Bt ( throat width ), using weir formula.
If Bt is > 6 cm it is ok.
Otherwise select A.P.M. • Work out the Bt using the sluice formula setting the crest of outlet at less than 0.80 D from FSL of Parent
Channel and adjusting the height of outlet opening.
If Bt = or > 6 it is ok• Otherwise go for pipe semi module (PSM), if it is possible to do so.• Check for proportionally•
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Modular Outlets
DESIGN - EXAMPLES
HYDRAULIC DESIGN
OFM – APM - PSM
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Cross Masonry Works- Modular Outlets
Semi-Modular outlets or Flexible modules
• Open Flume Outlet (OFMs)
• Crump’s Adjustable proportional Module (Crump’s APM)
• Adjustable Orifice Semi module (AOSM)
• Pipe Semi Module – Pipe Out let (PSM)
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Modular Outlets
• The suitability of the type of the semi module outlet is determined based on the ratio of parent canal discharge (Q) to the discharge of the out let (q) and the throat width (Bt) as detailed below.
i) for (Q/q ) < or = 20 and B t ≥ 6 cm Open Flume Module( OFM)
ii) for (Q/q ) < or = 20 and B t < 6 cm Adjustable Proportional module ( APM )
for (Q/q ) > 20
• If the above requirements do not suit the site condition, provide pipe semi module (where possible) with diaphragm of required diameter inserted at the first joint. The minimum diameter of pipe used will be 150 mm.
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Modular Outlets
• The above conditions are further explained as below
Arrive at the ratio of parent channel / out let channel.
If it is < or = 20, select OFM. Calculate the Bt ( throat width ), using weir formula.
If Bt is > 6 cm it is ok.
Otherwise select A.P.M.
Work out the Bt using the sluice formula setting the crest of outlet at less than 0.80 D from FSL of Parent Channel and adjusting the height of outlet opening.
If Bt = or > 6 it is ok
Otherwise go for pipe semi module (PSM), if it is possible to do so.
Check for proportionally
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Canal Outlets & Modular Outlets
Open Flume Module(OFM):
• A smooth weir with a throat constricted sufficiently to ensure velocity above critical, and long enough to ensure that the controlling section remain with in the parallel throat at all discharges up to the maximum.
• A gradually expanded flume is provided at the outfall to recover the head.
• The entire work can be built in brick, but the controlling section is provided with cast iron or steel bed and check plates.
• Throat width Bt never kept less than 6cm hence it is necessary to raise the crest level of the out let much above bed level.
• Working head required with a 1 in 5 glacis and side walls splaying at 1 in 5 is 20% of depth of water above the crest of out let.
• Formation of hydraulic jump makes the out let independent of water level in the out let channel
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Canal Out lets & Modular Outlets
Open Flume Module (OFM):
• Q in Cumecs = K Bt H3/2
Where K = a constant depending upon the width of the flume
Bt = throat width of the weir (minimum 6 cm)For Bt , 6 cm to 9 cm K=1.6
9 cm to 12 cm K= 1.64> 12cm K= 1.66
H = head over crest in m.• It is most suited to tail cluster and proportionate distribution.• Length of throat (crest) = 2H• Setting H = 0.9 D, where D is FS dept of Parent canal• Minimum working head (modular ) = 0.2 H• Crest level = U/S FSL – 0.9 D• U/S approach to throat ----- one curved and diverging and another straight• D/S expansion------- splayed to 1 in 10 to meet the bed width of the out let
channel
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Canal Out lets & Modular Outlets
HYHDRAULIC DESIGN OF OFM
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Canal Out lets & Modular Outlets
Open Flume Module (OFM):
HYDRAULIC PARTICULARS
S. No.
Details Unit
Parent Canal Off Take
Kopparam Major
13 R Minor
1Discharge (Required) Cumecs 0.939 0.0802Bed Width m 1.200 0.3003F.S. Depth m 0.730 0.3104Free Board m 0.610 0.4605Bed Fall 1 in 2640 20006Side Slopes 1.5 : 1 1.5 : 17Velocity m/sec 0.561 0.3398n 0.020 0.0209CBL m 81.589 81.66210FSL m 82.319 81.97211TBL m 82.929 82.43212GL m 82.929 82.432
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Design of OFM
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Canal Out lets & Modular Outlets
Open Flume Module (OFM):
Hydraulic Design:
Ratio of Q/q = 0.939 / 0.08 = 11.738 < 20 Hence O.F.M. is Proposed. FSD in the parent channel, D = 0.730 m Depth of flow in the parent channel at 2/3rd discharge:
Dn = 0.594 m (assumed)
For 2/3rd Discharge in Parent Canal Qn = 2/3 x Q = 0.626 cumecs
Let Dn = 0.594 m , Area = 1.242 m2 Perimeter = 3.342 m, R = 0.372, and R2/3 = 0.517 Velocity = 0.504 m/sec Discharge = 0.626 cumecs Hence Dn i.e., depth of flow of 0.594 m in the parent channel assumed for 2/3rd discharge is correct.Difference in depths of flow for full discharge and 2/3rd discharge
x = D - Dn = 0.730 - 0.594 = 0.136 m
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Canal Out lets & Modular Outlets
Open Flume Module (OFM):
The discharge of the outlet q (in cumecs) is given by the formula: q = K x Bt x H3/2 Where K = Constant depending upon the width of flume Bt = Throat width of weir H = Head over crest in meters Hn = Head over crest at 2/3 Q = ( H – x )For full discharge q = K x Bt x H3/2 - ( 1 )
For 2/3 discharge q = K x Bt x (Hn)3/2 = K x Bt x (H-x)3/2 - ( 2 ) By dividing equation (1) by equation (2) q / 2/3 q = K x Bt x H3/2 / 2/3 (q) K x Bt x (H - x)3/2 3/2 = (H3/2 /(H - x)3/2 ) 2/3 (3/2)2/3 = (H3/2 /(H - x)3/2 ) 2/3 1.310 = H / (H - x) 0.31 . H = 1.31 . x H = 4.225 x x = 0.136 m
Hence, H = 4.225 x 0.136 = 0.575 m Crest Level = F.S.L. of Parent Channel - H
= 82.319 - 0.575 = 81.744 m
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Canal Out lets & Modular Outlets
Open Flume Module (OFM): Minimum Head required (modular) = 0.2 x H = 0.2 x 0.575 = 0.115 m Available Working Head = Difference of FSL's in Parent Canal and Off - Take Canal
= 82.319 - 81.972 = 0.347 m OK q = K x Bt x H3/2
Value of "K" as per IS: 12331-1988 = 1.64 Bt = q / (K . H3/2)
= 0.080 / 1.64 x (0.575)3/2 = 0.112 m q = K x Bt x H3/2
= 1.64 x 0.112 x 0.5753/2 = 0.080 cumecs OK
For 2/3rd q: qn = (2/3 x 0.080) = 0.053 cumecs
Hn = H - x = 0.575 - 0.136 = 0.439 m
qn = K x Bt x Hn3/2
= 1.64 x 0.112 x 0.4393/2 = 0.053 cumecs OK In order to maintain the modularity of the outlet, the following parameters are
adopted. Bt = 0.112 m H = 0.575 m Throat Length = 1.150 m Crest Level = 81.744 m
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Design of OFM
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Open Flume Module
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Canal Out lets & Modular Outlets
HYHDRAULIC DESIGN OF APM
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Canal outlets & Modules
• Adjustable Orifice Semi Module (A.O.S.M) or Adjustable Proportional Module (APM)
• Discharge through outlet in cumecs Q = 4.03 Bt Y Hs
1/2
Y =Height of opening in meters. Bt =Throat width (minimum 0.06 m )
H =Depth of water in parent canal over the crest in metersHs = Depth to under side of the roof block below FSL of parent canal.
Hs = H – Y , Hs ≤ 0.80 D
y > (2/3 ) HSetting of crest, H = 0.750 x D , where D = Full supply depth in the parent canalSetting of crest shall not be below D/S B.L.
•
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Canal outlets & Modules
Setting of crest shall not be below D/S B.L.Minimum modular head Hm = 0.75 Hs for modularity between full supply and any fraction of full supply.Crest level ≈ U/S FSL- 0.75 DLength of throat = width of roof block + HU/S slope of glacis = curve with radius 2H.U/s approach wings =one curved and the other straight, top at FSL + 0.15 mD/S expansion =1 in 10 to meet bed width of outlet channel
•
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Design of APM
• Hydraulic Particulars:
S.No. Details Kuppam Major DP 17-R Kuppam major DP 17-R
At FS Discharge Condition At 2/3 FS Discharge Condition
1. Discharge in Cumecs 0.636 0.018 0.424 0.012
2. Bed width in m 1.100 0.300 1.100 0.300
3. FSD in m 0.610 0.150 0.495 0.120
4. Bed fall 1 in 2500 2000 2500 2000
5. Value of ‘ n ‘ 0.020 0.020 0.020 0.020
6. Velocity in m/s 0.518 0.231 0.464 0.183
7. Side slopes 1.5 : 1 1.5 : 1 1.5 : 1 1.5 : 1
8. Free board in m 0.610 0.450 0.610 0.450
9. CBL m 80.269 80.422 80.269 80.422
10. FSL m 80.879 80.572 80.764 80.542
11. TBL m 81.489 81.022
12. GL m 81.489 81.489
Propose APM if Q / q < 20, or Q / q > 20, and Bt < 60 mm
Ratio of Q / q = 0.636 / 0.018 = 35.333 > 20
Hence APM is proposed.
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Design of APM
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Design of APM• Hydraulic Design of APM
Propose APM if Q/q < 20 and Bt < 6 or Q/q >20
Ratio of Q/q = 0.636 / 0.018 = 35.333 > 20 Hence A P M is proposed q = 4.03 x Bt x y x Hs
1/2
Where Y = Height of opening in meters
Bt = Throat width
H =Depth of water in parent canal over the crest in meters.
Hs = Depth of under side of the roof block below FSL of parent canal
For 2/3 full supply Parent canal Off take canal
Qn =2/3Q = 0.424 cum qn =2/3*q = 0.012 cum
Let Dn = 0.496 m Let dn = 0.120
Area = 0.913 sq.m 0.058 sq. m
perimeter = 2.887 m 0.733 m
R = 0.316 m 0.079 m
R3/2 = 0.464 0.183
velocity = 0.464 m/sec 0.205 m/sec
discharge = 0.424 0.012
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Design of APM
• Discharge through the outlet in cumecs.
q = 4.03 x Bt x y x ( Hs ) ½ (Page 11, Clause 6.3.1 of IS : 7986-1976)
Throat width Bt = q / (4.03 x (Hs)½ x Y)
Let Bt = 0.06 m
q = 4.03 x Bt x y x Hs1/2 --------------equation (1)
2/3 (q) = = 4.03 xBt x y x (Hsn)1/2 --------------equation (2)
Where Hsn = Hs - (D - Dn) = 4.03 x Bt x y x (Hs - (0.610 - 0.495))1/2
= 4.03 x Bt x y x (Hs - 0.115)1/2
Dividing equation (1) by (2) q/ = 2/3 (q) = 4.03 x Bt x y x Hs1/2 / 4.03 x Bt x y x (Hs - 0.115) ½
3/2 = Hs1/2 / (Hs - 0.115)1/2
= 2 x Hs1/2 = 3 x (Hs - 0.115)1/2
4 x Hs = 9x (Hs - 0.115)
5 Hs = 1.0332
Hs = 0.207 m and Hs1/2 = 0.455
Hsn = Hs – ( D – Dn ) = 0.207 – ( 0.610 – 0.495 ) = 0.092m
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Design of APM
Y = q / 4.03xBtx(Hs)1/2
= 0.018 / 4.03 x 0.06 x 0.455
Y = 0.164 m say 0.165 m
Q = 4.03 Bt Y ( Hs ) ½ = 4.03 x 0.06 x 0.165 x 0.455 = 0.018 cumecs
qn = 4.03 Bt Y ( Hsn ) ½ = 4.03 x 0.06 x 0.165 x 0.303 = 0.012 cumecs
The following Parameters may be adopted
Bt = 0.060 m
Crest Level = U/S FSL - H = + 80.507
H = 0.372 m
Y = 0.165 m
Hs = 0.207 m
W= Setting forward of the D/S wing wall of the approach =0.15
The setting of the Wing wall W = K q/Q (Bu + D/2)
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Design of APM
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CRUMP’S ADJUSTABLE PROPORTIONAL MODULE
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Canal Outlets & Modules
• Pipe semi module (PSM) • Design criteria
The discharge through pipe semi module is given by Q = Cd . A (2g hc )1/2
Where Cd = 0.62 for free pipe out let hc = head on U/S above the centre of pipe
hc should be more than 1.5 times the dia of the pipe proposed.
The above formulae can be reduced to Q = 0.62 x √ (2x 9.81 ) A √ (hcnt)
=2.746 A hc 1/2
• For free fall condition set the F.S.L of OT Channel below the pipe sill level keeping in view the command under the pipe sluice .It is a simplest type and the users will appreciate.
•
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Modular Outlets DESIGN OF PIPE SEMI MODULE (for DIRECT OUTLET )
HYDRAULIC PARTICULARS
DESCRIPTION UNIT ` PARTICULARS
PARENT CHANNEL OUTLET CHANNEL 1 Ayacut Acres 597.0 75.00
2 Discharge (Required/Designed) Cumecs 0.2370 / 0.3460 0.030 / 0.033
3 Bed width m 1.100 0.300
4 Full Supply Depth m 0.500 0.220
5 Free board m 0.300 0.300
6 Side slopes (Inner / Outer) - 1.50 / 2 : 1 1.50 / 2 : 1
7 Top width of banks L/R m 4.000 / 2.50 0.900 / 0.900
8 C.B.L. m + 473.655 + 473.500
9 F.S.L. m + 474.155 + 473.720
10 T.B.L. m + 474.455 + 474.020
11 G.L. M + 474.855 + 474.855
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Modular Outlets
Discharge through the Pipe Outlet by using Orifice formula:
Q = CA (2g hcnt)1/2
where C = 2. 476
Q = Discharge of Out Let
A = Cross section Area of Pipe
h(cnt) = Head of U/s water surface over the center of pipe
Q = CA (2g hcnt)1/2
Where C = 2.476
Provide Dia of Pipe = 16 cm
Area A = 0.020 m2
Q = 0.033 cumec
hcnt = Q CA 2
= 0.033 2.476x0.02
= 0.350 m > 1.5 times dia of pipe
Provide did. of pipe = 200mm
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Hydraulic Design of PSM
The Center line of the Pipe = 474.155 – 0.350 = 473.805m
Pipe sill level (Invert Level) = 474.155 - 0.350 - 0.08 (pipe radius)
= 473.725m
Height of pipe above CBL = 473.725 – 475.655 = 0.070m
Pipe invert level = 473.725m
FSL of 17-R = 473.720m
Hence the pipe is at free fall condition
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Design of PSM
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