Topic 12 Electromagnetic Induction

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Topic 12 Electromagnetic Induction

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Topic 12 Electromagnetic Induction. Electromagnetic induction. Make a coil using wire. The coil should be wide enough to easily move a magnet inside. Electromagnetic induction. Put your coil in this circuit. The multimeter should be on the μ A scale. μ A. Electromagnetic induction. - PowerPoint PPT Presentation

Transcript of Topic 12 Electromagnetic Induction

Page 1: Topic 12 Electromagnetic Induction

Topic 12 Electromagnetic Induction

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Electromagnetic induction

• Make a coil using wire. The coil should be wide enough to easily move a magnet inside

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Electromagnetic induction

• Put your coil in this circuit. The multimeter should be on the μA scale.

μA

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Electromagnetic induction

• MOVE a magnet in and out of the coil. Watch the meter!

μA

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Electromagnetic induction

If a magnet is moved inside a coil an electric current is induced (produced)

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Generator/dynamo

A generator works in this way by rotating a coil in a magnetic field (or rotating a magnet in a coil)

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Motor = generator

If electric energy enters a motor it is changed into kinetic energy, but if kinetic energy is inputted (the motor is turned) electric energy is produced!

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The Motor Effect

When a current is placed in a magnetic field it will experience a force (provided the current is not parallel to the field). This is called the motor effect.

Can you copy this sentence into your

books please.

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The Motor Effect

The direction of the force on a current in a magnetic field is given by Flemming’s left hand rule.

Centre finger = Conventional Current

First finger = Field direction

Thumb = Motion

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The Motor Effect

The direction of the force on a current in a magnetic field is given by Flemming’s left hand rule.

Centre finger = Conventional Current

First finger = Field direction

Thumb = Motion

Can you copy this please?

WITH DIAGRAM!

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Sample question

In this example, which way will the wire be pushed? (red is north on the magnets)

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Sample question

In this example, which way will the wire be pushed? (red is north on the magnets)

Current

Field

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IB Level!

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Electromagnetic Induction

Imagine a wire moving with velocity v in a magnetic field B out of the page.

vRegion of magnetic field B out of page

Wire moving with velocity v

L

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The electrons in the wire feel a force (the motor effect) which pushes the electrons to the right. This creates a potential difference in the wire.

v

L Electrons pushed this way (left hand rule)

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The field in the wire that produces this potential difference is given by E = V/L

v

L

e.m.f. (voltage) across the wire in the magnetic field

-+

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The force produced by this field E = V/L would push the electrons back again, but this is opposed by the force on the electrons due to the magnetic filed F = Bev

v

L

-+

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There exists a balance between the force on the electrons due to the field in the wire and the force due to the field

eE = Bev

v

L

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eE = Bev

since E = V/L, V = vBL

v

L

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V = vBLThis means that a conducting wire of length L moving with

speed v normally to a magnetic field B will have a e.m.f. of vBL across its ends. This is called a motional e.m.f.

vRegion of magnetic field B out of page

Wire moving with velocity v

L

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Faraday’s Law

My hero!

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Faraday’s Law

Consider a magnet moving through a rectangular plane coil of wire.

N

S

A

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Faraday’s Law

A current is produced in the wire only when the magnet is moving.

N

S

A

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Faraday’s Law

The faster the magnet moves, the bigger the current.

N

S

A

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Faraday’s Law

The stronger the magnet, the bigger the current.

N

S

A

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Faraday’s Law

The more turns on the coil (same area), the bigger the current.

N

S

A

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Faraday’s Law

The bigger the area of the coil, the bigger the current.

N

S

A

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Faraday’s Law

If the movement is not perpendicular, the current is less.

N

SA

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Magnetic Flux (Ф)

Imagine a loop of (plane) wire in a region where the magnetic filed (B) is constant.

B

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The magnetic flux (Ф) is defined as Ф = BAcosθ where A is the area of the loop and θ is the angle between the magnetic field direction and the direction normal (perpendicular) to the plane of the coil.

B

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If the loop has N turns, the flux is given by

Ф = NBAcosθ in which case we call this the flux linkage.

B

The unit of flux is the Weber (Wb) (= 1 Tm2)

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It can help to imagine the flux as the number of lines of magnetic field going through the area of the coil. We can increase the flux with a larger area, larger field, and keeping the loop perpendicular to the field.

B

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Faraday’s law (at last!)

As we seen, an e.m.f. is only induced when the field is changing. The induced e.m.f. is found using Faraday’s law, which uses the idea of flux.

I built the first electric motor and

generator too. I refused all prizes

and awards because that would detract from God’s

glory.

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Faraday’s law

The induced e.m.f. is equal to the (negative)

rate of change of magnetic flux,

E = -ΔФ/Δt

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Example question

The magnetic field through a single loop of area 0.2 m2 is changing at a rate of 4 t.s-1. What is the induced e.m.f?

“Physics for the IB Diploma” K.A.Tsokos (Cambridge University Press)

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Example question

The magnetic field (perpendicular) through a single loop of area 0.2 m2 is changing at a rate of 4 t.s-1. What is the induced e.m.f?

Ф = BAcosθ = BA

E = ΔФ = ΔBA = 4 x 0.2 = 0.8 V

Δt Δt

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Another example question!There is a uniform magnetic filed B = 0.40 T out of the page. A rod of length L = 0.20 m is placed on a railing and pushed to the right at a constant speed of v = 0.60

m.s-1. What is the e.m.f. induced in the loop?

L v

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The area of the loop is decreasing, so the flux (BAcosθ) must be changing. In time Δt the rod will move a distance vΔt, so the area will decrease by an area of LvΔt

L vLvΔt

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E = ΔФ = BΔA = BLvΔt = BLv

Δt Δt Δt

E = 0.40 x 0.20 x 0.60 = 48 mV

L vLvΔt

An important result, you may be asked to do this!

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Lenz’s Law

The induced current will be in such a direction as to oppose the change in magnetic flux that created the current

(If you think about it, this has to be so…….)

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Alternating current

A coil rotating in a magnetic field will produce an e.m.f.

N S

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Alternating current

The e.m.f. produced is sinusoidal (for constant rotation)

e.m.f.

V

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Slip ring commutator

To use this e.m.f. to produce a current the coil must be connected to an external circuit using a split-ring commutator.

Slip-rings

lamp

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Increasing the generator frequency?

e.m.f.

V

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Root mean square voltage and current

It is useful to define an “average” current and voltage when talking about an a.c. supply. Unfortunately the average voltage and current is zero!

To help us we use the idea of root mean square voltage and current.

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Root mean square voltage

e.m.f.

V

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Root mean square voltageFirst we square the voltage to get a quantity that is positive during a whole cycle.

e.m.f.

V

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Root mean square voltageThen we find the average of this positive quantity

e.m.f.

V

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Root mean square voltageWe then find the square root of this quantity.

e.m.f.

V

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Root mean square voltageWe then find the square root of this quantity.

e.m.f.

V

This value is called the root mean square voltage

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Root mean square voltageWe then find the square root of this quantity.

e.m.f.

V

Erms = Emax/√2

Emax

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Transformers

What can you remember about transformers from last year?

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Transformers

Np turns

Ns turns

Vp Vs

Primary coilSecondary coilIron core

“Laminated”

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Transformers

How do they work?

Np turns

Ns turns

Vp Vs

Primary coilSecondary coilIron core

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An alternating current in the primary coil produces a changing magnetic field in the iron core.

Np turns

Ns turns

Vp Vs

Primary coilSecondary coilIron core

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The changing magnetic field in the iron core induces a current in the secondary coil.

Np turns

Ns turns

Vp Vs

Primary coilSecondary coilIron core

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It can be shown using Faraday’s law that:

Vp/Vs = Np/Ns and VpIp = VsIs

Np turns

Ns turns

Vp Vs

Primary coilSecondary coilIron core

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Power transmission

When current passes through a wire, the power dissipated (lost as heat) is equal to

P = VI across the wire

Since V = IR

Power dissipated = I2R

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Power transmission

Power dissipated = I2R

Since the loss of power depends on the square of the current, when transmitting energy over large distances it is important to keep the current as low as possible.

However, to transmit large quantities of energy we therefore must have a very high voltage.

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Power transmission

Electricity is thus transmitted at very high voltages using step up transformers and then step down transformers.

Step-up

Step-down

Step-down

15,000 V

250,000 V

15,000 V

220 V

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Dangerous?

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Dangerous?

Low-frequency electromagnetic fields can induce currents in the human body!

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Dangerous?

Current evidence suggests that low-frequency fields do not harm genetic material. This is not fully proven or understood.

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Whew! That’s it!