Tong Hop Cac Chuyen de Luyen Thi Dai Hoc Hoa Hocmoi

7/30/2019 Tong Hop Cac Chuyen de Luyen Thi Dai Hoc Hoa Hocmoi

1/59

Thanh Tng_ sv HKHTN-HQGHN_ luyn thi i hc ho hc_ nm 2011-2012. Mithc mc v bi xin lin hst 098.555.6536hoc e-mail [email protected]

1

CHUYN TUYN TP CC DNGBI TP LUYN THI I HC, CAO

NG NM HC 2011-2012

1. CUNG CP Y CC DNG BI TP GIP HC SINH NH HNHC CC PHNG PHP SDNG TRONG CC BI TON

2. CUNG CP MT STHI I HC HO HC HAY V KH3.RT NGN THI GIAN N LUYN CA CC EM HC SINH

CHC CC EM MT K THI THNH CNG V T C CM


2/59

Chuyn bi tp n luyn thi i hc nm hc 2012-2013. Ngi son: V Thanh Tng svkhoa ha HKHTN_HQGHN

2

Chuyn 01: Cu to nguyn tv bng h thng tun hon

I/ Bi tp tlun

Bi1: Vit cu hnh e ca 26Fe, 29Cu , 35Br , 20Ca , 16S , Fe2+, Fe3+ , Cu2+, Br-. Xc nh v tr ca chng trong

bng h thng tun hon .Nu tnh cht ho hc c trng ca Fe, Cu, Ca, S, Br2, v vit phng trnh phn ngminh hoBi 2: Cation R+ c cu hnh e lp ngoi cng l 3p6-Vit cu hnh e v xc nh v tr ca chng trong bng h thng tun hon.-Anion X- c cu hnh e ging R+ vit cu hnh e ca X.Bi 3: Cho 3 ngyn t A, M, X c cu hnh e lp ngoi cng l ns1, ns2np1,ns2np5.-Da vo cu hnh e hy xc nh v tr ca A, M,X trong bng HTTH bit n = 3-Vit phng trnh phn ng gia cc cht trn vi H2O, dung dch NaOH, dung dch AlBr3Bi 4: A v B l 2 nguyn t thuc hai chu k k tip nhau trong cng mt phn nhm chnh ca bng HTTH

Tng s ht prton trong ht nhn nguyn t ca A v B l 32.-Vit cu hnh e ca A v B v xc nh v tr ca chng trong bng h thng tun hon.Bi 5: A v B l hai nguyn t thuc hai phn nhm chnh k tip nhau, B nhm V, trng thi n cht , Av B phn ng vi nhau. Tng s ht proton trong ht nhn nguyn t ca A v B l 23. Vit cu hnh e ca Av B. Xc nh v tr ca A, B trong bng HTTH-Vit 5 phng trnh phn ng iu ch trc tip A t cc cht khc nhau.Bi 6: Trong cc ng vsau y ca M th ng v no tha mn iu kin:S proton : sntron =13: 15 . (55M, 56M , 57M, 58M ).-Vit phng trnh phn ng ca M vi Cl2 , MCl3 , H2SO4, v cho MO tc dng vi HNO3c, KMnO4 trongH2SO4 long, CO nhit cao.Bi 7:Hp cht A c cng thc M2X. Tng s ht trong mt phn tA l 140, trong ht mang in nhiuhn ht khng mang in l 44, s khi ca M+ ln hn s khi ca X2- l 23. Tng s ht trong M+ ln hn X2

l 31-Vit cu hnh e ca M, M+, X, X2-v xc nh v tr ca M, X trong bng HTTH.

-Vit phng trnh phn ng ca M vi H2O, dung dch NaOH , dd CuCl2 dd NH4NO3, dd AlCl3Bi 8: (H Quc Gia TPHCM 2001)Nguyn t ca nguyn t A c tng s electron trong cc phn lp p l 7. Nguyn t ca nguyn t B c tng sht mang in nhiu hn s ht mang in ca A l 8. xc nh A v B

Bi 9: (H Hu 2001)Cho 2 nguyn t A v B c s hiu nguyn t ln lt l 11 va13Vit cu hnh e v cho bit v tr ca chng trong bng h thng tun honA c khnng to ra ion A+ , B to ion B3+. Hy so snh bn knh ca A v A+ , B v B3+ gii thch.Bi 10: (H Cn Th 2001)

Mt nguyn t R c tng s ht mang in l 34, trong ht khng mang in gp 1,833 ln s ht khngmang in. Xc nh R v v tr R trong bng HTTH.

Bi 11: (H Xy Dng 2001)Nguyn t ca mt nguyn t X c tng s ht c bn l 82, trong s ht mang in nhiu hn s ht khngmang in la 22 . Xc nh s hiu nguyn t , s khi v tn nguyn t . Vit cu hnh e ca nguyn t X vcc ion to thnh t X.Vit cc phng trnh phn ng ca X tc dng ln lt vi Fe2(SO4)3, HNO3 c nng.Bi 12: (HSPKT TPHCM 2001)Cation X3+ v anion Y2-u c cu hnh e phn lp ngoi cng l 2p6. Xc nh v tr ca X,Y trong bngHTTH.Bi 13: (H TCKT H Ni 2001)Cho Fe c s hiu nguyn t l 26


3/59


3

Khng dng bng HTTH hy xc nh v tr ca Fe trong bng. Cho bit s oxi ho c th c ca FeBi 14:( CSP Bn Tre 2003)

Mt kim loi M c s khi l 54. Tng s ht trong ion M2+ l 78Xc nh s th t ca M trong bng HTTH v cho bit M l nguyn t no trong cc nguyn t sau y54

24Cr,54

25Mn,54

26Fe,54

27CoBi 15: (H khi B 2003)

Tng s ht p v n ,e trong hai nguyn t kim loi A, B l 142. Trong tng s ht mang in nhiu hn sht khng mang in l 42. S ht mang in ca nguyn t B nhiu hn nguyn tA l 12. Xc nh 2 kimloi A, B Bit 11Na , 12Mg , 20Ca , 30Zn , 26FeBi 16: Hp cht X to bi hai nguyn t A, B c khi lng phn t l 76. A, B c s oxi ho cao nht l +a

+b v c s oxi ho m l -x, -y thomn iu kin; a = x, b = 3y. XCTPH ca X bit rng trong X th A c soxi ho l +a .

Bi 17: (H QG H Ni 2001)Hp cht Z c to bi hai nguyn t M, R c cng thc MaRbtrong R chim 6,667% v khi lng. Tronght nhn nguyn t M c n = p + 4, trong ht nhn nguyn t R c n, = p, .Bit rng tng s ht trong phn t Zbng 84, v a + b = 4. Tm cng thc phn t ca Z.Bi 18: Hp cht X c cng thc phn t l RAB3trong R chim 40% v khi lng. Trong ht nhn ca RA,B u c s proton bng sntron . Tng s proton trong phn tX l 50, B l phi kim. Xc nh cng thcphn t ca X

Bi 19: Tng s e trong anion AB 23 l 42, B l phi kim, trong ht nhn ca A, B u c s ht proton bng sntron. Vit cu hnh e ca A,B v tnh s khi ca A, B.Bi 20: Mt nguyn t ca mt nguyn t X ha hc c Z = 12,8.10-19C, vit cu hnh e ca nguyn t vcho bit v tr ca X trong bng HTTH, tnh cht ho hc c trng ca X l g? Vit phng btrinhf phn ngminh ho.

II/ Bi tp trc nghim

Cu 1: Mt ion M3+ c tng s ht proton, ntron, electron l 79, trong s ht mang in nhiu hn s htkhng mang in l 19. Cu hnh electron ca nguyn t M lA. [Ar]3d54s1. B. [Ar]3d64s2.* C. [Ar]3d64s1. D. [Ar]3d34s2.Cu 2: Cc cht m phn t khng phn cc l:A. HBr, CO2, CH4. B. Cl2, CO2, C2H2.* C. NH3, Br2, C2H4. D. HCl, C2H2, Br2.Cu 3:Cc kim loi X, Y, Z c cu hnh electron nguyn t ln lt l: 1s22s22p63s1; 1s22s22p63s2;1s22s22p63s23p1. Dy gm cc kim loi xp theo chiu tng dn tnh kh t tri sang phi l:A. Z, Y, X*. B. Y, Z, X. C. Z, X, Y. D. X, Y, Z.Cu 4:Mt nguyn t ca nguyn t X c tng s ht proton, ntron, electron l 52 v c s khi l 35. S hiunguyn t ca nguyn t X lA. 17*. B. 15. C. 23. D. 18.Cu 5:Trong hp cht ion XY (X l kim loi, Y l phi kim), s electron ca cation bng s electron ca anion vtng s electron trong XY l 20. Bit trong mi hp cht, Y ch c mt mc oxi ha duy nht. Cng thc XY lA. NaF. B. AlN. C. MgO. D. LiF.Cu 6:Nguyn t ca nguyn t X c tng s ht electron trong cc phn lp p l 7. S ht mang in ca mtnguyn t Y nhiu hn s ht mang in ca mt nguyn t X l 8 ht. Cc nguyn t X v Y ln lt lA. Al v P. B. Fe v Cl. C. Al v Cl*. D. Na v Cl.

Cu 7:Trong t nhin, nguyn tng c hai ng v l

63

29Cu

v

65

29Cu

. Nguyn t khi trung bnh ca ng l63,54. Thnh phn phn trm tng s nguyn t ca ng v65

29 Cu lA. 73%*. B. 54%. C. 50. D. 27%.

Cu 8: Dy gm cc ion X+, Y- v nguyn tZ u c cu hnh electron 1s22s22p6 l:A. K+, Cl-, Ar. B. Na+, F-, Ne*. C. Na+, Cl-, Ar. D. Li+, F-, Ne.Cu 9: Anion X- v cation Y2+ u c cu hnh electron lp ngoi cng l -3s23p6. V tr ca ccnguyn t trong bng tun hon cc nguyn t ha hc l:A. X c s th t 17, chu k 3, nhm VIIA ;Y c s th t 20, chu k 4, nhm IIA *B. X c s th t 18, chu k 3, nhm VIIA; Y c s th t 20, chu k 3, nhm IIA


4/59


4

C. X c s th t 17, chu k 4, nhm VIIA; Y c s th t 20, chu k 4, nhm IIAD. X c s th t 18, chu k 3, nhm VIA; Y c s th t 20, chu k 4, nhm IIACu 10:Cu hnh electron ca ion X2+ l 1s22s22p63s23p63d6. Trong bng tun hon cc nguyn t ho hc,nguyn t X thuc.A. chu k 3, nhm VIB. B. chu k 4, nhm VIIIB*.C. chu k 4, nhm IIA. D. chu k 4, nhm VIIIA.Cu 11:Nguyn t ca nguyn t X c electron mc nng lng cao nht l 3p. Nguyn t ca nguyn t Y

cng c electron mc nng lng 3p v c mt electron lp ngoi cng. Nguyn t X v Y c s electronhn km nhau l 2. Nguyn t X, Y ln lt lA. kh him v kim loi. B. kim loi v kim loi.C. phi kim v kim loi*. D. kim loi v kh him.

Cu 12:Trong mt nhm A (phn nhm chnh), tr nhm VIIIA (phn nhm chnh nhm VIII), theo chiu tngca in tch ht nhn nguyn t th.A. tnh kim loi tng dn, m in tng dn. B. tnh kim loi tng dn, bn knh nguyn t gim dn.C. m in gim dn, tnh phi kim tng dn. D. tnh phi kim gim dn, bn knh nguyn ttng dn*.Cu 13: Cho cc nguyn t11M , 17X , 9Y v 19R m in ca cc nguyn ttng dn theo th t.A. R < M < X < Y*. B. M < X < R < Y. C. Y < M < X < R. D. M < X < Y < R.Cu 14: Bn knh nguyn t ca cc nguyn t: 3Li, 8O, 9F, 11Na c xp theo th ttng dn t tri sang phil

A. F, Li, O, Na. B. F, Na, O, Li. C. Li, Na, O, F. D. F, O, Li, Na.*Cu 15: Cho cc nguyn t: 19K , 7N, 14Si , 12Mg . Dy gm cc nguyn tc sp xp theo chiu gim dn

bn knh nguyn t t tri sang phi l:A. K, Mg, N, Si. B. Mg, K, Si, N. C. K, Mg, Si, N*. D. N, Si, Mg, K.Cu 16: Dy cc nguyn t sp xp theo chiu tng dn tnh phi kim t tri sang phi l:

A. P, N, O, F.* B. P, N, F, O. C. N, P, F, O. D. N, P, O, F.Cu 17: Cng thc phn t ca hp cht kh to bi nguyn tR v hiro l RH3. Trong oxit m R c ho trcao nht th oxi chim 74,07% v khi lng. Nguyn t R l

A. As. B. S. C. N.* D. P.Cu 18: Nguyn t ca nguyn t X c cu hnh electron lp ngoi cng l ns2np4. Trong hp cht kh canguyn t X vi hiro, X chim 94,12% khi lng. Phn trm khi lng ca nguyn t X trong oxit cao nhtl

A. 40,00%. B. 50,00%. C. 27,27%. D. 60,00%.Cu 19: Hp cht trong phn t c lin kt ion l

A. NH4Cl.* B. HCl. C. NH3. D. H2O.Cu 20: Dy gm cc cht trong phn t ch c lin kt cng ho tr phn cc l:

A. HCl, O3, H2S. B. H2O, HF, H2S*. C. O2, H2O, NH3. D. HF, Cl2, H2O.Cu 21: Nguyn t ca nguyn t X c cu hnh electron 1s22s22p63s23p64s1, nguyn t ca nguyn t Y ccu hnh electron 1s22s22p5. Lin kt ho hc gia nguyn t X v nguyn t Y thuc loi lin kt.

A. cho nhn. B. kim loi. C. cng ho tr. D. ion*.Cu 22: Pht biu no sau y l ng ?A. th rn, NaCl tn ti di dng tinh th phn t. B. Photpho trng c cu trc tinh th nguyn t*.C. Kim cng c cu trc tinh th phn t. D.Nc thuc loi tinh th nguyn t.Cu 23: Khi so snh NH3 vi NH4

+, pht biu khng ng l:A. Trong NH3 v NH4

+, nit u c s oxi ha -3.B. NH3c tnh baz, NH4

+ c tnh axit.C. Trong NH3 v NH4

+, nit u c cng ha tr 3. *

D. Phn t NH3 v ion NH4+

u cha lin kt cng ha tr.Cu 24: Cu hnh electron ca ion Cu2+ v Cr3+ ln lt l :A. [Ar]3d9 v [Ar]3d3 *. B. [Ar]3d74s2 v [Ar]3d14s2.C. [Ar]3d9 v [Ar]3d14s2. D. [Ar]3d74s2 v [Ar]3d3.

Cu 25Pht biu no sau y l sai?A. Tinh thnc , tinh thiot u thuc loi tinh th phn t.B. Trong tinh th NaCl, xung quanh mi ion u c 6 ion ngc du gn nht.C. Tt c cc tinh th phn tu kh nng chy v kh bay hi.*D. Trong tinh th nguyn t, cc nguyn t lin kt vi nhau bng lin kt cng ha tr.


5/59


5

Cu 26 Trong tnhin clo c hai ng v bn: 3717 Cl chim 24,23% tng s nguyn t, cn li l35

17 Cl . Thnhphn % theo khi lng ca 3717 Cl trong HClO4 l:

A. 8,92% * B. 8,43% C. 8,56% D. 8,79%Cu 27 Mc phn cc ca lin kt ho hc trong cc phn tc sp xp theo th t gim dn t tri sangphi l:A. HBr, HI, HCl B. HI, HBr, HCl C. HCl , HBr, HI * D. HI, HCl , HBr

Chuyn 2: Sin ly

1. (C-2008) Cho cc dung dch c cng nng : Na2CO3 (1), H2SO4 (2), HCl (3), KNO3 (4). Gi tr pH cacc dung dch c sp xp theo chiu tng dn t tri sang phi l:

A. (3), (2), (4), (1) B. (4), (1), (2), (3) C. (1), (2), (3), (4) D. (2), (3), (4)(1)2. (C-2008) Cho dy cc cht: KOH, Ca(NO3)2, SO3, NaHSO4, Na2SO3, K2SO4. S cht trong dy to thnhkt ta khi phn ng vi dung dch BaCl2 l

A. 4 B. 6 C. 3 D. 2

3. (H B-2008) Cho dy cc cht: KAl(SO4)2.12H2O, C2H5OH, C12H22O11(saccaroz), CH3COOH, Ca(OH)2CH3COONH4. S cht in li lA. 3 B. 4 C. 5 D. 2

4. (H B-2008) Trn 100ml dung dch c pH=1 gm HCl v HNO3 vi 100ml dung dch NaOH nng a(mol/l) thu c 200ml dung dch c pH=12. Gi tr ca a l (bit trong mi dung dch [H+][OH-]=10-14)

A. 0,15 B. 0,30 C. 0,03 D. 0,125. (H B-2008) Cho 0,1mol P2O5 vo dung dch cha 0,35 mol KOH. Dung dch thu c c cc cht:

A. K3PO4, K2HPO4 B. K2HPO4, KH2PO4 C. K3PO4, KOH D. H3PO4KH2PO46. (C-2007) Trong s cc dung dch: Na2CO3, KCl, CH3COONa, NH4Cl, NaHSO4, C6H5ONa. Nhng dungdch c pH>7 l

A. Na2CO3, C6H5ONa, CH3COONa B. Na2CO3, NH4Cl, KClC. NH4Cl, CH3COONa, NaHSO4 D. KCl, C6H5ONa, CH3COONa

7. (H B-2008) Trn ln V ml dung dch NaOH 0,01M vi V ml dung dch HCl 0,03M c 2V ml dung dchY. Dung dch Y c pH lA. 4 B. 3 C. 2 D. 1

8. (C-2008) Cho dy cc cht: NH4Cl, (NH4)2SO4, NaCl, MgCl2, FeCl2, AlCl3. S cht trong dy tc dng vlng d dung dch Ba(OH)2 to thnh kt ta l

a. 5 B. 4 C. 1 D. 39. (C-2008) Dung dch X cha cc ion: Fe3+, SO4

2, NH4+, Cl-. Chia dung dch X thnh 2 phn bng nhau:

- Phn 1 tc dng vi lng d dung dch NaOH, un nng thu c 0,672 lt kh (ktc) v 1,07 gam kt ta- Phn 2 tc dng vi lng d dung dch BaCl2, thu c 4,66 gam kt ta. Tng khi lng mui khan thuc khi c cn dung dch X l (qu trnh c cn chc nc bay hi)

A. 3,73 gam B. 7,04 gam C. 7,46 gam D. 3,52 gam10. (H A-2009) Nung 6,58 gam Cu(NO3)2 trong bnh kn khng cha khng kh, sau mt thi gian thu c4,96 gam cht rn v hn hp kh X. Hp thhon ton X vo nc c 300ml dung dch Y. Dung dch Yc pH bng

A. 1 B. 4 C. 3 D. 211. (H A-2009) Dy gm cc cht u tc dng vi dung dch HCl long l:

A. KNO3, CaCO3, Fe(OH)3 B. Mg(HCO3)2, HCOONa, CuOC. FeS, BaSO4, KOH D. AgNO3, (NH4)2CO3, CuS

12. (H A-2009) Dung dch X cha hn hp gm Na2CO3 1,5M v KHCO3 1M. Nh t t tng git cho nht 200ml dung dch HCl 1M vo 100ml dung dch X, sinh ra V lit kh (ktc). Gi tr ca V l

A. 3,36 B. 1,12 C. 4,48 D. 2,24


6/59


6

13. (H A-2009) C nm dung dch ng ring bit trong nm ng nghim: (NH4)2SO4, FeCl2, Cr(NO3)3K2CO3, Al(NO3)3. Cho dung dch Ba(OH)2n d vo nm dung dch trn. Sau khi phn ng kt thc, sngnghim c kt ta l

A. 3 B. 5 C. 2 D. 414. (H B-2009) Trn 100ml dung dch hn hp gm H2SO4 0,05M v HCl 0,1M vi 100ml dung dch hnhp gm NaOH 0,2M v Ba(OH)20,1M, thu c dung dch X. Dung dch X c pH l

A. 13,0 B. 1,2 C. 1,0 D. 12,815. (H B-2009) Cho cc phn ng ha hc sau:(1) (NH4)2SO4 + BaCl2 (2) CuSO4 + Ba(NO3)2(3) Na2SO4 + BaCl2 (4) H2SO4 + BaSO3(5) (NH4)2SO4 + Ba(OH)2 (6) Fe2(SO4)3 + Ba(NO3)2

Cc phn ng u c cng 1 phng trnh ion rt gn l:A. (1), (2), (3), (6) B. (1), (3), (5), (6) C. (2), (3), (4), (6) D. (3), (4), (5)

(6)16. (H B-2009) Cho dung dch X cha hn hp gm CH3COOH 0,1M v CH3COONa 0,1M. Bit 25

0C, Kca CH3COOH l 1,75.10

-5 v b qua s phn li ca nc. Gi tr pH ca dung dch X 250C lA. 1,00 B. 4,24 C. 2,88 D. 4,76

17. (H A-2010) Dung dch X cha: 0,07 mol Na+; 0,02 mol SO42 v x mol OH-. Dung dch Y c cha ClO4

-

NO3- v y mol H+; tng s mol ClO4

- v NO3- l 0,04. Trn X v Y c 100ml dung dch Z. Dung dch Z c

pH (b qua sin li ca nc) lA. 2 B. 12 C. 13 D. 118. (H A-2010) Nh t t tng git n ht 30ml dung dch HCl 1M vo 100ml dung dch cha Na2CO3 0,2Mv NaHCO3 0,2M, sau phn ng thu c s mol CO2 l

A. 0,015 B. 0,020 C. 0,010 D. 0,03019. (H A-2010) Cho dung dch X gm: 0,007 mol Na+; 0,003 mol Ca2+; 0,006 mol Cl-; 0,006 mol HCO3

- v0,001 mol NO3

-. loi b ht Ca2+ trong X cn mt lng va dung dch cha a(g) Ca(OH)2. Gi tr ca al

A. 0,444 B. 0,222 C. 0,180 D. 0,12020. (C-2010) Dy cc ion cng tn ti trong mt dung dch l

A. K+, Ba2+, OH-, Cl- B. Na+, K+, OH-, HCO3-

C. Ca2+, Cl-, Na+, CO32- D. Al3+, PO4

3-, Cl-, Ba2+21. (C-2010) Dung dch no sau y c pH>7?

A. Dung dch CH3COONa B. Dung dch Al2(SO4)3C. Dung dch NH4Cl D. Dung dch NaCl

22. (H B-2007) Trong cc dung dch: HNO3, NaCl, Na2SO4, Ca(OH)2, KHSO4, Mg(NO3)2. Dy gm cc chtu tc dng c vi dung dch Ba(HCO3)2 l

A. HNO3, Ca(OH)2, KHSO4, Mg(NO3)2 B. HNO3, Ca(OH)2, KHSO4, Na2SO4C. NaCl, Na2SO4, Ca(OH)2 D. HNO3, NaCl, Na2SO4

23. (H B-2007) Cho bn phn ng:(1) Fe + 2HCl FeCl2 + H2(2) 2NaOH + (NH4)2SO4 Na2SO4 + 2NH3 + 2H2O(3) BaCl2 + Na2CO3 BaCO3 + 2NaCl(4) 2NH3 + 2H2O + FeSO4 Fe(OH)2 + (NH4)2SO4

S phn ng thuc loi phn ng axit-baz l

A. (1), (2) B. (2), (3) C. (2), (4) D. (3), (4)24. (H A-2007) Dung dch HCl v dung dch CH3COOH c cng nng mol/l, pH ca hai dung dch tngng l x v y. Quan h gia x v y l (gi thit, c 100 phn t CH3COOH th c 1 phn tin li)

A. y = 100x B. y = x-2 C. y = 2x D. y = x+225. (H A-2007) Cho dy cc cht: Ca(HCO3)2, NH4Cl, (NH4)2CO3, ZnSO4, Al(OH)3, Zn(OH)2. S cht trongdy c tnh cht lng tnh l

A. 5 B. 4 C. 3 D. 2Chuyn 3: kim loi, phi kim


7/59


7

Dng 1. XC NH TN NGUYN T KIM LOI

Bi 1. Ho tan hon ton 2 gam kim loi thuc nhm IIA vo dung dch HCl v sau c cn dung dch ngita thu c 5,55 gam mui khan. Kim loi nhm IIA l:

A. Be. B. Ba. C. Ca. D. Mg.Bi 2. Nhit phn hon ton 3,5 gam mt mui cacbonat kim loi ho tr2 thu c 1,96 gam cht rn. Muicacbonat ca kim loi dng l:

A. FeCO3. B. BaCO3. C. MgCO3. D. CaCO3.Bi 3. Ho tan hon ton 0,575 gam mt kim loi km vo nc. trung ho dung dch thu c cn 25 gamdung dch HCl 3,65%. Kim loi ho tan l:

A. Li. B. K. C. Na. D. Rb.Bi 4. Lng kh clo sinh ra khi cho dung dch HCl c d tc dng vi 6,96 gam MnO2 oxi ho kim loi M(thuc nhm IIA), to ra 7,6 gam mui khan. Kim loi M l:

A. Ba. B. Mg. C. Ca. D. Be.Bi 5. Ho tan 2,52 gam mt kim loi bng dung dch H2SO4long d, c cn dung dch thu c 6,84 gammui khan. Kim loi l:A. Mg. B. Al. C. Zn. D. Fe.

Bi 6. Ho tan ht m gam kim loi M bng dung dch H2SO4 long, ri c cn dung dch sau phn ng thuc 5m gam mui khan. Kim loi M l:A. Al. B. Mg. C. Zn. D. Fe.

Bi 7: Ngm mt l kim loi c khi lng 50 gam trong dung dch HCl. Sau khi thu c 336 ml kh H2(ktc)th khi lng l kim loi gim 1,68%. Kim loi lA. Zn. B. Fe. C. Ni. D. Al.Bi 8. Ho tan 1,3 gam mt kim loi M trong 100 ml dung dch H2SO4 0,3M. trung ho lng axit d cn200 ml dung dch NaOH 0,1M. Xc nh kim loi M?

A. Al. B. Fe. C. Zn. D. Mg.Bi 9. Khi in phn mui clorua kim loi nng chy, ngi ta thu c 0,896 lt kh (ktc) anot v 3,12 gamkim loi catot. Cng thc mui clorua in phn l

A. NaCl. B. CaCl2. C. KCl. D. MgCl2.Bi 10. Cho 19,2 gam kim loi (M) tan hon ton trong dung dch HNO3long th thu c 4,48 lt kh NO

(ktc, sn phm kh duy nht). Kim loi (M) l:A. Cu. B. Zn. C. Fe. D. Mg.Bi 11: t mt kim loi trong bnh cha kh Clo thu c 32,5 gam mui, ng thi th tch kh Clo trongbnh gim 6,72 lt (ktc). Kim loi em t l:

A. Mg B. Al C. Fe D. CuBi 12: Ha tan hon ton 3,2 gam mt kim loi R ha tr II bng dung dch H2SO4c nng thu c 1,12 ltkh SO2(ktc). Xc nh tn ca R.Bi 13: Ha tan 1,35 gam mt kim loi R bng dung dch HNO3 long d thu c 2,24 lt hn hp kh X gmNO v NO2. Xc nh tn ca R, bit t khi ca X so vi H2 bng 21.Bi 14 : C 15,06 gam mt hn hp A gm Fe v mt kim loi R (ha tkhng i) c chia thnh 2 phnbng nhau.-Phn 1: Ha tan ht vi dung dch HCl thu c 3,696 lt kh ktc.- Phn 2: Ha tan ht vi dung dch HNO3long thu c 3,36 lt (ktc) mt kh khng mu ha nu ngoi

khng kh duy nht. Tm R.Bi 15: Kh 3,48 gam mt oxit ca kim loi R cn 1,344 lt H2(ktc). Ton blng kim loi to thnh ccho tan ht trong dung dch HCl thu 1,008 lt H2(ktc). Tm kim loi R v oxit ca n.Bi 16: Cho 10,5 gam hn hp gm bt Al v mt kim loi kim R vo H2O, sau phn ng thu c dung dchA v 5,6 lt kh (ktc). Cho tt t dung dch HCl vo dung dch A thu c lng kt ta l ln nht. Lc lykt ta, sy kh, cn c 7,8 gam. Xc nh R.Bi 17: Ha tan 4,95 gam hn hp A gm 2 kim loi Fe v R (c ha trkhng i) trong dung dch HCl dthu c 4,032 lt kh H2 (ktc). Mt khc nu cng ha tan mt lng hn hp kim loi trn bng dung dchHNO3d th c 1,344 lt hn hp kh B gm NO v N2O c t khi hi so vi H2 bng 20,25. Xc nh R.


8/59


8

Bi 18: Ha tan hon ton 19,2 gam kim loi R trong dung dch HNO3 d thu c 8,96 lt (ktc) hn hp khgm NO2 v NO c t l thtch 3:1. Xc nh R.Bi 19: Hn hp A cha Fe v kim loi R c ha trkhng i, t l s mol ca R v Fe trong hn hp l 1:3.Cho 19,2 gam hn hp A tan ht trong dung dch HCl thu c 8,96 lt kh H2. Cho 19,2 gam hn hp A tcdng ht vi kh Clo th cn dng 12,32 lt kh Clo. Xc nh R.Bi 20: Ha tan kim loi M vo HNO3thu c dung dch A(khng c kh thot ra). Cho NaOH d vo dung

dch A thu c 2,24 lt kh (ktc) v 23,2g kt ta. Xc nh M.A. Fe B. Mg C. Al D. CaBi 21 : Cho 17 gam hn hp gm 2 kim loi kim ng k nhau trong nhm IA tc dng ht vi H2O thu c6.72 lt kh H2(ktc) v dung dch Y.a- Xc nh tn ca hai kim loi trn.b- Tnh th tch dung dich HCl 2M cn dng trung ha ht dung dch YBi 22: Cho 7,2 gam mui cacbonat ca hai kim loi k tip nhau trong nhm IIA ha tan ht trong dung dchH2SO4 long thu c kh B. Cho ton b kh B hp th vo 450 ml dung dch Ba(OH)2 0,2M thu c 15,76gam kt ta. Tm cng thc ca hai mui cacbonat ban u.Bi 23: Cho 7,505 gam hp kim gm hai kim loi tc dng vi dung dch H2SO4long, d thu c 2,24 lt khH2, ng thi cn 1,005 gam kim loi khng tan. Ha tan lmg kim loi cn li ny trong dung dch H2SO4c, d th thu c 112ml SO2. Cc kh o ktc. Xc nh tn ca hai kim loi trong hp kim.Bi 24: Ha Tan hon ton 3,6 gam hn hp gam mui cacbonat ca hai kim loi k tip nhau trong phn

nhm chnh nhm II trong dung dch HCl thu c kh B. Cho ton b kh B tc dng ht vi 3 lt dung dchCa(OH)20,015M thu c 4 gam kt ta. Hai kim loi l:A. Mg,Ca B. Ca,Ba C. Be,Mg D. A v C u ng.

Bi 25: Ha tan hon ton 7,6 gam hn hp hai kim loi kim th lin tip nhau tc dng vi dung dch HCl dthu c 5,6 lt kh (ktc). Hai kim loi ny l:

A. Be,Mg B. Mg,Ca C. Ca,Sr D. Sr,BaBi 26. Cho 9,1 gam hn hp hai mui cacbonat trung ho ca 2 kim loi kim 2 chu k lin tip tan honton trong dung dch HCl d thu c 2,24 lt CO2(ktc). Hai kim loi l:

A. K v Cs. B. Na v K. C. Li v Na. D. Rb v Cs.Bi 27: Cho 1,67 gam hn hp gm hai kim loi 2 chu k lin tip thuc nhm IIA tc dng ht vi dung dchHCl (d), thot ra 0,672 lt kh H2 (ktc). Hai kim loi l (Mg= 24, Ca= 40, Sr= 87, Ba = 137)A. Be v Mg. B. Mg v Ca. C. Sr v Ba. D. Ca v Sr.Bi 28: X l kim loi thuc phn nhm chnh nhm II (hay nhm IIA). Cho 1,7 gam hn hp gm kim loi X vZn tc dng vi lng d dung dch HCl, sinh ra 0,672 lt kh H2 (ktc). Mt khc, khi cho 1,9 gam X tcdng vi lng d dung dch H2SO4 long, th thtch kh hiro sinh ra cha n 1,12 lt (ktc). Kim loi XlA. Ba. B. Ca. C. Sr. D. Mg.

Dng 2 KIM LOI TC DNG VI DUNG DCH AXIT.

Bi 1. Cho 10 gam hn hp cc kim loi Mg v Cu tc dng ht vi dung dch HCl long d thu c 3,733 litH2(kc). Thnh phn % ca Mg trong hn hp l:

A. 50%. B. 35%. C. 20%. D. 40%.Bi 2. Mt hn hp gm 13 gam km v 5,6 gam st tc dng vi dung dch axit sunfuric long d. Th tch khhidro (ktc) c gii phng sau phn ng l.

A. 2,24 lit. B. 4,48 lit. C. 6,72 lit. D. 67,2 lit.Bi 3. Cho 4,05 gam Al tan ht trong dung dch HNO3 thu V lt N2O (kc) duy nht. Gi tr V lA. 2,52 lt. B. 3,36 lt. C. 4,48 lt. D. 1,26 lt.

Bi 4: Hn hp X gm Fe v Cu, trong Cu chim 43,24% khi lng. Cho 14,8 gam X tc dng ht vidung dch HCl thy c V lt kh (ktc) bay ra. Gi tr ca V lA. 1,12 lt. B. 3,36 lt. C. 2,24 lt. D. 4,48 lt.Bi 5: Ho tan hon ton 1,5 gam hn hp bt Al v Mg vo dung dch HCl thu c 1,68 lt H2(kc). Phn %khi lng ca Al trong hn hp lA. 60%. B. 40%. C. 30%. D. 80%.


9/59


9

Bi 6: Ha tan 6,5 gam Zn trong dung dch axit HCl d, sau phn ng c cn dung dch th s gam mui khanthu c l (Cho H = 1, Zn = 65, Cl = 35,5)A. 20,7 gam. B. 13,6 gam. C. 14,96 gam. D. 27,2 gam.Bi 7. Ho tan hon ton 7,8 gam hn hp gm Mg, Al trong dung dch HCl d thy to ra 8,96 lt kh H2(kc). C cn dung dch sau phn ng thu c m gam mui khan. Gi tr ca m l

A. 18,1 gam. B. 36,2 gam. C. 54,3 gam. D. 63,2 gam.

Bi 8: Cho 20 gam hn hp bt Mg v Fe tc dng ht vi dung dch HCl thy c 1 gam kh H2bay ra. Lngmui clorua to ra trong dung dch l bao nhiu gam ?A. 40,5g. B. 45,5g. C. 55,5g. D. 60,5g.Bi 9. Cho 11,9 gam hn hp gm Zn, Al tan hon ton trong dung dch H2SO4long d thy c 8,96 lit kh(kc) thot ra. Khi lng hn hp mui sunfat khan thu c l:

A. 44,9 gam. B. 74,1 gam. C. 50,3 gam. D. 24,7 gam.Bi 10. Cho 1,86 gam hn hp Al v Mg tc dng vi dung dch HNO3long d th thu c 560 ml lt khN2O (ktc, sn phm kh duy nht) bay ra. Khi lng mui nitrat to ra trong dung dch l:

A. 40,5 gam. B. 14,62 gam. C. 24,16 gam. D. 14,26 gam.Bi 11: Ho tan 6,4 gam Cu bng axit H2SO4

c, nng (d), sinh ra V lt kh SO2

(sn phm kh duy nht,

ktc). Gi tr ca V lA. 4,48. B. 6,72. C. 3,36. D. 2,24.Bi 12: Ho tan 5,6 gam Fe bng dung dch HNO3

long (d), sinh ra V lt kh NO (sn phm kh duy nht,

ktc). Gi tr ca V lA. 6,72. B. 4,48. C. 2,24. D. 3,36.Bi 13: Cho 10 gam hn hp gm Fe v Cu tc dng vi dung dch H2SO4 long (d). Sau phn ng thu c2,24 lt kh hiro (ktc), dung dch X v m gam cht rn khng tan. Gi tr ca m l (Cho H = 1, Fe = 56, Cu =64)A. 6,4 gam. B. 3,4 gam. C. 5,6 gam. D. 4,4 gam.Bi 14: Cho m gam hn hp X gm Al, Cu vo dung dch HCl (d), sau khi kt thc phn ng sinh ra 3,36 ltkh (ktc). Nu cho m gam hn hp X trn vo mt lng d axit nitric (c, ngui), sau khi kt thc phnng sinh ra 6,72 lt kh NO2 (sn phm kh duy nht, ktc). Gi tr ca m lA. 15,6. B. 10,5. C. 11,5. D. 12,3.Bi 15. Cho m gam Fe vo dung dch HNO3 ly d ta thu c 8,96 lit(kc) hn hp kh X gm 2 kh NO vNO2 c t khi hi hn hp X so vi oxi bng 1,3125. Gi tr ca m l

A. 0,56 gam. B. 1,12 gam. C. 11,2 gam. D. 5,6 gam.Bi 16Cho 60 gam hn hp Cu v CuO tan ht trong dung dch HNO3long d thu c 13,44 lit kh NO (kc,sn phm kh duy nht). Phn % v khi lng ca Cu trong hn hp l:

A. 69%. B. 96%. C. 44% D. 56%.Bi 17. Cho 2,8 gam hn hp bt kim loi bc v ng tc dng vi dung dch HNO3c, d th thu c 0,896lt kh NO2 duy nht (ktc). Thnh phn phn trm ca bc v ng trong hn hp ln lt l:

A. 73% ; 27%. B. 77,14% ; 22,86% C. 50%; 50%. D. 44% ; 56%Bi 18: Ho tan hon ton 1,23 gam hn hp X gm Cu v Al vo dung dch HNO3c, nng thu c 1,344lt kh NO2 (sn phm kh duy nht, ktc). Phn trm v khi lng ca Cu trong hn hp X l

A. 21,95%. B. 78,05%. C. 68,05%. D. 29,15%.Bi 19. Cho a gam bt Al tc dng va vi dung dch HNO3long thu c dung dch A ch cha mt muiduy nht v 0,1792 lt (ktc) hn hp kh NO, N2 c t khi hi so H2 l 14,25. Tnh a ?

A. 0,459 gam. B. 0,594 gam. C. 5,94 gam. D. 0,954 gam.

Bi 20: Cho hn hp A gm Cu v Mg vo dung dch HCl d thu c 5,6 lt kh (kc) khng mu v mt chtrn khng tan B. Dng dung dch H2SO4c, nng ho tan cht rn B thu c 2,24 lt kh SO2(kc). Khilng hn hp A ban u l:A. 6,4 gam. B. 12,4 gam. C. 6,0 gam. D. 8,0 gam.Bi 21: Cho a gam hn hp Mg v Al vo 250 ml dung dch X cha 2 axit : HCl 1M v H2SO40,5M c dungdch B v 4,368 lt H2(ktc) th trong dung dch B s:

A. D axit B. Thiu axit C. Dung dch mui D. Tt cu saiBi 22: Cho 2,06 gam hn hp gm Fe, Al, Cu tc dng vi dung dch HNO3long d thu c 0,896 lt NOduy nht ktc. Khi lng mui NO3

- sinh ra l :A. 9,5 gam B. 7,44 gam C. 7,02 gam D. 4,54 gam


10/59


10

Bi 23: Cho 2,16 gam Mg tc dng vi dung dch HNO3 (d). Sau khi phn ng xy ra hon ton thu c0,896 lt kh NO (ktc) v dung dch X. Khi lng mui khan thu c khi lm bay hi

dung dch X lA. 8,88 gam. B. 13,92 gam. C. 6,52 gam. D. 13,32 gam.

Bi 24: Cho m gam hn hp X gm Al, Cu vo dung dch HCl (d), sau khi kt thc phn ng sinhra 3,36 lt kh (ktc). Nu cho m gam hn hp X trn vo mt lng d axit nitric (c, ngui), sau khi

kt thc phn ng sinh ra 6,72 lt kh NO2 (sn phm kh duy nht, ktc). Gi tr ca m lA. 11,5. B. 10,5. C. 12,3. D. 15,6.Bi 25: Th tch dung dch HNO3 1M (long) t nht cn dng ho tan hon ton mt hn hp gm 0,15 moFe v 0,15 mol Cu l (bit phn ng to cht kh duy nht l NO)

A. 1,0 lt. B. 0,6 lt. C. 0,8 lt. D. 1,2 lt.Bi 26: Chia hn hp 2 kim loi c ho trkhng i lm 2 phn bng nhau. Phn 1 tan ht trong dung dch HCto ra 1,792 lt H2(ktc). Phn 2, nung trong oxi thu c 2,84 gam hn hp oxit. Khi lng hn hp 2 kimloi ban u l:

A. 2,4 gam B. 3,12 gam C. 2,2 gam D. 1,8 gamBi 27: Cho m gam Cu tc dng ht vi dung dch HNO3thu c 1,12 lt (ktc) hn hp kh NO v NO2 c tkhi so vi H2 l 16,6 . Gi tr ca m l:

A. 3,9 gam B. 4,16 gam C. 2,38 gam D. 2,08 gamBi 28: Cho hn hp X gm Mg v Fe vo dung dch axit H2SO4 c, nng n khi cc phn ng xy ra hon

ton, thu c dung dch Y v mt phn Fe khng tan. Cht tan c trong dung dch Y lA. MgSO4 v FeSO4. B. MgSO4.C. MgSO4 v Fe2(SO4)3. D. MgSO4, Fe2(SO4)3 v FeSO4

Bi 29: Cho 6,72 gam Fe vo dung dch cha 0,3 mol H2SO4 c, nng (gi thit SO2 l sn phm kh duynht). Sau khi phn ng xy ra hon ton, thu c (cho Fe = 56)

A. 0,03 mol Fe2(SO4)3 v 0,06 mol FeSO4. B. 0,05 mol Fe2(SO4)3v 0,02 mol Fe d.C. 0,02 mol Fe2(SO4)3 v 0,08 mol FeSO4. D. 0,12 mol FeSO4.

Bi 30: Ha tan hon ton 12 gam hn hp Fe, Cu (t l mol 1:1) bng axit HNO3, thu c V lt (ktc) hnhp kh X (gm NO v NO2) v dung dch Y (ch cha hai mui v axit d). T khi ca X i vi H2 bng19. Gi tr ca V l:A. 2,24. B. 4,48. C. 5,60. D. 3,36.Bi 31: Cho m gam hn hp Mg, Al vo 250 ml dung dch X cha hn hp axit HCl 1M v axit H2SO40,5M, thu c 5,32 lt H2 (ktc) v dung dch Y (coi th tch dung dch khng i). Dung dch Y c pH lA. 1. B. 6. C. 7. D. 2.Bi 32: Cho hn hp Fe, Cu phn ng vi dung dch HNO3 long. Sau khi phn ng hon ton, thu cdung dch ch cha mt cht tan v kim loi d. Cht tan lA. Cu(NO3)2. B. HNO3. C. Fe(NO3)2. D. Fe(NO3)3.Bi 33: Thc hin hai th nghim:1) Cho 3,84 gam Cu phn ng vi 80 ml dung dch HNO3 1M thot ra V1 lt NO.2) Cho 3,84 gam Cu phn ng vi 80 ml dung dch cha HNO3 1M v H2SO4 0,5 M thot ra V2 lt NO.Bit NO l sn phm kh duy nht, cc th tch khocng iu kin. Quan h gia V1 v V2 lA. V2 = V1. B. V2 = 2V1. C. V2 = 2,5V1. D. V2 = 1,5V1.Bi 34: Ha tan hon ton 3,22 gam hn hp X gm Fe, Mg v Zn bng mt lng va dung dchH2SO4 long, thu c 1,344 lt hiro (ktc) v dung dch cha m gam mui. Gi tr ca m l (Cho H = 1O = 16; Mg = 24; S = 32; Fe = 56; Zn = 65)

A. 9,52. B. 10,27. C. 8,98. D. 7,25Bi 35: Ho tan hon ton hn hp X gm Fe v Mg bng mt lng va dung dch HCl 20%, thu cdung dch Y. Nng ca FeCl2 trong dung dch Y l 15,76%. Nng phn trm ca MgCl2 trong dung dchY l (Cho H = 1; Mg = 24; Cl = 35,5; Fe = 56)A. 24,24%. B. 11,79%. C. 28,21%. D. 15,76%.Bi 36: Cho 3,6 gam Mg tc dng ht vi dung dch HNO3 (d), sinh ra 2,24 lt kh X (sn phm kh duy nhtktc). Kh X lA. N2O. B. NO2. C. N2. D. NO.Bi 37: Ho tan ht 7,74 gam hn hp bt Mg, Al bng 500 ml dung dch hn hp HCl 1M v H2SO4 0,28Mthu c dung dch X v 8,736 lt kh H2 (ktc). C cn dung dch X thu c lng mui khan l


11/59


11

A. 38,93 gam. B. 103,85 gam. C. 25,95 gam. D. 77,86 gam.Bi 38 Cho 3,2 gam bt Cu tc dng vi 100 ml dung dch hn hp gm HNO3 0,8M v H2SO4 0,2M. Sau khicc phn ng xy ra hon ton, sinh ra V lt kh NO (sn phm kh duy nht, ktc). Gi tr ca V lA. 0,746. B. 0,448. C. 1,792. D. 0,672.Bi 39: Cho 2,16 gam Mg tc dng vi dung dch HNO3 (d). Sau khi phn ng xy ra hon ton thu c0,896 lt kh NO (ktc) v dung dch X. Khi lng mui khan thu c khi lm bay hi dung dch X l

A. 8,88 gam. B. 13,92 gam. C. 6,52 gam. D. 13,32 gam.Bi 40: Cho m gam hn hp X gm Al, Cu vo dung dch HCl (d), sau khi kt thc phn ng sinh ra 3,36 ltkh (ktc). Nu cho m gam hn hp X trn vo mt lng d axit nitric (c, ngui), sau khi kt thc phnng sinh ra 6,72 lt kh NO2 (sn phm kh duy nht, ktc). Gi tr ca m lA. 11,5. B. 10,5. C. 12,3. D. 15,6.Bi 41: Cho 2,7 g hh Mg, Al, Cu tan vo dd HNO3 d to ra 0,02 mol NO, 0,08 mol NO2.Khi lng mui thu c l:A. 6,42 g B. 8,68 g C. 11,38 g D. 7,66

Bi 42: Ha tan ht cng mt Fe trong dung dch HNO3 d thy sinh ra hn hp kh cha 0,03 mol NO2 v0,02 mol NO. Khi lng Fe b ha tan bng bao nhiu gam?A. 0,56 gam B. 1,12 gam C. 1,68 gam D. 2,24 gamBI TP IN PHNBi 1. Khi cho dng in mt chiu I=2A qua dung dch CuCl2 trong 10 pht. Khi lng ng thot ra catod

l A. 40 gam. B. 0,4 gam. C. 0,2 gam. D. 4 gam.Bi 2. in phn n ht 0,1 mol Cu(NO3)2 trong dung dch vi in cc tr, th sau in phn khi lng dungdch gim bao nhiu gam?A. 1,6 gam. B. 6,4 gam. C. 8,0 gam. D. 18,8 gam.Bi 3. in phn dng in cc tr dung dch mui sunfat kim loi ho tr 2 vi cng dng in 3A. Sau1930 giy thy khi lng catot tng 1,92 gam. Mui sunfat in phn l

A. CuSO4. B. NiSO4. C. MgSO4. D. ZnSO4.Bi 4. in phn hon ton 1 lt dung dch AgNO3 vi 2 in cc tr thu c mt dung dch c pH= 2. Xemth tch dung dch thay i khng ng kth lng Ag bm catod l:

A. 0,54 gam. B. 0,108 gam. C. 1,08 gam. D. 0,216 gam.Bi 5: in phn 200 ml dung dch mui CuSO4 trong thi gian, thy khi lng dung dch gim 8 gam. Dungdch sau in phn cho tc dng vi dd H2S d thu c 9,6g kt ta en. Nng mol ca dung dch CuSO4ban u lA. 1M. B.0,5M. C. 2M. D. 1,125M.Bi 6: in phn dung dch AgNO3(in cc tr) trong thi gian 15 pht, thu c 0,432 gam Ag catot. Sau lm kt ta ht ion Ag+ cn li trong dung dch sau in phn cn dng 25 ml dung dch NaCl 0,4M.Cng dng in v khi lng AgNO3ban u l (Ag=108)A. 0,429 A v 2,38 gam. B. 0,492 A v 3,28 gam.C. 0,429 A v 3,82 gam. D. 0,249 A v 2,38 gam.Bi 7: in phn 200 ml dung dch AgNO30,4M (in cc tr) trong thi gian 4 gi, cng dng in l0,402A. Nng mol/l cc cht c trong dung dch sau in phn l

A. AgNO3 0,15M v HNO3 0,3M. B. AgNO3 0,1M v HNO3 0,3M.C. AgNO3 0,1M D. HNO3 0,3M

Bi 8: Sau mt thi gian in phn 200 ml dung dch CuCl2thu c 1,12 lt kh X (ktc). Ngm inh st vo

dung dch sau in phn, khi phn ng xy ra hon ton thy khi lng inh st tng thm 1,2 gam. Nng mol ca CuCl2ban u lA. 1M. B. 1,5M. C. 1,2M. D. 2M.Bi 9: in phn bng in cc tr dung dch mui sunfat ca kim loi ho tr II vi dng in c cng 6ASau 29 pht in phn thy khi lng catot tng ln 3,45 gam. Kim loi l:A. Zn. B. Cu. C. Ni. D. Sn.Bi 10: in phn 400 ml dung dch CuSO4 0,2M vi cng dng in 10A trong 1 thi gian thu c 0,224lt kh (kc) anot. Bit in cc dng l in cc tr v hiu sut in phn l 100%. Khi lng catot tnglA. 1,28 gam. B. 0,32 gam. C. 0,64 gam. D. 3,2 gam.


12/59


12

Bi 11: Khi in phn NaCl nng chy (in cc tr), ti catt xy raA. s kh ion Cl-. B. s oxi ho ion Cl-. C. s oxi ho ion Na+. D. s kh ion Na+.Bi 12: in phn c mng ngn 500 ml dung dch cha hn hp gm CuCl20,1M v NaCl 0,5M (in cc trhiu sut in phn 100%) vi cng dng in 5A trong 3860 giy. Dung dch thu c sau in phn ckh nng ho tan m gam Al. Gi tr ln nht ca m l

A. 4,05. B. 2,70. C. 1,35. D. 5,40

Bi 13: in phn nng chy Al2O3vi anot than ch (hiu sut in phn 100%) thu c m kg Al catot v67,2 m3 ( ktc) hn hp kh X c t khi so vi hiro bng 16. Ly 2,24 lt ( ktc) hn hp kh X sc vodung dch nc vi trong (d) thu c 2 gam kt ta. Gi tr ca m l

A. 108,0. B. 75,6. C. 54,0. D. 67,5.Bi 14: in phn 100ml dung dch cha ng thi HCl0,1M v NaCl 0,2M vi in cc tr v mng ngn xpti khi anot tot ra 0,224 lt kh (KTC) th ngng in phn. Coi th tch dung dch khng thay i, dungdch sau in phn c pH l:

A. 6 B. 7 C. 12 D. 13Bi 15: Dung dch X cha HCl, CuSO4 v Fe2(SO4)3. Ly 400ml dung dch X em in phn (in cc tr) vcng dng in I = 7,72 A n khi Catot c 0,08 mol Cu th dng li. Khi anot c 0,1 mol chkh bay ra. Thi gian in phn v nng mol/l ca Fe2+ trong dung dch sau phn ng l

A. 2300s v o,1M B. 2500s v 0,1M C. 2300s v 0,15M D. 2500s v 0,15MBi 16: in phn (vi in cc tr) 200 ml dung dch CuSO4 nng x mol/l, sau mt thi gian thu c dung

dch Y vn cn mu xanh, c khi lng gim 8g so vi dung dch ban u. Cho 16,8g bt Fe vo Y, sau khicc phn ng xy ra hon ton, thu c 12,4g kim loi. Gi tr ca x l A. 2,25 B. 1,5 C. 1,25 D. 3,25

Bi 17: Tin hnh in phn dung dch CuSO4 mt hti gian, khi ngng in phn Catt xut hin 3,2 gam kimloi Cu. Tnh thtch kh KTC thu c Anot.Bi 18: Tin hnh in phn 200ml dung dch CuSO4 vi dng in c I = 1,93A cho n khi Catt xut hinkh th thi gian cn l 250 giy. Tnh nng mol/l ca dung dch CuSO4 v thtch kh thu c Ant.Bi 19: Tin hnh in phn dung dch CuCl2 bng in graphit vi thi gian l 16 pht thy Catt xut hin0,554 gam kim loi. Tnh cng dng in dng tin hnh in phn.Bi 20: in phn dung dch CuCl2 vi in cc tr, sau mt thi gian thu c 0,32 gam Cu Catt v lngkh X Ant. Hp thhon ton lng kh X trn vo 200ml dung dch NaOH (nhit thng). Sau phnng nng dung dch NaOH trong dung dch cn li 0,05M (gi thit th tch dung dch khng thay i). Tnhnng mol/l ca dung dch NaOH ban u.Bi 21: in phn 0,8 lt dung dch hn hp HCl, Cu(NO3)2 vi in cc tr, cng dng in I = 2,5A, thigian t giy c mt kh duy nht ant c thtch 3,136 lt (KTC). Dung dch sau khi in phn phn ngva vi 550ml dung dch NaOH 0,8M c 1,96 gam kt ta. Tnh thi gian in phn v nng mol/l cacc cht trong dung dch ban u.Bi 22: C hai bnh in phn mc ni tip: Bnh 1 cha dug dch AgNO3, bnh 2 ng dung dch RSO4. Tinhnh in phn mt thi gian ri ngng th thy Catt bnh 1 tng 5 gam cn Catt bnh 2 tng 1,48 gam. T mR.Bi 23: C hai bnh in phn mc ni tip: Bnh 1 cha 10ml dung dch CuSO4 0,1M; bnh 2 cha 100ml dungdch NaOH 0,1M. Tin hnh in phn c mng ngn xp cho n khi bnh 2 to ra dung dch c pH = 13 thngng in phn. Gi s th tch dung dch 2 bnh khng thay i. Tnh nng mol/l ca Cu2+ trong dungdch sau in phn.Bi 23: in hn dung dch cha a mol CuSO4v b mol NaOH (in cc tr, mng ngn xp). Xc nh iu

kin v mi lin quan ca a v b dung dnh sau in phn lm Phenolphtalein chuyn sang mu hng.Bi 24: Cho dng in mt chiu, cng khng i, qua hai bnh in phn mc ni tip: Bnh 1 cha 100mdung dch CuSO4 0,01M; bnh 2 cha 100ml dung dch AgNO3 0,01M. Tin hnh in phn trong thi gian 500giy th bnh 2 bt u xut hin khCatot. Tnh thtch kh (KTC) xut hin Catt bnh 1.Bi 25: Tin hnh in phn c mng ngn xp, hai in ctr 500ml dung dch hn hp HCl 0,02M v NaCl0,2M. Sau khi anot thot ra 0,448 lt kh (KTC) th ngng in phn. Gi s th tch dung dch khng thayi. Tnh pH ca dung dch thu c sau in phn.


13/59


13

Bi 26: Tin hnh in phn 150 ml dung dch CuSO4 1M vi hai in cc tr. Sau mt thi gian, khi ngngin phn thy khi lng dung dch gim 8 giam. Tnh ngng mol/l ca cc cht trong dung dch thu csau phn ng.Bi 27: in phn nng chy a gam mui G to bi kim loi R v halogen X, ta thu c 0,96 gam kim loi R Catot v 0,04 mol kh X Anot. Mt khc ha tan hon ton a gam mui G vo nc, sau cho tc dng vidung dch AgNO3d thu c 11,48 gam kt ta. Xc nh X.

Bi 28: in phn vi in cc tr dung dch AgNO3 trong thi gian 14 pht 15 giy, cng dng in 0,8Aa. Tnh khi lng Ag iu chc.b. Tnh thtch kh (KTC) thu c Catt.Bi 29: in phn dung dch CuSO4 vi in cc ng (ng knh 1mm, nhng su trong dung dch 4cm)cng dng in 1,2A. Tnh thi gian ton b phn anot nhng vo dung dch bi ha tan ht.Bi 30: in pn 200ml dung dch hn hp dung dch gm CuSO4 0,1M v MgSO40,05M cho khi bt uxut hin kh th ngng in phn. Tnh khi lng kim loi bm vo Catot ca bnh in phn.

BI TON KIM LOI TC DNG VIDUNG DCH MUI

Bi 1. Ngm mt inh st sch trong 200 ml dung dch CuSO4 sau khi phn ng kt thc, ly inh st ra khidung dch ra nh lm kh nhn thy khi lng inh st tng thm 0,8 gam. Nng mol/lt ca dung dch

CuSO4 dng l:A. 0,25M. B. 0,4M. C. 0,3M. D. 0,5M.Bi 2. Ngm mt l km vo dung dch c ho tan 8,32 gam CdSO4. Phn ng xong ly l km ra khi dungdch, ra nh, lm kh th thy khi lng l km tng thm 2,35% so vi khi lng l km trc phn ng.Khi lng l km trc phn ng l:

A. 80gam B. 60gam C. 20gam D. 40gamBi 3. Nhng mt inh st c khi lng 8 gam vo 500ml dung dch CuSO4 2M. Sau mt thi gian ly inh stra cn li thy nng 8,8 gam. Nng mol/l ca CuSO4 trong dung dch sau phn ng l:

A. 0,27M B. 1,36M C. 1,8M D. 2,3MBi 4: Ngm l km trong dung dch cha 0,1 mol CuSO4. Phn ng xong thy khi lng l km:A. tng 0,1 gam. B. tng 0,01 gam. C. gim 0,1 gam. D. khng thay i.Bi 5: Ho tan hon ton 28 gam bt Fe vo dung dch AgNO3d th khi lng cht rn thu c lA. 108 gam. B. 162 gam. C. 216 gam. D. 154 gam.Bi 6: Nhng 1 thanh nhm nng 50 gam vo 400ml dung dch CuSO4 0,5M. Sau mt thi gian ly thanh nhmra cn nng 51,38 gam. Hi khi lng Cu thot ra l bao nhiu?

A. 0,64gam. B. 1,28gam. C. 1,92gam. D. 2,56gam.Bi 7: Ngm mt l Fe trong dung dch CuSO4. Sau mt thi gian phn ng ly l Fe ra ra nhlm kh, emcn thy khi lng tng thm 1,6 gam. Khi lng Cu bm trn l Fe l bao nhiu gam?A. 12,8 gam. B. 8,2 gam. C. 6,4 gam. D. 9,6 gam.Bi 8: Ngm mt l km trong 100 ml dung dch AgNO3 0,1M. Khi phn ng kt thc, khi lng l km tngthm

A. 0,65 gam. B. 1,51 gam. C. 0,755 gam. D. 1,3 gam.Bi 9: Cho m gam hn hp bt Zn v Fe vo lng d dung dch CuSO4. Sau khi phn ng kt thc, lc bphn dung dch, thu c m gam bt rn. Thnh phn % theo khi lng ca Zn trong hn hp ban u l:A. 12,67% B. 82,2% C. 85,3% D. 90,27%Bi 10: Cho 16 gam Cu vo dung d ch cha 0,075 mol Cu(NO3)2 v 0,4 mol HCl thy c V1 lt kh NO thot rav dung dch A. Cho thm H2SO4 long, d vo dung dch A thy thot ra V2 lt kh NO na. Cc kh o KTC. Gi tr V1 v V2 l:A. V1= 1,12 v V2= 2,24 B. V1=1,12 v V2=3,36C. V1=V2=2,24 D. V1=2,24 v V2=1,12Bi 11: Cho hn hp bt Al, Fe vi dung dch cha Cu(NO3)2 v AgNO3. Sau khi cc phn ng xy rahon ton, thu c hn hp rn gm ba kim loi l:

A. Fe, Cu, Ag. B. Al, Cu, Ag. C. Al, Fe, Cu. D. Al, Fe, Ag.


14/59


14

Bi 12: Ho tan hon ton Fe3O4 trong dung dch H2SO4long (d) c dung dch X1. Cho lng d bt Fevo dung dch X1 (trong iu kin khng c khng kh) n khi phn ng xy ra hon ton, thu c dung dchX2 cha cht tan lA. Fe2(SO4)3 v H2SO4. B. FeSO4. C. Fe2(SO4)3. D. FeSO4 v H2SO4.Bi 13: Cho hn hp bt gm 2,7 gam Al v 5,6 gam Fe vo 550 ml dung dch AgNO3 1M. Sau khicc phn ng xy ra hon ton, thu c m gam cht rn. Gi tr ca m l (bit th t trong dy th

in ho: Fe3+

/Fe2+

ng trc Ag+

/Ag)A. 59,4. B. 64,8. C. 32,4. D. 54,0.Bi 14: Cho 6,72 gam Fe vo 400 ml dung dch HNO31M, n khi phn ng xy ra hon ton, thu c khNO (sn phm kh duy nht) v dung dch X. Dung dch X c th ho tan ti a m gam Cu. Gi tr ca m l

A. 1,92. B. 3,20. C. 0,64. D. 3,84.Bi 15: Cho hn hp gm Fe v Zn vo dung dch AgNO3 n khi cc phn ng xy ra hon ton, thu cdung dch X gm hai mui v cht rn Y gm hai kim loi. Hai mui trong X l

A. Fe(NO3)3 v Zn(NO3)2. B. Zn(NO3)2 v Fe(NO3)2.C. AgNO3 v Zn(NO3)2. D. Fe(NO3)2 v AgNO3

Bi 16: Cho hn hp gm 1,12 gam Fe v 1,92 gam Cu vo 400 ml dung dch cha hn hp gm H2SO4 0,5Mv NaNO3 0,2M. Sau khi cc phn ng xy ra hon ton, thu c dung dch X v kh NO (sn phm kh duynht). Cho V ml dung dch NaOH 1M vo dung dch X th lng kt ta thu c l ln nht. Gi tr ti thiuca V l

A. 360. B. 240. C. 400. D. 120.Bi 17: Cho hn hp gm 1,2 mol Mg v x mol Zn vo dung dch cha 2 mol Cu 2+ v 1 mol Ag+n khi ccphn ng xy ra hon ton, thu c mt dung dch cha ba ion kim loi. Trong cc gi tr sau y, gi tr noca x tho mn trng hp trn?A. 1,8. B. 1,5. C. 1,2. D. 2,0.Bi 18: Cho 2,24 gam bt st vo 200 ml dung dch cha hn hp gm AgNO3 0,1M v Cu(NO3)2 0,5M. Saukhi cc phn ng xy ra hon ton, thu c dung dch X v m gam cht rn Y. Gi tr ca m l

A. 2,80. B. 2,16. C. 4,08. D. 0,64Bi 19: Cho m gam bt Fe vo 800 ml dung dch hn hp gm Cu(NO3)2 0,2M v H2SO4 0,25M. Sau khi ccphn ngxy ra hon ton, thu c 0,6m gam hn hp bt kim loi v V lt kh NO (sn phm kh duy nht, ktc). Gi tr ca m v V ln lt l

A. 10,8 v 4,48. B. 10,8 v 2,24. C. 17,8 v 2,24. D. 17,8 v 4,48Bi 20: Nhng mt thanh st nng 100 gam vo 100 ml dung dch hn hp gm Cu(NO3)2 0,2M v AgNO30,2M. Sau mt thi gian ly thanh kim loi ra, ra sch lm kh cn c 101,72 gam (gi thit cc kim loi tothnh u bm ht vo thanh st). Khi lng st phn ng l

A. 1,40 gam. B. 2,16 gam. C. 0,84 gam. D. 1,72 gamBi 21: Ho tan hon ton 24,4 gam hn hp gm FeCl2v NaCl (c t l s mol tng ng l 1 : 2) vo mtlng nc (d), thu c dung dch X. Cho dung dch AgNO3 (d) vo dung dch X, sau khi phn ng xy rahon ton sinh ra m gam cht rn. Gi tr ca m l

A. 57,4. B. 28,7. C. 10,8. D. 68,2.Bi 22: Nhng mt thanh kim loi R ho tr II vo dung dch cha a mol CuSO4, sau mt thi gian thy khilng thanh kim loi gim 0,05%. Cng thanh kim loi trn nhng vo dung dch cha a mol Pb(NO3)2 th khilng thanh kim loi tng 7,1%. Kim loi R l:A. Mg B.Fe C.Zn D.NiBi 23: Cho a gam bt Fe phn ng vi hn hp gm 14,6 gam HCl v 25,6 gam CuSO4, sau khi phn ng xy

ra hon ton thu c hn hp kim loi c khi lng 0,7a gam v x lt kh (KTC). Gi tr ca a v X l:A. 33.067 v 22.4 B. 3.3067 v 4.48 C. 3.3067 v 2,24 D. 33.067 v 4,48Bi 24: Cho 3,08 gam Fe vo 150 ml dung dch AgNO3 1M, lc kcho n khi phn ng xy ra hon ton thuc m gam cht rn. Gi tr ca m l:A. 11.88 B. 16,2 C. 18,2 D. 17,96Bi 25: Cho 19,2 gam Cu vo 1 lt dung dch hn hp gm H2SO4 0,1M v KNO30,2M thu c V lt kh NOduy nht (KTC). Gi tr ca V l:A. 1.12 B. 2.24 C. 4.48 D. 3.36Bi 26: Nhng mt thanh graphit c ph mt lp kim loi ho tr II vo dung dch CuSO4d. Sau khi phnng xy ra hon ton thy khi lng thanh graphit gim 0,24 gam. Cng thanh graphit trn nhng vo dung


15/59


15

dch AgNO3d th sau khi phn ng xy ra hon ton khi lng thanh graphit tng 0,52 gam. Kim loi ho trII l:A. Pb B. Cd C. Al D. SnBi 27: Ngm mt vt bng Cu c khi lng 15 gam vo 340 gam dung dch AgNO3 6%. Sau mt thi giannhc thanh Cu ra thy khi lng AgNO3 trong dung dch gim 25%. Khi lng ca vt sau phn ng l:A. 3.24 gam B. 2,28 gam C. 17,28 gam D. 24,12 gam.Bi 28: Cho 3,78 gam bt Al phn ng va vi dung dch mui XCl3 to thnh dung dch Y. Khi lngcht tan trong dung dch Y gim 4,06 gam so vi dung dch X. Xc nh cng thc ca mui XCl3.A. InCl3 B. GaCl3 C. FeCl3 D. GeCl3.Bi 29: Cho 0,3 mol bt Cu v 0,6 mol Fe(NO 3)2 vo dung dch cha 0,9 mol H2SO4 (long). Sau khi cc phnng xy ra hon ton, thu c V lt kh NO (sn phm kh duy nht, ktc). Gi tr ca V lB. A. 6,72 B. 8,96 C. 4,48 D. 10,08

BI TON NHIT KIM LOIII- BI TP VN DNG

Bi 1: Cho V lt hn hp kh (ktc) gm CO v H2 phn ng vi mt lng d hn hp rn gm CuO vFe3O4 nung nng. Sau khi cc phn ng xy ra hon ton, khi lng hn hp rn gim 0,32 gam. Gi tr ca VlA. 0,448. B. 0,112. C. 0,224. D. 0,560.Bi 2: Dn t t V lt kh CO (ktc) i qua mt ng sng lng d hn hp rn gm CuO, Fe2O3 (nhit

cao). Sau khi cc phn ng xy ra hon ton, thu c kh X. Dn ton b kh X trn vo lng d dungdch Ca(OH)2 th to thnh 4 gam kt ta. Gi tr ca V lA. 1,120. B. 0,896. C. 0,448. D. 0,224.Bi 3: Cho kh CO khhon ton n Fe mt hn hp gm: FeO, Fe2O3, Fe3O4 thy c 4,48 lt CO2(ktc) thotra. Thtch CO (ktc) tham gia phn ng lA. 1,12 lt. B. 2,24 lt. C. 3,36 lt. D. 4,48 lt.Bi 4: Thi mt lung kh CO i qua ng sng m gam hn hp Fe3O4v CuO nung nng thu c 2,32 gamhn hp rn. Ton b kh thot ra cho hp th ht vo bnh ng dung dch Ca(OH)2d thu c 5 gam kt taGi tr ca m l:A. 3,22 gam. B. 3,12 gam. C. 4,0 gam. D. 4,2 gam.Bi 5: kh hon ton 30 gam hn hp CuO, FeO, Fe2O3, Fe3O4, MgO cn dng 5,6 lt kh CO (ktc). Khilng cht rn sau phn ng lA. 28 gam. B. 26 gam. C. 22 gam. D. 24 gam.Bi 6: Kh hon ton 17,6 gam hn hp X gm Fe, FeO, Fe2O3 cn 2,24 lt CO (ktc). Khi lng st thuc l A. 5,6 gam. B. 6,72 gam. C. 16,0 gam. D. 8,0 gam.Bi 7: Cho lung kh CO (d) i qua 9,1 gam hn hp gm CuO v Al2O3nung nng n khi phn ng honton, thu c 8,3 gam cht rn. Khi lng CuO c trong hn hp ban u l

A. 0,8 gam. B. 8,3 gam. C. 2,0 gam. D. 4,0 gam.Bi 8. Cho dng kh CO d i qua hn hp (X) cha 31,9 gam gm Al2O3, ZnO, FeO v CaO th thu c 28,7gam hn hp cht rn (Y). Cho ton b hn hp cht rn (Y) tc dng vi dung dch HCl d thu c V lt H2(kc). Gi tr V l

A. 5,60 lt. B. 4,48 lt. C. 6,72 lt. D. 2,24 lt.Bi 9: Kh 6,4 gam CuO bng H2nhit cao thu c cht rn A v hn hp kh B. Dn ton blng khB qua bnh ng H2SO4m c, thy khi lng bnh tng 0,9 gam. Thnh phn % CuO b kh trong phnng trn l:

A.

62,5% B. 75% C. 80% D. 65%.Bi 10: Dn t t lung kh H2 qua 16 gam hn hp gm MgO v CuO un nng n khi khi lng hn hpkhng i thu pc cht rn A. Cht rn A tc dng va vi 1 lt dung dch H2SO4 0,2M. Phn trn theokhi lng ca CuO trong hn hp ban u l:A. 40% B. 60% C. 75% D. 50%Bi 11: Cho lung kh CO d qua ng sng 1,6 gam Fe2O3 n khi phn ng xy ra hon ton thu c chrn A v kh B. Cho ton blng kh B thu c vo bnh ng dung dch Ca(OH)2d, thy xut hin 3 gamkt ta. Phn trm khi lng Fe2O3 b kh l:A. 75% B. 80% C. 90% D. 100%


16/59


16

Bi 12: C m gam hn hp cha Fe v Fe2O3. Cho lung kh CO d i qua m gam hn hp trn, un nng nkhi phn ng xy ra hon ton thu c 11,2 gam Fe. Cng m gam hn hp trn cho tc dng vi dung dchHCl d ngi ta thu c 2,24 lt kh H2(ktc). Thnh phn % theo khi lng ca Fe trong hn hp ban ul:A. 30% B. 41,7% C. 58,83% D. 70%Bi 13: Kh hon ton 4,06 gam oxit kim loi R bi kh CO thu c 1,568 lt kh CO2. Lng kim loi sinh ra

cho tc dng hon ton vi dung dch HCl d thuc 0,0525 mol H2. Cng thc phn t ca oxit kim loi l:A. Al2O3 B. CuO C. Fe2O3 D. Fe3O4Bi 14: Cho lung kh CO qua ng sng 0,04 mol hn hp X gm FeO v Fe2O3nung nng, c cht rnY nng 4,784 gam v 0,046 mol CO2. S mol tng cht trong hn hp X l.A. 0,015 mol FeO v 0,0025 mol Fe2O3 B. 0,01 mol FeO v 0,03mol Fe2O3C. 0,02 mol FeO v 0,02 mol Fe2O3. D. 0,02 mol FeO v 0,03 mol Fe2O3.Bi 15: Cho mt lung kh CO i qua 29 gam mt oxit st. Sau khi phn ng xy ra hon ton ngi ta thuc mt cht rn c khi lng 21 gam. Xc nh cng thc oxit st.A. Khng xc nh c B. Fe2O3 C. FeO D. Fe3O4Bi 16: Dng CO d kh hon tan m gam bt st oxit. Dn tan blng kh sinh ra i tht chm qua 1 ltdung dch Ba(OH)2 0,1M th va v thu c 9,85gam kt ta. Mt khc ha tan tan b m gam bt st oxitrn bng dd HCl d ri c cn th thu c 16,25gam mui khan. m c gi tr l bao nhiu gam? V cng thcoxit (FexOy).

A, 8gam; Fe2O3 B. 15,1gam, FeO C. 16gam; FeO D. 11,6gam; Fe3O4Bi 17: Dng CO d kh han tan m gam bt st oxit(FexOy) dn tan blng kh sinh ra i tht chmqua 1 lt dung dch Ba(OH)2 0,1M th phn ng va thu c 9,85gam kt ta. S mol kh CO2thu c lbao nhiu?

A. 0,05mol B. 0,15 mol C. 0,025mol D. 0,05 v 0,075 molBi 18: Dng CO d kh han tan m gam bt st oxit (FexOy), dn tan blng kh sinh ra i tht chmqua 1 lt dung dch Ba(OH)2 0,1M th va v thu c 9,85gam kt ta. Mt khc ha tan tan b m gam bst oxit bng dung dch HCl d ri c cn th thu c 16,25 gam mui khan. m c ga tr l?A. 8 gam B. 15,1gam C. 16gam D. 11,6gamBi 19: Hn hp X gm Fe v oxit st c khi lng 2,6gam. Cho kh CO d i qua X nung nng, Kh sinh rahp th vo dung dch nc vi trong d th c 10gam kt ta. Tng khi lng Fe c trong X l?A. 1 gam B. 0,056gam C. 2 gam D. 1,12gamBi 20: Dn 1 lung CO d qua ng ng m gam hn hp X gm Fe2O3v CuO nung nng thu c cht rnY; kh ra khi ng c dn vo bnh ng dung dch Ca(OH)2d, thu c 40 gam kt ta. Ha tan cht rn Ytrong dung dch HCl d thy c 4,48 lt kh H2bay ra (ktc). Ga tr m l?A. 24 B. 16 C. 32 D. 12Bi 21: Nung nng 7,2gam Fe2O3 vi kh CO. Sau mt thi gian thu c m gam cht rn X. Kh sinh ra sauphn ng c hp th ht bi ddBa(OH)2c 5,91g kt ta, tip tc cho Ba(OH)2d vo dung dch trn thyc 3,94 gam kt ta na. Tm m?A. 0,32gam B. 64gam C. 3,2gam D. 6,4gamBi 22: Cho kh CO qua ng s cha 15,2gam hn hp cht rn CuO v Fe3O4 nung nng , thu c kh X v13,6 gam cht rn Y. Dn t t kh X vo dung dch Ca(OH)2d thy c kt ta. Lc ly kt ta v nung nkhi lng khng i c m gam cht rn. m c ga tr l?A. 10gam B. 16gam C. 12gam D. 18gamBi 23: Cho lung kh H2 (d) qua hn hp cc oxit CuO, Fe2O3, ZnO, MgO nung nhit cao. Sau phn ng

hn hp rn cn li l:A. Cu, Fe, Zn, MgO. B. Cu, Fe, ZnO, MgO. C. Cu, Fe, Zn, Mg. D. Cu, FeO, ZnO, MgOBi 24: Phn ng ho hc xy ra trong trng hp no di y khng thuc loi phn ng nhit nhm?A. Al tc dng vi Fe3O4 nung nng. B. Al tc dng vi CuO nung nng.C. Al tc dng vi Fe2O3 nung nng. D. Al tc dng vi axit H2SO4c, nngBi 25: Cho kh CO (d) i vo ng snung nng ng hn hp X gm Al2O3, MgO, Fe3O4, CuOthu c cht rn Y. Cho Y vo dung dch NaOH (d), khuy k, thy cn li phn khng tan Z. Gis cc phn ng xy ra hon ton. Phn khng tan Z gmA. MgO, Fe, Cu. B. Mg, Fe, Cu. C. MgO, Fe3O4, Cu. D. Mg, Al, Fe, Cu.


17/59


17

Bi 26: Cho 4,48 lt kh CO (ktc) t ti qua ng snung nng ng 8 gam mt oxit st n khi phn ngxy ra hon ton. Kh thu c sau phn ng c t khi so vi hiro bng 20. Cng thc ca oxit st v phntrm th tch ca kh CO2 trong hn hp kh sau phn ng l (Cho H = 1; C = 12; O = 16; Fe = 56)A. FeO; 75%. B. Fe2O3; 75%. C. Fe2O3; 65%. D. Fe3O4; 75%.Bi 27: Cho V lt hn hp kh (ktc) gm CO v H2 phn ng vi mt lng d hn hp rn gm CuO vFe3O4 nung nng. Sau khi cc phn ng xy ra hon ton, khi lng hn hp rn gim 0,32 gam. Gi tr ca V

lA. 0,448. B. 0,112. C. 0,224. D. 0,560.Bi 28: Nung nng m gam hn hp Al v Fe2O3 (trong mi trng khng c khng kh) n khiphn ng xy ra hon ton, thu c hn hp rn Y. Chia Y thnh hai phn bng nhau:- Phn 1 tc dng vi dung dch H2SO4long (d), sinh ra 3,08 lt kh H2 (ktc);- Phn 2 tc dng vi dung dch NaOH (d), sinh ra 0,84 lt kh H2 (ktc). Gi tr ca m lA. 22,75 B. 21,40. C. 29,40. D. 29,43.Bi 29: Dn t t V lt kh CO (ktc) i qua mt ng sng lng d hn hp rn gm CuO, Fe2O3 (nhi cao). Sau khi cc phn ng xy ra hon ton, thu c kh X. Dn ton b kh X trn vo lng d dungdch Ca(OH)2 th to thnh 4 gam kt ta. Gi tr ca V lA. 1,120. B. 0,896. C. 0,448. D. 0,224.Bi 30: t nng mt hn hp gm Al v 16 gam Fe2O3(trong iu kin khng c khng kh) n khi phnng xy ra hon ton, thu c hn hp rn X. Cho X tc dng va vi V ml dung dch NaOH 1M sinh ra

3,36 lt H2 (ktc). Gi tr ca V lA. 150. B. 100. C. 200. D. 300.Bi 31: Cho lung kh CO (d) i qua 9,1 gam hn hp gm CuO v Al2O3 nung nng n khi phn ng honton, thu c 8,3 gam cht rn. Khi lng CuO c trong hn hp ban u lA. 0,8 gam. B. 8,3 gam. C. 2,0 gam. D. 4,0 gam.Bi 32: Nung nng m gam hn hp gm Al v Fe 3O4trong iu kin khng c khng kh. Sau khi phn ngxy ra hon ton, thu c hn hp rn X. Cho X tc dng vi dung dch NaOH (d) thu c dung dch Y,cht rn Z v 3,36 lt kh H2( ktc). Sc kh CO2(d) vo dung dch Y, thu c 39 gam kt ta. Gi tr ca ml

A. 45,6. B. 48,3. C. 36,7. D. 57,0.Bi 33: Kh hon ton m gam oxit MxOy cn va 17,92 lt kh CO (ktc), thu c a gam kim loi M. Hatan ht a gam M bng dung dch H2SO4c nng (d), thu c 20,16 lt kh SO2 (sn phm kh duy nht, ktc). Oxit MxOy l

A. Cr2O3. B. FeO. C. Fe3O4. D. CrO

Chuyn 04: Bi tp vhirocacbon

Cu 1. t chy hon ton hn hp X gm 2 hidrocacbon mch hcng dy ng ng hp th hon ton snphm vo 1,8 lt dung dch Ca(OH)20,05M thu c kt ta v khi lng dung dch tng 3,78g. Cho Ba(OH)2d vo dung dch thu c kt ta v tng khi lng tng cng c 2 ln l 18,85g. T khi ca X vi H2 l 20.Dy ng dng ca hai hidrocacbon l:a. Ankin b. Ankadien c. Aren d. Ankin hoc Ankadien

Cu 2. Cho hn hp kh X gm 2 hidrocacbon A, B mch thng v khi lng phn t ca A nhhn khilng phn t ca B. Trong hn hp X, A chim 75% theo thtch . t chy hon ton X cho sn phm chyhp th qua b nh cha dung dch Ba(OH)2d, sau th nghim khi lng dung dch trong b nh gim 12,78g ngthi thu c 19,7g kt ta. Bit t khi hi ca X i vi hidro bng 18,5 v A, B cng dy ng ng.1) Xc nh dy ng ng ca 2 hidrocacbon

a. Ankan b. Anken c. Aren d. Ankadien2) T m cng thc phn t ca A, B?

a. C3H6 v C4H8 b. C2H6 v C4H10b. C4H8 v C5H10 d. C2H6 v C3H8

Cu 3. Mi hn hp X gm 2 hidrocacbon A, B ( thuc mt trong 3 dy ng ng ankan, anken, ankin) s


18/59


18

nguyn t C trong mi phn t nhhn 7; A v B c trn theo t lmol l 1:2. t chy hon ton 14,8g hnhp X bng oxi ri thu ton b sn phm ln lt dn qua b nh cha dung dch H2SO4c, d; b nh 2 cha890ml dung dch Ba(OH)2 1M th khi lng b nh 1 tng 14,4g v b nh 2 thu c 133,96g kt ta trng.Xc nh dy ng ng ca A v B.

a. Ankin b. Anken c. Ankedien d. AnkanCu 4. t chy hon ton mt hidrocacbon X vi mt lng va oxi. Dn hn hp sn phm chy qua

H2SO4m c th th tch kh gim hn mt na. Dy ng dng ca hidrocacbon X l:a. Ankin b. Anken c. Ankedien d. AnkanCu 5. Cho 2 hidrocacbon X v Y ng ng nhau, phn t khi ca X gp i phn t khi ca Y.

a) Xc nh cng thc tng qut ca 2 hidrocacbon.a. CnH2n2 b. CnH2n + 2 b. CnH2n6 c. CnH2n

b) Xc nh cng thc phn t ca X v Y, bit rng: T khi ca hn hp ng th tch X v Y so vikh C2H6 bng 2,1.

a. C3H8 v C6H14 b. C3H4 v C6H6c. C3H6 v C6H12 b. Cu C ng

Cu 6. t chy V (lit) hn hp kh X iu kin tiu chun gm 2 hidrocacbon to thnh 4,4g CO2 v 1,8gH2O. Cho bit 2 hidrocacbon tren cng hay khc dy ng ng v thuc dy ng ng no? ( Chxt cc dyng ng hc trong chng tnh).

a. Cng dy ng ng Anken hay cng dy ng ng xicloankan.

b. Khc dy ng ng: anken v xicloankan.c. Khc dy ng ng: ankan v ankin ( s mol bng nhau)d. Khc dy ng ng: ankan v ankadien (s mol bng nhau )

Cu 7. t chy hon ton 2,8g mt hp cht hu c X ri cho ton b sn phm hp th vo dd NaOH th dungdch ny c khi lng tng thm 12,4g, thu c 2 mui ny c t l1:1 Xc nh dy ng ng ca cht X.

a. a. Ankin b. Anken c. Ankadien d. AnkanCu 8. t chy hon ton 2,8 cht hu c X bng 6,72 lit O2(ktc) ch to thnh kh CO2v hi nc c thtch bng nhau trong cng iu kin.a) T m dy ng ng ca hp cht hu c X.

a. Anken b. Ankan c. Ankadien d. Kt qu khcc) Nu cho 2,8g X ni trn vo dung dch Br2 d th c 9,2g sn phm cng. T m cng thc phn t.

a. C5H10 b. C4H8 c. C4H10 d. Kt qu khcCu 9. t chy 2 lit hn hp hai hidrocacbon X, Y thkh v cng dy ng ng, cn 10 lit O2 to thnh6 lit CO2 ( cc thtch u ktc).a) Xc nh dy ng ng ca 2 hidrocacbon?

a. Ankan b. Anken c. Aren d. AnkadienCu 10. t chy hon ton 24,64 lit (27,3oC; 1 atm) hn hp kh X gm 3 hidrocacbon ng ng lin tip, thusn phm cho hp th ht vo mt b nh nc vi trong d thi khi lng ton b nh tng 149,4g v khi lc thuc 270g kt ta trng.a) Xc nh dy ng ng ca 3 hidrocacbon

a. CnH2n2 b. CnH2n + 2 b. CnH2n6 d. CnH2nb) Xc nh cng thc phn t 3 hidrocacbon:

a. C2H4, C3H6 v C4H8 b. C6H6, C7H8 v C8H10b. C2H6, C3H8 v C4H10 d. C2H2, C3H4 v C4H6

CH2 : Xc nh CTPTCTCT ca hidrocacbon

Dng 1:Hn hp hidrocacbon cng dy ng ng k tipCu 11. Mt hn hp gm hai cht ng ng ankan k tip c kl 24,8g. Thtch tng ng l 11,2 lit (ktc).Hy xc nh cng thc phn t ca ankan.

a. C6H8 v C3H8 b. C5H12 v C6H14c. C3H8 v C4H10 d. Cu C ng

Cu 12. Cho 5,6 lit hn hp hai olefin l ng ng k tip nhau hp nc (c xc tc) c hn hp 2 ru.Chia hn hp hai ru ny dng khan ri chia lm 2 phn bng nhau. Phn th nht phn ng ht vi Na dthu c 840ml kh. t chy ht phn th hai ri cho ton b sn phm chy hp th vo b nh ng NaOH dth khi lng b nh NaOH tng 13,75g.Cng thc phn t ca hai olefin l:


19/59


19

a. C2H6 v C3H8 b. C3H4 v C4H6c. C2H4 v C3H6 d. C4H8 v C3H6

Dng 2:Hn hp hidrocacbon cng dy ng ng khng k tipCu 13. Cho 6,72 lit hn hp kh gm 2 olefin li qua nc brom d thy khi lng b nh tng 16,8g. Hy tmcng thc phn t cc olefin bit rng s nguyn t cacbon trong mi olefin khng qu 5.

a. C2H4 v C4H8 b. C3H6 v C4H8

c. C5H10 v C6H12 d. C2H4 v C4H8 ; C3H6 v C4H8Cu 14. t chy 560cm3 hn hp kh (ktc) gm hai hidrocacbon c cng s nguyn tcacbon ta thu c4,4g CO2v 1,9125g hi nc. Xc nh cng thc phn t cc hidrocacbon.

a. C4H8 v C4H10 b. C4H6 v C4H10c. C4H4 v C4H10 d. Cu A, B, C cha cp p s

Dng 3: S dng mt s d kin thc nghim khi xc nh cng thc , thnh phn ca hidrocacbonCu 15. t 10cm3 mt hidrocacbon bng 80cm3 oxi (ly d). Sn phm thu c sau khi cho H2O ngng t cn65cm3 trong 25cm3 l oxi. Cc thtch u o ktc. Xc nh cng thc phn t ca hidrocacbon.

a. C4H10 b. C4H6 c. C5H10 d. C3H8Cu 16. Mt hn hp gm hai hidrocacbon mch h. Cho 1680ml hn hp trn i chm qua nc brom d.Sauk hi phn ng hon ton cn li 1120ml v lng brom tham gia phn ng l 4,0g. Mt khc nu t chyhon ton 1680ml hn hp trn ri cho ton b sn phm chy hp thvo nc vi trong d th thu c 12,5gkt ta.

Cng thc phn t ca hai hidrocacbon l:a. C4H8 v C3H6 b. C2H6 v CH4c. C4H10 v CH4 d. C3H6 v CH4

Cu 17. Hn hp kh A gm hidro, mt paraffin v hai olefin l ng ng lien tip. Cho 560ml A i qua ngcha bt niken nung nng c 448ml hn hp kh A1 li qua b nh nc brom thy nc brom nht mu mtphn v khi lng b nh nc brom tng thm 0,343g. Hn hp kh A2i ra khi b nh nc brom chim th tch291,2ml v c t khi i vi khng kh bng 1,313. Gi thit cc phn ng xy ra hon ton, cc olefin phnng vi tc bng nhau ( ngha l t l vi thnh phn % th tch ca chng) v cc thtch kh o ktc. Xcnh cng thc phn t ca cc hidrocacbon.a. C2H4; C3H6 v C5H10 b. C2H6; C3H6 v C4H8c. C3H8; C4H10 v C5H12 d. C2H6; C4H8 v C5H10Cu 18. Cho 0,672 lit (ktc) hn hp kh A gm hai hidrocacbon mch h. Chia A thnh 2 phn bng nhau. Chophn 1 qua dung dch Br2d, khi lng dung dch tng Xg, lng Br2 phn ng ht 3,2g khng c kh thotra khi dung dch. t chy phn 2 v cho sn phm chy qua b nh dung dch P2O5. Sau cho qua KOH rn.Sau th nghim b nh ng P2O5 tng Yg v b nh ng KOH tng 1,76g. T m cng thc phn t ca 2hidrocacbon.

a. C2H4 v C3H6 b. C3H6 v C4H8c. C2H4 v C4H6 hoc C2H2 v C3H6 d. Cu C ng

Cu 19. Cho 0,896 lit (ktc) hn hp kh A gm 2 hidrocacbon mch h. Chia A thnh 2 phn bng nhau:Phn 1: Cho qua dung dch Br2 c tha, lng Br2 nguyn cht phn ng 5,6gPhn 2: t chy hon ton to ra 2,2g CO2. T m cng thc phn t 2 hidrocacbon.

a. C4H8 v C2H2 b. C4H2 v C2H4c. C4H8 v C2H2 ; C4H2 v C2H4 d. p s khc

Cu 20. Trn hn hp X1 gm hidrocacbon B vi H2c d dx/H2 = 4,8. Cho X1i qua Ni nung nng n phnng hon ton c hn hp X2 c dX2/H2 = 8. Cng thc phn t hidrocacbon B l:

a. C3H6 b. C3H4 c. C4H8 d. C5H8Cu 21. Trn hn hp X gm 1 hidrocacbon khi (A) v H2 vi dX/H2= 6,1818. Cho X qua Ni un nng n khiphn ng hon ton thu c hn hp Y dY/H2= 13,6. Xc nh cng thc phn t ca A.

a. C3H4 b. C3H6 c. C4H6 d. C5H12Cu 22. Cho 1,568 lit hn hp kh X gm 2 hidrocacbon mch h vo b nh nc brom d. Sauk hi phn nghon ton ch cn li 448cm3kh thot ra v c 8 gam brom phn ng. Mt khc, nu t chy hon tonlng X trn ri dn ton b sn phm chy vo b nh nc vi trong th c 15g kt ta. Lc b kt ta ri unnng nc lc, thu thm ti a 2 gam kt ta na. ( Cc th tch kh u c o ktc).T m cng thc cu to 2 phn t hidrocacbon.



20/59


20

c. C2H2 v C5H12 d. C2H6 v C3H6Cu 23. Cho 0,42 lit hn hp kh B gm hai hidrocacbon mch hi rt chm qua b nh ng nc brom d.Sauk hi phn ng hon ton thy c 0,28 lit kh i ra khi b nh v c 2 gam brom tham gia phn ng. Cc thtch kh o ktc. T khi hi ca B so vi hidro l 19. Hy xc nh cng thc phn t hai hidrocacbon.

a. C2H6 v C4H6 b. C3H8 v C2H2c. C2H6 v C4H6 hoc C3H8 v C2H2

d. C3H6 v C4H6 hoc C2H8 v C2H2Dng 4: Bin lun xc nh CTPT hidrocacbonCu 24. t chy hon ton 3,24 gam hn hp X gm 2 cht hu c (A) v (B) khc dy ng ng, trong (A) hn (B) mt nguyn tcacbon,ngi ta chthu c H2O v 9,24 gam CO2. Bit t khi hi ca X i vihidro l dx/H2 = 13,5. T m cng thc phn t ca (A), (B)?

a. C2H4 v C2H5OH b. C2H6 v C3H8c. C2H2 v CH2O d. C3H8O v C2H6O

Cu 25. t hon ton hn hp 2 hidrocacbon X, Y thuc cng mt dy ng ng (ankan, anken, ankin), hpthu sn phm chy vo 4,5 lit dung dch Ca(OH)2 0,02M th thu c kt ta, khi lng dung dch tng ln3,78g. Cho dung dch Ba(OH)2d vo dung dch thu c kt ta. Tng kt ca 2 ln nng 18,85g. Bit rng smol X bng 60% tng s mol X, Y trong hn hp. Xc nh cng thc phn t ca X, Y?.

a. C2H4 v C3H6 b. C3H4 v C5H6c. C2H6 v C3H8 d. C2H2 v C4H6

Cu 26. t chy mt hidrocacbon X mch h, kh vi 1,92 gam kh oxi trong b nh kn ri cho cc sn phm sauphn ng qua b nh mt cha trong H2SO4c d, b nh hai cha 3,5 lit Ca(OH)20,01M thu c 3g kt ta, khduy nht bay ra c thtch 0,224 lit o 27,3oC v 1,1 atm. Xc nh cng thc phn t ca X, gi thit ccphn ng xy ra hon ton.

a. C2H2 b. C2H8 c. C3H8 hoc C2H2d. C3H8 hoc C2H2 hoc CH4

Cu 27. Cho hn hp kh gm hidrocacbon A v oxi ly d, trong c 10% A theo th tch vo mt kh nhink, to p sut 1 atm 0oC. Bt tia la in A chy hon ton ri cho nc ngng t0oC th p sut trongb nh gim cn 0,8 atm. Bit lng oxi d khng qu 50% lng oxi ban u. Hy tm cng thc phn t ca A.

a. C4H8 b. C4H10 c. C4H4 d. C5H12Cu 28. Mt hn hp gm hai hidrocacbon, mch h, trong phn t mi cht cha khng qu mt lien kt bahay hai lien kt i. S cacbon mi cht ti a bng 7. t chy hon ton 0,05 mol hn hp thu c 0,25 molCO2 v 0,23 mol H2O. T m cng thc phn t ca 2 hidrocacbon?

a. C2H2 v C7H14 b. C5H8 v C5H10c. C5H8 v C5H12 d. p s A + B + C

Cu 29. t chy mt hidrocacbon X vi lng va oxi. Ton b sn phm chy c dn qua b nh ngcanxi clorua khan c d th tch gim i hn mt na. Bit rng X cacbon chim 80% v khi lng. Xc nhcng thc cu to ca X.

a. C3H8 b. C2H4 c. C4H6 d. C2H6Cu 30. t chy hai hidrocacbon c cng cng thc tng qut CnH2n + 22kthu c sn phm sau khi t chyc khi lng 22,1g. Khi cho ton blng sn phm ny vo 400g dung dch NaOH th thu c dung dchgm hai mui c nng 9,0026%. T l s mol hai mui l 1:1.Cho bit t l s mol ca chng trong hn hp l 1:2 ( theo chiu khi lng phn ttng dn). Bit k < 3. Cngthc phn thc phn t ca hai hidrocacbon l:


c. C2H2 v C3H4 d. Kt qu khcCu 31. Mt hidrocacbon X c cng thc CnH2n + 22k. Khi t X ta c t l s mol ca CO2 v H2O bng 2 (k hiu l b), ng vi k nh nht. Cng thc phn t ca X l:

a. C2H4 b. C2H6 c. C2H2 d. C6H6Cu 32. C mt hn hp hai hidrocacbon A v B th kh. Phn t khi ca B ln hn phn t khi ca A 24vC. T khi hi so vi H2 ca B bng 9/5 t khi hi so vi H2 ca A. Khi t chy V lit hn hp thu c 11,2lit CO2(ktc) v 8,1g H2O. Hi A v B l nhng hidrocacbon no?

a. C2H8 v C4H10 b. C2H6 v C4H6c. C3H8 v C5H10 d. Kt qu khc

Cu 33. t chy hon ton hn hp X gm hi ca hidrocacbon A v kh oxi d thu c hn hp kh v hi.


21/59


21

Lm lnh hn hp ny, th tch gim 50%. Nu cho hn hp cn li qua KOH, th tch gim 83,3% s cn li.Xc nh cng thc phn t ca hidrocacbon.

a. C2H6 b. C5H8 c. C5H12 d. C6H6Cu 34. Trong mt hn hp kh X gm hidrocacbon A v kh oxi d trong b nh ri t chy, sau khi xong,lmlnh hn hp kh thu c, nhn thy th tch gim 33,3% so vi th tch hn hp thu c. Nu dn hn hpkh tip tc qua dung dch KOH th tc b gim 75% s cn li. T m cng thc phn t hidrocacbon A.

a. C3H6 b. C3H4 c. C2H6 d. C6H6Cu 35. nhit 100oC, khi lng phn t trung b nh ca hn hp gm mt s hidrocacbon lien tip trongcng dy ng ng no bng 64. Sau khi lm lnh nhit png th mt s cht trong hn hp b halng. Khi lng phn t trung b nh ca nhng cht cn li th kh bng 54, cn khi lng phn t trung b nhca nhng cht lng l 74. Tng khi lng phn t cc cht trong hn hp ban u bng 252 vC v phn tkhi ca ng ng nng nht bng 2 ln ca phn t khi ca ng ng nh nht. Hy xc nh cng thcphn t ca cc cht trong hn hp ban u?

a. C3H8; C4H10; C5H12 b. C2H6 v C3H6 c. C4H8; C5H10 v C6H12 d. Kt qu khcCu 36. Mt hn hp kh c khi lng 7,6g gm 2,24 lit mt hidrocacbon mch thng A v 1,12 lit mt ankinB (ktc). t chy hon ton hn hp trn ri cho ton b sn phm chy hp th ht trong dung dch Ba(OH)2d th c 108,35g kt ta. A thuc loi hidrocacbon no?

a. C3H4 v C4H8 b. C2H2 v C3H8 c. C6H6 v C7H8 d. Kt qu khcCu 37. Hn hp hai olefin (th kh) lien tip trong cng dy ng ng hp nc to thnh 2 ru (mt ru

c dng mch nhnh) hiu sut u bng 40%. Bit th tch hn hp V lit (0oC, 1 atm)Chia hn hp ru thnh 2 phn bng nhau. Cho Na tc dng vi phn 1 thu c 2,464 lit H2 (27,3oC, 1

atm). un nng phn 2 vi H2SO4c to 3,852g hn hp 3 ete. 50% lng ru c s nguyn tcacbon t hnv 40% lng ru c s nguyn t cacbon nhiu hn to thnh ete. Xc nh cng thc phn t 2 olefin.

a. C3H6 v C4H8 b. C2H4 v C4H8 c. C4H8 v C5H10 d. C2H4 v C3H6Cu 38a) Trn 0,02 mol C2H2 v 0,03 mol H2 vi 1,68 lit O2(kct) np vo mt kh k c th tch 4 lit ri tchy.p sut hn hp sau phn khi to = 109,2oC l:

a. 0,392 atm b. 1,176 atm c. 0,784 atm d. 1,568 atmb) Cho 11 gam hn hp gm 6,72 lit mt hidrocacbon mch hA v 22,4 lit mt ankin. t chy hn hp nyth tiu th 25,76 lit oxi. Cc thtch o trong iu kin tiu chun.Cng thc phn t ca hidrocacbon A v B ln lt l:

a. C2H6 v C2H2 b. C3H6 v C3H4 c. C2H2 v C3H4 d. C2H4 v C2H2Cu 39a) Trong mt b nh kn th tch 5,6 lit cha 3,36 lit H2 v 2,24 lit C2H4(ktc) v mt t bt niken. tnng b nh mt thi gian, Sau lm lnh v 0oC, p sut trong b nh lc l p. Nu cho hn hp kh trong b nhsau phn ng li qua nc brom thy c 0,8g Br2 tham gia phn ng.Hy tnh phn trm phn ng:

a. 31,65% b. 63,3% c. 94,95% d. 100%b) t chy hon ton 50 cm3 hn hp kh A gm C2H6, C2H4, C2H2 v H2thu c 45 cm

3 CO2. Mt khcnung nng th tch hn hp kh A c mt Pd xc tc th thu c 40 cm3 hn hp kh B. Sau cho hn hpkh B qua Ni un nng cho mt kh duy nht. (Gi s cc phn ng xy ra hon ton) Thnh phn phn trmtheo th tch cc kh trong hn hp A ( H2, C2H2, C2H4, C2H6) ln lt l:

a. 20%, 30%, 20%,30% b. 25%, 15%, 30%, 30%c. 55%, 20%, 15%, 10% d. Kt qu khc

Cu 40a) t chy 60 cm3 hn hp ankin X, Y l hai ng ng lien tip nhau thu c 220 cm3 CO2 ( cc thtch kh o trong cng iu kin). Cng thc phn t ca X v Y ln lt l:

a. C2H2 v C3H4 b. C3H4 v C4H6 c. C4H6 v C5H8 d. Kt qu khcb) Mt b nh kn 2 lit 27,3oC cha 0,03 mol C2H2; 0,015 mol C2H4 v 0,04 mol H2 c p sut p1.Nu trong b nh c mt t bt Ni lm xc tc ( thtch khng ng k), nung b nh n nhit cao phn ngxy ra hon ton, sau a v nhit ban u c hn hp kh A c p sut p2. Cho hn hp A tc dngvi lng d dung dch AgNO3 trong NH3thu c 3,6g kt ta. Hy tnh p sut p2:a. 0,277 atm b. 0,6925 atm c. 1,108 atm d. 0,554 atm

Cu 41. a) t chy hon ton 2,24 lit kh C2H4(ktc) ri hp th ton b sn phm vo dung dch cha 11,1gam Ca(OH)2. Hi sau khi hp th khi lng phn dung dch tng hay gim bao nhiu gam?a. tng 4,8g b. gim 2,4g c. tng 2,4g d. gim 3,6g e. tng 3,6g

b) Mt hn hp A gm 0,12 mol C2H2 v 0,18 mol H2. Cho A qua Ni nung nng,phn ng khng hon ton v


22/59


22

thu c kh B. Cho B qua b nh dung dch Br2d, thu hn hp kh thot ra X. t chy hon ton X ri cho tonb sn phm vo b nh cha dung dch Ca(OH)2d, thu c 12 gam kt ta v khi lng b nh tng ln 8,88gam. Tnh tng khi lng ca b nh dung dch Br2.a. 0,82g b. 2,46g c. 1,64g d. 3,28g e. kt qu khc

Cu42. a) Trn 11,2 lit hn hp X gm C3H6 (chim 40%V) v C3H4 (chim 60%V) vi H2 trong b nh kn 33,6lit c t bt Ni ktc. Sau thi gian t chy nng b nh v a v nhit ban u thy p sut kh trong b nh l

2/3 atm. Bit khi cho hn hp qua dung dch mui Ag+

trong ammoniac th tch ca n gim 1/10. Hy xcnh thnh phn v s mol hn hp kh thu c sau phn ng:a. C3H8 (0,5 mol) v H2 (0,5 mol) b. C3H8 (0,9 mol) v C3H6 (0,1mol)c. C3H8 (0,3 mol) v C3H6 (0,1 mol) d. C3H4 (0,1 mol) v H2 (0,5 mol)e. Kt qu khc

b) Mt hn hp R gm C2H4 v C3H6, trong C3H6 chim 71,43% v th tch. Mt hn hp X gm R v H2vi s mol R bng 5 ln s mol H2. Ly 9,408 lit X (ktc) ung nng vi Ni xc tc, phn ng hon ton, thuc hn hp kh Z. Bit t l mol ca 2 ankan sinh ra bng t l mol ca 2 olefin tng ng ban u.S mol cc kh C2H6, C3H8, C2H4, C3H6 ln lt l:

a. 0,01; 0,06; 0,08 v 0,2 b. 0,03; 0,04; 0,06 v 0,22 c. 0,02; 0,05; 0,08 v 0,2 d. kt qu khcCu43. a) t mt hn hp gm hai hidrocacbon A, B (c M hn km nhau 28g) th thu c 0,3 mol CO2 v0,5 mol H2O.Cng thc phn t ca A v B ln lt l:

a. C2H6 v C3H8 b. CH4 v C4H10 c. CH4 v C2H6 d. CH4 v C3H8

b) Hp cht A c 8 nguyn t ca hai nguyn t MA< 32. Hy lp lun tm ra cng thc ca A:a. C4H4 b. C3H5 c. C2H6 d. Kt qu khcCu44. a) Hn hp D gm hp cht C2H6 v mt ankin B ( th kh) trn vi nhau theo t l mol 1:1. Thm O2vo hn hp D c hn hp D1 c t khi so vi H2 = 18. Hy tm cng thc phn t ca ankin B?

a. C3H4 b. C2H2 c. C4H6 d. C5H8b) t chy 0,3 mol hn hp 2 hidrocacbon mch h( thuc trong s 3 loi hidrocacbon paraffin, olefin vankin) c t l khi lng phn t l 22/13, ri cho sn phm sinh ra i vo b nh dng dung dch Ba(OH)2 d th thy b nh nng thm 46,5g v c 147,75g kt ta. hy xc nh cng thc phn t hai hidrocacbon.a. C3H8 v C3H4 b. C2H2 v C2H6 c. C3H8 v C3H6 d. C3H8 v C2H2Cu45. t chy hon ton mt hn hp c t l mol bng nhau ca cht C8H8 v mt hidrocacbon B trong oxitthu c CO2v hi nc theo t l th tch 13/10. Bit rng cht B ch to ra mt sn phm duy nht cha mtnguyn t brom trong phn t v khi lng phn tdi 152 vC. Cht B c cng thc phn t l:

a. CH4 b. C5H12 c. C3H6 d. C5H8Cu46. t chy hon ton 3,24 gam hn hp X gm hai cht huuwx c A v B khc dy ng ng, trong s A hn B mt nguyn tcacbon, ngi ta chthu c H2O v 9,4g gam CO2. Bit t khi hi ca X i viHidro l 13,5. Cng thc phn t ca A v b l:

a. CH4 v C2H2 b. CH4O v C2H2 c. CH2O v C2H2 d. CH2O2 v C2H2Cu47. t chy V lit hn hp X ktc gm 2 hidrocacbon to thnh 4,4g CO2 v 1,8g H2O.Hy cho bit hai hidrocacbon trn cng hay khc dy ng ng v thuc dy ng ng no? ( chxt cc dyng ng hc trong chng tnh).a. Cng dy ng ng c hai hidrocacbon l anken hay xicloankanb.Khc dy ng ng: 1 ankan v 1 ankadienc.Khc dy ng ng: 1 ankin v 1 ankan d.Cu A + B + C u ngCu48. t chy hon ton mt hn hp A gm 2 hidrocacbon ( iu kin thng, th kh), c khi lngmol phn t km nhau 28g, sn phm to thnh cho i qua b nh ng P2O5 v b nh CaO. B nh ng P2O5 nng

thm 9g cn b nh ng CaO nng thm 13,2g.a) Cc hidrocacbon thuc dy ng ng no?a. ankan b. anken c. ankin d. aren

b) Cng thc 2 hidrocacbon l:a. C2H4 v C4H8 b. C2H2 v C4H6 c. CH4 v C3H8 d. Kt qu khc

Cu49. t chy hon ton hn hp hai hidrocacbon ng ng hp th hon ton sn phm sinh ra bngBa(OH)2d cha trong b nh thy nng thm 22,1g v c 78,8g kt ta trng.a) Xc inh dy ng ng ca 2 hidrocacbon, bit chng thuc mt trong ba dy ankan, anken v ankin.a. ankan b. ankin c. anken d. cu A ng

b) Xc nh hai hidrocacbon cho, bit chng ( xp theo th ttng dn phn t khi) c trn theo t l s


23/59


23

mol 1:2.a. C2H4 v C3H6 b. C2H2 v C3H4 c. C3H4 v C4H6 d. CH4 v C2H6

Cu50. A l hn hp kh (ktc) gm 3 hidrocacbon X, Y, Z thuc 3 dy ng ng. B l hn hp O2 v O3 c tkhi so vi hidro bng 19,2. t chy 1 mol hn hp A cn 5 mol hn hp B, thu c CO2v hi nc csmol nh nhau.Khi cho 22,4 lit hn hp A i qua b nh nc brom d thy c 11,2 lit kh bay ra, khi lng b nh nc brom tng

27g, cn khi cho 22,4 lit hn hp A i qua dung dch AgNO3 trong NH3 thy to thnh 32,4g kt ta vng. Cckh o c ktc. Ba hidrocacbon trong hn hp l:a. C3H8, butin-1 v butadiene-1 b. C4H10, butin-1 v butadiene-1c. C5H12, butin-1 v butadiene-1 hoc butadiene 1-3d. Kt qu khcCu51. Mt hn hp X gm hidrocacbon lien tip nhau trong dy ng ng c khi lng 10,5g v c th tchhn hp l 2,352 lit 109,2oC v 2,8at. H nhit xung 0oC, mt s hidrocacbon (c sC 5) ha lngconfli hn hp Y c th tch 1,24 lit 2,8at. T khi hi ca hn hp Y so vi khng kh bng 1,402. Tng phn tkhi ca hn hp bng 280.Xc nh dy ng ng ca hidrocacbon, bit rng phn t khi ca cc cht saucng bng 1,5 ln phn t khi ca cht th 3.a. anken b. arken c. ankadien arenCu52. Mt hn hp X gm hi hidrocacbon mch hA v H2d c t khi hi vi Hli bng 3. Cho hn hpX qua bt Ni nung nng trong iu kin xy ra phn ng hon ton thu c hn hp kh Y c t khi hi so

vi He bng 7,5. Bit s nguyn t cacbon trong mt mol A nhhn 7. Cng thc phn t ca A l:a. C3H4 b. C4H4 c. C5H10 d. C3H6Cu53. t chy hon ton hidrocacbon trong b nh kn c th tch 10 lit bng lng khng kh gp i lngcn thit. Sau phn ng lm lnh b nh xung 0oC thy p sut trong b nh l 1,948 atm.Mt khc khi hp thlng nc sinh ra bng 25ml dung dch H2SO4 98% (D = 1,84g/cm

3) sc dung dchc nng 95,75%. T m cng thc phn t ca A bit n khng c ng phn.a. C3H6 b. C2H2 c. C2H4 d. C6H6

Cu54. Cho hp cht c cng thc phn t C8H8, bit 3,12g cht ny phn ng ht vi dung dch cha 4,8g Br2hoc vi ti a 2,688 lit H2(ktc). Hidro ha C8H8 theo t l1:1 c hidrocacbon cng loi X. Khi Brom hamt ng phn Y ca X vi xc tc bt Fe theo t lmol 1:1 c mt sn phm duy nht. Cng thc cu toca C8H8 l:a. C6H4(CH3)2 b. C6H5CH=CH2 c. C6H5CH2=CH3 d. Cu b ngCu55. Mt hn hp hai ankan k cn trong dy ng ng c t khi hi vi H2 l 24,8.a) Cng thc phn t ca hai ankan l:

a. C2H2 v C3H4 b. C2H4 v C4H8 c. C3H8 v C5H12 d. Kt qu khcb) Thnh phn % th tch, thnh phn hn hp l:

a. 30% v 70% b. 35% v 65% c. 60% v 40% d. Cng 50%Cu56. ktc c mt hn hp kh hidrocacbon no A v B t khi hi so vi hidro l 12 (dhh/H2 = 12).a) T m khi lng CO2v hi nc sinh ra khi t 15,68 lit hn hp ( ktc)

a. 24,2g v 16,2g b. 48,4g v 32,4g c. 40g v 30g d. Kt qu khcb) Cng thc phn t ca A v B l:

a. CH4 v C2H6 b. CH4 v C3H8 c. CH4 v C4H10 d. C ba cu a + b + cCu57. Mt hn hp gm 2 kh hidrocacbon mch h. T khi hi hn hp so vi H2 l 17. ktc 400cm

3 hnhp tc dng va vi 71,4cm3 dung dch Br2 0,2M v cn li 240cm

3kh. Xc nh cng thc phn t ca hai

hidrocacbon.a. C2H6 v C2H2 b. C3H8 v C3H4 c. C2H6 v C3H4 d. C4H10 v C2H2Cu58. Hn hp kh A gm hai hidrocacbon c cng s nguyn tcacbon (ktc).a) T m t khi hi ca hn hp A i vi Nito, bit rng 560cm3 hn hp nng 1,3625g.

a. 1,9 b. 2 c. 1,6 d. kt qu khcb) t chy Vcm3 hn hp A cho cc sn phm phn ng ln lt qua b nh 1 ng P2O5 v b nh 2 ng Ba(OH)2thy khi lng b nh 1 tng 2,34g v b nh 2 tng 7,04g. Xc nh cng thc phn t ca cc hidrocacbon bitrng c mt hidrocacbon l olefin.

a. C4H8 v C4H6 b. C4H8 v C4H4 c. C4H8 v C4H2 d. C ba cu a + b + cCu59. Cho 10 lit hn hp kh ( 54oC v 0,8064 atm) gm hai anken li qua b nh ng nc brom d thy


24/59


24

khi lng b nh nc brom tng ln 16,8g.a) Tnh tng s mol ca 2 anken.

a. 0,1 mol b. 0,2 mol c. 0,3 mol d. Kt qu khcb) Hy bin lun cc cp anken c th c trong hn hp kh ban u bit rng s nguyn t C trong mi ankenkhng qu 5.

a. C5H10 v C2H4 b. C5H10 v C3H6 c. C5H10 v C4H8 d. C hai cu a + b

Cu60. Cho 1232cm3

hn hp gm ankan A v anken B th kh ( s nguyn tC trong A, B nh nhau) vonc brom d thy khi lng b nh tng thm1,4g. t chy hon ton cht kh sau khi qua nc brom v chosn phm chy vo dung dch NaOH d thu c 180ml dung dch mui 0,5M. Cng thc phn t ca A, B l:

a. C2H4 v C2H6 b. C3H8 v C4H8 c. C4H8 v C5H12 d. C2H4 v C4H10Cu61. Mt hn hp gm ankan v ankin. t chy hon ton hn hp ny thu c 12,6g H2O. Khi lngoxi cn dung cho phn ng l 36,8g. Th tch CO2 sinh ra bng 8/3 th tch hn hp kh ban u.a) Tng s mol ca hn hp ban u l:

a. 0,3 mol b. 0,2 mol c. 0,4 mol d. Kt qu khcb) Xc nh cng thc cu to c th ca ankan v ankin.

a. C3H8 v C2H2 b. C2H6 v C3H4 c. C4H10 v C2H2 d. C hai cu b + cCu62. Mt hn hp gm hai hidrocacbon mch h. Cho 840ml hn hp li qua dung dch brom d th cn li560ml, ng thi c 2g Br2 tham gia phn ng. Ngoi ra nu t chy hon ton 840ml hn hp ri cho khCO2 qua dung dch Ca(OH)2 d th c 6,25g kt ta (cc kh o ktc).

Cng thc phn t ca 2 hidrocacbon l:a. CH4 v C4H10 b. C2H6 v C3H6 c. CH4 v C3H6 d. Kt qu khc

chuyn bi tp 05: ancol, anhit, xeton1/ bi tp ancolCu 1: C bao nhiu ancol no bc 2, n chc mch h, l ng phncu to ca nhau m phn t ca chngc phn trm khi lng C l : 68,18%Cu 2: Mt loi go cha 75% tinh bt. Ly 78,28 kg go ny i nu ru etylic , hiu sut pu ca c qutrnh l 60%. Khi lng ring ca ru etylic l 0,8 g/ml. Thtch ru thu c l?

Cu 3: t chy hon ton 27,6 gam hn hp X gm thu c 32,4 gamv V lt (ktc). Gi tr ca V l

Cu 4: Tch nc hn hp ng mol X gm metanol v etanol c c, thu c sn phm etev 1.8 gam nc vi hiu sut 70%.Khi lng hn hp X lCu 5: Oxi ha 6g ru n chc thu c 8,4g hn hp gm andehit, ru d v nc. Hiu sut phnng OXI ha ru t bao nhiu %Cu 6: Cho m gam mtancol no, n chc X qua bnh ng d nung nng.Sau khi phn ng hon ton.khi lng cht rn trong bnh gim 0.32g.Hn hp hi thu c c t khii vi l 15.5Cu 7: Cho 1,52g hn hp haiancol n chc l ng ngk tip nhau tc dng vi Na va , sau phn ngthu c 2,18g cht rn. Cng thc phn t ca haiancol lCu 8: Hn hp X gmancol metylic v ancol no, n chc A. Cho 7,6g X tc dng vi Na d thu c 1,68lt (ktc), mt khcoxi ha hon ton 7,6g X bng CuO ( ) ri cho ton b sn phm thu c tc dngvi dung dch d thu c 21,6g kt ta. Cng thc cu toca A l:Cu 9: t chy hon ton m gam hn hp X gm haiancol A v B thuc cng dy ng ngthu c 6,72 lt

v 7,65g . Mt khc khi cho m gam hn hp X tc dng vi Na d thu c 2,8 lt . Bit t

khihi ca mi cht so vi hiro u nh hn 40, cc th tch kh o ktc. A v B c cng thc phn t lnlt l

Cu 10: un 132,8g hn hp 3ancol no, n chc vi c thu c hn hp gm cc ete cs mol bng nhau v c khi lng l 111,2g. S mol ca mi ete trong hn hp l gi tr no di y ? Cu 11: t chy hon ton 0,3 mol hn hp Xgm 2 ru lin tip trong dy ng ngCu 24: Oxi ha ht0,2 mol ru n chc A, B lin tip trong dy ng ngbng CuO un nng c hn hp X gm 2 anhit.Cho X tc dng vi lng d dung dich c 54g bc. A, B l 2 ru no ?c v 0,5 mol . Cng thc phn t 2 ru trn ln lt l?
http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#bhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#bhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=733http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=733http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=733http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=708#lkhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=744#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=770#ahttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=770#ahttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=744#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=743#6http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=743#6http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#00http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#00http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=744#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=744#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=153#51http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=153#51http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=743#6http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=743#6http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=743#6http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=744#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=744#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=743#6http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=743#6http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=153#51http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=744#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#00http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=743#6http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=744#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=770#ahttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=770#ahttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=744#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=708#lkhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=733http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#bhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1


25/59


25

Cu 12: Dn 4g hi ru n chc A qua CuO nung nng c 5,6g hn hp hi. A l ru c cng thc cuto

Cu 13: Khi phn tch cht hu c A (cha C,H,O) th c . Ly hai ru n chc X,Y em un nng vi c nhit thch hp th thu c A.Cng thc (mch h) A, X, Y (bit A lete) l

Cu 14: Ru A tc dng vi d cho mt th tch bng vi th tch hi ru A dng. Mt khc tchy ht mt th tch hi ru A thu c cha n ba th tch kh (cc th tch o cng iu kin).Ru A c tn giCu 15: Mt hn hp X gm 2 ru no n chc A, B ng ngk tip. t chy 0,2 mol X cn 10,08 lt(dkc). Cng thc phn t v s mol ca A v B lCu 16: Hn hp A gm 2 ru. un nng m gam hn hp A vi m c, thu c 3,584 lt hn hp2 olefin k tip nhau trong dy ng ng(ktc). Nu em t chy ht lng olefin ny, ri cho hp th snphm chy trong bnh ng dung dch NaOH d, th khi lng bnh tng 24,18g. Cc phn ng xy ra honton. Tr s ca m lCu 17: Mt ru no a chc mch h X, c n nguyn t cacbon v m nhm . Cho 7,6 gam X phn ngvi d, thu c 0,1 mol kh . Biu thc lin h gia n v m lCu 18: Cho hn hp X gmancol etylic v ancol Y thuc dy ng ngcaancol etylic, cho 0.76 gam X tcdng ht vi Na thy thot ra 0,168 lt kh (kc), cho bit t l s mol caancol etylic v ancol Y l 2:1, cng

thc phn t caancol Y lCu 19: Hn hp ru X gm 2 ru no mch h A v B c cng s nguyn tC trong phn t. Chia 14.7gamX thnh 2 phn bng nhau:- Phn 1 tc dng ht vi Na to ra 1.68lit (ktc)- Phn 2 t chy hon ton, sinh ra 14,85gam khC my cp ru tho mn iu kin trnCu 20: t chy hon ton 5,6 lt hi 2 ru no, n chc thu c 7,84 lt (cc th tch u o ktc).Dn ton b sn phm chy vo bnh ng 200 ml dung dch 1,5M. Khi lng dung dch sau phnng so vi khi lng dung dchCu 21: Hn hp A gm 0,1 mol etylenglicol v 0,2 mol cht X . t chy hon ton hh A cn 21,28 lv thu c 35,2g v 19,8g .Tnh khi lng phn t X ( X cha C, H ,O)Cu 22: un nng mt hn hp gm 2 ru vi c thu c 21,6gam v 72gam hnhp 3 ete c s mol bng nhau. Cng thc hai ru l?Cu 23: Hn hp X gm 1 ancol v 2 sn phm hp nc ca propen. T khi hi ca X so vi hiro bng 23.Cho m gam X i qua ng s ng CuO (d) nung nng. Sau khi cc phn ng xy ra hon ton, thu c hnhp Y gm 3 cht hu c v hi nc, khi lng ng s gim 3,2 gam. Cho Y tc dng hon ton vi lngd dung dch AgNO3 trong NH3, to ra 48,6 gam Ag. Tnh phn trm khi lng ca propan-1-ol trong X

Cu 25: Cho 7,8 gam hn hp 2 ancol n chc k tip nhau trong dy ng ng tc dng ht vi 4,6 gam Nac 12,25 gam cht rn. Xc nh CTPT ca 2 ancolCu 29: un nng hn hp hai ankanol lin tip trong dy ng ng vi H2SO4c 140

0C, thu c 21,6gam H2O v 139,2 gam hn hp ba ete c s mol bng nhau.Xc nh CTPT ca hai ankanolCu 30 : un nng hn hp gm hai ru (ancol) n chc, mch h, k tip nhau trong dy ngng viH2SO4c 140

oC. Sau khi cc phn ng kt thc, thu c 6 gam hn hp gm ba ete v1,8 gam nc. Xcnh cng thc phn t ca hai ru trn

Cu 31 : un nng ancol n chc X vi H2SO4c 140oC thu c Y. T khi hi ca Y i vi X l1,4375. Xc nh CTPT ca XCu 32: Khi un nng mt ancol n chc no A vi H2SO4 c iu kin nhit thch hp thu c snphm B c t khi hi so vi A l 0,7. Xc nh cng thc ca A.Cu 33: Cho 12,9g hn hp 3 ancol no, n chc, mch htham gia phn ng tch nc iu kin thch hpthu c hn hp X gm 2 kh l ng ng k tip, c t khi so vi hn hp ancol ban u l 0,651a. Xc nh CTPT ca cc ancol
http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=153#51http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=153#51http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=153#51http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=142#55http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=920http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#2http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#2http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#2http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#2http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#2http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#2http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=142#55http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=142#55http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=142#55http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#2http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#2http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#1http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=709#2http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=920http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=142#55http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=702#jhttp://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=153#51http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=153#51


26/59


26

b. Nu cho ton blng ancol trn phn ng vi CuO un nng, sn phm thu c cho tc dng vi lng dddAgNO3/NH3 d thu c 37,8g kim loi bc. Xc nh phn trm khi lng mi ancol trong hn hp banucu 34: t chy han tan m gam hn hp X gm ba ancol (n chc, thuc cng dy ng ng), thu c8,96 lt kh CO2(ktc) v 11,7 gam H2O. Mt khc, nu un nng m gam X vi H2SO4c tnh tng khi lngete ti a thu

Tong Hop Cac Chuyen de Luyen Thi Dai Hoc Hoa Hocmoi

Documents

Transcript of Tong Hop Cac Chuyen de Luyen Thi Dai Hoc Hoa Hocmoi