TM 661 Engineering Economics for Managers

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TM 661 Engineering Economics for Managers Break Even & Sensitivity

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TM 661 Engineering Economics for Managers. Break Even & Sensitivity. Motivation. Suppose that by investing in a new information system, management believes they can reduce inventory costs. Your boss asks you to figure out if it should be done. 25,000. 1 2 3 4 5. 100,000. - PowerPoint PPT Presentation

Transcript of TM 661 Engineering Economics for Managers

Page 1: TM 661 Engineering Economics for Managers

TM 661Engineering Economics

forManagers

Break Even &Sensitivity

Page 2: TM 661 Engineering Economics for Managers

Motivation

Suppose that by investing in a new information system, management believes they can reduce inventory costs. Your boss asks you to figure out if it should be done.

Page 3: TM 661 Engineering Economics for Managers

Motivation

Suppose that by investing in a new information system, management believes they can reduce inventory costs. After talking with software vendors and company accountants you arrive at the following cash flow diagram.

1 2 3 4 5

100,000

25,000

i = 15%

Page 4: TM 661 Engineering Economics for Managers

Motivation

Suppose that by investing in a new information system, management believes they can reduce inventory costs. After talking with software vendors and company accountants you arrive at the following cash flow diagram.

1 2 3 4 5

100,000

25,000

NPW = -100 + 25(P/A,15,5) = -16,196

i = 15%

Page 5: TM 661 Engineering Economics for Managers

Motivation

Suppose that by investing in a new information system, management believes they can reduce inventory costs. After talking with software vendors and company accountants you arrive at the following cash flow diagram.

1 2 3 4 5

100,000

25,000

NPW = -100 + 25(P/A,15,5) = -16,196

i = 15%

Page 6: TM 661 Engineering Economics for Managers

MotivationBoss indicates $25,000 per year savings is too low & is based on current depressed market. Suggests that perhaps $40,000 is more appropriate based on a more aggressive market.

1 2 3 4 5

100,000

40,000

Page 7: TM 661 Engineering Economics for Managers

MotivationBoss indicates $25,000 per year savings is too low & is based on current depressed market. Suggests that perhaps $40,000 is more appropriate based on a more aggressive market.

1 2 3 4 5

100,000

40,000

NPW = -100 + 40(P/A,15,5) = 34,086

Page 8: TM 661 Engineering Economics for Managers

MotivationBoss indicates $25,000 per year savings is too low & is based on current depressed market. Suggests that perhaps $40,000 is more appropriate based on a more aggressive market.

1 2 3 4 5

100,000

40,000

NPW = -100 + 40(P/A,15,5) = 34,086

Page 9: TM 661 Engineering Economics for Managers

MotivationTell your boss, new numbers indicate a go. Boss indicates that perhaps he was a bit hasty. Sales have fallen a bit below marketing forecast, perhaps a 32,000 savings would be more appropriate

1 2 3 4 5

100,000

32,000

Page 10: TM 661 Engineering Economics for Managers

MotivationTell your boss, new numbers indicate a go. Boss indicates that perhaps he was a bit hasty. Sales have fallen a bit below marketing forecast, perhaps a 32,000 savings would be more appropriate

1 2 3 4 5

100,000

32,000

NPW = -100 + 32(P/A,15,5) = 7,269

Page 11: TM 661 Engineering Economics for Managers

MotivationTell your boss, new numbers indicate a go. Boss indicates that perhaps he was a bit hasty. Sales have fallen a bit below marketing forecast, perhaps a 32,000 savings would be more appropriate

1 2 3 4 5

100,000

32,000

NPW = -100 + 32(P/A,15,5) = 7,269

Page 12: TM 661 Engineering Economics for Managers

Motivation

Tell your boss, new numbers indicate a go. Boss leans back in his chair and says, you know . . . .

Page 13: TM 661 Engineering Economics for Managers

Motivation

Tell your boss, new numbers indicate a go. Boss leans back in his chair and says, you know . . . .

I’ll do anything, justtell me what numbersyou want to use!

Page 14: TM 661 Engineering Economics for Managers

Motivation

1 2 3 4 5

100,000

A

NPW = -100 + A(P/A,15,5) > 0

Page 15: TM 661 Engineering Economics for Managers

Motivation

1 2 3 4 5

100,000

A

NPW = -100 + A(P/A,15,5) > 0

A > 100/(A/P,15,5) > 29,830

Page 16: TM 661 Engineering Economics for Managers

A < 29,830

A > 29,830

Motivation

1 2 3 4 5

100,000

A

Page 17: TM 661 Engineering Economics for Managers

Break-Even Analysis

Site Fixed Cost/Yr Variable CostA=Austin $ 20,000 $ 50 S= Sioux Falls 60,000 40 D=Denver 80,000 30

TC = FC + VC * X

Page 18: TM 661 Engineering Economics for Managers

Break-Even (cont)Break-Even Analysis

0

50,000

100,000

150,000

200,000

250,000

0 500 1,000 1,500 2,000 2,500 3,000 3,500 4,000

Volume

To

tal

Co

st

Austin

S. Falls

Denver

Page 19: TM 661 Engineering Economics for Managers

Class Problem A firm is considering a new product line and the following data have been recorded:

Sales price $ 15 / unitCost of Capital $300,000Overhead $ 50,000 / yr.Oper/maint. $ 50 / hr.Material Cost $ 5 / unitProduction 50 hrs / 1,000 unitsPlanning Horizon 5 yrs.MARR 15%

Compute the break even point.

Page 20: TM 661 Engineering Economics for Managers

Class Problem

Profit Margin = Sale Price - Material - Labor/Oper.

= $15 - 5 - $50 / hr

= $ 7.50 / unit

50 hrs1000 units

Page 21: TM 661 Engineering Economics for Managers

Class Problem

Profit Margin = Sale Price - Material - Labor/Oper.

= $15 - 5 - $25 / hr

= $ 7.50 / unit

50 hrs1000 units

1 2 3 4 5

300,000

7.5X

50,000

Page 22: TM 661 Engineering Economics for Managers

Class Problem

Profit Margin = Sale Price - Material - Labor/Oper.

= $15 - 5 - $25 / hr

= $ 7.50 / unit

50 hrs1000 units

1 2 3 4 5

300,000

7.5X

50,000

300,000(A/P,15,5) + 50,000 = 7.5X

139,495 = 7.5X

X = 18,600

Page 23: TM 661 Engineering Economics for Managers

Suppose we consider the following cash flow diagram:

NPW = -100 + 35(P/A,15,5) = $ 17,325

Sensitivity

1 2 3 4 5

100,000

35,000

i = 15%

Page 24: TM 661 Engineering Economics for Managers

Suppose we don’t know A=35,000 exactly but believe we can estimate it within some percentage error of + X.

Sensitivity

1 2 3 4 5

100,000

35,000(1+X) i = 15%

Page 25: TM 661 Engineering Economics for Managers

Then,

EUAW = -100(A/P,15,5) + 35(1+X) > 0

35(1+X) > 100(.2983)

X > -0.148

Sensitivity

1 2 3 4 5

100,000

35,000(1+X)

i = 15%

Page 26: TM 661 Engineering Economics for Managers

Sensitivity (cont.)NPV vs. Errors in A

(20,000)

(10,000)

0

10,000

20,000

30,000

40,000

50,000

-0.30 -0.20 -0.10 0.00 0.10 0.20

Error X

NP

V

Page 27: TM 661 Engineering Economics for Managers

Now suppose we believe that the initial investment might be off by some amount X.

Sensitivity (Ao)

1 2 3 4 5

100,000(1+X)

35,000

i = 15%

Page 28: TM 661 Engineering Economics for Managers

Sensitivity (Ao)NPV vs Initial Cost Errors

(20,000)

(10,000)

0

10,000

20,000

30,000

40,000

50,000

-0.30 -0.20 -0.10 0.00 0.10 0.20

Error X

NP

V

Page 29: TM 661 Engineering Economics for Managers

Sensitivity (A & Ao)

NPV vs Errors

(20,000)

(10,000)

0

10,000

20,000

30,000

40,000

50,000

-0.30 -0.20 -0.10 0.00 0.10 0.20

Error X

NP

V

Errors in initial cost

Errors in Annual receipts

Page 30: TM 661 Engineering Economics for Managers

Now suppose we believe that the planning horizon might be shorter or longer than we expected.

Sensitivity (PH)

1 2 3 4 5 6 7

100,000

35,000i = 15%

Page 31: TM 661 Engineering Economics for Managers

Sensitivity (PH)NPV vs Planning Horizon

(30,000)

(20,000)

(10,000)

0

10,000

20,000

30,000

40,000

50,000

0 1 2 3 4 5 6 7

NPV

PH

Page 32: TM 661 Engineering Economics for Managers

Sensitivity (Ind. Changes)

NPV vs Errors

(20,000)

(10,000)

0

10,000

20,000

30,000

40,000

50,000

-0.30 -0.20 -0.10 0.00 0.10 0.20

Error X

NP

V

Errors in initial cost

Errors in Annual receipts

n=3

n=7

Planning Horizon

MARR

Page 33: TM 661 Engineering Economics for Managers

Multivariable Sensitivity

Suppose our net revenue is composed of $50,000 in annual revenues which have an error of X and $20,000 in annual maint. costs which might have an error of Y (i=15%).

1 2 3 4 5

100,000

50,000(1+X)

20,000(1+Y)

Page 34: TM 661 Engineering Economics for Managers

Multivariable Sensitivity

Suppose our net revenue is compose of $50,000 in annual revenues which have an error of X and $20,000 in annual maint. costs which might have an error of Y (i=15%).

1 2 3 4 5

100,000

50,000(1+X)

20,000(1+Y)

Multivariable SensitivitySuppose our net revenue is compose of $50,000 in annualrevenues which have an error of X and $20,000 in annualmaint. costs which might have an error of Y.

1 2 3 4 5

100,000

50,000(1+X)

20,000(1+Y)

You Solve It!!!

You Solve It!!!

Page 35: TM 661 Engineering Economics for Managers

Multivariable Sensitivity

EUAW = -100(A/P,15,5) + 50(1+X) - 20(1+Y) > 0

50(1+X) - 20(1+Y) > 29.83

1 2 3 4 5

100,000

50,000(1+X)

20,000(1+Y)

Page 36: TM 661 Engineering Economics for Managers

Multivariable Sensitivity

EUAW = -100(A/P,15,5) + 50(1+X) - 20(1+Y) > 0

50(1+X) - 20(1+Y) > 29.83

50X - 20Y > -0.17

X > 0.4Y - 0.003

1 2 3 4 5

100,000

50,000(1+X)

20,000(1+Y)

Page 37: TM 661 Engineering Economics for Managers

Multivariable Sensitivity

Simultaneous Errors (Rev. vs. Cost)

-0.4

-0.3

-0.2

-0.1

0

0.1

0.2

0.3

0.4

-0.15 -0.1 -0.05 0 0.05 0.1 0.15

Error X

Err

or Y

Unfavorable

Favorable

+ 10%

Page 38: TM 661 Engineering Economics for Managers

Mutually Exclusive Alt.

Suppose we work for an entity in which the MARR is not specifically stated and there is some uncertainty as to which value to use. Suppose also we have the following cash flows for 3 mutually exclusive alternatives.t A1t A2t A3t

0 (50,000) (75,000) (100,000)1 18,000 25,000 32,000 2 18,000 25,000 32,000 3 18,000 25,000 32,000 4 18,000 25,000 32,000 5 18,000 25,000 32,000

Page 39: TM 661 Engineering Economics for Managers

Mutually Exclusive Alt.t A1t A2t A3t

0 (50,000) (75,000) (100,000)1 18,000 25,000 32,000 2 18,000 25,000 32,000 3 18,000 25,000 32,000 4 18,000 25,000 32,000 5 18,000 25,000 32,000 MARR = NPV1 NPV2 NPV3

4.0% 30,133 36,296 42,458 6.0% 25,823 30,309 34,796 8.0% 21,869 24,818 27,767 10.0% 18,234 19,770 21,305 12.0% 14,886 15,119 15,353 14.0% 11,795 10,827 9,859 16.0% 8,937 6,857 4,777 18.0% 6,289 3,179 69 20.0% 3,831 (235) (4,300)

Page 40: TM 661 Engineering Economics for Managers

Mutually Exclusive Alt.

NPV vs. MARR

(10,000)

0

10,000

20,000

30,000

40,000

50,000

0.0% 5.0% 10.0% 15.0% 20.0%

MARR

NP

V

NPV1

NPV2

NPV3