TIKUNGAN HUSNUL

8/16/2019 TIKUNGAN HUSNUL

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Perencanaan Jalan

1. Trase (garis arah)2. Menetukan koordinat

Langkah - langkah pencarian koordinat

1. Titik A : = 59 ! 1"#9 (25) atau

= $% - "9 (25) =

: = $1 - "9 (25) =

= $5 ! "$ (25) =

: = $% ! 1 (25) =

= $$ - "95 (25) =

: = $5 ! 1"$# (25) =

= $& - 1 (25) =

: = $& ! 1"&' (25) =

= $' ! "& (25) =

%. Menetukan arak

=

= 19$& . $ ! 5$# $.25= 2&5.'2

=

= %9 $.25 ! 11'2$.5$25= 225.#$

=

= & &5$ ! 2$2$.5$25= 2& .'9

=

= #1#12.25 ! 2 % $.25= 2#'.#%

* A+ A

2. Titik , 1 * 1+ 1

%. Titik , 2 * 2+ 2

#. Titik , % * %+ %

5. Titik , *

+

d A / , 1

d , 1 / , 2

d , 2 / , %

d , % /


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Tc = 5$"& 2 )c = #"

c = 11T 2

3a)4ar Lengkun

Ls6 = 5 )

7u)4u8alan

en= -29

%:# Ls6

T 2

1 :# Ls6

-29 -29

-29%"559

Lengku ng pe ralihan


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1'0Tc = 5$"& 2 )c = #" #$% )

c = 112"##' ) T 2

3a)4ar Lengkung ull ircle , 2

Ls6 = 5 )

Lc = 112.##' )

4un

= -29

%:# Ls6 %:# Ls6

Ls6 = 5 )

1:# Ls6

T 2 T 2

1 :# Ls6

-29

-29%"559

Lengku ng peralihan Lengkung peralihanagian Lengkung

5"#9

;iagra) super ele


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4.

= arc tan-

± arc tan-

- -

= arc tan6077.5 - 5937.25

± arc tan6275 -

6515 - 6277.5 6623.75 -

= arc tan 0.5905263 ± arc tan 1.8161

= 30.5630 ± 61.1614

= 91.7243 ° (+)= -30.5984 ° (-)

= arc tan - ± arc tan -- -

= arc tan6275 - 6077.5

± arc tan6541 -

6623.75 - 6515 6675 -

= arc tan 1.816092 ± arc tan 5.1902= 61.1614 ± 79.0945

= 140.256 ° (+)= -17.9331 ° (-)

= arc tan-

± arc tan-

- -

= arc tan6541 - 6275

± arc tan6744.5 -

6675 - 6623.75 6817.5 -

= arc tan 5.1902439 ± arc tan 1.4281= 79.0945 ± 54.9985

= 134.093 ° (+)= 24.0960 ° (-)

Menentukan Sudut Putar ( )

P! 1" 1 " # " 2$ 1 $ # $ 2

P! 2 "2 " 1 " 3

$ 2 $ 1 $ 3

P! 3" 3 " 2 " %$ 3 $ 2 $ %


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6077.56515

62756623.75

65416675

" 1$ 1

" 2$ 2

" 3$ 3


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;irencanakan Lengkungan ull ircle ( )

;ata-data perencanaanlasi>ikasi alan = olektor

? = 1' ⁰

ecepatan rencana (@ ) = $ k aLe4ar alan = &.Le4ar 4ahu = 1.5

in = %5 rencana = %5'

B aC = . 5# Ta4el #.&Ls = 5 Ta4el #.&

Tc = c D tan D? 2 == 5$.& 2

c = Tc D tan (? #)= 5$"& 2 C tan #"5= #.#$%

Lc == . 1 C 1' C %5'

= 112.##'

7Earat untuk lengkungan ontrol =

= 112.##' F 11%.# %259 Gke

Lengkungan Horizontal II (PI 2)

%5' & tan 9

. 1 C ' C c

Lc F 2 & c


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Menggunakan lengkung 4usur lingkaran d

;ata-data perencanaanlasi>ikasi alan =

? =ecepatan rencana (@ ) =

Le4ar alan =Le4ar 4ahu =

in = rencana =

B aC =Ls =

H esar sudut spiral* == 5 C 9 %.1# C 2 5= $.991

H esar sudut pusar lingkaran== % "$ - 2($"991)= 1$.$1' ⁰

H,an ang Lengkung ircleLc =

= 1$"5$' %$ C 2 C%.1= 59.#29

L = Lc ! 2 Ls= 59"25 ! 2 C 5= 159.#29

, === 2. %252 %252 -= .5 '

k = Ls - (LsI% # C cI= 5 -= 2#.9&5

Lengkungan Horizontal I (PI 1)

Ls C 9 , C c

' c ' - 2 Js

?c %$ C 2, c

Ls $ C c - c(1-5 $C2 5 -2 5 (1-


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Ts == (2 5! "5 ') tan 15"= '1.19$

s = ( c!,) sec ? 2 - c= 21%. 59'$&1$ -= '. $

ontrolL F 2 Ts

159.#29 F 1$2.%91#$2&

( c!,) tan ' 2 ! k


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engan lengkung peralihan (spiral - lingkaran - spiral )

olektor % "$⁰

$ k a&.1.51152 5

. ' Ta4el #.&5 Ta4el #.&

C 2 5

1.52# ##''

) - ( c sin Js). %$ 5 - 2#.95 $$51199

os Js)os $"991)


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! 2#"9&5

2 5

Gke


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Menggunakan lengkung 4usur lingkaran dengan lengkung peralihan (spiral - ling

;ata-data perencanaanlasi>ikasi alan = olektor

? = 2#"512 ⁰

ecepatan rencana (@ ) = $ k aLe4ar alan = &.Le4ar 4ahu = 1.5

in = 115 rencana = %1'

B aC = . 59 Ta4el #.&Ls = 5 Ta4el #.&

H esar sudut spiral* == 5 C 9 %.1# C %1'= #.5 &

H esar sudut pusar lingkaran== 2#"512 - 2(#.5 &)= 15.#99 ⁰

H,an ang Lengkung ircleLc =

= 15"#99 %$ C 2 C%.1# C %1'= '5.9&$

L = Lc ! 2 Ls= '5"9&$ ! 2 C 5= 1'5.9&$

, === 1.%1 2&25%$& - .9'%19##'= .%2&

k == 5 - . % 9 2$5 - 2#.9'$'9$9= 2#.9'2

Lengkungan Horizontal III (PI 3)

Ls C 9 , C c

' c ' - 2 Js

?c %$ C 2, c

Ls $ C c - c(1- os Js)5 $C%1' -%1' (1- os #.5 &)

Ls - (Ls % # C cI2) - ( c sin Js)


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Ts == (%1'! . .%2&) tan 12"25$ ! 2#.9'2= 9#.1%%

s = ( c!,) sec ? 2 - c= %25.&51%1#&%'' - %1'= &.&51

ontrolL F 2 Ts

1'5.9&$ F 1''.2$5%'%19'

( c!,) tan ' 2 ! k


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Jarak Pandang Henti

= 60 k / a

n = 75 (ta e )t = 2.5 det k

= -0.000625 + 0 192= 0.1542

= 0 278 + t= 41.7

=

= 91.91

d == 133.61

:ntr:d ; n

133.61 ; 75

Jarak Pandang Menyiap

= 60 k / a

= 15 k / a (k:n*tantan)

ar atan ( )

t 1

d 1 0 278 t 1 ( - + (a t 1 /2))

t2


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== 157.4592

= 80 (keteta>an)

== 104.9728

d == 392.7381

d 2 0 278 t 2

d 3

d 4 2/3 d 2

d 1 + d 2 + d 3 + d 4


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Perhitungan Diagram uperele!a"i

= 60 k / a

< rencana = 205e n:r a = 2 ?e ak* = 8 ?@e ar a an = 7A eBa* #* a an = 1365

Ak a a = A eBa* #* Ca an - 1/2 % e ak*= 1365 - 1/2 7 0 08= 1364.72

Ak enDaE = A eBa* #* Ca an - e n:r a= 1365 - 0 02= 1364.98

Ak @uar = A eBa* #* Ca an + 1/2 % e ak*= 1365 + 1/2 7 08= 1365.28

= 60 k / a< rencana = 358e n:r a = 2 ?e ak* = 5.4 ?@e ar a an = 7A eBa* #* a an = 1373



Ak @uar = A eBa* #* Ca an + 1/2 % e ak*= 1373 + 1/2 7 0 054= 1373.189

= 60 k / a

Tikungan PI 1 (S-C-S)

<

Tikungan PI 2 (FC)

<

Tikungan PI 3 (S-C-S)


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< rencana = 115e n:r a = 2 ?e ak* = 5.9 ?@e ar a an = 7A eBa* #* a an = 1368



Ak @uar = A eBa* #* Ca an + 1/2 % e ak*= 1368 + 1/2 7 0 059= 1368.207

TIKUNGAN HUSNUL

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