Tibre table of contents
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Transcript of Tibre table of contents
Table Of Contents
A. Determining the minimum number of lighting branch circuits: 3
Maximum power based on the Total Floor Area:..............................................................................................................4
BRANCH CIRCUIT CALCULATIONS..........................................................................................................................................6
BRANCH CIRCUIT NO. 1(General Purpose Branch Circuit).................................................................................................6
BRANCH CIRCUIT NO. 2 (General Purpose Branch Circuit)................................................................................................7
BRANCH CIRCUIT NO. 3 ((small) Appliance Branch Circuit)...............................................................................................9
BRANCH CIRCUIT NO. 4(Individual Branch Circuit)..........................................................................................................11
BRANCH CIRCUIT NO. 5(Individual Branch Circuit)..........................................................................................................12
BRANCH CIRCUIT NO. 6(Individual Branch Circuit)..........................................................................................................14
Load Summary:...................................................................................................................................................................16
TotalConnected Load=7,601Watts................................................................................................................................18
MATERIALS& NUMBER OF QUANTITIES..............................................................................................................................21
Single Line Diagram.............................................................................................................................................................23
A. Determining the minimum number of lighting branch circuits:
“The NEC tells us that the minimum load requirement for dwelling units is 3volt−amperes(VA ) per square ft (0.093m2) of occupied area.”
Conversion Unit:
1 ft=0.3048m
CALCULATIONS:
15m( 1 ft0.3048m )=49.21 ft
18m( 1 ft0.3048m )=59.05 ft
The estimated Floor Area:
AT=Lenght X Widht=49.21 ft X59.05 ft=2,906.25 ft2≈270m2
Scale Conversion:
5m¿
10m¿
3m¿
Floor Area18m (59.05ft)
15m (49.21ft)
Scale :1.5∈. :0.5m1∈.: 0.33m3∈. :1m
6m ¿Steps to determine the minimum number of 15-ampere lighting branch circuits required for a residence:
Calculations:
N L=3VA x AT
220V∙115 A
N L=3VA x2,906.25 ft2
220V∙115 A
N L=2.642≈3 lighting Branchcircuit
Comment:
Maximum power based on the Total Floor Area:Wattage required per square meter for dwelling unit:
24watts
m2
The maximum power in watts needed for lighting with an Total Floor Area AT=270m2=2,906.25 ft2 .
Pmax=AT x 24W /m2=270m2 x24W
m2=6,480Watts
Comments:
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A minimum of not less than three 15-A lighting branch circuits is required. (Below 3 branches is not safe!)
300W + 400W = 700W is the maximum power for lighting branch circuits which is still below thePmax=6,480Watts .The 700W maximum lighting power is safe to use.
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BRANCH
CIRCUIT
CALCULATION
BRANCH CIRCUIT CALCULATIONS
BRANCH CIRCUIT NO. 1(General Purpose Branch Circuit)Lighting Load (3 lighting outlets)
Calculation no.1The Maximum Power Load For 3 Lighting Outlets:
“The NEC provides that “100 watts shall be the maximum load for each household lighting outlet.”
therefore:
3 lighting outlets x100W max
lighting outlets=300W max
Comment:
Calculation no.2The Maximum Total Current Load:
recall: P=VI
300W max
220V=1.36 Amax
Comment:
Calculation no.3The Size Of The Conductor or Wire Needed For This Branch:
Refer to tables: 2-5 and 4-2Maximum expected current load: 1.36 Amax
Use:Wire No.:#14AWG copper wireWire Diameter:2.0 mm2
Wire Type:TW, THW, or THWNNo. of pieces of wire needed:2 pcs.Wire Temperature Rating:60 C(140 F) or 75 C(167 F)
Comment:
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The 300W is the maximum power expected when all 3 lights operates at the same time.
The 1.36-A current is the maximum current expected when all 3 lights operates at the same time.
Calculation no.4The Size Of The Conduit Pipe To Accommodate The Wires In Calculation No.3:
Refer to tables: 2-9No. of pieces of wire needed:2 pcs.Use:
Conduit Diameter:13 mm dia.Maximum number of wire can accommodate:3Size of wire: # 14
Comment:
Calculation no.5The Size or Rating Of Over Current Fuse/Circuit Breaker Protection:
Refer to Tables: 4-1Maximum expected current load: 1.36 Amax
Use: Fuse/Breaker Rating:15-AReceptacle Rating:Not over 15-AMaximum load the fuse/breaker can carry:12 A(non-continuous), 8 A(continuous)
Comment:
BRANCH CIRCUIT NO. 2 (General Purpose Branch Circuit)Lighting Load (4 lighting outlets)
Calculation no.1The Maximum Power Load For 4 Lighting Outlets:
“The NEC provides that “100 watts shall be the maximum load for each household lighting outlet.”
therefore:
4 lighting outlets x100W max
lighting outlets=400W max
Comment:The 300W is the maximum power expected when all 3 lights operates at the same time.
Calculation no.2The Maximum Total Current Load:
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recall: P=VI
400W max
220V=1.81 Amax
Comment:
Calculation no.3The Size Of The Conductor or Wire Needed For This Branch:
Refer to tables: 2-5 and 4-2Maximum expected current load: 1.81 Amax
Use:Wire No.:#14AWG copper wireWire Diameter:2.0 mm2
Wire Type:TW, THW, or THWNNo. of pieces of wire needed:2 pcs.Wire Temperature Rating:60 C(140 F) or 75 C(167 F)
Comment:
Calculation no.4The Size Of The Conduit Pipe To Accommodate The Wires In Calculation No.3:
Refer to tables: 2-9No. of pieces of wire needed:2 pcs.Use:
Conduit Diameter:13 mm dia.Maximum number of wire can accommodate:3Size of wire: # 14
Comment:
Calculation no.5The Size or Rating Of Over Current Fuse/Circuit Breaker Protection:
Refer to Tables: 4-1Maximum expected current load: 1.81 Amax
Use: Fuse/Breaker Rating:15-AReceptacle Rating:Not over 15-AMaximum load the fuse/breaker can carry:12 A(non-continuous), 8 A(continuous)
Comment:
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The 1.81-A current is the maximum current expected when all 4 lights operates at the same time.
BRANCH CIRCUIT NO. 3 ((small) Appliance Branch Circuit)Convenience Receptacles Load (8 convenience receptacles outlets)
Calculation no.1Counting the total number of plugs in all receptacle outlets:
“The NEC provides that “for each single receptacle shall be considered at no less than 180 watts rating.”
Pmax=not less than180Watts
plug∨gang
Pmax<180W
plug∨gang
therefore:
8outlets x2 gang=16 pieces
Comment:
Calculation no.2The Total EstimatedPower Load:
No . of pieces x180W /gang∨outlet
hence,
16 x180watts /gang∨outlet=2,880watts
Comment:
Calculation no.3The Maximum Expected Current Load:
recall: P=VI thus ,⇒ I= PV
2,880W max
220V=13.09 Amax
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The total number of plugs or gang in all receptacle outlets is 16 pieces.
The power value 2,880 watts is the maximum power the 8 convenience receptacle outlets can handle. The branch circuit no. 3 is not safe above this value.
Comment:
Calculation no.4The Size Of The Conductor or Wire Needed For This Branch:
Refer to tables: 2-5 and 4-2Maximum expected current load: 13.09 Amax
Use:Wire No.:#12AWG copper wireWire Diameter:3.5 mm2
Wire Type:TW, THW, or THWNNo. of pieces of wire needed:2 pcs.Wire Temperature Rating:60 C(140 F) or 75 C(167 F)
Comment:
Calculation no.5The Size Of The Conduit Pipe To Accommodate The Wires In Calculation No.4:
Refer to tables: 2-9No. of pieces of wire needed: 2 pcs.Use:
Conduit Diameter:13 mmMaximum number of wire can accommodate:2 pcs.Size of wire:#12AWG copper wire
Comment:
Calculation no.6The Size or Rating Of Over Current Fuse/Circuit Breaker Protection:
Refer to Tables: 4-1Maximum expected current load: 13.09 Amax
Use: Fuse/Breaker Rating:20-AReceptacle Rating:15 A or 20 AMaximum load the fuse/breaker can carry:16-A(non-continuous and Continuous)
Comment:
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Derated value of 15-A is 15 x 0.80 = 12 A. 13.09A12A, thus, use #12 AWG wire conductor. The NEC Code specifically mandated the use of 3.5 mm2 or no.12AWG copper wire as the minimum size for all types of convenience outlet wiring.
Branch Circuit Nos. 4, 5, and 6 are for the other loads (Heavy Loads), which are categorized as Individual Branch Circuits .
BRANCH CIRCUIT NO. 4(Individual Branch Circuit)Refrigerator and Water Heater Load (only 1 outlet)
Calculation no.1The Total EstimatedPower Load (Total maximum power output of the machines):
1-unit Refrigerator @ 0.175 kW = 175 Watts1-unit Water Heater @ 2 kW = 2,000 Watts
Total load: 2,175 Watts
Comment:
Calculation no.2The Maximum Expected Current Load:
recall: P=VI thus ,⇒ I= PV
2,175W max
220V=9.89 Amax
Comment:
Calculation no.3The Size Of The Service Conductor or Wire Needed For This Branch:
Refer to tables: 2-5 and 4-2Maximum expected current load: 9.89 Amax
Use:Wire No.:#12AWG copper wireWire Diameter:3.5 mm2
Wire Type:TW, THW, or THWNNo. of pieces of wire needed:2 pcs.Wire Temperature Rating:60 C(140 F) or 75 C(167 F)
Comment:
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Calculation no.4The Size Of The Conduit Pipe To Accommodate The Wires In Calculation No.3:
Refer to tables: 2-9No. of pieces of wire needed: 2 pcs.Use:
Conduit Diameter:13 mmMaximum number of wire can accommodate:2 pcs.Size of wire:#12AWG copper wire
Comment:
Calculation no.6The Size or Rating Of Over Current Fuse/Circuit Breaker Protection:
Refer to Tables: 4-1Maximum expected current load: 9.89 Amax
Use: Fuse/Breaker Rating:20-AReceptacle Rating:15 A or 20 AMaximum load the fuse/breaker can carry:16-A(non-continuous and Continuous)
Comment:
BRANCH CIRCUIT NO. 5(Individual Branch Circuit)Electric STOVE Load (only 1 outlet)
Calculation no.1The Total EstimatedPower Load (Total maximum power output of the machines):
1-unit Electric Stove @ 1.1 kW= 1,100 WattsTotal load: 1,100 Watts
Comment:
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Calculation no.2The Maximum Expected Current Load:
recall: P=VI thus ,⇒ I= PV
1,100W max
220V=5 Amax
Comment:
Calculation no.3The Size Of The Service Conductor or Wire Needed For This Branch:
Refer to tables: 2-5 and 4-2Maximum expected current load: 5 Amax
Use:Wire No.:#12AWG copper wireWire Diameter:3.5 mm2
Wire Type:TW, THW, or THWNNo. of pieces of wire needed:2 pcs.Wire Temperature Rating:60 C(140 F) or 75 C(167 F)
Comment:
Calculation no.4The Size Of The Conduit Pipe To Accommodate The Wires In Calculation No.3:
Refer to tables: 2-9No. of pieces of wire needed: 2 pcs.Use:
Conduit Diameter:13 mmMaximum number of wire can accommodate:2 pcs.Size of wire:#12AWG copper wire
Comment:
Calculation no.6The Size or Rating Of Over Current Fuse/Circuit Breaker Protection:
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Refer to Tables: 4-1Maximum expected current load: Use:
Fuse/Breaker Rating:20-AReceptacle Rating:15 A or 20 AMaximum load the fuse/breaker can carry:16-A(non-continuous and Continuous)
Comment:
BRANCH CIRCUIT NO. 6(Individual Branch Circuit)Air Conditioning Equipment Load (only 1 outlet per unit)
Calculation no.1The Total EstimatedPower Load (Total maximum power output of the machines):
Air-con rating:1horsepower or 1hpConversion Unit: 1 hp = 746 Watts
thus,
1-unit Air Conditioning @ 0.746 kW= 746 WattsTotal load: 746 Watts
Comment:
Calculation no.2The Maximum Expected Current Load:
recall: P=VI thus ,⇒ I= PV
746W max
220V=3.4 Amax
Article 6.7 of the Philuppine Electrical Code (PEC) provides that : “Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of the full load current.”
thus,
3.4 Amax x125%=4.25 A125%ampacity
Comment:
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Calculation no.3The Size Of The Service Conductor or Wire Needed For This Branch:
Refer to tables: 2-5 and 4-2Maximum expected current load: 4.25 A125%ampacity
Use:Wire No.:#12AWG copper wireWire Diameter:3.5 mm2
Wire Type:TW, THW, or THWNNo. of pieces of wire needed:2 pcs.Wire Temperature Rating:60 C(140 F) or 75 C(167 F)
Comment:
Calculation no.4The Size Of The Conduit Pipe To Accommodate The Wires In Calculation No.3:
Refer to tables: 2-9No. of pieces of wire needed: 2 pcs.Use:
Conduit Diameter:13 mmMaximum number of wire can accommodate:2 pcs.Size of wire:#12AWG copper wire
Comment:
Calculation no.6The Size or Rating Of Over Current Fuse/Circuit Breaker Protection:
PEC Code on branch circuit protection for a single motor provides that: “It shall be increased by 250% of the full load current of the motor.”
thus,
3.4 Amax x250%=8.5 A250% increase
Refer to Tables: 4-1Maximum expected current load: 8.5 A250% increase
Use: Fuse/Breaker Rating:30-A
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A current load of 4.25-A can be served by a 2pcs., N0.14 TW copper wire, but the PEC Code limits the size of the convenience outlet to No.12AWG copper wire. Specify No. 12 THW copper wire for branch circuit no.6.
Receptacle Rating:30 AMaximum load the fuse/breaker can carry:24-A(non-continuous ) and 12-A (Continuous)
Comment:
Load Summary:
BRANCH CIRCUIT NO .1⇒Lighting outlets(3)BRANCH CIRCUIT NO .2⇒Lighting outlets (4 )BRANCH CIRCUIT NO .3⇒Convenience Receptacle outlets (8 )BRANCH ∘UIT NO .4⇒Refrigerator (1 )∧Water Heater (1 ) outletsBRANCH CIRCUIT NO .5⇒ Electric Stove outlet (1 )BRANCH CIRCUIT NO .6⇒ Aircon outlet(1)
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For continuous load use 2- 30A trip breaker.
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Calculation for the Size
and Ampaci
ty of the
Service Entran
ce& Main
Disconnecting Means
CALCULATING THE SIZE AND AMPACITY OF THE SERVICE ENTRANCE CONDUCTOR AND THE MAIN DISCONNECTING MEANSSize of supply conductor and equipment for delivering energy from the electricity supply to the wiring system of the residential:
Calculation no.1The Total EstimatedPower Load from Branch Circuit 1 to Branch Circuit 6 (TOTAL CONNECTED LOAD:
TotalConnected Load=∑i=1
N
Pmaxi
where :Pmax i=the maximum power abranchcircuit cangenerate
thus,
TotalConnected Load=Pmaxbranch 1+Pmaxbranch 2
+Pmaxbranch 3+Pmax branch 4
+Pmaxbranch 5+Pmax branch 6
TotalConnected Load=300W +400W +2,880W +746W +2,175W +1,100W
TotalConnected Load=7,601Watts
Comment:
Calculation no.2The Total Load of the Branch Circuit 1 to Branch Circuit 6:
recall: P=VI thus ,⇒ I= PV
therefore,
TotalCurrent Load=TotalConnected LoadVoltage rating
TotalCurrent Load=∑i=1
N
Pmax i
220V
TotalCurrent Load=7,601W max
220V=34.55 Amax
Comment:
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Calculation no.3The Computation for the Demand Factor:Apply 80% demand factor as permitted by the National Electrical Code(NEC)
TotalCurrent Loa d80%d .f .=0.80 x 34.55 Amax=27.64 A80%d.f.
Calculation no.4The Size Of The Service Conductor based on the calculation in No.3:
Refer to tables: 2-5 and 4-2Maximum expected current load: 27.64 A80%d.f.
Use:Wire No.:#8 AWG copper wireWire Diameter:8.0 mm2
Wire Type:T or TWNo. of pieces of wire needed:2 pcs.Wire Temperature Rating:60 C(140 F)
Comment:
Calculation no.5The Size Of The Conduit Pipe To Accommodate The Wires In Calculation No.4:
Refer to tables: 2-9No. of pieces of wire needed: 2 pcs.Use:
Conduit Diameter:20 mm dia.Maximum number of wire can accommodate:2 pcs. max.Size of wire:#8 AWG copper wire
Comment:
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TABLE OF
MATERIALS AND
QUANTITY
MATERIALS& NUMBER OF QUANTITIES
MATERIALS QUANTITY
Safety Switch, 30-A, 2 DPST, 250 volts 1 pcs.
Fuse cutout, two branches 1 unit
30-A fuse 2 pcs.
20-A fuse 2 pcs.
15-A fuse 2 pcs.
8.0 mm2 TW copper wire 50 mts.
3.5 mm2 TW copper wire 1 roll
2.0 mm2 TW copper wire ½ roll
13 mm diameter PVC conduit pipe 18 pcs.
20 mm diameter PVC conduit pipe 5 pcs.
One gang switch with plate 4 pcs.
two gang switch with plate 2 pcs.
two gang convenience outlet (small appliance)
6 pcs.
Cooking unit outlet 2 pcs.
Junction box with screw 7 pcs.
Receptacle with screw 8 pcs.
Utility box 14 pcs.
Incandescent lamp 4 pcs.
Fluorescent lamp 4 pcs.
Meter base 1 pcs.
Electrical tape (large) 2 pcs.
comment:
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SINGLE–LINE DIAGRAM &
SCHEMATIC
RISER DIAGR
AM
Single Line Diagram
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M
Lighting Outlets (3) Lighting Outlets (4)
Convenience Receptacle Outlets (8) Refrigerator & Heater Outlet (1)
Electric Stove Outlet (1) Air conditioning Equipment Outlet (1)
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