Theory of Algorithms: Divide and Conquer James Gain and Edwin Blake {jgain | edwin} @cs.uct.ac.za...
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Transcript of Theory of Algorithms: Divide and Conquer James Gain and Edwin Blake {jgain | edwin} @cs.uct.ac.za...
![Page 1: Theory of Algorithms: Divide and Conquer James Gain and Edwin Blake {jgain | edwin} @cs.uct.ac.za Department of Computer Science University of Cape Town.](https://reader030.fdocuments.net/reader030/viewer/2022032606/56649eb35503460f94bba6b6/html5/thumbnails/1.jpg)
Theory of Algorithms:Theory of Algorithms:Divide and ConquerDivide and Conquer
Theory of Algorithms:Theory of Algorithms:Divide and ConquerDivide and Conquer
James Gain and Edwin Blake{jgain | edwin} @cs.uct.ac.za
Department of Computer Science
University of Cape Town
August - October 2004
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ObjectivesObjectives
To introduce the divide-and-conquer mind set
To show a variety of divide-and-conquer solutions: Merge Sort
Quick Sort
Multiplication of Large Integers
Strassen’s Matrix Multiplication
Closest Pair and Convex Hull by Divide-and-Conquer
To discuss the strengths and weaknesses of a divide-and-conquer strategy
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Divide-and-ConquerDivide-and-Conquer
Best known algorithm design strategy:1. Divide instance of problem into two or more smaller
instances
2. Solve smaller instances recursively
3. Obtain solution to original (larger) instance by combining these solutions
The Master Theorem applies Recurrences are of the form T(n) = aT(n/b) + f (n), a
1, b 2
Silly Example (Addition): a0 + …. + an-1 = (a0 + … + an/2-1) + (an/2 + … an-1)
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Divide-and-Conquer IllustratedDivide-and-Conquer Illustrated
SUBPROBLEM 2 OF SIZE n/2
SUBPROBLEM 1 OF SIZE n/2
A SOLUTION TO SUBPROBLEM 1
A SOLUTION TO THEORIGINAL PROBLEM
A SOLUTION TO SUBPROBLEM 2
A PROBLEM OF SIZE n
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MergesortMergesort
Algorithm:1. Split A[1..n] in half and copy of each half into arrays B[1.. n/2 ]
and C[1.. n/2 ]
2. Recursively MergeSort arrays B and C
3. Merge sorted arrays B and C into array A
Merging: REPEAT until no elements remain in one of B or C
1. Compare 1st element in the rest of B and C
2. Copy smaller into A, incrementing index of corresponding array
3. Once all elements in one of B or C is processed, copy the remaining unprocessed elements from the other array into A
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Mergesort ExampleMergesort Example
7 2 1 6 4
7 2 1 6 4
7 2 1 6
4
7
2
2 7
1 2 7
4 6
1 2 4 6 7
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Efficiency of MergesortEfficiency of Mergesort
Recurrence: C(n) = 2 C(n/2) + Cmerge(n) for n > 1, C(1) = 0
Cmerge(n) = n - 1 in the worst case
All cases have same efficiency: ( n log n)
Number of comparisons is close to theoretical minimum for comparison-based sorting: log n! ≈ n lg n - 1.44 n
Space requirement: ( n ) (NOT in-place)
Can be implemented without recursion (bottom-up)
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QuicksortQuicksort
Select a pivot (partitioning element)
Rearrange the list into two sublists: All elements positioned before the pivot are ≤ the pivot
Those positioned after the pivot are > the pivot
Requires a pivoting algorithm
Exchange the pivot with the last element in the first sublist The pivot is now in its final position
QuickSort the two sublists
p
A[i]≤p A[i]>p
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The Partition AlgorithmThe Partition Algorithm
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Quicksort ExampleQuicksort Example
5 3 1 9 8 2 7
5 3 1 9 8 2 7
i j
i j
5 3 1 2 8 9 7 j i
2 3 1 5 8 9 7
2 3 1 8 9 7 i j
2 1 3
5 3 1 2 8 9 7 i j
i j
2 1 3 j i
1 2 3
Recursive Call Quicksort (2 3 1) & Quicksort (8 9 7)
Recursive Call Quicksort (1) & Quicksort (3)
i j
8 7 9 i j
8 7 9 j i
7 8 9
Recursive Call Quicksort (7) & Quicksort (9)
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Worst Case Efficiency of QuicksortWorst Case Efficiency of Quicksort
In the worst case all splits are completely skewed
For instance, an already sorted list! One subarray is empty, other reduced by only one:
Make n+1 comparisons Exchange pivot with itself Quicksort left = Ø, right = A[1..n-1] Cworst = (n+1) + n + … + 3 = (n+1)(n+2)/2 - 3 = (n2)
p
A[i]≤p A[i]>p
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General Efficiency of QuicksortGeneral Efficiency of Quicksort
Efficiency Cases: Best: split in the middle — ( n log n) Worst: sorted array! — ( n2) Average: random arrays — ( n log n)
Improvements (in combination 20-25% faster): Better pivot selection: median of three partitioning
avoids worst case in sorted files Switch to Insertion sort on small subfiles Elimination of recursion
Considered the method of choice for internal sorting for large files (n ≥ 10000)
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QuickHull AlgorithmQuickHull Algorithm
Inspired by Quicksort
1. Sort points by increasing x-coordinate values
2. Identify leftmost and rightmost extreme points P1 and P2 (part of hull)
3. Compute upper hull: Find point Pmax that is farthest away from line P1P2
Quickhull the points to the left of line P1Pmax
Quickhull the points to the left of line PmaxP2
4. Similarly compute lower hull
P1
Pmax P2
L
L
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Finding the Furthest PointFinding the Furthest Point
Given three points in the plane p1 , p2 , p3
Area of Triangle = p1 p2 p3 = 1/2 D
D =
D = x1 y1 + x3 y1 + x2 y3 - x3 y2 - x2 y1 - x1 y3
Properties of D : Positive iff p3 is to the left of p1p2
Correlates with distance of p3 from p1p2
x1 y1 1
x2 y2 1
x3 y3 1
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Efficiency of QuickhullEfficiency of Quickhull
Finding point farthest away from line P1P2 is linear in the number of points
This gives same efficiency as quicksort: Worst case: (n2)
Average case: (n log n)
If an initial sort is required, this can be accomplished in ( n log n) — no increase in asymptotic efficiency class
Alternative Divide-and-Conquer Convex Hull: Graham’s scan and DCHull
Also ( n log n) but with lower coefficients
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Strassen’s Matrix MultiplicationStrassen’s Matrix Multiplication
Strassen observed [1969] that the product of two matrices can be computed as follows:
Op Count: Each of M1, …, M7 rrequires 1 mult and 1 or 2 add/sub Total = 7 mul and 18 add/sub Compared with brute force which requires 8 mults and 4 add/sub
n/2 n/2 submatrices are computed recursively by the same method
C00 C01
C10 C11
A00 A01
A10 A11
B00 B01
B10 B11
M1 + M4 -M5+M7 M3+ M5
M2 + M4 M1 + M3 - M2 + M6
=
= *
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Efficiency of Strassen’s AlgorithmEfficiency of Strassen’s Algorithm
If n is not a power of 2, matrices can be padded with zeros
Number of multiplications: M(n) = 7 M(n/2) for n > 1, M(1) = 1
Set n = 2k, apply backward substitution
M(2k) = 7M(2k-1) = 7 [7 M(2k-2)] = 72 M(2k-2) = … = 7k
M(n) = 7log n = nlog 7 ≈ n2.807
Number of additions: A(n) (nlog 7)
Other algorithms closer to the lower limit of n2 multiplications, but are even more complicated
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Strengths and Weaknesses of Strengths and Weaknesses of Divide-and-ConquerDivide-and-Conquer
Strengths: Generally improves on Brute Force by one base
efficiency class
Easy to analyse using the Master Theorem
Weaknesses: Often requires recursion, which introduces overheads
Can be inapplicable and inferior to simpler algorithmic solutions