The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ,...

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The Theorem of R.L. Brooks Talk by Bjarne Toft at the Yoshimi Egawa 60 Conference. Kagurazaka, Tokyo, Japan, September 10-14, 2013 Joint work with Michael Stiebitz.

Transcript of The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ,...

Page 1: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

The Theorem of R.L. BrooksTalk by Bjarne Toft at the Yoshimi Egawa 60 Conference.

Kagurazaka, Tokyo, Japan, September 10-14, 2013

Joint work with Michael Stiebitz.

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Proc. Cambridge Phil. Soc. 1941

Page 3: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Colouring abstract graphs(rather than maps and graphs on surfaces)

MILESTONES:

• A.B.Kempe (1849-1922) 1879

• K. Wagner (1910-2000) 1937

• R.L. Brooks (1916- 1993) 1941

• H. Hadwiger (1908.1981) 1943

• G.A. Dirac (1925-1984) 1951

• T. Gallai (1912-1992) 1963

Page 4: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Klaus Wagner 1910-2000

Page 5: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Hugo Hadwiger 1908-1981

1973

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Vierteljahrschr. der Naturf. Gesellschaft in Zürich 1943

Page 7: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.
Page 8: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

It does not seem quite right to me that the conjecture now is named after me. In my Zürich lecture I just took your starting point, that contained the decisive idea, and carried it over to general chromatic numbers.

Page 9: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Rowland Leonard Brooks (1916 - 1993)

• Born February 6, 1916, in Lincolnshire, England

• Cambridge University 1935

• Tax-inspector in London

• Brooks’s famous note with his theorem was communicated to the Proc. Cambridge Phil. Soc. by W.T. Tutte in Nov. 1940 and published in 1941

• Died in London, June 18, 1993.

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Further biographical information is not included

1993

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Trinity Mathematical Society 1938

Page 12: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Trinity Four (Brooks, Smith, Stone, Tutte)

Page 13: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.
Page 14: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Smith and Brooks met at Trinity in 1935

• At the end of the first lecture Smith said to the young man sitting next to him: That was confusing.

• The young man answered: I thought it was a very good lecture. When is the next one?

• As for the next lecture the lecturer came in and started: IVANKEHIOSUTOKLSTMNDEJLSZIRTUNG

• The two realized after half an hour that they were perhaps in the wrongroom. They were! They left together, and the young man introducedhimself to Smith as Leonard Brooks.

• Leonard Brooks introduced Smith (and Stone) to a chess-playing friend (by the name Bill Tutte).

• A life-long friendship started!

Page 15: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Brooks’ Theorem 1941

• Let G be a graph of maximum degree Δ, where Δ ≠ 2, and supposethat that no connected component of G is a complete (Δ + 1)-graph. Then G has chromatic number at most Δ.

• Let G be a graph of maximum degree 2, and suppose that that noconnected component of G is an odd cycle. Then G has chromaticnumber 2.

ALTERNATIVELY:

• Let G be a connected graph of maximum degree Δ. Then G has chromatic number ≤ Δ+1, and it has chromatic number equal to Δ+1 if and only if it is a complete (Δ+1)-graph or an odd cycle.

Page 16: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Wiley 2014 ??

• Degree Bounds for the ChromaticNumber

• Degeneracy and Colorings

• Orientations and Colourings

• Properties of Critical Graphs

• Critical Graphs with Few Edges

• Homomorphisms and Colorings

• Coloring hypergraphs

• Coloring Graphs on Surfaces

• Graph Coloring Problems

Page 17: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Gabriel Andrew Dirac 1925-1984

CRITICAL GRAPHS WERE FIRST DEFINED IN G.A. DIRAC’s PhD-thesis 1951

Page 18: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Dirac’s Ph.D. Dissertation 1951

Page 19: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.
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Dirac proved Brooks’ Theorem independently

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Dénes König 1884-1944

Vielleicht noch mehr als der Berührung der Menschheit mit der Natur verdankt die Graphentheorie der Berührung der Menschen untereinander.

GALLAI made the picturesfor the book

Perhaps Graph Theory owes even more to the contact of human beings with human beings than to the contact of mankind with nature.

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König in Göttingen 1904/05

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Proofs of Brooks’ Theorem

• Sequential colouring and colour-interchange (Brooks 1942)

• Sequential colouring (Lovász 1975)

• Kempe chains (Melnikov and Vizing 1969)

• Maximum independent sets and Δ-reduction (Gerencsér 1965; Catlin1979; Tverberg 1983)

• Δ-Reduction (Rabern 2013)

• List-colourings (Erdős, Rubin and Taylor 1979)

• Critical graphs (Dirac 1951; Gallai 1963)

Page 24: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Sequential colouring

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Δ-reduction (Landon Rabern - recent)

Page 26: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

The case Δ = 3

Page 27: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

List-colourings

• Let G be a connected graph, and let for each vertex v of G a list L(v) of at least d(v) different colours be given. Then G may be coloured suchthat each vertex gets a colour from its list, except if each block of G is either a complete graph or an odd cycle (G is a Gallai-tree).

In fact: except if

1) |L(v)| = d(v) for all v

2) If G has only one block, then L(v) is the same for all v

3) G is a Gallai-tree

Page 28: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Proof of the list colour theorem

• Suppose that (G,L) is a bad pair NOT SATISFYING 1), 2) and 3).

• If u is a non-separating vertex of G and c L(u), then let L’ denote the lists obtained from L by removing c from L(u) and from L(v) for all neighbours v of u in G.

• Then (G-u, L’) is a bad pair SATISFYING 1), 2) and 3)

Page 29: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

We assume that (G,L) is a bad pair We shall prove that G satisfes 1), 2) and 3)

We know that G-u satisfies 1), 2) and 3)

Page 30: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Critical k-chromatic graphs

• BROOKS 1941: If G is k-critical (k≥4) on n vertices (n>k) then2𝑒 ≥ 𝑘 − 1 𝑛 + 1

• DIRAC 1957: If G is k-critical (k≥4) on n vertices (n>k) then2𝑒 ≥ 𝑘 − 1 𝑛 + (𝑘 − 3)

with equality for n= 2k-1.

• GALLAI 1963: 2𝑒 ≥ 𝑘 − 1 𝑛 + ((𝑘 − 3)/(𝑘2 − 3))𝑛

• KOSTOCHKA & STIEBITZ 1999: If G is k-critical (k≥4) on n vertices(n≥k+2 and n≠2k-1) then

2𝑒 ≥ 𝑘 − 1 𝑛 + 2(𝑘 − 3)

with equality for n=2k

Page 31: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

We all have a favorite paper -I have two (both exactly 50 years old):

Page 32: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Or rather: I have three favorites!

• Gallai’s beautiful theory of alternating paths.

• The Gallai-Edmonds decomposition theorem.

• AN INTRIGUING FOOTNOTE :

• With the present methods I have succeeded in getting factorization theorems for general graphs besides σ=1 only for σ=2. I shall discussthese results on another occation

Page 33: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Smolenice June 1963

Page 34: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Tibor Gallai (1912 – 1992)

Page 35: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Critical graphs I• The blocks in the minor subgraphs are complete and/or odd

cycles (the minor graph is a forest of Gallai trees)

• This is best possible (by construction)

• If G is k-critical (k≥4) on n vertices (n>k) then2𝑒 ≥ 𝑘 − 1 𝑛 + ((𝑘 − 3)/(𝑘2 − 3))𝑛

• Gallai’s Conjecture:

2𝑒 ≥ [(𝑘2 − 𝑘 − 2)𝑛 − 𝑘(𝑘 − 3)]/(𝑘 − 1))

and this is sharp for n=1 mod (k-1)

• Krivelevich 1997, Kostochka&Stiebitz 1999, 2000 and 2002, Kostochka&Yancey 2012

Page 36: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Critical graphs II

• A k-critical graph with ≤ 2k-2 vertices has disconnected complement

• The proof uses Gallai’s theory of alternating paths from the 1950 paper

• Other proofs by Molloy 1999 and Stehlik 2003

• The right minimum number of edges for all n at most 2k-1

Page 37: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Hajós’ Construction

Page 38: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Ore’s Conjecture

Page 39: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

f(k,n) = minimum number of edges in k-criticalgraph on n vertices (4 ≤ k ≤ n and n ≠ k+1)

• Dirac 1957: f(k,2k-1) known

• Gallai 1963: f(k, n) known for all n ≤ 2k-1

• Ore 1967: f(k,n+k-1) ≤ f(k,n) + k(k-1)/2 – 1.

• Kostochka and Stiebitz 1999: f(k,2k) is known.

• Equality in Ore’s inequality would therefore imply that f(k,n) is knownfor all values of k and n.

• Kostochka and Yancey 2013: f(k,n) is known for n = 1 mod (k-1)

• Fekete 1923: lim f(k,n)/n exists for all k, and it is known (2013).

• Kostochka and Yancey 2012: f(k,n) is known for k=4 and k=5.

Page 40: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

f(4,n) = minimum number of edges in 4-critical graph on n vertices (4 ≤ n and n ≠ 5) • f(4,n) = the integer part of 5n/3, i.e.

• f(4,n) = 5n/3 for n = 0 mod 3

• f(4,n) = (5n-2)/3 for n = 1 mod 3

• f(4,n) = (5n-1)/3 for n = 2 mod 3

Page 41: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Proof outline of f(4,n) = 5n/3

Page 42: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Grötzsch’s Theorem (1959): Every planartriangle-free graph is 3-colourable.

Page 43: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

4-critical graphs with empty minor graph

Page 44: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Planar 4-critical graphs without vertices of degree 3 (Koester 1984).

Page 45: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

4-critical graphs with many edges/high min degree

Page 46: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

4-critical graphs with all vertices of highdegree ( max min δ(G) )

• Simonovits and Toft 1971

• Max min d(G) ≥ c 3|𝑉 𝐺 |

• BEST POSSIBLE ??

Page 47: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Critical k-chromatic graphs (on n vertices) with just one Major vertex

• Min max |C| ≤ c log n

• BEST POSSIBLE –

• Alon, Krivelevich, Seymour 2000

• Shapira&Thomas 2011

• Max min |C| ~ c log n Erdős 1959 and 1962

• Max min |odd C| ??

Page 48: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Critical 4-chromatic graphs with long shortestodd cycles

• Max min |odd C| ≥ c 𝑛

• BEST POSSIBLE

Page 49: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Critical k-chromatic graphs with precisely twoMajor vertices• IF there are precisely two major

vertices and they areindependent

• THEN the minor graph is disconnected

• Gallai’s Conjecture: the numberof conn. components in the minor graph is at least the number of components in the major graph

• PROVED by Stiebitz in 1982

• USED by Krivelevich in 1997

Page 50: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

A recent generalization by Landon Rabern

•Brooks’ Theorem: Every graph G with Δ(G) ≥ 3 satisfies (G) ≤ max{ , Δ}

• Landon Rabern 2013:Every graph G with Δ(G) ≥ 3 satisfies (G) ≤ max{ , Δ2 , 5(Δ+1)/6}, where Δ2 is the maximum degree of a vertex v adjacent to another vertex of degree at least as large as the degree of v.

Page 51: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Unsolved Problem 1

•Give the exact value of f(k,n) for all n ≥ k ≥ 4 and n ≠ k+1

•I.e. prove or disprove Ore’sConjecture that

f(k,n+k-1) = f(k,n) + k(k-1)/2 – 1

Page 52: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Unsolved Problem 2

•The exact value of f(4,n) for all n ≥ 4 and n ≠ 5 is known.

•Describe all the extremal 4-critical graphs

Page 53: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Unsolved Problem 3

•Determine the exact value of the minimum number of edges in a planar 4-critical graph on n vertices.

•Describe the extremal 4-critical graphs

Page 54: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

All 4-critical graphs with at most 9 vertices

Page 55: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Unsolved Problem 4

•Prove or disprove the existenceof a constant c such that any 4-critical graph with minimum degreeδ satisfies |V(G)| ≥ cδ3.

Page 56: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Unsolved Problem 5

•Borodin & Kostochka 1977, Catlin 1978, Lawrence 1978 proved that(G) ≤ Δ(G) + 1 - (Δ+1)/(+1) provided3 ≤ (G) ≤ Δ(G).• It follows that (G) ≤ Δ(G) – 2 provided

3 ≤ (G) ≤ (Δ(G) – 2)/3 .• It follows that (G) ≤ Δ(G) – 3 provided

3 ≤ (G) ≤ (Δ(G) – 3)/4 .OBTAIN BETTER/OPTIMAL CONDITIONS

Page 57: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Results by Reed (1999), Cranston and Rabern(2013), Farzad, Molloy and Reed (2005)

• = Δ ≥ 1014 ⇒ = • = Δ ≥ 13 ⇒ ≥ -3• = Δ-1 large ⇒ ≥ -1 • = Δ-2 large ⇒ = -1• More general results by Molloy and Reed 2001 for large Δ

Page 58: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Unsolved Problem 6

•Borodin & Kostochka’s Conjecture1977:(G) ≤ Δ(G) – 1 provided(G) ≤ Δ(G) – 1 and Δ(G) ≥ 9.•I.e. : = Δ ≥ 9 ⇒ = •Proved for Δ(G) ≥ 1014 (Reed1999).

Page 59: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Unsolved Problem 7

•Reed 1999 conjectured:

•(G) ≤ 1

2(Δ(G) + 1) +

1

2(G)

•(G) ≤ 2

3(Δ(G) + 1) +

1

3(G) , provided Δ(G) ≥ 3

Page 60: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Unsolved Problem 8

•Brooks’ Theorem: If k ≥ 3 and G is a graph , not containing the complete bipartite graphK(1, k+1), nor the complete (k+1)-graph Kk+1, then (G) ≤ k.•Gyarfás’ Conjecture 1988: For any tree T thereis a function f such that if G is a graph not containing T as an induced subgraph then (G) ≤ f((G)).

Page 61: The Theorem of R.L. Brooks · Brooks’ Theorem 1941 •Let G be a graph of maximum degree Δ, where Δ≠2, and suppose that that no connected component of G is a complete (Δ+ 1)-graph.

Thank you for your attention.And congratulations, thanks and

all best wishes to Yoshimi Egawa!