The Definite Integral. In the previous section, we approximated area using rectangles with specific...

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The Definite Integral ( ) - the symbol is called an INTEGRAL sign

Transcript of The Definite Integral. In the previous section, we approximated area using rectangles with specific...

Page 1: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥

- the symbol is called an INTEGRAL sign

Page 2: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥

- the symbol is called an INTEGRAL sign- the numbers and are called the LIMITS of INTEGRATION

Page 3: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥

- the symbol is called an INTEGRAL sign- the numbers and are called the LIMITS of INTEGRATION- the function is the INTEGRAND

Page 4: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥

- the symbol is called an INTEGRAL sign- the numbers and are called the LIMITS of INTEGRATION- the function is the INTEGRAND

- ** sometimes is referred to as the LOWER LIMIT

Page 5: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥

- the symbol is called an INTEGRAL sign- the numbers and are called the LIMITS of INTEGRATION- the function is the INTEGRAND

- ** sometimes is referred to as the LOWER LIMIT- ** and is referred to as the UPPER LIMIT

Page 6: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥

Definition : Let be continuous and nonnegative on , and let be the region between the graph of and the axis on . The AREA of is defined by :

0𝑥

𝑦

𝑅

𝑎 𝑏

𝑓

Page 7: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions” ( rectangles with equal width ) whose width would approach zero into our curve, we would get a very good approximation of the area under this curve.

Page 8: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions” ( rectangles with equal width ) whose width would approach zero into our curve, we would get a very good approximation of the area under this curve.

Hence, we could use a summation notation to show this :

∫𝑏

𝑎

𝑓 (𝑥 )𝑑𝑥=∑𝑖=1

𝑛

𝑓 (𝑥 𝑖 ) (△ 𝑥 𝑖)

- as the largest subinterval approaches a zero width

Page 9: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions” ( rectangles with equal width ) whose width would approach zero into our curve, we would get a very good approximation of the area under this curve.

Hence, we could use a summation notation to show this :

∫𝑏

𝑎

𝑓 (𝑥 )𝑑𝑥=∑𝑖=1

𝑛

𝑓 (𝑥 𝑖 ) (△ 𝑥 𝑖)

We will simplify this into :

∫𝑏

𝑎

𝑓 (𝑥 )𝑑𝑥=𝑔 (𝑏)−𝑔 (𝑎)

- Where is the anti - derivatve of our function

Page 10: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫1

3

(𝑥+1 )𝑑𝑥=¿¿EXAMPLE # 1 : Find

Page 11: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫1

3

(𝑥+1 )𝑑𝑥=¿¿EXAMPLE # 1 : Find

Using the power rule for anti – derivatives :

Page 12: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫1

3

(𝑥+1 )𝑑𝑥=¿¿EXAMPLE # 1 : Find

Using the power rule for anti – derivatives :

So now we will calculate

Page 13: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫1

3

(𝑥+1 )𝑑𝑥=¿¿EXAMPLE # 1 : Find

Using the power rule for anti – derivatives :

So now we will calculate

Page 14: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫1

3

(𝑥+1 )𝑑𝑥=¿¿EXAMPLE # 1 : Find

Using the power rule for anti – derivatives :

So now we will calculate

** in future examples, it is acceptable to disregard C when calculating as it will always become zero…

Page 15: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫1

3

(−𝑥2+10 )𝑑𝑥=¿¿EXAMPLE # 2 : Find

Page 16: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫1

3

(−𝑥2+10 )𝑑𝑥=¿¿EXAMPLE # 2 : Find

Using the power rule for anti – derivatives :

Page 17: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫1

3

(−𝑥2+10 )𝑑𝑥=¿¿EXAMPLE # 2 : Find

Using the power rule for anti – derivatives :

Now calculate

Page 18: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫1

3

(−𝑥2+10 )𝑑𝑥=¿¿EXAMPLE # 2 : Find

Using the power rule for anti – derivatives :

Now calculate

Page 19: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥=𝑔 (𝑥)𝑏

𝑎

This is the customary notation to show

Page 20: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥=𝑔 (𝑥)𝑏

𝑎

This is the customary notation to show

∫−1

3

(3 𝑥2−2𝑥+1 )𝑑𝑥EXAMPLE # 3 : Evaluate

Page 21: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥=𝑔 (𝑥)𝑏

𝑎

This is the customary notation to show

∫−1

3

(3 𝑥2−2𝑥+1 )𝑑𝑥EXAMPLE # 3 : Evaluate

3

−1

Page 22: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥=𝑔 (𝑥)𝑏

𝑎

This is the customary notation to show

∫−1

3

(3 𝑥2−2𝑥+1 )𝑑𝑥EXAMPLE # 3 : Evaluate

3

−1

3

−1

Page 23: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥=𝑔 (𝑥)𝑏

𝑎

This is the customary notation to show

∫−1

3

(3 𝑥2−2𝑥+1 )𝑑𝑥EXAMPLE # 3 : Evaluate

3

−1

3

−1

¿ [(3)3− (3 )2+3 ]− [(−1)3− (−1 )2+(−1)]

Page 24: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥=𝑔 (𝑥)𝑏

𝑎

This is the customary notation to show

∫−1

3

(3 𝑥2−2𝑥+1 )𝑑𝑥EXAMPLE # 3 : Evaluate

3

−1

3

−1

Page 25: The Definite Integral. In the previous section, we approximated area using rectangles with specific widths. If we could fit thousands of “partitions”

The Definite Integral

∫𝑎

𝑏

𝑓 (𝑥 )𝑑𝑥=𝑔 (𝑥)𝑏

𝑎

This is the customary notation to show

∫−1

3

(3 𝑥2−2𝑥+1 )𝑑𝑥EXAMPLE # 3 : Evaluate

3

−1

3

−1