The Comparison Test...2019/01/09 ย ยท The Comparison Test Let โ๐ ๐ and โ๐ ๐ be...
Transcript of The Comparison Test...2019/01/09 ย ยท The Comparison Test Let โ๐ ๐ and โ๐ ๐ be...
The Comparison Test
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 1
The Comparison Test
Let โ๐๐ and โ๐๐ be series with positive terms and suppose
๐๐ โค ๐๐,๐๐+1 โค ๐๐+1,๐๐+2 โค ๐๐+2,โฏ , a) If the โbigger seriesโ โ๐๐ converges, then
the โsmaller seriesโ โ๐๐ also converges. b) On the other hand, if the โsmaller seriesโ
โ๐๐ diverges, then the โbigger seriesโ โ๐๐ also diverges.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 2
Informal Principle #1
Suppose โ๐ข๐ is series with positive terms. Constant terms in the denominator of ๐ข๐ can usually be deleted without affecting the convergence of divergence of the series.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 3
Example 1
Guess if the series converge or diverge.
a) โ 12๐+1
โ๐=1
b) โ 1๐โ2
โ๐=1
c) โ 1
๐+123
โ๐=1
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 4
Example 1 (continued)
Solution:
(a) โ 12๐+1
โ๐=1 we expect to behave like
โ 12๐
โ๐=1 , which is a convergent geometric
series (๐ = 12
, ๐ = 12)
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 5
Example 1 (continued)
(b) โ 1๐โ2
โ๐=1 we expect to behave like
โ 1๐
โ๐=1 , which is a divergent ๐-series (๐ = 1
2)
(c) โ 1
๐+123
โ๐=1 we expect to behave like
โ 1๐3
โ๐=1 , which is a convergent ๐-series
(๐ = 3)
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 6
Informal Principle #2
If a polynomial in ๐ appears as a factor in the numerator or denominator of ๐ข๐, all but the highest power of ๐ in the polynomial may usually be deleted without affecting the convergence of divergence behavior of the series.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 7
Example 2
Guess if the series converge or diverge.
a) โ 1๐3+2๐
โ๐=1
b) โ 6๐4โ2๐3+1๐5+๐2โ2๐
โ๐=1
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 8
Example 2 (continued)
Solution:
(a) โ 1๐3+2๐
โ๐=1 we expect to behave like
โ 1๐3
โ๐=1 , which is a convergent ๐-series (๐ = 3
2).
(b) โ 6๐4โ2๐3+1๐5+๐2โ2๐
โ๐=1 we expect to behave like
โ 6๐4
๐5โ๐=1 = 6โ 1
๐โ๐=1 , which is a constant times
the divergent harmonic series.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 9
Example 3
Use the Comparison Test to determine whether
๏ฟฝ1
2๐2 + ๐
โ
๐=1
converges or diverges. Solution:
We expect this series to behave like โ 12๐2
โ๐=1 =
12โ 1
๐2โ๐=1 , which is a constant times a convergent ๐-series
(๐ = 2).
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 10
Example 3 (continued)
Since we expect the series to converge, we want to find โ๐๐ such that โ๐๐ converges and
12๐2 + ๐
โค ๐๐.
Notice 1
2๐2 + ๐โค
12๐2
for ๐ โฅ 1.
Since โ 12๐2
โ๐=1 converges, so does โ 1
2๐2+๐โ๐=1 by
the Comparison Test. J. Gonzalez-Zugasti, University of
Massachusetts - Lowell 11
Example 4
Use the Comparison Test to determine whether
๏ฟฝ1
2๐2 โ ๐
โ
๐=1
converges or diverges. Solution:
We expect this series to behave like โ 12๐2
โ๐=1 =
12โ 1
๐2โ๐=1 , which is a constant times a convergent ๐-series
(๐ = 2).
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 12
Example 4 (continued)
Since we expect the series to converge, we want to find โ๐๐ such that โ๐๐ converges and
12๐2 โ ๐
โค ๐๐ .
Unfortunately 1
2๐2 โ ๐>
12๐2
for ๐ โฅ 1.
So โ 12๐2
โ๐=1 cannot be our choice for โ๐๐.
J. Gonzalez-Zugasti, University of
Massachusetts - Lowell 13
Example 4 (continued)
We want to decrease the denominator of 12๐2โ๐
.
If we try ๐๐ = 12๐2โ๐2
= 1๐2
we get 1
2๐2 โ ๐โค
12๐2 โ ๐2
=1๐2
for ๐ โฅ 1.
Since โ 1๐2
โ๐=1 is a convergent ๐-series (๐ = 2),
our series โ 12๐2โ๐
โ๐=1 converges by the
Comparison Test.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 14
Example 5
Use the Comparison Test to determine whether
๏ฟฝ1
๐ โ 14
โ
๐=1
converges or diverges. Solution:
We expect this series to behave like โ 1๐
โ๐=1 , which is
the divergent harmonic series. J. Gonzalez-Zugasti, University of
Massachusetts - Lowell 15
Example 5 (continued) Since we expect the series to diverge, we want to find โ๐๐ such that โ๐๐ diverges and
๐๐ โค1
๐ โ 14
.
Notice 1๐โค
1
๐ โ 14
for ๐ โฅ 1.
Since โ 1๐
โ๐=1 diverges, our series โ 1
๐โ14
โ๐=1 diverges by the
Comparison Test.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 16
Example 6 Use the Comparison Test to determine whether
๏ฟฝ1๐ + 5
โ
๐=1
converges or diverges. Solution: We expect this series to behave like โ 1
๐โ๐=1 , which is a
divergent ๐-series (๐ = 12).
J. Gonzalez-Zugasti, University of
Massachusetts - Lowell 17
Example 6 (continued)
Since we expect the series to diverge, we want to find โ๐๐ such that โ๐๐ diverges and
๐๐ โค1๐ + 5
.
Unfortunately, 1๐โฅ
1๐ + 5
for ๐ โฅ 1.
So โ 1๐
โ๐=1 cannot be our choice for โ๐๐.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 18
Example 6 (continued)
We want to increase the denominator of 1๐+5
.
If we try ๐๐ = 1๐+ ๐
= 12 ๐
we get 1
๐ + ๐=
12 ๐
โค1๐ + 5
for ๐ โฅ 25.
Since โ 12 ๐
โ๐=1 = 1
2โ 1
๐โ๐=1 is a constant times a
divergent ๐-series (๐ = 12),
our series โ 1๐+5
โ๐=1 diverges by the Comparison
Test.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 19
The Limit Comparison Test
Let โ๐๐ and โ๐๐ be series with positive terms and suppose
๐ = lim๐โโ
๐๐๐๐
a) If ๐ is finite and ๐ > 0, then the series both converge or both diverge.
b) If ๐ = 0 and โ๐๐ converges, then โ๐๐ converges.
c) If ๐ = โ and โ๐๐ diverges, then โ๐๐ diverges.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 20
Example 7 Use the Limit Comparison Test to determine whether
๏ฟฝ3๐3 โ 2๐2 + 4๐5 โ ๐3 + 2
โ
๐=1
converges or diverges. Solution:
We expect this series to behave likeโ 3๐3
๐5โ๐=1 = โ 3
๐2โ๐=1 =
3โ 1๐2
โ๐=1 , which is a constant times a convergent ๐-series
(๐ = 2).
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 21
Example 7 (continued)
๐ = lim๐โโ
3๐3 โ 2๐2 + 4๐5 โ ๐3 + 2
3๐2
= lim๐โโ
3๐3 โ 2๐2 + 4๐5 โ ๐3 + 2
โ๐2
3
Since this is a rational function with the degree of the numerator equal to the degree of the denominator (=5), this limit is equal to the ratio of the leading coefficients.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 22
Example 7 (continued)
๐ = lim๐โโ
3๐3 โ 2๐2 + 4๐5 โ ๐3 + 2
โ๐2
3=
33
= 1 > 0
So, by the Limit Comparison Test,
โ 3๐3โ2๐2+4๐5โ๐3+2
โ๐=1 converges.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 23
Thomas Simpson (1720 - 1761) Simpson was a successful text writer and did most of his work in probability. He taught at the Royal Military Academy in Woolwich. His first articles were published in the Ladies' Diary. Later he became editor of this popular journal. Simpson's rule to approximate definite integrals was developed and used before he was born. It is another of history's beautiful quirks that one of the ablest mathematicians of the 18th century is remembered not for his own work or his textbooks but for a rule that was never his, that he never claimed, and that bears his name only because he happened to mention it in one of his books.
J. Gonzalez-Zugasti, University of Massachusetts - Lowell 24