The ‘a priori’ mean error of levelling. Computation of heighting lines and joints Budapesti...
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Transcript of The ‘a priori’ mean error of levelling. Computation of heighting lines and joints Budapesti...
The ‘a priori’ mean error of levelling. Computation of heighting lines and joints
Budapesti Műszaki és Gazdaságtudományi EgyetemÁltalános- és Felsőgeodézia Tanszék
The determination of the mean oscillation of the line-of-sight (automatic level)
nmmm ,...,2
,1
imnm 1
immiv
1
2
niv
mm
2m
mm
d
m
precise level (staff reading is taken with optical micrometers)
n ,...,,21
in 1
iiv
1
2
nivm
d
m
The determination of the line-of-sight
The mean error of a single elevation differenceThe mean error of the backsight and foresight readings
are the same:
m
The elevation difference in a single station: m = back – fore
2mmm
The mean error of a single elevation difference:
Why?
The mean error of all the single elevation differences are constant for a levelling line:
The mean error of the total elevation difference (according to the law of error propagation)
nm
mm
mnnm
mm
mm
mmm 22...2
2
2
1
Substitutin the mean error of the staff reading:
mm
nmm
mm
mm ...
21The elevation difference of the endpoints:
nmmmm ...21
,
nmmm 2)2( mmm
When the instrument-staff distance is: d
Then the total length of the levelling line:
dnL 2 dLn 2/
nm
mmm
n should be substituted to the eq. of the mean error:
dLm
dLm
22
dLmmm
Thus the total mean errorof the total elevation difference is:
Substituting the formula of the mean error ofa single staff reading:
dm
the following formula is obtained:
dLmm
The one-way ‘a priori’ kilometric mean error of levelling(L = 1 km)
dm 1000km
The two-way ‘a priori’ kilometric mean error of levelling:
dmm 5002km
(km)
The preliminary elevation difference of the endpoints for the i-th section:
2)( ,, backwardiforwardii
mmm
The observed elevation difference between the endpoints (K-V):
n
iimm
1)()(
The given elevation difference of the endpoints:
kv MMm
(m) = (BS – FS) = BS – FS
Computation of heighting lines (levelling)
The closure error:
)( mm
The mean error is proportional to the squareroot of the length.
Thus the weights are inverse proportional with the length. 2
2
im
ip
Thus the corrections are proportional with the length of the sections.
The corrected elevation difference:
iii mm )(
The final elevation of the i-th point:
iii mMM 1
The correction of the elevation difference (i-th section):
in
ii
i tt
1
Point D FW BW Mean CorrCorr. Elev. Diff.
Elevation
81526 452,924
81523 1,5 +1236 -1238 +1237 -4 +1,233 454,157
81522 1,0 -1256 +1254 -1255 -3 -1,258 452,899
81521 1,6 -1244 +1248 -1246 -4 -1,250 451,649
81520 1,0 -1135 +1133 -1134 -3 -1,137 450,512
81525 0,5 -1030 +1030 -1030 -1 -1,031 449,481
Σ 5,6 -3428 -15 -3,443 -3,443
The preliminary elevation difference of the endpoints for the i-th section
2)( ,, visszaiodaii
mmm
The observed elevation difference of the endpoints (K-V)
n
iimm
1)()(
The true elevation difference of the endpoints (K-V):
kv MMm
k1R2
dzcotdhm 2
Computation of heighting lines (trig. Height.)
The closure error:
)( mm
Normally mainly on the mean error of the zenith angle:
zzm mz
dm
z
dm
sinsin
22
2
How shall we distribute this error?
What depends the mean error of the trig. heighting on?
k1R2
dzcotdhm 2
Note that the mean error is proportional with the length in this case (note the squareroot of the length as in case of levelling)
The weights of the sections are inverse proportional with the square of the length!
Thus the corrections should be proportional to the square of the length of the section.
The corrected elevation difference:
iii mm )(
The final elevation of the i-th endpoint:
iii mMM 1
The correction of the i-th elev. diff.:
2
1
2 in
ii
i tt
Point D D2 FW BW MeanCorr.
Corr Elev Diff
Elevation
3025 152,92
301 1,5 2,2 +1,25 -1,28 +1,26 -2 +1,24 154,16
302 1,0 1,0 -2,56 +2,58 -2,57 -1 -2,58 151,58
303 1,6 2,6 +1,97 -2,01 +1,99 -3 +1,96 153,54
304 1,0 1,0 +5,65 -5,63 +5,64 -1 +5,63 159,17
3026 0,5 0,2 -0,03 -0,01 -0,01 0 -0,01 159,16
Σ – 7,0 – – +6,31 -7 +6,24 +6,24
-(+6,31)
-0,07
Computation of heighting joints
ji
n
i
jj mMM
199
(j=10, 20, 30)
30
10
30
1099
99
jp
pMM
j
j
jj
Based on the three independent observations, three preliminary values for the elevation of 99 can be computed.
The adjusted elevation of the joint is the weighted mean of the three preliminary values:
n
i
ji
j
tp
1
12
1
j
j
tp
How shall we determine the weights?
Levelling: Trigonometric heighting:
Lmm
2
2
im
ip
Lmm
2
2
im
ip