TEMA 2 NEW M4 .pdf
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Transcript of TEMA 2 NEW M4 .pdf
1
Tema 1
NOT¼A. Tema const¼a în câte un subpunct, corespunz¼ator num¼arului curent alstudentului din Apelul grupei (a�sat pe platform¼a). Dac¼a num¼arul curent dep¼aseste20; se va considera restul împ¼artirii acestui num¼ar la 20; de exemplu, un studentavând num¼arul curent 34; va aborda subpunctul 14
S¼a se calculeze integrala dubl¼a:
1.RRD
x2
ydxdy; D = [0; 1]� [1; e] :
2.RRD
(cosxy � xy sin xy) dxdy; D =�p
�6;p
�2
���p
�6;p
�2
�:
3.RRD
x�y(x+y)3
dxdy; D = [1; 3]� [1; 2] :
4.RRD
exy (xy + 1) dxdy; D = [1; 3]� [1; 3] :
5.RRD
ex2y (2x3y + 2x) dxdy; D = [0; 1]� [0; 1] :
6.RRD
exy2(2xy3 + 2y) dxdy; D = [0; 1]� [0; 1] :
7.RRD
x3
ydxdy; D = [0; 1]� [1; e] :
8.RRD
y4
xdxdy; D = [1; e]� [0; 1] :
9.RRD
(6x2y � 8y3) dxdy; D = [0; 1]� [1; 2] :
10.RRD
1(x+y)3
dxdy; D = [1; 2]� [1; 3] :
11.RRD
x cosxydxdy; D = [1; 2]���4; �2
�:
12.RRD
xy(x+y)3
dxdy; D = [0; 1]� [1; 2] :
13.RRD
(2x4y + x2 � 3y2)dxdy; D = [0; 1]� [1; 2] :
2
14.RRD
exy (x2y2 + 3xy + 1) dxdy; D = [0; 1]� [0; 1] :
15.RRD
(lnxy + 2) dxdy; D = [1; e]� [e; e2] :
16.RRD
lnxydxdy; D = [1; e]� [1; e2] :
17.RRD
xy (1 + ln xy) dxdy; D = [1; e]� [1; e] :
18.RRD
xyx+ydxdy; D = [0; 1]� [1; e] :
19.RRD
1(x+y)2
dxdy; D = [0; e]� [1; e2] :
20.RRD
xy sin xdxdy; D =�0; �
2
���0; �
2
�: