Symmetry in crystals

137
Symmetry in crystals

description

Symmetry in crystals. Infinitely repeating lattices. An integral number of unit translations along any axis will arrive at an identical point. A unit translation along any axis will arrive at an identical point. The composition of each unit should be identical. - PowerPoint PPT Presentation

Transcript of Symmetry in crystals

Page 1: Symmetry in crystals

Symmetry in crystals

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Infinitely repeating lattices

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An integral number of unit translations

along any axis will arrive at

an identical point.

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A unit translation along any axis will

arrive at an identical point

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The composition of each unit should

be identical.

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A unit translation parallel to any axis will

arrive at an identical point

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Face centered lattice

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Unit Cell

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3 axes, a, b, c and 3 angles , , and

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4 3-fold axes along diagonals

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4-fold axis

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3 2-fold axes

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1 6-fold axis

6-fold

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A cube with 1 diagonal shortened or lengthened.

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3-fold axis

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1 2-fold axis

2-fold

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2-fold axis

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2-fold axis3-fold axis4-fold axis6-fold axis

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Symmetry in Crystals

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Rotational symmetry

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Rotational symmetry

Possible: 2, 3, 4, 6 - fold axes

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Rotational inversion

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Mirror plane

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Screw axes:

a combination

of rotation and

translation.

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Screw axes:

a combination

of rotation and

translation.

21 screw = 180o rotation + 1/2 cell translation

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31 screw =

120o rotation +

1/3 unit translation

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Glide plane:

a combination

of mirror and

translational

symmetry.

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Glide plane:

a combination

of mirror and

translational

symmetry.

1/2 unit translation

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Given the 7 crystal systems

and various symmetry operations,

the number of ways a continuously

repeating lattice can be formed is

limited.

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Theoretical studies of the

geometries of crystals

completed in 1890 demonstrated

that there are 230 ways to put

together an infinitely repeating

lattice.

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Unit Cell

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Unit Cell

Space group P1

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Unit Cell

P1 = primitive cell + inversion center

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Unit Cell

P1 = primitive cell + inversion center

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Unit Cell

x, y, z = 0, 0, 0

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Unit Cell

x, y, z = 1, 0, 0

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Unit Cell

x, y, z = 0, 1, 0

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Unit Cell

x, y, z = 0, 0, 1

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Unit Cell

x, y, z = 1, 0, 1

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Unit Cell

x, y, z = 1, 1, 1

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Unit Cell

P1 = primitive cell + inversion center

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Inversion Center

Cartesian Coordinates:

x, y, z 0, 0, 0

-x, -y, -z -0, -0, -0

Fractional coordinates: the fraction onemust move along each axis to arrive at a point.

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Inversion Center

Cartesian Coordinates:

x, y, z 0, 0, 0 1, 0, 0

-x, -y, -z -0, -0, -0 -1, -0, -0

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Inversion Center

Cartesian Coordinates:

x, y, z 0, 0, 0 1, 0, 0

-x, -y, -z -0, -0, -0 -1, -0, -0

An integral number of unit translations results in an identical point in the lattice.

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Unit Cell

P1 = primitive cell + inversion center

1/2, 1/2, 1/2

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Inversion Center

Cartesian Coordinates:

x, y, z 0, 0, 0 1/2, 1/2, 1/2

-x, -y, -z -0, -0, -0 -1/2, -1/2, -1/2

An integral number of unit translations results in an identical point in the lattice.

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Unit Cell

P1 = primitive cell + inversion center

1, 1, 1/2

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Inversion Center

Cartesian Coordinates:

x, y, z 0, 0, 0 1, 1, 1/2

-x, -y, -z -0, -0, -0 -1, -1, -1/2

An integral number of unit translations results in an identical point in the lattice.

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What causes crystals to

form and take a particular structure?

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Strong Forces:

Electrostatic forces in ionic crystals.

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NaCl

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NaCl+ -

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NaCl+ -

+ +

+ +

++

- -

--

- -

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NaCl ionic bond energy

is 785 kj/mol.

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NaCl CsCl

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NaCl CsCl

Na+ 1.00 Å Cl- 1.81 Å Cs+ 1.69 Å

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NaCl CsCl

Two different cells; same charges;

same stoichiometry.

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Determining the contents of

the unit cell.

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NaCl

Ion within cell = 1 per cell

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NaCl

Ion on face of cell = 1/2 per cell

Ion within cell = 1 per cell

(shared with 2 cells)

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NaCl

Ion on face of cell = 1/2 per cell

Ion on edge of cell = 1/4 per cell

Ion within cell = 1 per cell

(shared with 4 cells)

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NaCl

Ion on face of cell = 1/2 per cell

Ion on edge of cell = 1/4 per cell

Ion at corner of cell = 1/8 per cell

Ion within cell = 1 per cell

(shared with 8 cells)

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NaCl

Ion on face of cell = 1/2 per cell 0 6

Ion on edge of cell = 1/4 per cell 12 0

Ion at corner of cell = 1/8 per cell 0 8

Na+ Cl-

1 0Ion within cell = 1 per cell

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NaCl

Ion on face of cell = 1/2 per cell 0 6

Ion on edge of cell = 1/4 per cell 12 0

Ion at corner of cell = 1/8 per cell 0 8

Na+ Cl-

1 0

Total ions in cell: Na+ Cl-

1 3

Ion within cell = 1 per cell

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NaCl

Ion on face of cell = 1/2 per cell 0 6

Ion on edge of cell = 1/4 per cell 12 0

Ion at corner of cell = 1/8 per cell 0 8

Na+ Cl-

1 0

Total ions in cell: Na+ Cl-

1 3 3 1

Ion within cell = 1 per cell

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NaCl

Ion on face of cell = 1/2 per cell 0 6

Ion on edge of cell = 1/4 per cell 12 0

Ion at corner of cell = 1/8 per cell 0 8

Na+ Cl-

1 0

Total ions in cell: Na+ Cl-

1 3 3 1

Z = 4

Ion within cell = 1 per cell

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Determining ionic radii using

crystal structures.

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CsCl

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CsCl

Ion on face of cell = 1/2 per cell

Ion on edge of cell = 1/4 per cell

Ion at corner of cell = 1/8 per cell

Ion within cell = 1 per cell

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CsCl

Ion on face of cell = 1/2 per cell 0 0

Ion on edge of cell = 1/4 per cell 0 0

Ion at corner of cell = 1/8 per cell 0 8

1 0

Cs+ Cl-

Ion within cell = 1 per cell

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CsCl

Ion on face of cell = 1/2 per cell 0 0

Ion on edge of cell = 1/4 per cell 0 0

Ion at corner of cell = 1/8 per cell 0 8

1 0

Cs+ Cl-

Z = 1

Ion within cell = 1 per cell

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Ionic crystals are held together

by strong electrostatic forces.

The crystal unit cell is influenced

by ionic sizes.

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CaCl2

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Ion within cell = 1 per cell

Ion on face of cell = 1/2 per cell

Ion on edge of cell = 1/4 per cell

Ion at corner of cell = 1/8 per cell

CaCl2

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Ion within cell = 1 per cell

Ion on face of cell = 1/2 per cell

Ion on edge of cell = 1/4 per cell

Ion at corner of cell = 1/8 per cell

CaCl2

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Ion within cell = 1 per cell

Ion on face of cell = 1/2 per cell

Ion on edge of cell = 1/4 per cell

Ion at corner of cell = 1/8 per cell

CaCl2

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Ion within cell = 1 per cell

Ion on face of cell = 1/2 per cell

Ion on edge of cell = 1/4 per cell

Ion at corner of cell = 1/8 per cell

CaCl2

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Ion within cell = 1 per cell 1 2

Ion on face of cell = 1/2 per cell 0 4

Ion on edge of cell = 1/4 per cell 0 0

Ion at corner of cell = 1/8 per cell 8 0

CaCl2

Ca2+ Cl-

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Ion within cell = 1 per cell 1 2

Ion on face of cell = 1/2 per cell 0 4

Ion on edge of cell = 1/4 per cell 0 0

Ion at corner of cell = 1/8 per cell 8 0

CaCl2

Ca2+ Cl-

Z = 2

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Diamond

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The strengths of chemical bonds: kJ/mol Weak < 200

Average <500>

Strong >800

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Diamond

C - C covalent bond = 1.544 Å

Bond enthalpy 348 kJ/mol

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Diamond

C - C covalent bond = 1.544 Å

Bond enthalpy 348 kJ/mol

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Diamond

Atom within cell = 1 per cell

Atom on face of cell = 1/2 per cell

Atom on edge of cell = 1/4 per cell

Atom at corner of cell = 1/8 per cell

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Diamond

Atom within cell = 1 per cell 4

Atom on face of cell = 1/2 per cell

Atom on edge of cell = 1/4 per cell

Atom at corner of cell = 1/8 per cell

C

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Diamond

Atom within cell = 1 per cell 4

Atom on face of cell = 1/2 per cell 6

Atom on edge of cell = 1/4 per cell

Atom at corner of cell = 1/8 per cell

C

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Diamond

Atom within cell = 1 per cell 4

Atom on face of cell = 1/2 per cell 6

Atom on edge of cell = 1/4 per cell 0

Atom at corner of cell = 1/8 per cell

C

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Diamond

Atom within cell = 1 per cell 4

Atom on face of cell = 1/2 per cell 6

Atom on edge of cell = 1/4 per cell 0

Atom at corner of cell = 1/8 per cell 8

C

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Diamond

Atom within cell = 1 per cell 4

Atom on face of cell = 1/2 per cell 6

Atom on edge of cell = 1/4 per cell 0

Atom at corner of cell = 1/8 per cell 8

C

Z = 8

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Molecular Crystals

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Molecular Crystals:

Consist of repeating arrays

of molecules and/or ions.

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C17H24NO2+ Cl- . 3 H2O

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V = 974.45 Å3

C17H24NO2+ Cl- . 3 H2O FW = 363.87 g/mol

Z = 2

Density =727.74 g

5866.19 x 10-1cm3

Density =363.87 g (2)

974.45 x 10-24 x 6.02 x 1023

= 1.241 g/cm3

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C17H24NO2+ Cl- . 3 H2O

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Although Z = 2, the unit cell containsportions of a number of molecules.

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Cl-

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Cl-

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Cl-

H2O

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Cl-

H2O

Hydrogen bondsCl OH2

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Hydrogen bond

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Model with atoms having VDW radii.

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C17H24NO2+ Cl- . 3 H2O

Although this material is ionic, the + and - chargesare not close enough tocontribute to the formationof the crystal.

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Molecular crystals tend to be

held together by forces weaker than

chemical bonds.

van der Waal’s forces are always

a factor.

Hydrogen bonding is often present.

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A layer in an ionic solid with ionsof similar radii.

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