Statistical process control

71
PROCESS CONTROL CUSTOMER & COMPETITIVE INTELLIGENCE FOR PRODUCT, PROCESS, SYSTEMS & ENTERPRISE EXCELLENCE DEPARTMENT OF STATISTICS DR. RICK EDGEMAN, PROFESSOR & CHAIR SIX SIGMA BLACK BELT [email protected] OFFICE: +1-208-885-4410 TATISTICA L S

Transcript of Statistical process control

Page 1: Statistical process control

PROCESS

CONTROLCUSTOMER & COMPETITIVE INTELLIGENCE FOR

PRODUCT, PROCESS, SYSTEMS & ENTERPRISE

EXCELLENCE

DEPARTMENT OF

STATISTICSDR. RICK EDGEMAN, PROFESSOR & CHAIR – SIX SIGMA BLACK BELT

[email protected] OFFICE: +1-208-885-4410

TATISTICAL

S

Page 2: Statistical process control

Quality Management:

Statistical Process Control

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Statistical Process Control

Statistical Process Control (SPC) can be thought of as the application of statistical methods for the purposes of quality control and improvement.

Quality Improvement is perhaps foremost among all areas in business for application of statistical methods.

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Data Driven Decision Making

“In God we trust. ... all others must bring data.” --- The Statistician’s Creed

SPC is one method that assists in enabling “data-driven decision making”.

SPC is a key quantitative aid to quality improvement efforts.

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Control Charts:Recognizing Sources of

Variation• Why Use a Control Chart?– To monitor, control, and improve process performance over time by

studying variation and its source.

• What Does a Control Chart Do?– Focuses attention on detecting and monitoring process variation over

time;– Distinguishes special from common causes of variation, as a guide to

local or management action;– Serves as a tool for ongoing control of a process;– Helps improve a process to perform consistently and predictably for

higher quality, lower cost, and higher effective capacity;– Provides a common language for discussing process performance.

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Control Charts:Recognizing Sources of

Variation• How Do I Use Control Charts?

– There are many types of control charts. The control charts that you or your team decides to use should be determined by the type of data that you have.

– Use the following tree diagram to determine which chart will best fit your situation. Only the most common types of charts are addressed.

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Control Chart Selection: Variable Data

Measured & Plotted on a Continuous Scale such as Time, Temperature, Cost, Figures.

n = 1 2 < n < 9 median

n is ‘small’ 3 < n < 5

n is ‘large’ n > 10

X & RmX & R X & R X & S

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Control Chart Selection: Attribute Data

Counted or Plotted as Discrete Events Such as Shipping Errors, Waste or Absenteeism.

c chart u chart p or np chart p chart

Defect orNonconformity Data

Defective Data

Constant Variable Constant Variablesample size sample size n > 50 n > 50

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Control Chart Construction

• Select the process to be charted;• Determine sampling method and plan;

– How large a sample needs to be selected? Balance the time and cost to collect a sample with the amount of information you will gather.

– As much as possible, obtain the samples under the same technical conditions: the same machine, operator, lot, and so on.

– Frequency of sampling will depend on whether you are able to discern patterns in the data. Consider hourly, daily, shifts, monthly, annually, lots, and so on. Once the process is “in control”, you might consider reducing the frequency with which you sample.

– Generally, collect 20-25 groups of samples before calculating the statistics and control limits.

– Consider using historical data to establish a performance baseline.

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Control Chart Construction

• Initiate data collection:

– Run the process untouched, and gather sampled data.

– Record data on an appropriate Control Chart sheet or other graph paper. Include any unusual events that occur.

• Calculate the appropriate statistics and control limits:– Use the appropriate formulas.

• Construct the control chart(s) and plot the data.

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Control Chart Interpretation: Time, Production & Spatial Analysis: Still-

Life Photography

An event taken in isolation or a group of items each selected from a process during the same (brief) time span can generally provide information about process performance ONLY during that brief span.

Unless process performance is static through time this will be true.

Dynamic processes vary through time.

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Control Chart Interpretation: Time, Production & Spatial Analysis: The

Video Generation If a process varies through time, it is often useful

to know how the process varies so that it can be “controlled” or “guided” in its behavior.

This requires monitoring through time, similar to videotaping the process - in some sense, the process has a “life of its own” and we want to nurture that life.

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Control Chart Interpretation:

Persistence Through Time• A process can be characterized by:– Examining its behavior during a sufficiently brief interlude of time– Examining its behavior across a greater expanse of time.

• Stable process: one which performs with a high degree of consistency at an essentially constant level for an extended period of time– “In-control”

• A process that is not stable is referred to as being in an out-of-control state

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Data Plot with PAT Zones

36.10 (A)

34.36 (B)

32.62 (C)

30.88

29.14 (C)

27.40 (B)

25.66 (A)0 5 10 15 20 25 30

Item

36

34

32

30

28

26

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• PAT 1: One point plots beyond zone A on either side of the mean

• PAT 2: Nine points in a row plot on the same side of the mean

• PAT 3: Six consecutive points are strictly increasing or strictly decreasing

• PAT 4: Fourteen consecutive points which alternate up and down

Control Chart Interpretation:

Pattern Analysis Tests (PATs)

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• PAT 5: Two out of three consecutive points plot in zone A or beyond, and all three points plot on the same side of the mean

• PAT 6: Four out of five consecutive points plot in zone B or beyond, and all five points plot on the same side of the mean

Control Chart Interpretation:

Pattern Analysis Tests

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• PAT 7: Fifteen consecutive points plot in zones C, spanning both sides of the mean

• PAT 8: Eight consecutive points plot at more than one standard deviation away from the mean with some smaller than the mean and some larger than the mean

Control Chart Interpretation:

Pattern Analysis Tests

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• The performance of every process will be composed of two primary components:– Controlled or guided performance which is

predictable in both an instantaneous and long-term sense

– Uncontrolled variation• Special or assignable causes• Common causes

Control Chart Interpretation:

Monitoring & Improving Processes

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• True process improvement is typically a result of either:– Breakthrough thinking

– Efforts to identify and reduce or eliminate common causes of variation; methodical quantitatively oriented tools which monitor a process over time --- the approach taken generally by “control charts”.

Control Chart Interpretation:

Monitoring & Improving Processes

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Control Chart Interpretation

• The vertical axis coordinate of a point plotted on the chart corresponding to the value of an appropriate PPM and the horizontal axis coordinate of a point plotted on the chart corresponding to the time in sequence at which the observation was made with the time between observations divided into equal increments.

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CL

U1SL

U2SWL

UCL

L1SL

L2SWL

LCL

A

B

C

C

B

A

Control Charts: Colors Used

*

** *

** *

**

**

*

*

**

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P Charts for the Process Proportion

Based on m preliminary samples from the process. While the number of items, n, may vary from sample to sample, it is customary for each of the samples in a given application to include the same number of items, n. For the ith of these m samples, let

Then the proportion defective for the ith sample is:

Yi = number of defective units in the sample

pi = Yi / ni

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Control Chart Interpretation

• Center line (CL) positioned at the estimated mean

• Upper and lower one standard deviation lines (U1SL and L1SL) positioned one standard deviation above and below the mean.

• Upper and lower two standard deviation warning lines (U2SWL and L2SWL) positioned at two standard deviations above and below the mean.

• Upper and lower control lines (UCL and LCL) positioned at three standard deviations above and below the mean.

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P Charts for the ProportionAn estimate of the overall process proportion defective is

p = (Y1+Y2+...+ Ym) / (n1+n2+...+ nm)

= (total defectives) / (total items)

When all samples have n items each then p = (p1 + p2 + ... + pm)/m

The estimated standard deviation of the process proportion defective is

Sp = √ p (1-p)/ ni

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P Chart Control Lines & Limits

The coordinates for the seven lines on the P chart are positioned at:

CL = p

U1SL = p + Sp L1SL = p - Sp

U2SWL = p + 2Sp L2SWL = p - 2Sp

UCL = p + 3Sp LCL = p - 3Sp

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South of the Borders, Inc.Custom Wallpapers & Borders

Free Estimates(013) 555-9944

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South of the Borders, Inc. is a custom wallpapers and borders manufacturer. While their products vary in visual design, the manufacturing process for each of the products is similar. Each day a sample of 100 rolls of wallpaper border is sampled and the number of defective rolls in the sample is noted.

The number of defective rolls in samples from 25 consecutive production days follows.

Determine all coordinates; construct & interpret the p chart. PATs 1, 2, 3 and 4 apply to p charts.

South of the Borders, Inc.

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123456789

10111213

1347

118

1029

126479

Day Defective Rolls

141516171819202122232425

8935

1410116693

10

South of the Borders, Inc. Day Defective Rolls

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Total # of items sampled = 2500

Total # of defective items = 196

p = 196/2500 = .0784

Sp = √ .0784(.9216)/100 = .02688

South of the Borders, Inc.

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CL = .0784

UCL = .0784 + 3(.0269) = .1590

LCL = .0784 - .0806 = -.0022 (na)

U2SWL = .0784 + 2(.0269) = .1322

L2SWL = .0784 - .0538 = .0246

U1SL = .0784 + .0269 = .1053

L1SL = .0784 - .0269 = .0515

South of the Borders, Inc.

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0Subgroup 252015105

0.15

0.10

0.05

0.00

Pro

port

ion

P Chart for Defective Wallpaper Rolls

Proportion of Defective Rolls ReceivedRolls 1011968

P=0.07840

1.0SL=0.1053

2.0SL=0.1322

3.0SL=0.1590

-1.0SL=0.05152

-2.0SL=0.02464

-3.0SL=0.000

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South of the Borders, Inc.

P Chart Interpretation• No violations of PATs one through four are apparent. This implies that the process is “in a state of statistical control”.

• It does not indicate that we are satisfied with the performance of the process.

• It does, however, indicate that the process is stable enough in its performance that we may seriously engage in PDCA for the purpose of long-term process improvement.

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C and U Charts for Nonconformities

• When data originates from a Poisson process, it is customary to monitor output from the process with a defects or C chart

• Recall the Poisson Distribution with mean = c and standard deviation = c

• P(y) = cye-c/y!

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C & U Charts for Nonconformities

• C represents the average number of defects (nonconformities) per measured unit with all units assumed to be of the same “size” and all samples are assumed to have the same number of units

• m = 20 to 40 initial samples• C = (number of defects in the m samples) / m

• Estimated standard deviation= √ C

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C Control Chart Coordinates

• CL = C

• UCL = C+3 C and LCL = C-3 C

• U2SWL= C+2 C and L2SWL = C- 2 C

• U1SL = C+ C and L1SL = C- C

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Scientific & Technical Materials, Inc.

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Scientific & Technical Materials, Inc.

• Scientific & Technical Materials, Inc. produces material for use as gaskets in scientific, medical, and engineering equipment. Scarred material can adversely affect the ability of the material to fulfill its intended use.

• A sample of 40 pieces of material, taken at a rate of 1 per each 25 pieces of material produced gave the results on the following slide. Use this information to construct and interpret a C chart.

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Scientific & Technical Materials, Inc.

PieceScars

PieceScars

PieceScars

PieceScars

14

111

212

312

24

121

221

321

32

132

230

331

43

143

243

343

51

150

255

352

62

164

264

360

70

173

272

371

82

182

281

385

93

192

294

399

101

201

302

401

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Scientific & Technical Materials, Inc.

• C= 90/40= 2.25= CL, Sc= 2.25 = 1.5• UCL= 2.25+ 3(1.5) = 6.75• LCL= 2.25- 4.5 = -2.25 (NA)• U2SWL= 2.25+ 2(1.5)= 5.25• L2SWL= 2.25- 3 = -0.75 (NA)• U1SL= 2.25+ 1.5 = 3.75• L1SL= 2.25- 1.5 = 0.75

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Scientific & Technical Materials, Inc.C Chart for Gasket Material Data

U2SWLU2SWL

UCLUCL

U1SLU1SL

CLCL

L1SLL1SL

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Scientific & Technical Materials, Inc.

C Chart Interpretation • Application of PATs one through four indicates a

violation of PAT 1 at sample number 39 where 9 scars appear on the surface of the sampled material.

• Corrective measures would be identified and implemented.

• After process stability was (re) assured, we would move into PDCA mode.

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U Chart

U = (u1+u2+...+um) / (n1+n2+...+nm)

= (total # of defects) / (total # of units in the m samples)

Variation of the C chartwhere Sample size may vary

• CL = U

• UCL = U+ 3 U/ni, LCL= U-3 U/ni

• U2SWL= U+ 2 U/ni, L2SWL= U- 2 U/ni

• U1Sl= U+ U/ni, L1SL= U- U/ni

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Control Charts for theProcess Mean and Dispersion ‘X bar’ Chart

Typically used to monitor process centrality (or location)Limits depend on the measure is used to monitor process dispersion (R or S may be used).

‘S’ or ‘Standard Deviation’ Chart:Used to monitor process dispersion

‘R’ or ‘Range’ Chart:Also used to monitor process dispersion

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• m = 20 to 40 initial samples of n observations each.

• Xi = mean of ith sample

• Si = standard deviation of ith sample

• Ri = range of ith sample

Sample Summary Information

X = (X1 + X2 +... + Xm) / m R = (R1 + R2 + ... +Rm)/m

S = (S1 + S2 + ... + Sm)/m

= R/d2 where d2 depends only on n

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Coordinates for the X-bar Control Chart: “R”

• CL= X,

• UCL= X+ A2R,

• UCL= X- A2R

• U2SWL= X+ 2A2R/3

• L2SWL= X- 2A2R/3

• U1SL= X+ A2R/3

• L1SL= X- A2R/3A2 is a constant that depends only on n.

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Coordinates for anR Control Chart

• CL= R

• UCL= D4R

• LCL= D3R

• U2SWL= R+ 2(D4-1)R/3

• L2SWL= R- 2(D4-1)R/3

• U1SL= R+ (D4-1)R/3

• L1SL= R- (D4-1)R/3

• where D3 and D4 depend only on n

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Championship

Championship Card Company

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Championship Card Company

Championship Card Company (CCC) produces collectible sports cards of college and professional athletes.

CCCs card-front design uses a picture of the athlete, borderedall-the-way-around with one-eighth inch gold foil. However,the process used to center an athlete’s picture does not functionperfectly.

Five cards are randomly selected from each 1000 cards producedand measured to determine the degree of off-centeredness of eachcard’s picture. The measurement taken represents percentageof total margin (.25”) that is on the left edge of a card. Data from 30 consecutive samples is included with your materials,and summarized on the following slides.

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Championship Card Company

Sample X-bar R Sample X-bar R Sample X-bar R 1 55.6 22 11 51.2 15 21 50.0 11 2 61.0 23 12 49.4 14 22 47.0 14 3 45.2 20 13 44.0 32 23 50.6 15 4 46.2 11 14 51.6 14 24 48.8 16 5 46.8 18 15 53.2 12 25 44.6 22

6 49.8 23 16 52.4 23 26 46.8 16 7 46.8 18 17 50.6 8 27 49.2 8 8 44.2 20 18 56.0 18 28 45.6 19 9 50.8 32 19 50.2 19 29 57.6 40 10 48.4 16 20 44.0 23 30 51.4 17

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Championship Card Company

Summary Informationn = 5

X = 49.63

S = 7.42

R = 18.63

d2 = 2.326

A2 = 0.577

A3 = 1.427

B3 = NA

B4 = 2.089

D3 = NA

D4 = 2.115

= R/d2 = 8.01

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UCLU2SWLU1SLCLL1SLL2SWLLCL

X based on R R

60.3856.8053.2249.6346.0542.4738.89

39.4032.4825.5518.6311.71 4.79 ------

Championship Card Company

X-bar and R Control Chart Limits

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3020100

60

50

40

Sample Number

Sam

ple

Mea

n

X Bar Chart for Sports Cards Centering Values

Samples of 5 from each 1000 Cards Printed

1

X=49.63

1.0SL=53.22

2.0SL=56.80

3.0SL=60.38

-1.0SL=46.05

-2.0SL=42.47

-3.0SL=38.89

Championship Card Company

Limits Based on R

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3020100

40

30

20

10

0

Sample Number

Sam

ple

Rang

e

R Chart for Sports Card Centering

Samples of 5 Cards from each 1000 Produced

R=18.63

1.0SL=25.55

2.0SL=32.48

3.0SL=39.40

-1.0SL=11.71

-2.0SL=4.791

-3.0SL=0.000

Championship Card Company

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Championship Card Company

X-bar & R Chart Interpretation• Application of all eight PATs to the X-bar chart indicated a

violation of PAT 1 (one point plotting above the UCL) at sample 2. Apparently, a successful process adjustment was made, as suggested by examination of the remainder of the chart.

• Application of PATs one through four to the R chart indicated a violation of PAT 1 at sample 29. Measures would be investigated to reduce process variation at that point. The violation was a “close call” and was out of character with the remainder of the data.

• We are close to being able to apply PDCA to the process for the purpose of achieving lasting process improvements.

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Coordinates for the X bar Control Chart: “S”• CL= X

• UCL= X= A3S

• LCL= X- A3S

• U2SWL= X+ 2A3S/3

• L2SWL= X- 2A3S/3

• U1SL= X+ A3S/3

• L1SL= X- A3S/3

• where A3 depends only on n

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Coordinates on an S Control Chart

• CL= S

• UCL= B4S

• LCL= B3S

• U2SWL= S+ 2(B4-1)S/3

• L2SWL= S- 2(B4-1)S/3

• U1SL= S+ (B4-1)S/3

• L1SL= S- (B4-1)S/3

• where B3 and B4 depend only on n

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Championship Card Company

Championship Card Company

Sample X-bar S Sample X-bar S Sample X-bar S 1 55.6 9.63 11 51.2 6.83 21 50.0 5.15 2 61.0 8.63 12 49.4 5.46 22 47.0 5.15 3 45.2 7.40 13 44.0 14.35 23 50.6 5.55 4 46.2 4.09 14 51.6 5.18 24 48.8 6.50 5 46.8 7.22 15 53.2 5.36 25 44.6 8.96

6 49.8 8.76 16 52.4 9.48 26 46.8 6.50 7 46.8 6.72 17 50.6 3.44 27 49.2 3.19 8 44.2 8.53 18 56.0 7.00 28 45.6 7.96 9 50.8 11.95 19 50.2 7.60 29 57.6 14.38 10 48.4 6.19 20 44.0 8.46 30 51.4 6.80

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UCLU2SWLU1SLCLL1SLL2SWLLCL

X based on S S

60.2256.6953.1649.6346.1142.5839.05

15.4912.8010.11 7.42 4.72 2.03 ------

Championship Card Company X-bar and S Chart Limits

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3020100

60

50

40

Sample Number

Sam

ple

Mea

n

X Bar Chart for Sports Cards Centering Values

Samples of 5 from each 1000 Cards Printed

1

X=49.63

1.0SL=53.16

2.0SL=56.69

3.0SL=60.22

-1.0SL=46.11

-2.0SL=42.58

-3.0SL=39.05

Championship Card Company

Limits Based on S

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3020100

15

10

5

0

Sample Number

Sam

ple

Stde

v

S Chart for Sports Card Centering Values

5 Cards Sampled from each 1000 Cards Produced

S=7.416

1.0SL=10.11

2.0SL=12.80

3.0SL=15.49

-1.0SL=4.724

-2.0SL=2.032

-3.0SL=0.000

Championship Card Company

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Championship Card Company

X-bar & S Chart Interpretation• Application of all eight PATs to the X-bar chart indicates a

violation of PAT 1 (one pt. above the UCL) at sample 2. Judging from the remainder of the chart, the process was successfully adjusted.

• Application of the first four PATs to the S chart indicates no violations.

• In summary, the process appears to have been temporarily “out-of-control” w.r.t. its mean at sample 2. The process was successfully adjusted and may now be subjected to PDCA for permanent improvement purposes.

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Common Questions for Investigating an

Out-of-Control Process• Are there differences in the measurement accuracy of instruments /

methods used?• Are there differences in the methods used by different personnel?• Is the process affected by the environment, e.g.

temperature/humidity?• Has there been a significant change in the environment?• Is the process affected by predictable conditons such as tool wear?• Were any untrained personnel involved in the process at the time?• Has there been a change in the source for input to the process such as

a new supplier or information?• Is the process affected by employee fatigue?

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Common Questions for Investigating an Out-of-Control Process

• Has there been a change in policies or procedures such as maintenance procedures?

• Is the process frequently adjusted?

• Did the samples come from different parts of the process? Shifts? Individuals?

• Are employees afraid to report “bad news”?

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Process Capability:The Control Chart Method for Variables Data

1. Construct the control chart and remove all special causes.NOTE: special causes are “special” only in that they come and go, not because their impact is either “good” or “bad”.

2. Estimate the standard deviation. The approach used depends onwhether a R or S chart is used to monitor process variability.

^ _ ^ _

= R / d2 = S / c4

Several capability indices are provided on the following slide.

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Process Capability Indices: Variables Data

^ ^CP = (engineering tolerance)/6 = (USL – LSL) /

6

This index is generally used to evaluate machine capability.

tolerance to the engineering requirements. Assuming that the process is (approximately) normally distributed and that the process average is centered between the specifications, an index value of “1” is considered to represent a “minimally capable” process. HOWEVER … allowing for a drift, a minimum value of 1.33 is ordinarily sought … bigger is better. A true “Six Sigma” process that allows for a 1.5 shift will

have Cp = 2.

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Process Capability Indices: Variables Data

^ ^CR = 100*6 / (Engineering Tolerance) = 100* 6 /(USL –

LSL)

This is called the “capability ration”. Effectively this is the reciprocal of Cp so that a value of less than 75% is generally needed and a Six Sigma process (with a 1.5 shift) will lead to a CR of 50%.

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Process Capability Indices: Variables Data

^ ^CM = (engineering tolerance)/8 = (USL – LSL) /

8

This index is generally used to evaluate machine capability.

Note … this is only MACHINE capability and NOT the capability of the full process. Given that there will be additional sources of variation (tooling, fixtures, materials, etc.) CM uses an 8 spread,

rather than 6. For a machine to be used on a Six Sigma process, a 10 spread would be used.

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Process Capability Indices: Variables Data

= ^ = ^ZU = (USL – X) / ZL = (X – LSL) /

Zmin = Minimum (ZL , ZU)

Cpk = Zmin / 3

This index DOES take into account how well or how poorly centered a process is. A value of at least +1 is required with a value of at least +1.33 being preferred.

Cp and Cpk are closely related. In some sense Cpk represents the current capability of the process whereas Cp represents the potential gain to be had from perfectly centering the process between specifications.

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Process Capability: Example Assume that we have conducted a capability analysis using X-

bar and R charts with subgroups of size n = 5. Also assume the process is in statistical control with an average of 0.99832 and

an average range of 0.02205. A table of d2 values gives d2 =

2.326 (for n = 5). Suppose LSL = 0.9800 and USL = 1.0200

^ _ = R / d2 = 0.02205/2.326 = 0.00948

Cp = (1.0200 – 0.9800) / 6(.00948) = 0.703

CR = 100*(6*0.00948) / (1.0200 – 0.9800) = 142.2%

CM = (1.0200 – 0.9800) / (8*(0.00948)) = 0.527

ZL = (.99832 - .98000)/(.00948) = 1.9

ZU = (1.02000 – .99832)/(.00948) = 2.3 so that Zmin = 1.9

Cpk = Zmin / 3 = 1.9 / 3 = 0.63

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Process Capability: Interpretation

Cp = 0.703 … since this is less than 1, the process is not regarded as being capable.

CR = 142.2% implies that the “natural tolerance” consumes 142% of the specifications (not a good situation at all).

CM = 0.527 = Being less than 1.33, this implies that – if we were dealing with a

machine, that it would be incapable of meeting requirements.

ZL = 1.9 … This should be at least +3 and this value indicates that approximately 2.9% of product will be undersized.

ZU = 2.3 should be at least +3 and this value indicates that approximately 1.1% of product will be oversized.

Cpk = 0.63 … since this is only slightly less that the value of Cp the indication is that there is little to be gained by centering and that the need is to reduce process variation.

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PROCESS

CONTROL

DEPARTMENT OF

STATISTICSDR. RICK EDGEMAN, PROFESSOR & CHAIR – SIX SIGMA BLACK BELT

[email protected] OFFICE: +1-208-885-4410

TATISTICAL

S

End of Session