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Transcript of States, operators and matrices Starting with the most basic form of the Schrödinger equation, and...
States, operators and matricesStarting with the most basic form of the Schrödinger equation, and the wave function ():
2
22
2 xmti
tkxitkxi BeAe The state of a quantum mechanical system is . This state can be expanded to a vector and the system can be more complicated (e.g. with spin, etc.):
jmjmjmjm M Here, a hermitian matrix M was introduced, to extract properties from the wave function (hermitian matrices have real eigenvalues).
Dirac notation
jmjmMjm jmjm ˆ
Note: to extract the expectation value of a property, one needs to sum over the expanded state:
mj
jmmjmj
jmjmmjmj
jmmj cMcc,
2,
,
*2,
,,
mj
jmmjmj
mj cjmMjmcM,
2,
,
2,
ˆˆ
Combining operators
Operator T, transforms the original state.
originaldtransformejmTjm ˆ
Hence, to get the expectation value:
orgorgtrftrfjmTMTjmjmMjm ˆˆˆˆ 1
1ˆˆˆˆ TMTM
Adding spin (1)
• Projection is known (m quantum number)
• Length of the two spins is known (j1 and j2)
• Several possibilities to construct projection by adding the two spins
< j1, j1 - 2 | j2, j2 >
Example: m = jmax - 2
jmax - 2
j1 - 2 j2 < j1, m1 | j2, m2 > =
m
Adding spin (1)
• Projection is known (m quantum number)
• Length of the two spins is known (j1 and j2)
• Several possibilities to construct projection by adding the two spins
< j1, j1 - 1 | j2, j2 - 1 >
Example: m = jmax - 2
jmax - 2
j1 - 1 j2-1 < j1, m1 | j2, m2 > =
m
Adding spin (1)
• Projection is known (m quantum number)
• Length of the two spins is known (j1 and j2)
• Several possibilities to construct projection by adding the two spins
<j1, j1 | j2, j2 - 2 >
Example: m = jmax - 2
jmax - 2
j1 j2- 2 < j1, m1 | j2, m2 > =
m
Adding spin (2)
• Projection is known (m quantum number)
• Length of the maximum total spin known
jmax = j1 + j2• Several possibilities to construct projection
from different sizes of total spin j
jmax - 2
j = j1 + j2 -1
j = j 1 + j 2
j = j1 + j2 -2
< j, m > =< j, m > =< j, m > = < j1 + j2, j1 + j2 - 2 >
< j1 + j2 - 1, j1 + j2 - 2 >
< j1 + j2 - 2, j1 + j2 - 2 >} m ≥ jm
j1 j2
j
| j1 –j2 | ≤ j ≤ j1 + j2
Note:j1, j2 and j can be interchanged. However, changing the composite state with one of the constituent states is not trivial and requires re-weighting of the constituent states
Adding spin (3)
• Note:- j1 m1 j1 , thus m1 has (2 . j1+1) possible values and m2 (2 . j2 +1).
Each combination shows up exactly ones in the second column of the tableso the total number of states is (2 . j1+1) (2 . j2 +1).
• The third column has the same amount of states as the second column.The quantum number j is a vector addition, thus it will never be lower than |j1 – j2|, which is called jmin.
• For m < jmin the amount of states is jmax – jmin + 1 = (j1+j2) – |j1 – j2| + 1 for each m.This situation occurs for - |j1 – j2| m |j1 – j2| , thus (2 |j1 – j2| + 1) times.
Number of states: (2 |j1 – j2| + 1) . [(j1+j2)-|j1 – j2| + 1]
• For m -jmin and m jmin the amount of states is jmax m +1. This results in the following sum:
Number of states:
• Together these contributions add up to (2 . j1 + 1) (2 . j2 + 1)
m=jmax m1=j1 & m2=j2 j=j1+j2 & m=jmax
m=jmax-1 m1=j1 & m2=j2-1
m1=j1-1 & m2=j2
j=j1+j2 & m=jmax-1
j=j1+j2-1 & m=jmax-1
m=jmax-2 m1=j1 & m2=j2-2
m1=j1-1 & m2=j2-1
m1=j1-2 & m2=j2
j=j1+j2 & m=jmax-2
j=j1+j2-1 & m=jmax-2
j=j1+j2-2 & m=jmax-2
1221
21 121
mjjjjm
jjm
jmax - 2
j = j1 + j2 -1
j = j 1 + j 2
j = j1 + j2 -2
m
Adding spin – Clebsch GordanExample: m = jmax - 2
jmax - 2
j1 j2- 2
m
21
1
21
21
,11,,
21,
21,,,
,:
::,
mmmMJ
mmmmMJ
mMmCJMor
mmMandMJwithmmCJM
213212211 ,21,12,2,1 jjCjjCjjCJJ e.g.
From symmetry relations and ortho-normality, the C coefficients can be calculated. The first few:
½ x ½ 1, 1 1, 0 0, 0 1, -1
+½, +½ 1 0 0 0
+½, -½ 0 ½ ½ 0
-½, +½ 0 ½ ½ 0
-½, -½ 0 0 0 1
JM
m1,m2
Combining spin and boostLorentz transformations:
For:
Jackson (section 11.7) calculates the corresponding operator:
Extracting rotations:
Allowing definition of the canonical state:
w
E
w
p
E
p
pLz
)cosh()sinh()tanh(
)cosh(00)sinh(
0100
0010
)sinh(00)cosh(
zRpppEp ˆ0,,,
piepL ˆ
22 pEw
0,,ˆˆ0,,ˆˆ 1 RpLRpL z
jmpjmpL ,ˆ
Intermezzo: rotation properties– The total spin commutes with rotation
– However, the projection is affected with a phase.Consider the rotation around the quantization axis
– Euler rotations, convention: z y’ z’’Advantage: quantization axis used twice for rotation
– Rotations are unitary operators. The rotation around y’ includes a transformation of the previous rotation.
– This results in:
jmJni
jmJni
jmJni ejjJeeJ
122
mimm
JiJni
mjm
Jnijm
ejmejmjmejmge
jmejmR
zz
'
''
''..
'
zyz JiJiJi eeeR '''ˆ
'1 yzyzy JiJiJiJiJi eeeeeUU zyz JiJiJi eeeR ˆ i.e. Rotations can all be carried out in same
coordinate system when order is inverted.
Intermezzo: the rotation matrixSummary of the result from the previous page
– Euler z y z convention makes left and right term easy
– The expression for djm´m is complicated, but is used mainly for the
deduction of symmetry relations:
' ''''
''
'
'
m m
jmmjm
jmm
mjm
JiJiJijm
jmDD
jmeeejmR zyz
mijmm
mimiJimi
JiJiJi
edeejmejme
jmeeejmy
zyz
''' '
'
jmm
mmjmm dd '
''
jmm
jmm dd ','
Note 1: Inverse rotation is accomplished by performing the rotations through negative angles in opposite order:
( Djm’m(, , ) )-1 = Dj
m’m(-,-,-)
Note 2: Since rotations are hermitic, the conjugate matrix is:
Djm’m(-,-,-)=Dj*
mm’()
Note 3: Combination of all this gives: Dj*
m’m()=(-)m’-mDj-m’,-m()
Rotations, boosts and spin
jmRpLRRjmpLRjmpR z100111ˆˆˆˆˆˆ,ˆ
',',
'ˆ'ˆ
ˆˆˆˆˆˆˆˆˆˆ
11,''
11,'
'11,'
'1,'1
110,10,11
11
1001
jmpRDjmpRD
jmpRLDjmDpRL
jmRRpLRjmRRRpLRR
jmm
m
jmm
m
jmm
m
jmm
zz
Describing the rotation of a canonical state:
i.e. rotation of a canonical state rotates the boost and affects the spin state in the same way as it would in the `particle at rest’ state.
'
1,'11 'ˆm
jmmjm jmDjmRR
Remember:
Helicity jpjRpLjp ,ˆˆ, 0
The helicity state is defined with:
',ˆˆˆˆˆˆ
',ˆˆ
0,'01000
0,'0
jmpDjmRRLRjmLR
jmpDjmRpL
m
jmmzz
m
jmm
Compared to the same operations on the spin state:
Hence: jmpDjpm
jm ,, 0,
In other words: helicity () is the spin component (m) along the direction of the momentum.
Note that the helicity state does not change with rotations:
jpRjRpRLjRRLR
jLRRjRpLRjpR
z
z
,ˆˆˆˆˆˆ
ˆˆˆˆˆˆ,ˆ
1011011010
01011
Note that the helicity state does not change with boosts (as long as the direction is not reversed):
jpRjRpLjRRpLR
jRRpLRRpLRjppL
z
zz
,ˆˆˆˆˆˆ
ˆˆˆˆˆˆˆ,ˆ
10010010100
01000
101001
jLRjRRLRjRpL zzˆˆˆˆˆˆˆˆ
001000
Note:
Discrete symmetriesParity
JpxJ
pdt
dxp
xx
Commutation relations:
ˆˆˆˆ
ˆˆˆˆ
pLpL
RR
Left-handed Left-handed
Mirror analogy
Charge conjugation
lesantiparticparticlesCˆ
c
0 MiDirac:
Conjugating+transposing gives:
0 TTMi
C is the matrix doing the transformation: 1CC
T
Resulting in:
0
0
011
11
T
T
TT
CMi
CCMCiC
CCMiCC
antiparticle
particle
bbC e.g.
Time reversalb c
cs
W+
Vcb*
Vcs
b
c
c
s
W+
Vcb*
Vcs
Note that time reversal changes t in –t and input states
in output states (in other words: < bra | to | ket > ).
ˆˆˆ ˆ
ˆ
ti
tiH
tiH
'i.e. the transformed state does not obey the description of motion of the
Hamiltonian, it needs an extra ‘–’ sign.
Another way to show this:
The solution is to make time reversal anti-unitary:
tt
i
ti
tiH
*
*
ˆˆˆ ˆ
Note: this can alsobe shown with the
commutation relation: '
e.g.
ixpixp ,,
Time reversal continued
*ˆ..ˆ AeiAA
Next, the the time reversal operator is split in a unitary part
and a complex conjugation.The m states consist of real numbers, i.e. projections.
mm
m
mmmKm
mmKK
*
ˆ~
',
1''~~
mm
mmmm
Hence a time reversed expectation value can be described with:
Calculating the expectation value of operator Â:
*1
1**
ˆˆ~ˆ~
ˆ~ˆ~
~~ˆ
ˆˆ
ˆˆˆˆ
AAA
AA
A
And combining with the time reversal operator:
AAA ˆ~ˆ~ 1ˆˆSince a second time reversal should
restore the original equation:
AAA ˆ~~ˆ~~ 22 ˆˆ
Hermitic AAAA ˆˆˆˆ 122 ˆˆˆˆ
~~~~
Time reversal and spin
kijkjikijkji JiJJJiJJ
,,ˆ
From the commutation relation:
Consistent with:
JpxJ
pdt
dxp
xx
And: 0ˆ,ˆ R
"''ˆ
"'ˆ'ˆˆˆ
"'
*
'
**
'
*
''
"''''
*
ˆˆˆ
ˆ
jmTDjmDjmDjmDjmR
jmDTjmRTjmTRjmRjmR
jmm
jmmtt
jmm
jmm
jmm
jmm
jmm
jmm
jmmtt
j
mmmjj
mmmmj
mmmjj
mmmmj
mmjmm
jmm
mjjmmmm
mjjmm
jmm
DDDTD
DDDT
",",'2
',"'
','
"'
*
'
","','"''
jmm
jmm
jmm
jmm TDDT "'
*
'"'' The equation: holds if:
jmm
mmmjj
mm
d
T
'
,''
Time reversal and spin continued
mjpjmpormjp
jmpjmpTjmpjmpmjmj
mmmjj
mmtt
,,,,,:,,
',',,,
ˆ
ˆ ,''
*
Time reversal of a canonical state:
Time reversal of a helicity state:
jpDjmpjmpDjp jm
m
jm ,,,,
*
j
mjimj
mmj
m
jm
mjmj
jm
jm
DeDDwith
jpDmjp
andjpDjpDjmp
,
*
,
*
,
*
,,:
,,,,,,,
,,, ˆˆˆ
,,,, ,ˆ jpDejpD j
mjimmjj
m
Should give: jpeDjpD ijm
jm ,,,ˆ
Hence:
Parity and spin
jmpjmpjmp ,,,,ˆ The parity operation on a canonical state:
The parity operation on a helicity state:
jpDjmpjmpDjp jm
m
jm ,,,,
*
j
mjimj
mmj
m
jm
jm
mjm
jm
DeDDwith
jpDjmp
andjpDjpDjpDjmp
,,
*
*
,
**
,,:
,,,,,
,,,, ˆˆˆˆ
jpDejpD j
mjimj
mm ,,, ,, ˆ
Should give: ,,,,ˆ jpejp ji Hence:
Note: jpjp ,,, jmpjmp ,,, but:
Since helicity states include rotational properties: jLRjRpLjp zˆˆˆˆ, 00
Composite states
b-quark s-quark
Bs-meson
21,2
121
21,2
1210,0
Bs ground state:
This ground state can decay to two vector mesons:
b-quark s-quark
Bs-meson
s-quarks-quark
c-quark c-quarkW+
J/-meson
-meson
(easy to detect)
Isospin = 0Spin = 1Parity = -(C-parity = -)
Isospin = 0Spin = 1Parity = -(C-parity = -)
Isospin = 0Spin = 0Parity = -
21
21
21 ,21,,
,2121
mmmmS
mm
mmCmmSMmmSM
Note: M = m1 + m2
Two body decay properties
1,1310,03
11,1310,0 Spin states of Bs, J/ and :
2121 ||, mpmpamm
Not the complete story… Consider momentum in two particle decay (Bs rest frame):
Normalization
21,, mm=
21
21,
21,, ,,mm
mmS mmCSM Hence:
'
' 'ˆm
jmm jmDjmR
Remember:
'
' ',,ˆm
jmm SMDSMR
Still no complete story… Consider angular momentum:
SMYdSMlm lm ,,
Angular momentum
Total spin
With: 0,4
12 *
0
lm
lm D
lY
21
21
21 ,21,,
,2121
mmmmS
mm
mmCmmSMmmSM
Missing: Formalism that describes angular momentum and Yml states.
Rotation with angular momentum ',',ˆ,ˆ
' SMDYdSMRYdSMlmR SMM
lm
lm
','0,4
12','
*
0'' SMDDdl
SMYDd lm
SMM
lm
SMM
Split up the Yml state, to match with new rotation:
'12
4
0,'0,'?0,
'
*
0'1*
'
*
0'
*
'
*
0
lm
lmm
lm
lmm
lm
lmm
lm
Yl
D
DRDDDD
','',',ˆ''''' SMlmDDSMYDDdSMlmR lmm
SMM
lm
lmm
SMM
i.e. the transformation is a product of the rotation of two rest states:
',',ˆ,ˆ'' SMlmDDSMlmRSMlmR lmm
SMM
21
21,
21,, ,mm
mmS mmC
Angular momentum and spinWe can also express them as states with a sum of angular momentum and spin:
S
S
S
S
S
S
S
S
S
Mm mm
lmmmSMmJ
Mm mmSMmJ
MmSMmJ
MmSMmJ
MmSJSJ
mmYdCC
mmMmmlmCSMlmC
SMlmCSMlmJMSMlmlSJM
, ,21,,,,
, ,2121,,
,,,
,,,
,
21
21
21
,
,
,,,,Note: MJ = m + MS
Note: MS = m1 + m2
',',ˆ'' Slmm
SMMS SMlmDDSMlmRSS
Since:
And: JJ
JJSSMM
JMMSJSJ
lmm
SMM DmMMmMMDD
,',''' '''
lSJMDlSJMR JS
MMJ JJ,',ˆ
' The state can be rotated with:
Note that (as expected) the sum of angular momentum and spin (J) is not affected by the rotation, neither are the angular momentum (l) and the total
spin (S). This result is the equivalent of the non-relativistic L-S coupling.
(see 1 page back)
Two body decay and helicity (1)
21
1111
112121
|00ˆ
ˆˆˆˆˆˆˆ
ˆˆˆˆ||
R
pLpLRpLRpLR
RpLRpLppa
zzzz
As with spin, we need to consider momentum in the helicity state:
Angles are zero. Particles are boosted back to back along the positive and negative Z-axis
,,21
*
,,,,
,,21
*
2121
21
**
2121
,
|00ˆ
,,
||,
1212
2
22
1
11
S
SS
S
S
MS
SMSmMS
MS
SMs
sm
sm
DCC
RDSmmSMa
ppDDa
mpmpamm
The link with previous page is provided via the relation between canonical and helicity states:
MS = m1 + m2 = 1 - 2 Why?
21,1 a
p
wa 4
Single state normalization.Rest mass: wMomentum: p
Two body decay and helicity (2)
S
J
S
SS
S
J
S
SS
JSSJ
S
S
S
SS
S S
SSS
S
S
Mm mm
JM
MSSmMSmmSMmJ
Mm mm
JM
MSSmMSmmSMmJ
JM
lm
SM
lm
lm
lm
SM
JM
Mm mm
SM
lm
MSSmMSmmSMmJ
Mm mm MS
SMSmMS
lmmmSMmJ
Mm mm
lmmmSMmJJ
DJ
dmlfJ
lCCCC
Dmlfdl
CCCC
DDDJ
lCD
J
lCDD
DDl
dCCCC
DCCYdCC
mmYdCClSJM
, ,21
*
,,,,,,,,,,
, ,21
*
,,,,,,,,,,
***
0
*
0
*
, ,21
**
0,,
,,,,,,,,
, , ,,21
*
,,,,,,,,
, ,21,,,,
21
121221
21
121221
21
121221
21
121221
21
21
,4
12),('
12
12
,),(4
12
12
12
12
12
,4
12
,
,,
21, JJM
Intermezzo, check…
Expressing states with the sum of angular momentum and spin in helicity states:
NJNormalization (later, easier the other way around)
Two body decay and helicity (3)
21'
21
*
''
',21
*
'
*
'
21
*
21
*
21
,'
|00'ˆ'
|00'ˆ'
|00ˆ
|00ˆˆ,ˆ
JSMM
SMJ
SMM
M
SM
SMMJ
SMJ
SMJJ
JMD
RDdND
RDDdN
RDdN
RRDdNJMR
JJ
JJJ
J
JJJ
J
J
Check the transformation properties for rotations:
Transforms as it should…Remember: jpRjpR ,,ˆ
1
i.e. Mj transforms, but 1 and 2 do not.
Canonical versus helicity states
21
*
21
*
21 ,4
12,, J
MJMJJ JJ
DJ
dDNdJM
212121
**
,,21
*
,,,,21
,,,
,,
2
22
1
11
2
22
1
11
1212
mmDDDD
DCCmm
sm
sm
sm
sm
MS
SMSmMS
S
SS
(2 pages back)
(3 pages back)
21,
212121
*
0
*
0
*
,,2121
21
*
21
*
21
,012
4
4
12
12
12,
12
4
012
12
,4
12,,
2
22
1
11
2
22
1
11
mmYdmmMllmMMl
J
J
lJM
Yl
D
DllmMMJ
lDD
DmmMDD
mmDDDJ
dDNdJM
lm
MSS
lmJSJ
lm
lm
lm
lmJS
JM
SM
MS
SMS
sm
sm
sm
sm
JM
JMJJ
S
JS
S
S
JJ
lSJM J ,
Combine
(4 pages back)
Normalization
Sl mM
lmSJSJ
S
mmYdmmMlmMMlJ
lJM
,
21212121 ,012
12,
Decay amplitudes
JJJ
JJ
J
JMJMJMp
w
JMp
wJMa
JMppA
m
mm
m
212121
2121
21
4
4
,|,
2121 ,|,, ppa
*
2121
*
21
*
212121
,,
,,,,
JMJ
JMJ
JMJJ
JJ
J
DNDNd
DNdJM
Remember:
p
wa 4
2121 ,,|, app
The transition amplitude to a helicitystate is calculated with the matrix element:
With:
Check…
Hence: JJMJJJ
JMJ FDNJMJM
p
wDNA
JJm
21
*
21
*4
Helicity amplitude
Complete setAnd:
Momentum of decay products: pResonance rest mass: w
Helicity amplitude
SlJJ
SlJJ
JJ
SlJJ
JJJJ
JJJ
JMlSJMp
wll
JMlSJMlJ
lJ
p
wFN
JMlSJMlJ
l
p
w
JMlSJMlSJMJMp
w
JMJMp
wF
m
m
m
m
m
,4012
,012
12
4
124
,012
124
,,,4
,4
21
21
21
21
21
21
21
Sl
JJ lSJMlJ
lJM
,012
12, 2121Remember:
Switch to canonical states:
Complete set
412
J
N JAnd:
Partial wave amplitude: als
Canonical states
Bs0 → J/ , tree level
b c
s
c
ss
Bs0
J/
W+
Vcb*
Vcs
s
c
s
c
J/
W-
Vcb*
Vcs
s
b
Bs0 Bs
0
b
s
W W
Oscillation Decay
0
0
0
0
M
M
Schrödinger2
a ad ii M
b bdt
0
0a
b
M
M
0
0a
b
20
20
iM t
iM t
a ea
bb e
a b
a b
M M
Particle and anti-particle:
No mixing, just 2 states
The basics0 0a X b X
en
Eigen states of the Hamiltonian:1 0
0 1
Time evolution of eigen states
2
a ad ii M
b bdt
12
21
12
21
M M
M M
Hermitic:*
12 21*
12 21
M M
The basics0 0s sa B b B
12*12
12*12
M M
M M
Mixing:
Note: to obtain properties with real values, the matrix needs to be Hermitic.
The basics0 0s sa B b B
12 12* *12 12
* *12 12 12 12
* *12 12 12 12
2
02 2 2
02 2 2
M M ai
M M b
i i iM M M
a
bi i iM M M
The matrix equation is 0 if:* *12 12
12 12
2
2
iMq
a p b qip M
Eigen-states: p p
q q
The basics0 0s sp B q B
0 01
0 02
s s
s s
B p B q B
B p B q B
2 2
1p q
Eigen-states: p p
q q
1,2 1,221,2 1,2( )
ii M t
B t B e
Note 1: No particle and anti-particle. Two different masses and decay times
Note: The Hamiltonian describes the quantum mechanical system. Only for the eigen-states of the Hamiltonian Mass and Decay time have meaning
Note 2: What is the meaning of time (t) at this point. This is a composite system, one particle contains two states. The time is calculated in the rest frame of the particle… On the next slide it becomes obvious.
The basics
1 1 2 2
1 1 2 2
0 0 0 02 2
1 20 0 0
0 0 0 02 2
1 20 0 0
2 2
2 2
i ii M t i M t
s s s s
s s st
i ii M t i M t
s s s s
s s st
p B q B e p B q B eB B qB f t B f t B
p p p
p B q B e p B q B eB B pB f t B f t B
q q q
1 1 2 22 2
2
i ii M t i M t
e ef
2 20 0 0 0
22
0 0 0 0
s s s st
s s s st
P B B B B t f t
qP B B B B t f t
p
1 2
1 22
22 1cos
tt tf t e e e M M t
Note: So time (t) is just the decay time of the measured particle.