Stability Lecture3
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Transcript of Stability Lecture3
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8/3/2019 Stability Lecture3
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Stability :longitudinal stability
Stability while underway
Dynamic stability
Ship Theory
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Stability while underway and
dynamic stability
Up to now and in general in hydrostatics, we
consider that :
The boat is not underway
T e water is ca m
The external forces are apply slowly
Here we will see what happens when these
assumptions are not verified.
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Degrees of freedomA boat has 6 degrees of freedom.
3 translations : Surge (longitudinal)
Sway (transverse)
3 rotations: Roll (longitudinal)
Pitch (transverse)
eave vert ca Yaw vertical
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Degrees of freedom Translational movements are a-periodic and uncontrolled and
caused by waves. Ship does not come back at its originalposition
Rotational movements are periodic and the ship comes back
.
Underway, a ship will make combination of these movements.
So, external forces change all the time in sea
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Ship in rough sea Because waterplane changes
all the time, stability also will
change.
In function of the waves
waterplane change:
Increase when crest in
the middle
Decrease when trough inthe middle
In case of quarter beam sea, much
more complex
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ExampleContainer ship :
Length WL : 192.9 m
Beam WL : 32.2 m
Draft : 10.56 m
Diplacement : 34700 t CB : 0.511
CP : 0.544
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Example : wave position In function of the sea, the waterplane will change..
Most extreme case : wave lenght = length of the ship
2
3
4
-4
-3
-2
-1
0
1
0 20 40 60 80 100 120GZ(m)
Heeling angle ()
Still water
Trough in the middle
Crest in the middle
So, stability changes all
along the time !
Wave heigth : 8.717 m
Wave length : 206.25 m
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Example : wave height If the wave height changes
Attention : not realistic waves, only the height change (not theperiod)
3
-4
-3
-2
-1
0
1
2
0 20 40 60 80 100 120
GZ(m)
Heeling angle ()
Still water
Wave height : 2 m
Wave height : 4 m
Wave height : 6 m
Wave height : 8 m
Wave height : 10 m
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Other problems Stability varies during the movement, and can
become negative
Resonance p enomenon can ea to capsize
Impact of wave can cause extreme rolling
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Broaching Broaching is a type of ship motion instability
which is exhibited in the horizontal plane by a
sudden large yaw from the initial course. Theresulting Transverse forces acting on the shipsunderwater body can introduce large heelingmoments.
It may happen with big wave length, in case of stern quartering seas.
It is due to the movement of
particle of the waves :
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Broaching
The crest is on thestern and the bow is
in a trough
change of yaw,creation of a turning
moment
If rudder is not bigenough : broaching
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Longitudinal stabilityLength > beam
Because thee length of the ship is greater than the beam,the moment of inertia of the watetline is also much greaterlongitudinally than laterally.
So, no pro em o ongitu ina sta i ity
Longitudinal stability, thus, has no direct relationship to theships safety. Therefore, there is also no need to calculate or
evaluate the ships longitudinal stability.
But
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Center Of Flotation The ships trim around the centre of floatation.
In case of a barge with rectangular shapes, the. ,
1 m, bow will rises out of the water of 0.5 mand stem will immerse of 0.5 m.
So COF has a direct relationship to draft andtrim
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Moment to change trim To change the trim, a longitudinal moment
should be exerted.
T is moment can e create y a c ange inthe longitudinal direction of some weight.
How to determine it without the 3D model
and a stability software?
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Moment to change trim (2)Displacement 139,097 tonne
Volume 135,704 m^3
Draft to Baseline 1,5 m
Immersed depth 1,5 m
Lwl 30,208 m
Beam wl 4,342 m
WSA 168,439 m^2
Max cross sect area 6,365 m^2
Waterplane area 100,806 m^2
C 0 706
Serie 60
Cb 0,69
Cm 0,978
Cwp 0,769
LCB from zero pt 0,476 m
LCF from zero pt 0,022 m
KB 0,791 m
KG 0 m
BMt 0,961 m
BMl 37,276 m
GMt 1,751 m
GMl 38,066 m
KMt 1,751 m
KMl 38,066 m
Immersion (TPc) 1,033 tonne/cm
MTc 1,709 tonne.m
RM at 1deg =
GMt.Disp.sin(1) 4,251 tonne.m
Moment to change trim
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Moment to change trim (3) To calculate the change of trim :
With
p the transferred weight, a = the distance over which weight is
MTc
ap
trim
=
p the loaded weight, a = the distance from the pivot (COF) to thearea where the weight has been loaded
p = unloaded weight, a=distance from the place where the weightwas located to COF.
and MTc the moment to change trim.
Attention, it is the change of trim and not the trim.
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How to calculate the trim Another way to write it (with the equilibrium
of the moment):GB
Trimlongi
=
Or, we can calculate the difference of LCB and
LCG :
c
=
MTctrimLCGLCB
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Trim Remark :
Distribution of trim around the COF.
foreaft TTtrim =
So :
And :
length
LCFtrimtotalTrimaft
=
aftfore trimtrimtotalTrim =