Solved Problems (Ice)
4
Eu Christian Dale L. Olorvida BSME LP 4 SOLVED PROBLEMS 1.) A gasoline-type fuel is generated by blending 15% by weight of butene-1, 70% triptane and 15% isodecane. MON RON butene-1 80 99 triptane 101 112 isodecan e 92 113 Detemine: (a) The anti-knock index. (b) The anti-knock index if 0.4 gm of TEL is added per liter of fuel. (A 0.4 gm of TEL added gives an increase of ON about 7) (c) The Fuel sensitivity of the fuel SOLUTION: (a) Research: RON=( 0.15 )( 0.99) + ( 0.70)( 112 ) +( 0.15)( 113 ) RON=110.2 Motor: MON=( 0.15 )( 80 ) +( 0.7)( 101) +( 0.15)( 92) MON=96.5 Anti-knock index: AKI = ( MON+RON ) 2 = ( 96.5+110.2) 2 AKI =103 ANS. (b) Since a 0.4 gm of TEL added gives an increase of about 7 AKI with TEL = AKI+7 AKI withTEL =103 +7
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solved problems in internal combustion engine
Transcript of Solved Problems (Ice)
Eu Christian Dale L. Olorvida BSME LP 4
SOLVED PROBLEMS
1.) A gasoline-type fuel is generated by blending 15% by weight of butene-1, 70% triptane and 15% isodecane.
MON RONbutene-1 80 99triptane 101 112
isodecane 92 113
Detemine:(a) The anti-knock index.
(b) The anti-knock index if 0.4 gm of TEL is added per liter of fuel. (A 0.4 gm of TEL added gives an increase of ON about 7)
(c) The Fuel sensitivity of the fuel
SOLUTION:
(a)
Research:
RON=(0.15 ) (0.99 )+ (0.70 ) (112)+(0.15 ) (113 )
RON=110.2
Motor:
MON= (0.15 ) (80 )+ (0.7 ) (101 )+ (0.15 ) (92 )
MON=96.5
Anti-knock index:
AKI=(MON+RON )2
=(96.5+110.2)2
AKI=103 ANS.
(b) Since a 0.4 gm of TEL added gives an increase of about 7
AKIwith TEL=AKI+7
AKIwith TEL=103+7
AKIwith TEL=110 ANS.
(c) Fuel Sensitivity
FS=RON−MON=110.2−96.5
FS=13.7 ANS.
Eu Christian Dale L. Olorvida BSME LP 4
2.) 4-13. Isodecane is used as a fuel.
MON RONIsodecane 92 113
Calculate: (a) Anti-knock index.(b) MON if 0.2 gm/L of TEL is added to the fuel. (A 0.2 gm of TEL added gives an increase of ON about 4).
SOLUTION:
(a)
AKI=(MON+RON )2
=92+1132
AKI=102.5 ANS.
(b) Since a 0.2 gm of TEL added gives an increase of about 4
MONwith TEL=MON+4
MONwith TEL=92+4
MONwith TEL=96 ANS.
3.) Based from the previous problem, find the mass of isodecane.
SOLUTION:
m=(10 gal )(3.785 Lgal )( 0.001m3
L )(768 kgm3 )=29.07 kg
( x+29.07 ) (87 )=x (80 )+(29.07)(92)
Solving for x
x=20.764 kg
Gallons of butene-1 needed
20.764 kg
[(595 kgm3 )(0.001 m3
L )(3.785 Lgal )]
=9.22 gal ANS.
Eu Christian Dale L. Olorvida BSME LP 4
4.) A CI engine running at 2400 RPM has an ignition delay of 15° of crankshaft rotation. What is the ID in seconds?
SOLUTION:
N=(2400 revmin )(360 deg
rev )( 160
minsec )=14,400 deg
sec
ID= 15deg
14,400 degsec
ID=0.0010 sec
5.) When tested in the standard test engine, the fuel is found to have the same ignition characteristics as a mixture of 23% hexadecane and 77% heptamethylnonane. Calculate the cetane number of the fuel.
SOLUTION:
CN of fuel=( percent of hexadecane )+(0.15)( percent of HMN)
CN=(23 )+ (0.15 ) (77 )
CN=34.55
