Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x...

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Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x = 2 2 x = (32 1/5 ) 2 x = 4 (x 2/3 ) 3/2 = 9 3/2 x = (9 1/2 ) 3 x = 3 3 x = 27 (x 3/4 ) 4/3 = 27 4/3 x = (27 1/3 ) 4 x = 3 4 x = 81

Transcript of Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x...

Page 1: Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x = 2 2 x = (32 1/5 ) 2 x = 4 (x 2/3 ) 3/2 = 9 3/2 x.

Solve.

1. x5/2 = 32 2. x2/3 + 15 = 24

3. 4x3/4 = 108 x3/4 = 27

(x5/2 )2/5 = 322/5

x2/3 = 9

x = 22

x = (321/5)2

x = 4

(x2/3)3/2 = 93/2

x = (91/2)3

x = 33

x = 27

(x3/4)4/3 = 274/3

x = (271/3)4

x = 34

x = 81

Page 2: Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x = 2 2 x = (32 1/5 ) 2 x = 4 (x 2/3 ) 3/2 = 9 3/2 x.

7.5 Solving Radical Equations7.5 Solving Radical Equations

Objective - To be able to solve square root and other radical equations.

Radical Equation: an equation that has a variable in a radicand or a fractional exponent

Page 3: Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x = 2 2 x = (32 1/5 ) 2 x = 4 (x 2/3 ) 3/2 = 9 3/2 x.

Solve: x – 4 = 0Solve: x – 4 = 033

( x) = 4( x) = 43333 33

x = 64x = 64

Example 1:

x = 4x = 433

7.5 Solving Radical Equations7.5 Solving Radical Equations

Page 4: Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x = 2 2 x = (32 1/5 ) 2 x = 4 (x 2/3 ) 3/2 = 9 3/2 x.

Example 2:

Solve: 2xSolve: 2x3/23/2 = 250 = 250

xx3/23/2 = 125 = 125

(x(x3/23/2))2/32/3 = 125 = 1252/32/3

x = 125 x = 125 2/32/3

x = 25x = 25

x = 5x = 522

Page 5: Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x = 2 2 x = (32 1/5 ) 2 x = 4 (x 2/3 ) 3/2 = 9 3/2 x.

Example 3:

Solve: 3x + 2 – 2 x = 0Solve: 3x + 2 – 2 x = 0

3x + 2 = 2 x3x + 2 = 2 x

( 3x+2)( 3x+2)2 2 = ( 2 x )= ( 2 x )22

3x + 2 = 4x3x + 2 = 4x

2 = x2 = x

Page 6: Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x = 2 2 x = (32 1/5 ) 2 x = 4 (x 2/3 ) 3/2 = 9 3/2 x.

Example 4:

Solve: x – 4 = 2xSolve: x – 4 = 2x

(x – 4)(x – 4)22 = ( 2x ) = ( 2x )22

xx22 – 8x + 16 = 2x – 8x + 16 = 2x

xx22 – 10x + 16 = 0 – 10x + 16 = 0

(x – 2)(x – 8) = 0(x – 2)(x – 8) = 0

x – 2 = 0 and x – 8 = 0x – 2 = 0 and x – 8 = 0

x = 2 and x = 8x = 2 and x = 8

Page 7: Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x = 2 2 x = (32 1/5 ) 2 x = 4 (x 2/3 ) 3/2 = 9 3/2 x.
Page 8: Solve. 1. x 5/2 = 32 2. x 2/3 + 15 = 24 3. 4x 3/4 = 108 x 3/4 = 27 (x 5/2 ) 2/5 = 32 2/5 x 2/3 = 9 x = 2 2 x = (32 1/5 ) 2 x = 4 (x 2/3 ) 3/2 = 9 3/2 x.

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Ejercicios Método Simplex€¦ · Ernesto Pacheco Ejercicios Método Simplex Problem # 1 Max Z = 3 x 1 + x 2 + 2x 3 s. t. x 1 + x 2 + 2x 3 ≤ 260 2 x 2 + x 3 ≤ 400 2 x 1 + x 3

CONFIDENTIAL1 LEAST COMMON MULTIPLE. CONFIDENTIAL2 Find the prime factorization of each number: 1)36 =2 x 2 x 3 x 3 2)76 =2 x 2 x 19 3)105 =3 x 5 x 7.

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