Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution...

21
Solutions Percent Concentration

Transcript of Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution...

Page 1: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Solutions

Percent Concentration

Page 2: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Percent Concentration

Describes the amount of solute dissolved in 100 parts of solution

amount of solute

100 parts solution

Page 3: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Mass-Mass % Concentration

mass/mass % = g solute x 100% 100 g solution

Page 4: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Mixing Solute and Solvent

Solute + Solvent

4.0 g KCl 46.0 g H2O

50.0 g KCl solution

Page 5: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Calculating Mass-Mass %

g of KCl = 4.0 g

g of solvent = 46.0 g

g of solution = 50.0 g

%(m/m) = 4.0 g KCl (solute) x 100 = 8.0% KCl

50.0 g KCl solution

Page 6: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Grams, Moles & %Composition

A solution contains 15 g Na2CO3 and 235 g of

H2O? What is the mass % of the solution?

1) 15% (m/m) Na2CO3

2) 6.4% (m/m) Na2CO3

3) 6.0% (m/m) Na2CO3

Page 7: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Solution

mass solute = 15 g Na2CO3

mass solution = 15 g + 235 g = 250 g

%(m/m) = 15 g Na2CO3 x 100

250 g solution

= 6.0% Na2CO3 solution

Page 8: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Mass-Volume %

mass/volume % = g solute x 100% 100 mL solution

Page 9: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Moles & Volume & %Composition

An IV solution is prepared by

dissolving 25 g glucose

(C6H12O6) in water to make 500.

mL solution. What is the

percent (m/v) of the glucose in

the IV solution?

1) 5.0% 2) 20.% 3) 50.%

Page 10: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Solution

1) 5.0%

%(m/v) = 25 g glucose x 100

500. mL solution

= 5.0 %(m/v) glucose solution

Page 11: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Writing Factors from %

A physiological saline solution is a 0.85% (m/v) NaCl solution.

Two conversion factors can be written for the % value.

0.85 g NaCl and 100 mL NaCl soln

100 mL NaCl soln 0.85 g NaCl

Page 12: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

% (m/m) Factors

Write the conversion factors for a 10 %(m/m) NaOH solution

NaOH and NaOH soln

NaOH soln NaOH

Page 13: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

% (m/m) Factors

Write the conversion factors for a 10 %(m/m) NaOH solution

NaOH and NaOH soln

NaOH soln NaOH

10 g

10 g100 mL

100 mL

Page 14: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Moles, Volume & %Composition

Write two conversion factors for each of the following solutions:

A. 8 %(m/v) NaOH

B. 12 %(v/v) ethyl alcohol

Page 15: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Solution

Write conversion factors for the following:

A. 8 %(m/v) NaOH

8 g NaOH and 100 mL__100 mL 8 g NaOH

B. 12 %(v/v) ethyl alcohol

12 mL alcohol and 100 mL 100 mL 12 mL alcohol

Page 16: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Using % Factors

How many grams of NaCl are needed to prepare 250 g of a 10.0% (m/m) NaCl solution?

Complete data:____________ g solution

____________% or (______/_100 g_) solution

____________ g solute

Page 17: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Clculation Using % Factors

250 g solution

10.0% or (10.0 g/100 g) solution

? g solute

250 g NaCl soln x 10.0 g NaCl = 25 g NaCl100 g NaCl soln

Page 18: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Calculations using %Compostion

How many grams of NaOH do you need to measure out to prepare 2.0 L of a 12%(m/v) NaOH solution?

1) 24 g NaOH

2) 240 g NaOH

3) 2400 g NaOH

Page 19: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Solution

2.0 L soln x 1000 mL = 2000 mL soln

1 L

12 % (m/v) NaOH = 12 g NaOH

100 mL NaOH soln

2000 mL x 12 g NaOH = 240 g NaOH

100 mL NaOH soln

Page 20: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Moles, Volume & %Composition

How many milliliters of 5 % (m/v) glucose solution are given if a patient receives 150 g of glucose?

1) 30 mL

2) 3000 mL

3) 7500 mL

Page 21: Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.

Solution

5% m/v factor

150 g glucose x 100 mL = 3000 mL

5 g glucose