Solution: Physics 1710 Chapter 7&8—Power & Energy K = ½ mv 2 = ½ (2.0 kg) (5.0 m/s) 2 = 25. kg m...
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Transcript of Solution: Physics 1710 Chapter 7&8—Power & Energy K = ½ mv 2 = ½ (2.0 kg) (5.0 m/s) 2 = 25. kg m...
Solution:Solution:
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
K = ½ mv K = ½ mv 2 2
= ½ (2.0 kg) (5.0 m/s) = ½ (2.0 kg) (5.0 m/s) 22
= 25. kg m= 25. kg m22/s/s22
= 25. J= 25. J
What is the minimum height What is the minimum height from which a small rolling ball from which a small rolling ball must be started from rest so that must be started from rest so that it will complete a loop-the-loop?it will complete a loop-the-loop?
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
RR
hh
No Talking!No Talking!Think!Think!
Confer!Confer!
Peer Instruction Peer Instruction TimeTime
What is the minimum height What is the minimum height from which a small rolling ball from which a small rolling ball must be started from rest so must be started from rest so that it will complete a loop-the-that it will complete a loop-the-loop?loop?
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
What is the minimum height What is the minimum height from which a small rolling ball from which a small rolling ball must be started from rest so that must be started from rest so that it will complete a loop-the-loop?it will complete a loop-the-loop?
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
RR
hh
vv22/R = g/R = g
K = U K = U
½ mv ½ mv 22 = mg(h-R) = mg(h-R)
v v 22 = 2 g (h-R) = 2 g (h-R)
g R = 2g (h-R)g R = 2g (h-R)
h = 3Rh = 3R
vv
What is the minimum height What is the minimum height from which a small rolling from which a small rolling ball must be started from ball must be started from rest so that it will complete a rest so that it will complete a loop-the-loop?loop-the-loop?
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
K = ½ mv K = ½ mv 2 2
= ½ (2.0 kg) (5.0 m/s) = ½ (2.0 kg) (5.0 m/s) 22
= 25. kg m= 25. kg m22/s/s22
= 25. J= 25. J
11′′ Lecture Lecture • Power is the time rate of change in Power is the time rate of change in energy. energy.
[Power]= [Watt] = [Joule]/[second][Power]= [Watt] = [Joule]/[second]
• Potential Energy Potential Energy UU is the energy stored is the energy stored in a in a system and may later produce work.system and may later produce work.
• The Potential Energy is equal to the The Potential Energy is equal to the negative of negative of the work done on the the work done on the system to put it in its system to put it in its present state.present state.
• The sum of all energy, potential and The sum of all energy, potential and kinetic, is kinetic, is conserved in an isolated system.conserved in an isolated system.
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Power:Power:
P P = = dE/dtdE/dt
• Power is the time rate of change in the Power is the time rate of change in the energy of a system, the rate of work down energy of a system, the rate of work down on or by the system.on or by the system.
•Unit of power = Joule/second = WattUnit of power = Joule/second = Watt
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Unit of Work and Energy:Unit of Work and Energy:
[[F F ‧ ‧ d d ] = N] = N‧m = Joule = ‧m = Joule = JJ
JouleJoule
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Power: Power: Watt = Joule/secondWatt = Joule/second
James WattJames Watt
Watt’s Steam Engine Watt’s Steam Engine 17741774
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Power:Power:
P P = = dE/dtdE/dt
P P = = ∆∆E/E/∆∆tt
∆∆E E = = PP ∆∆tt
∆∆E E ==(100 W)(3600 s) (100 W)(3600 s)
∆∆E E ==360 000 J = 360 kJ360 000 J = 360 kJ
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Potential Energy:Potential Energy:
W = W = ∫ ∫ F•F•d d rr
U = -WU = -W
• Potential Energy is the negative of the work Potential Energy is the negative of the work required to put the system in the current state.required to put the system in the current state.
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Potential Energy:Potential Energy:
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
FF
-F-F
hh
U = U = - (- F h)- (- F h)
= = m g hm g h
Example: Elevated Mass Example: Elevated Mass
F = -mg F = -mg • Potential Energy:Potential Energy:
UUgg = - = -∫∫00
hhFdy = Fdy = --∫∫00
hh(- mg) dy(- mg) dy
UUgg = mg∫ = mg∫00
h h dy = mgh dy = mgh
• Thus, the potential energy stored in an elevated Thus, the potential energy stored in an elevated mass is proportional to the mass is proportional to the height hheight h and the and the weightweight of the mass.of the mass.
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
No Talking!No Talking!Think!Think!
Confer!Confer!
Peer Instruction Peer Instruction TimeTime
Where does the energy come from to Where does the energy come from to produce electrical power in a produce electrical power in a hydroelectric dam?hydroelectric dam?
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Potential Energy:Potential Energy:
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
FF
-F-F
hh
U = U = m g hm g h
P P = = dU/dt dU/dt
= mg dh/dt= mg dh/dtmg =(100. mg =(100. kg)(9.8N/kg)kg)(9.8N/kg)
= 98.0 N= 98.0 N
dh/dt dh/dt = 10 m/10 = 10 m/10 s s
= 1 m/s= 1 m/s
P P = 98. W= 98. W
Relationship Between Relationship Between F F and and U:U:
U = -U = -∫ ∫ F•F•dd r r SoSo
U = -∫ [ FU = -∫ [ Fx x dx + Fdx + Fyy dy + F dy + Fzz dz] dz]ThenThen
FFx x =-dU/dx ; F=-dU/dx ; Fyy =-dU/dy; F =-dU/dy; Fzz =-dU/dz =-dU/dz
FF = - = -∇∇UU
F= -gradient of F= -gradient of UU
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Example: Mass on a SpringExample: Mass on a Spring
Potential Energy:Potential Energy:
U = ½ k x U = ½ k x 22
F =dU/dxF =dU/dxF= -½ k dxF= -½ k dx22/dx/dx
F= -k xF= -k x
• Thus, the force is equal to the negative of the gradient of Thus, the force is equal to the negative of the gradient of the potential energy.the potential energy.
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
The FThe Force is equal to the negative orce is equal to the negative gradient of the potential energy:gradient of the potential energy:
FF = - = -∇∇UUFFx x = -∂U/∂x = -∂U/∂x
FFyy = -∂U/∂y = -∂U/∂y
FFzz = -∂U/∂z = -∂U/∂z
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Physics 1710Physics 1710 Chapter 8 Potential Energy and Chapter 8 Potential Energy and ConservationConservation
Example:Example: Ball on a slopeBall on a slope
• h = ax + byh = ax + by• U = mghU = mgh• FFxx = - = -∂U/∂x = ∂U/∂x = --∂(mgh)/∂x = -mg∂h/∂x ∂(mgh)/∂x = -mg∂h/∂x Similarly:Similarly:
FFyy = = --∂U/∂y = -mg b∂U/∂y = -mg b
• Thus, Thus, F = -F = -mgmg( ( aa i + i + b b j j ))
Conservation of EnergConservation of Energy:y:
• The sum of all energy in a system is The sum of all energy in a system is conserved, i.e. remains the same.conserved, i.e. remains the same.
E = U + KE = U + K
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Example: PendulumExample: Pendulum
U = mg hU = mg hh = L(1- cos h = L(1- cos ))
U = mg L(1- cos U = mg L(1- cos ))
K = ½ m v K = ½ m v 22
=½ m (Ld =½ m (Ld /dt) /dt) 22
E = mg L(1- cos E = mg L(1- cos ) + ½ m (Ld ) + ½ m (Ld //dt) dt) 2 2
= constant= constant
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Thought (Thought (Gedanken) Gedanken) Experiment:Experiment:
• Why does a pendulum stop Why does a pendulum stop moving?moving?
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Dissipative (non-conservative) Forces:Dissipative (non-conservative) Forces:
W = W = ∫ ∫ F•F•d d rr
==∫ (C v∫ (C vxx 2 2 )dx)dx
==∫ (C v∫ (C vxx 2 2 )(dx /dt) dt)(dx /dt) dt
=∫ (C v=∫ (C vxx 3 3 )dt)dt
E = U + K -WE = U + K -W
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy
Summary:Summary:
•The Potential Energy is equal to the The Potential Energy is equal to the negative of the work done on the system to negative of the work done on the system to put it in its present state.put it in its present state.
U = -U = -∫ F•d r∫ F•d r• The sum of all energy, potential and The sum of all energy, potential and kinetic, of a system is conserved, in the kinetic, of a system is conserved, in the absence of dissipation.absence of dissipation.
E = U + K – WE = U + K – W• F = - F = - ∇U∇U
•P P = = dE/dtdE/dt
Physics 1710Physics 1710 Chapter 7&8—Power & Chapter 7&8—Power & EnergyEnergy