Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3)...

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Solution Chemistry Chapter 4

Transcript of Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3)...

Page 1: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Solution Chemistry

Chapter 4

Page 2: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Dissolving and Dissociation

• When ionic compounds dissolve in water, the anions and cations

are separated from each other. This is called dissociation.

Na2S(aq) 2 Na+(aq) + S2–(aq)

K2SO4(aq) 2 K+(aq) + SO42−(aq)

H2SO4(aq) 2 H+(aq) + SO42–(aq)

• When compounds (solutes) dissolve in water (solvent) and form

ions, the process is referred to as ionization.

Page 3: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Molarity of Ions

• Calculate the Molarity of a solution if 15.25 g of Mg(NO3)2 is dissolved in water to a final volume of 250 mL.

• Now, calculate the molarity of all of the ions found in the solution.

Page 4: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Not Everything that Dissolves Dissociates!!• Electrolytes can be described as:

– Strong:

• Chemical substances that IONIZE COMPLETELY into their ions

– Examples: Soluble salts and strong acids or bases

– HCl (aq) H+ + Cl- or CuCl2 Cu2+ + 2 Cl-

• Can conduct electrical current

– Weak:• Chemical substances that IONIZE PARTIALLY into their ions

– Examples: weak acids or weak bases

» CH3COOH(aq) CH3COO- (aq) + H+(aq)

• Can conduct electrical current

– Nonelectrolytes:• Chemical substances that DISSOLVE in water but NOT AS IONS• They do not conduct electricity.

– Example: polar substances such as sugar or alcohol

» C6H12O6(s) C6H12O6(aq)

Page 5: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Salts (ionic compound) ionize when dissolved in water to form ions

Molecular compounds do not dissociate when they dissolve; they DO NOT form ions.

Salt (Ionic compound) vs. Sugar Dissolved in Water

Page 6: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Electrolytes and Nonelectrolytes

Page 7: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Acid vs. Base

Acids

• Molecular compounds that ionize when dissolved in water

– When acids ionize, they form the cation H+ and an anion.

• The degree of ionization varies.

– Acids that ionize virtually 100% are called strong acids.

HCl(aq) H+(aq) + Cl−(aq)

– Acids that only ionize a small percentage are called weak acids.

HF(aq) H+(aq) + F−(aq)

Bases

• Ionic compounds that ionize when dissolved in water

– When bases ionize, they form the anion OH- and a cation.

• The degree of ionization varies.

– Bases that ionize virtually 100% are called strong bases.

NaOH(aq) OH-(aq) + Na+(aq)

– Acids that only ionize a small percentage are called weak bases.

NH3(aq) + H2O OH-(aq) + NH4+(aq)

Page 8: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Solubility of Ionic Compounds

• Compounds that dissolve in a solvent are said to be soluble, while those that do not are said to be insoluble.

– Example:

• NaCl is soluble in water.

• AgCl is insoluble in water.

• Solubility of a compound is affected by:

– Temperature

– Volume

– Pressure for gas solutes

• Even insoluble compounds dissolve, just not enough to be meaningful.

• Predicting whether a compound will dissolve in water is based on those experimental results.

– We call this method the empirical method.

Page 9: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Compounds Containing the Following Ions Are Generally

Soluble:

Exceptions(when combined with ions on the left, the compound is insoluble)

Li+, Na+, K+, NH4+ none

NO3–, C2H3O2

– none

Cl–, Br–, I– Ag+, Hg22+, Pb2+

SO42– Ag+, Ca2+, Sr2+, Ba2+, Pb2+

Solubility Rules (Table 4.1, provided on the exam)(Compounds That Are Generally Soluble in Water)

Page 10: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Compounds Containing the Following Ions Are Generally Insoluble:

Exceptions

(when combined with ions on the left, the compound is soluble or slightly soluble)

OH– Li+, Na+, K+, NH4+,

Ca2+, Sr2+, Ba2+

S2– Li+, Na+, K+, NH4+,

Ca2+, Sr2+, Ba2+

CO32–, PO4

3– Li+, Na+, K+, NH4+

Solubility Rules (Table 4.1, cont.)(Compounds That Are Generally Insoluble in Water)

Page 11: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

KOH

AgBr

CaCl2

Pb(NO3)2

PbI2

Which of the following salts are soluble in

water?

Page 12: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Mg(NO3)2(aq) + K2CrO4(aq) MgCrO4(s) + 2 KNO3(aq)

The above chemical reaction is written as a “molecular equation.”

– Because Pb(NO3)2 and K2CrO4 are strong electrolytes we can write

Mg2+(aq) + 2 NO3-(aq) + 2 K+(aq) + CrO4

2-(aq)

MgCrO4(s) + 2 K+(aq) + 2 NO3-(aq)

This is written now as a “complete ionic equation.”

Question: What about K+ and NO3- ions?

Answer: They are “spectator ions.” These ions DO NOT

participate in the reaction.

Net Ionic Equations

Page 13: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Complete ionic equation:

Pb2+(aq) + 2 NO3- (aq) + 2 K+(aq) + CrO4

2-(aq)

PbCrO4(s) + 2 K+(aq) + 2 NO3-(aq)

• Spectator ions are left out when writing net ionic equations.

Pb2+(aq) + CrO42-(aq) PbCrO4(s)

is the NET IONIC EQUATION for this reaction.

Net Ionic Equations

Page 14: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

K2SO4(aq) + 2 AgNO3(aq) Ag2SO4(s) + 2 KNO3(aq)

AlCl3 (aq) + NH4NO3 (aq) AlNO3 (aq) + NH4Cl (aq)

Page 15: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Evidence of a Reaction

1. Produces Light

2. Absorbs/Gives off Heat

3. Forms Bubbles

4. Forms a Precipitate (solid)

5. Color Change

Page 16: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Reactions in Solution

• Double Displacement Reactions (Exchange of Ions)

o Precipitation Reactions

o Acid/Base Neutralization Reactions

o Gas Evolution Reaction

( ) ( ) ( )AB aq CD aq AD s CB

2( ) ( ) ( ) ( )HA aq MOH aq H O l MA aq

( ) ( ) ( )AB aq CD aq AD g CB

Page 17: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Reactions in Solution

• Redox Reactions (Exchange of Electrons)

o Combustion Reactions

o Single Displacement Reactions (can sometimes be gas evolution reactions when A=H)

2 2 2fuel O CO H O

M AB MB A

Page 18: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity
Page 19: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Problem: Write the equation for the precipitation reaction between an aqueous solution of potassium carbonate and an aqueous solution of nickel(II) chloride.

Strategy for writing an equation for a double displacement reaction:

1. Write the formulas of the reactants.

2. Determine the possible products.

a) Determine the ions present.

b) Exchange the ions.

c) Write the formulas of the products.

3. Determine the solubility of each product.

4. If both products soluble, write no reaction.

5. Write (aq) next to soluble products and (s) next to insoluble products.

6. Balance the equation.

Page 20: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Answer:

1. Write the formulas of the reactants.

K2CO3(aq) + NiCl2(aq)

2. Determine the possible products.

a) Determine the ions present.

(K+ + CO32–) + (Ni2+ + Cl–)

b) Exchange the ions.

(K+ + CO32–) + (Ni2+ + Cl–) (K+ + Cl–) + (Ni2+ + CO3

2–)

c) Write the formulas of the products.

K2CO3(aq) + NiCl2(aq) KCl + NiCO3

3. Determine the solubility of each product.

KCl is soluble.

NiCO3 is insoluble.

Page 21: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Answer continued:

4. If both products soluble, write no reaction.

Does not apply since NiCO3 is insoluble.

5. For soluble products write (aq), and (s) next to insoluble products.

K2CO3(aq) + NiCl2(aq) KCl(aq) + NiCO3(s)

6. Balance the equation.

K2CO3(aq) + NiCl2(aq) 2 KCl(aq) + NiCO3(s)

Page 22: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Practice—Predict the products and balance the equation.

Problem: Write the equation for the following precipitation reactions:

a) Na2S(aq) + CaCl2(aq) ?

b) KCl(aq) + AgNO3(aq) ?

Page 23: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Review Problem

• What is the mass and identity of the precipitate formed when you mix 25 mL of 0.150M Fe(NO3)3 and 15mL of 0.204M NaOH?

Page 24: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

• The “driving force” for many strong acid- strong base reactions is the formation of water.

NaOH(aq) + HCl(aq) NaCl(aq) + H2O(l)

– Net ionic equation:

OH- (aq) + H+ (aq) H2O(l)

• A common product of many acid-base reactions is water and a SALT, MX.

HX + MOH MX + H2O

Mn+ comes from base and Xn- comes from acid.

• Acid-base reactions are referred to as NEUTRALIZATION reactions.

Acid-Base Reactions

Page 25: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity
Page 26: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Gas Evolution Reactions

• Direct Formation

– Acid + metal sulfide → H2S (g)

• Indirect Formation

– When H2SO3, H2CO3, or NH4OH are formed by a Double Displacement Rxn, they decompose forming a gas.

Page 27: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Other Patterns in Reactions:Transfer of electrons rather than ions

• The precipitation, acid/base, and gas-evolving reactions are all involved in exchanging the ions in the solution.

• Other kinds of reactions involve transferring electrons from one atom to another; these are called oxidation–reduction reactions.

– Known as redox reactions

– Many involve the reaction of a substance with O2(g)

4 Fe(s) + 3 O2(g) 2 Fe2O3(s)

Page 28: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Rules for Assigning Oxidation Numbers

1. Oxidation number of a free atom or an atom in its elemental state is 0.

2. The oxidation number of a monatomic ion is the same as its charge.

3. The sum of oxidation numbers in a polyatomic ion or compound usually has the same oxidation number it would have if it were a monatomic ion.a) Hydrogen is +1 with nonmetals, -1 if bound to a metal.

b) Oxygen is always -2 unless in a peroxide

c) Halogens are usually -1, unless bound to oxygen

4. The sum of the oxidation numbers of all elements is equal to the compound/ion’s charge.

Page 29: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Problem: Assign an oxidation state to each element in the following:

• Br2

• K+

• LiF

• H2O2

• CO2

• SO42−

• Na2Cr2O7

Page 30: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Oxidation and Reduction Reactions

Oxidation:

• The process that occurs when

– the oxidation number of an element increases

– an element loses electrons

• OXIDIZING AGENT is an electron acceptor; it causes another species to be OXIDIZED but it (agent) is being reduced.

Reduction:

• The process that occurs when

– the oxidation number of an element decreases

– an element gains electrons

• REDUCING AGENT is an electron donor; it causes another species to be REDUCED but it (agent) is being oxidized.

Page 31: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Oxidation and Reduction

• Oxidation and reduction MUST occur simultaneously.

• Oxidation occurs when an atom’s oxidation state increases during a reaction.

• Reduction occurs when an atom’s oxidation state decreases during a reaction.

CH4 + 2 O2 → CO2 + 2 H2O−4 +1 0 +4 –2 +1 −2

oxidation

reduction

Page 32: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity
Page 33: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Redox without Oxygen

Page 34: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Combustion Reactions

2 C8H18(g) + 25 O2(g) 16 CO2(g) + 18 H2O(g)

• Reactions in which O2(g) is a reactant are called

combustion reactions.

• Combustion reactions release lots of energy.

• Combustion reactions are a subclass of

oxidation–reduction reactions.

Page 35: Solution Chemistry...Molarity of Ions •Calculate the Molarity of a solution if 15.25 g of Mg(NO 3) 2 is dissolved in water to a final volume of 250 mL. •Now, calculate the molarity

Problem: Complete and balance the following reactions.

1. Combustion of acetic acid, HC2H3O2(l)

2. Combustion of isopropyl alcohol, C3H7OH(l)