SMARANDACHE FUNCTION (book series), Vol. 6
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Transcript of SMARANDACHE FUNCTION (book series), Vol. 6
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SM R
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Authors o f paper
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O
Marcela P
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= [ S ( ~ ) -
S
B l l ~
S(pf)
~ S pf-l)
for
e
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In
)]
it is proved
the
fo
5 l), wher
p is a prime
na.
r sing this formula., we heLve
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PROPERTIE
b
Depart
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Proof First
we
cons
x = 2
we
obtain Fs 2) = 5
Next we shall write th
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F(
) S
x+y).
X
+
Y
=
PI
T 'T
But
from
(1) we
have
t
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We consider now a
> 1
(n)
L
We try to find lim - - I = : :
(n)
Let
an = L P, - ;r(n)
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ON A L
N
by
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But ~ 2
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On
the oth
consequently:
r. S
(k)
~
( k+ l )
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R ~ F E R E N E S
1. Smarandache Func
Vol .4-5
1994,
Nu
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S
O
M
E
?
R
O
P
E
R
T
I
a
a
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It r e su l t . s t hat S k
s ing . Let
l I
so : )
n
1
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where 0 S t S p -
The p ~ o e d u ~ e o f
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q
~ ~ r e s u l ~
~ h ~
E
lc=1
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~ S p i
)
~ i
~ S p
Because have
S \.Cn
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SOME
P
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e
have
S(P
ra t io of S(p;)/(P p
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a,
a,
d
contains in f in i te ly
Proof
of claim:
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and
using
d • 100
10D
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Proof
I t is well-kno
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(2 2
. . . : ; . . .
2 2 2
And applying
~ l l
yie ld a valu
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p - p
Now,
examine
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S p) ,S p ·p )
,S
will
contain
a l l
posi t i
Proof
I t has already
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so we proceed to ca
However,
i t i s
numbers
that
i f
m
then mop
i s
the
sma
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Corollary:
Let
n be a posi
nand
k
another posi
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5
E
.:. 2
k·+
1
where s
is
the
num
integer such that
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such
tha t
mp
= n
gr
where
k i s the
expon
grows
on
the order o
of items in the
prod
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n=265225=5 'S ' :03 '10
n=84363
n=84363
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8 4900)
8 4901)
=
8
8 3211b)
8 32111)
=
8 368138) 8 368139)
8 415664)
i
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~ h t the resolut ion
perhaps
in f in i te ly
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A
B
O
U
C
I
on
B
I
Depa
1
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/J .
x) = p .1:. 1
2
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I
if
a/ is odd
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1)
Find the solutions o
If
m is
not
a
perfect sq
If m
is
a
perfect squ
equation
xa
(x)
=
Z2.
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u>v, u, v)=1 u and v h
xa x) =
12(U:
+V
ya y) = I: U
Z
+
za z) =
12(U
2
- V
indicated
in
the first pro
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a x)
=
3s+n
a y)
=
-m - 2s
a z)=2n+3m, m n
For
m
= 1,
n
=2,
S
=
(2a
2
y2), a ~ y EZ·.
solutions.
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S ME REM
. /OF
TO
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For k
= .. ,
q
2,
the
p
between
S(p
.... 1 and S(p).
q q l
H o w e v ~ r , if
there i a numb
has solutions. This condit
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r
> can
take o
,S r) J
o<
: _ r_ :
< ; S r)
l (
S r)
, r
I
Sex) _ _
=
S pa)2 >X ~
![Page 47: SMARANDACHE FUNCTION (book series), Vol. 6](https://reader033.fdocuments.net/reader033/viewer/2022052710/577cb62d1a28aba7118d4502/html5/thumbnails/47.jpg)
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:
We have O < ~ 5-
. x, r«
. 3 .
+ =>
52 ,xl
<
9, but this is
5 ,xl
Ifp=7
=>
S(x)=S(73)=
(.. X
I.
h
0
We ave
< < ~ <
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Let x be a solution
We have S(x)
is
divisible by m, so (S(x
(rnx). We know that S(
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If the equation has a solu
If m=n, the equation bec
and any prime number as we
solutions are x= 1 and x=2.
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SO
INSP
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def ined
by
mVn=m
0 ({.,}) =l=ey , then
1.PROPOSITION. Let
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e
have
VS- a)
=aVb=h
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CAl
Nt / P
s
) 2 - - ~ N
C l
o
: N-/p
s
) 2 - - ~ N
Moreover, N*/P
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and
C }()(flJ}) €G i f
Thatis
1 ,
In fac t the
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SMARANDAC
by I
Depar
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O
b
vi
o
u
sl
y,
.
2
)
SI
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5. Theorem [s
(N ,.)
in ( N , ~ , + )
and
(N °,·)
in N°
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Let p - l =
qj > p for j
el t.
It
follows
S(p
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T
HE PRO
Univ
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Ifp is
a
prime num
equation =
If q
s
a composite
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For x = y we ha.ve an equ
the
Lipschitz condition
Rema.rk
3.
In
it
is
.
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Proposition 4
The
~ " s l ' ~ ; t z
1 ' 1 ) , " " ; f ' , ~ "
-I ~ . . .
-'
-
- •.
P ~ ~ , ; f .
(Compa.re
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We
ha.ve:
Tndeed, if
.:t
= 1, then
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IUD'
BIS'rO
ADDENDA
(III) :
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cover
IV,
[106] Pe te r B
Losungen ,
Vol.
49, N
[107] Gh. Tomo
impotr iva
Ed.
Macar
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1993;
reviewed in <
11-06:
[131]
Gh.
Stroe
Bucharest ,
A
[132]
Dr. Dumi
Smarandache
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M a t e m a t i c ~ >
p . 43;
[148]
A.
Stuparu
Matematica
p .
43;
[149] Pedro
Me
Chisinau, R
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PROP
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A GENERAL
Let n be a
composi te
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N
IMPORT NT
FORM
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Henry Ibstedt, Smarandach
Marcela Popescu, Paul Popes
col lec t ion
of pa
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numbers
sequences i
qeometries alqebraic
and
loq ic etc .
Dr.
C Dum it r e s cu
Depar tment o f
Ma
Un ive r s i t y
o f
Cra